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JEE • PHYSICS • COMMUNICATION SYSTEMS

Communication systems practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 136 questions
91 Medium
91 of 136
Application +4 | -1
A carrier is simultaneously modulated by two sine waves having modulation indices of 0.3 and 0.4. The total modulation index will be
View answer and explanation
Correct option: B
0.5
Option B (0.5) is correct because the total modulation index is the square root of the sum of the squares of individual modulation indices.
92 Easy
92 of 136
Understanding +4 | -1
Through which mode of propagation, the radio waves can be sent from one place to another
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because radio waves can be sent from one place to another using ground wave, sky wave, and space wave propagation.
93 Medium
93 of 136
Remembering +4 | -1
Basically, a communication system is a
View answer and explanation
Correct option: C
Messenger
Option C (Messenger) is correct because a communication system essentially acts as a messenger, conveying information from one point to another.
94 Medium
94 of 136
Remembering +4 | -1
Which mode of communication is/are employed for the transmission of TV signals?
View answer and explanation
Correct option: C
Space wave propagation
Option C (Space wave propagation) is correct because TV signals are transmitted using space wave propagation or line of sight communication.
95 Medium
95 of 136
Application +4 | -1
A TV tower has a height 150 m. What is the total population covered by the TV tower, if the population density around the TV tower is 103  km−2?{10^3}\mathrm{\;k}{\mathrm{m}^{ - 2}}? Radius of the earth is 6.4×106  m.6.4 \times {10^6}\;\mathrm{m}.
View answer and explanation
Correct option: A
60.288 lakhs
Option A (60.288 lakhs) is correct because it is the total population covered by the TV tower, calculated using the given height, earth's radius, and population density.
96 Medium
96 of 136
Application +4 | -1
A radar sends an electromagnetic signal of electric field (E0)=2.25  V/m\left( {{E_0}} \right) = 2.25\,\,V/m and magnetic field (B0)=1.5 ×10−8T\left( {{B_0}} \right) = 1.5\, \times {10^{ - 8}}T which strikes a target on line of sight at a distance of 3 km in a medium. After that, a part of signal (echo) reflects back towards the radar with same velocity and by same path. If the signal was transmitted at time t=0t = 0 from radar, then after how much time echo will reach to the radar?
View answer and explanation
Correct option: B
4.0×10−5s4.0 \times {10^{ - 5}}s
Option B (4.0×10−5s4.0 \times {10^{ - 5}}s) is correct because the time taken for the echo to return is calculated by considering the distance and the velocity of the electromagnetic signal in the medium.
97 Medium
97 of 136
Understanding +4 | -1
What is the reason behind the disturbing of incoming and reflected signals when a low flying aircraft passes overhead, which results in slight shaking of the picture on our TV screen?
View answer and explanation
Correct option: A
Interference
Option A (Interference) is correct because the incoming and reflected signals interfere, causing fluctuations in the received signal strength.
98 Medium
98 of 136
Remembering +4 | -1
The characteristic impedance of a coaxial cable is of the order of
View answer and explanation
Correct option: C
270  Ω
Option A (50  Ω) is the closest to the typical characteristic impedance of a coaxial cable, which is usually around 50 or 75 ohms.
99 Medium
99 of 136
Understanding +4 | -1
The space wave propagation is utilized in
View answer and explanation
Correct option: D
Cannot be reflected by any layer of earth's atmosphere
Option D (Cannot be reflected by any layer of earth's atmosphere) is correct because space waves propagate directly through the atmosphere and are not reflected by any layer.
100 Hard
100 of 136
Understanding +4 | -1
In a radio receiver, the short wave and medium wave stations are tuned by using the same capacitor but coils of different inductance Ls{L_s} and Lm{L_m} respectively then
View answer and explanation
Correct option: B
Ls<Lm{L_s} < {L_m}
Option B (Ls<Lm{L_s} < {L_m}) is correct because short wave stations have higher frequencies than medium wave stations, and since frequency is inversely proportional to the square root of inductance, the inductance for short waves must be smaller.
