Given, below are two statements Statement I A speech signal of $2{\rm{ }}kHz$ is used to modulate a carrier signal of $1MHz.$ The bandwidth requirement for the signal is $4{\rm{ }}kHz$. Statement II The side band frequencies are $1002{\rm{ }}kHz$ and $998{\rm{ k}}Hz$. In the light of the above statements, choose the correct answer from the options given below

Statement I is true but Statement II is false.

Statement I is false but Statement II is true.

Both Statement I and Statement II are false.

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JEE • PHYSICS • COMMUNICATION SYSTEMS

Communication systems practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-136 of 136 questions

121 Medium

121 of 136

Remembering +4 | -1

The number of telephonic message which are carried by a fiber at an instant with much less intensity loss are

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Correct option: C

2000

Option C (2000) is correct because optical fibers can carry approximately 2000 telephonic messages at an instant with minimal intensity loss.

122 Medium

122 of 136

Remembering +4 | -1

Which of the following frequencies does not belong to FM broadcast.

View answer and explanation

Correct option: B

64 MHz

Option B (64 MHz) is correct because the FM broadcast frequency range is typically between 88 MHz and 108 MHz.

123 Hard

123 of 136

Understanding +4 | -1

Given, below are two statements
Statement I A speech signal of

2\mathrm{ }kHz

is used to modulate a carrier signal of

1MHz.

The bandwidth requirement for the signal is

4\mathrm{ }kHz

.
Statement II The side band frequencies are

1002\mathrm{ }kHz

and

998\mathrm{ k}Hz

. In the light of the above statements, choose the correct answer from the options given below

View answer and explanation

Correct option: C

Both Statement I and Statement II are true.

Option C is correct because the bandwidth requirement for AM is twice the modulating frequency, and the sideband frequencies are the carrier frequency plus or minus the modulating frequency.

124 Medium

124 of 136

Remembering +4 | -1

The fundamental radio antenna is a metal rod which has a length equal to

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Correct option: C

\lambda / 4

in free space at the frequency of operation

Option C (

\lambda / 4

in free space at the frequency of operation) is correct because a quarter-wave antenna is a fundamental and commonly used antenna design.

125 Medium

125 of 136

Understanding +4 | -1

A laser is a coherent source it contains

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Correct option: D

Coordinated waves of particular wavelength

Option D (Coordinated waves of particular wavelength) is correct because a laser emits coherent light, which consists of coordinated waves of a single wavelength.

126 Hard

126 of 136

Application +4 | -1

The glass of optical fiber has refractive index 1.55 and is clad with another glass of refractive index 1.51. When the surrounding is air, the numerical aperture will be

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Correct option: B

0.35

Option B (0.35) is correct because it is the result of applying the numerical aperture formula with the given refractive indices.

127 Medium

127 of 136

Remembering +4 | -1

Advantage of optical fibre is

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Correct option: D

High band width, high data transmission capacity and no EM interference

Option D (High band width, high data transmission capacity and no EM interference) is correct because optical fibers offer high bandwidth, high data transmission capacity, and immunity to electromagnetic interference.

128 Easy

128 of 136

Remembering +4 | -1

Modulation is the process of superposing

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Correct option: A

low frequency audio signal on high frequency waves

Option A (low frequency audio signal on high frequency waves) is correct because modulation involves superimposing a low-frequency audio signal onto a high-frequency carrier wave.

129 Medium

129 of 136

Application +4 | -1

A given fiber has core refractive index of 1.5 and a core cladding index difference factor (∆) of 0.01125. The numerical aperture is

View answer and explanation

Correct option: B

0.225

Option B (0.225) is correct because it is the result of applying the numerical aperture formula with the given refractive index and index difference factor.

130 Medium

130 of 136

Understanding +4 | -1

The closed structure of co-axial cable prevents inner copper wire or core or from radiating signal power. The statement is

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Correct option: A

TRUE

Option A (TRUE) is correct because the closed structure of a coaxial cable effectively shields the inner conductor, preventing signal power radiation.

131 Medium

131 of 136

Application +4 | -1

A diode AM detector with the output circuit consisting of

R = 1\;\mathrm{kW}

and

C = 1\;\mathrm{\mu F}

would be more suitable for detecting a carrier signal of

View answer and explanation

Correct option: D

10 kHz

Option D (

\frac{1}{3} \pi q f l^2

) is correct because the magnetic moment is calculated by integrating the current due to each infinitesimal charge element along the rod.

132 Medium

132 of 136

Understanding +4 | -1

The power radiated from a linear antenna of length

l

is proportional to

(Given,

\lambda=

Wavelength of wave):

View answer and explanation

Correct option: B

\left(\frac{l}{\lambda}\right)^{2}

Option B (

(\frac{l}{\lambda})^{2}

) is correct because the power radiated from a linear antenna is proportional to the square of the ratio of the antenna's length to the wavelength.

133 Medium

133 of 136

Application +4 | -1

In optical communication system operating at 1200 nm, only 2% of the source frequency is available for TV transmission having a bandwidth of 5 MHz. The number of TV channels that can be transmitted is

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Correct option: D

1 million

Option D (1 million) is correct because the number of channels is the total available bandwidth divided by the bandwidth per channel.

134 Medium

134 of 136

Application +4 | -1

To double the covering range of a TV transmission tower, its height should be multiplied by

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Correct option: B

Option B (4) is correct because the range of a TV transmission tower is proportional to the square root of its height, so to double the range, the height must be multiplied by 4.

135 Medium

135 of 136

Understanding +4 | -1

Venus looks brighter than other stars, due to

View answer and explanation

Correct option: B

It is closer to the earth than other stars

Option B (It is closer to the earth than other stars) is correct because proximity significantly affects apparent brightness.

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136 Medium

136 of 136

Understanding +4 | -1

Which of the following explain that all galaxies are receding from us?

View answer and explanation

Correct option: D

Red shift

Option D is correct. Redshift is the phenomenon where the light from distant galaxies is shifted towards the red end of the spectrum, indicating that they are moving away from us.

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