101 Medium
101 of 136
Application +4 | -1
The velocity factor of a transmission line is x. If dielectric constant of the medium is 2.6, the value of x is
View answer and explanation
Correct option: B
0.62
Option B (0.62) is correct because the velocity factor is the inverse of the square root of the dielectric constant.
102 Medium
102 of 136
Application +4 | -1
What should be the height of transmitting antenna and the population covered, if the television telecast is to cover a radius of 150 km? The average population density around the tower is 2000/km22000/k{m^2} and the value of Re=6.5×106 m{R_e} = 6.5 \times {10^6}\,m.
View answer and explanation
Correct option: A
Height = 1731 m= \,1731\,m population covered =1413×105= 1413 \times {10^5}
Option A (Height = 1731 m= \,1731\,m population covered =1413×105= 1413 \times {10^5}) is correct because it is calculated using the formula for the height of the antenna and the area covered by the telecast.
103 Medium
103 of 136
Understanding +4 | -1
Antenna is
View answer and explanation
Correct option: D
Resistive at resonant frequency
Option D (Resistive at resonant frequency) is correct because at the resonant frequency, the inductive and capacitive reactances of the antenna cancel each other out, leaving only the resistance.
104 Medium
104 of 136
Application +4 | -1
A FM Broad cast transmitter, using modulating signal of frequency 20kHz20 \mathrm{kHz} has a deviation ratio of 10. The Bandwidth required for transmission is
View answer and explanation
Correct option: D
440 kHz
Option D (440 kHz) is correct because the bandwidth is calculated using Carson's rule: BW = 2(Δf + fm), where Δf is the frequency deviation and fm is the modulating signal frequency.
105 Medium
105 of 136
Remembering +4 | -1
Frequencies in the UHF range normally propagate by means of
View answer and explanation
Correct option: D
Space waves
Option D (Space waves) is correct because UHF frequencies typically propagate via space waves, which travel in a straight line from the transmitting antenna to the receiving antenna.
106 Medium
106 of 136
Understanding +4 | -1
A signal Acos⁡ωtA\cos \omega t is transmitted using v0sin⁡ω0t{v_0}\sin {\omega _0}t as carrier wave. The correct amplitude modulated (AM) signal is
View answer and explanation
Correct option: D
v0sin⁡ω0t+A2sin⁡(ω0−ω)t+A2sin⁡(ω0+ω)t{v_0}\sin {\omega _0}t + \frac{A}{2}\sin \left( {{\omega _0} - \omega } \right)t + \frac{A}{2}\sin \left( {{\omega _0} + \omega } \right)t
Option D is correct because it represents the amplitude modulated signal as the sum of the carrier wave and sidebands resulting from the modulation process.
107 Medium
107 of 136
Application +4 | -1
An AM wave has 1800 watt of total power content, for 100%100 \% modulation the carrier should have power content equal to
View answer and explanation
Correct option: B
1200 W1200 \mathrm{~W}
Option B (1200 W1200 \mathrm{~W}) is correct because the carrier power is calculated using the formula Pt=Pc(1+ma22)P_t = P_c(1 + \frac{m_a^2}{2}) with 100% modulation.
108 Medium
108 of 136
Remembering +4 | -1
A communication between a fixed base station and several mobile units, located on ships or aircraft utilising two way radio communication in the VHF and UHF is of frequency band
View answer and explanation
Correct option: C
30 to 470MHz470 {MHz}
Option C (30 to 470MHz470 {MHz}) is correct because VHF and UHF radio communication between a base station and mobile units typically uses frequencies in this range.
109 Medium
109 of 136
Understanding +4 | -1
Which of the following is not the frequency of frequency modulated (FM) signal?
View answer and explanation
Correct option: D
100 kHz100 \,\mathrm{kHz}
Option D (100 kHz100 \,\mathrm{kHz}) is correct because FM signals operate in the MHz range, not kHz.
110 Medium
110 of 136
Remembering +4 | -1
In earth&#39;s atmosphere, for F2{\mathrm{F}_2}-layer, the virtual height and critical frequency in night time are
View answer and explanation
Correct option: D
350 km and 6 MHz
Option D (350 km and 6 MHz) is correct because the virtual height of the F2 layer is typically around 350 km and the critical frequency is around 6 MHz during nighttime.
111 Medium
111 of 136
Remembering +4 | -1
The waves relevant to telecommunications are
View answer and explanation
Correct option: D
Microwave
Option D (Microwave) is correct because microwaves are commonly used in telecommunications due to their ability to penetrate the atmosphere and carry large amounts of information.
112 Hard
112 of 136
Application +4 | -1
Two electrons are moving in opposite direction with speeds 0.8 c and 0.4 c, where c the speed of light in vacuum. Then the relative speed is about
View answer and explanation
Correct option: C
0.9 c
Option C (0.9 c) is correct because it is the relative speed calculated using the relativistic velocity addition formula.
113 Medium
113 of 136
Application +4 | -1
A transmitting antenna of height h and the receiving antenna of height 45 m are separated by a distance of 40 km for satisfactory communication in line of sight mode. Then the value of h is
View answer and explanation
Correct option: B
20m
Option B (20m) is correct because it is the height calculated using the formula for the maximum distance for line of sight communication.
114 Medium
114 of 136
Understanding +4 | -1
Identify the incorrect statement from the following
View answer and explanation
Correct option: C
Modulation index &mu; is kept &ge;1, to avoid distortion
Option C is correct because the modulation index must be less than or equal to 1 to avoid overmodulation and distortion of the signal.
115 Medium
115 of 136
Application +4 | -1
An oscillator is producing FM waves of frequency 2 kHz with a variation of 10 kHz. What is the modulating index?
View answer and explanation
Correct option: B
5
Option B (5) is correct because the modulation index is the ratio of frequency deviation to modulating frequency.
116 Medium
116 of 136
Understanding +4 | -1
A radio station has two channels. One is AM at 1020 kHz and the other FM at 89.5 Mhz. For good results you will use
View answer and explanation
Correct option: A
Longer antenna for the AM channel and shorter for the FM
Option A is correct because the antenna length is related to the wavelength of the signal, and AM has a longer wavelength than FM.
117 Medium
117 of 136
Remembering +4 | -1
A laser device produces amplification in the
View answer and explanation
Correct option: B
Ultraviolet or visible region
Option B (Ultraviolet or visible region) is correct because lasers operate in the ultraviolet, visible, or infrared regions of the electromagnetic spectrum.
118 Medium
118 of 136
Application +4 | -1
A TV transmission tower has a height of 140 m and the height of the receiving antenna is 40 m. What is the maximum distance upto which signals can be broadcasted from this tower in LOS (Line of Sight) mode? (Take, radius of earth =6.4×106m)= 6.4 \times {10^6}m)
View answer and explanation
Correct option: A
65 km
Option A (65 km) is correct because it is calculated by summing the distances from both the transmitting and receiving antennas using the given formula.
119 Medium
119 of 136
Understanding +4 | -1
In satellite communication, the communication satellite;
View answer and explanation
Correct option: C
Receives the coming modulated microwave signal, amplifies it and returns it to earth at a different frequency
Option C (Receives the coming modulated microwave signal, amplifies it and returns it to earth at a different frequency) is correct because communication satellites act as repeaters, amplifying and retransmitting signals at different frequencies.
120 Medium
120 of 136
Understanding +4 | -1
zone layer above earth's atmosphere will not
View answer and explanation
Correct option: D
Reflect back radio waves
Option D (Reflect back radio waves) is correct because the ozone layer primarily absorbs UV radiation and does not significantly reflect radio waves, which are reflected by the ionosphere.
Revision notes and key takeaways

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