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JEE • PHYSICS • ATOMS

Atoms practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 248 questions

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181 Medium
181 of 248
Analyzing +4 | -1
An X-ray tube with a copper target is found to be emitting lines other than those due to copper. The KαK_\alpha line of copper is known to have a wavelength 1.5405A∘1.5405 \mathop {\text{A}}\limits^ \circ and the other two KαK_\alpha lines observed have wavelengths 0.7090A∘0.7090 \mathop {\text{A}}\limits^ \circ and 1.6578A∘1.6578 \mathop {\text{A}}\limits^ \circ. Identify the impurities.
View answer and explanation
Correct option: C
Both (1) and (2)
Option C is correct because the impurities identified using Moseley's law are Molybdenum and Nickel, based on the given wavelengths of the emitted X-ray lines.
182 Medium
182 of 248
Analyzing +4 | -1
Assertion (A): Between any two given energy levels, the number of absorption transitions is always less than or equal to the number of emission transitions.

Reason (R): Absorption transitions start from the lowest energy level only and may end at any higher energy level. But emission trasitions may start from any higher energy level and end at an energy level below it.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A (Both (A) and (R) are true and (R) is the correct explanation of (A)) is correct because the number of absorption transitions is limited by the availability of electrons in the lowest energy level, while emission transitions can occur from multiple higher energy levels.
183 Medium
183 of 248
Application +4 | -1
The wavelength of radiation emitted is λ0{\lambda _0} when an electron jumps from the third to second orbit of hydrogen atom. For the electron jump from fourth to the second orbit of the hydrogen atom, the wavelength of radiation emitted will be
View answer and explanation
Correct option: B
(2027)λ0\left( {\frac{{20}}{{27}}} \right){\lambda _0}
Option B ((2027)λ0\left( {\frac{{20}}{{27}}} \right){\lambda _0}) is correct because it's the wavelength of radiation emitted when an electron jumps from the fourth to the second orbit, calculated using the Rydberg formula.
184 Medium
184 of 248
Understanding +4 | -1
Assertion: Bohr's atomic model can be applied for every atom.

Reason: The energy state of election in atom is continuous.
View answer and explanation
Correct option: D
If the assertion and reason both are false
Option D is correct because Bohr's model is only applicable to single-electron species, and the energy states of electrons in atoms are quantized, not continuous.
185 Medium
185 of 248
Understanding +4 | -1
The energy required to remove one of the electrons from a neutral helium atom is 24.6 eV. The energy required to remove both the electrons from a neutral helium atom is
View answer and explanation
Correct option: D
79 eV
Option D (79 eV) is correct because the total energy required is the sum of the energy to remove the first electron (24.6 eV) and the ionization energy of He+ (54.4 eV).
186 Medium
186 of 248
Application +4 | -1
Consider a hydrogen like atom in Bohr's model. It is given that difference between (n+1)th(n+1)^{\text {th}} Bohr's radius and nthn^{\text {th}} Bohr's radius is equal to (n−1)th(n-1)^{\text {th}} Bohr's radius, then the energy of nthn^{\text {th}} state (in eV\mathrm{eV}) is [Z={Z}= atomic number]
View answer and explanation
Correct option: A
−0.85 Z2-0.85 ~Z^2
Option A (-0.85 Z²) is correct because it is the energy of the nth state calculated after finding the value of n using the given condition on Bohr's radii.
187 Medium
187 of 248
Understanding +4 | -1
In the above figure DD and EE respectively represent
View answer and explanation
Correct option: A
Absorption line of Balmer series and the ionization energy of hydrogen
The correct answer is Absorption line of Balmer series and the ionization energy of hydrogen because D represents the absorption of energy to excite an electron from n=2, and E represents the energy required to remove an electron from the ground state.
188 Medium
188 of 248
Application +4 | -1
If scattering particles are 56\mathrm{56} for 90∘{90^\circ } angle, then at an angle 60∘{60^\circ } it will be
View answer and explanation
Correct option: A
224
Option A (224) is correct because the number of scattered particles is inversely proportional to the fourth power of the sine of half the scattering angle.
189 Medium
189 of 248
Understanding +4 | -1
The angular momentum of an electron in the first orbit of Li++{Li}^{++}ion is
View answer and explanation
Correct option: C
h2π\frac{h}{2 \pi}
Option C (h2π\frac{h}{2 \pi}) is correct because the angular momentum of an electron in the first orbit is given by nh2π\frac{nh}{2\pi} with n=1.
190 Medium
190 of 248
Understanding +4 | -1
Assertion (A): In a metal all the free electrons have same energy.

Reason (R): Electrons do not obey Pauli's exclusive principle.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D (Both (A) and (R) are false) is correct because free electrons in a metal do not have the same energy, and electrons do obey Pauli's exclusion principle.
191 Medium
191 of 248
Understanding +4 | -1
The electron in a hydrogen atom makes a transition from an excited state to the ground state. Which of the following statements is true
View answer and explanation
Correct option: A
Its kinetic energy increases and its potential and total energies decrease
Option A (Its kinetic energy increases and its potential and total energies decrease) is correct because as the electron transitions to a lower energy level, its kinetic energy increases while potential and total energies decrease.
192 Medium
192 of 248
Remembering +4 | -1
The voltage applied across an X-ray tube is nearly equal to
View answer and explanation
Correct option: D
10, 000 V
Option D (10,000 V) is correct because the voltage applied across an X-ray tube is typically in the kilovolt range to produce X-rays with sufficient energy.
193 Medium
193 of 248
Understanding +4 | -1
In Bohr’s atomic model of hydrogen, let K, P and E are the kinetic energy, potential energy and total energy of the electron respectively. Choose the correct option when the electron undergoes transitions to a higher level:
View answer and explanation
Correct option: B
K decreases, P and E increase
Option B (K decreases, P and E increase) is correct because as the electron transitions to a higher energy level, its kinetic energy decreases while its potential and total energy increase (become less negative).
194 Medium
194 of 248
Application +4 | -1
An electron in the hydrogen atom jumps excited state nn to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75  eV.2.75\;eV. If the stopping potential of the photoelectron is 10  eV,10\;eV, then the value of nn is
View answer and explanation
Correct option: D
4
Option D (4) is correct because the energy difference between the excited state n and the ground state corresponds to the energy of the emitted photon, which can be calculated from the work function and stopping potential.
195 Medium
195 of 248
Remembering +4 | -1
Davisson and Germer experiment proved
View answer and explanation
Correct option: A
Wave nature of light
Option A (Wave nature of light) is correct because the Davisson-Germer experiment demonstrated the wave-like properties of electrons, confirming de Broglie's hypothesis and thus the wave nature of matter, not light.
196 Medium
196 of 248
Analyzing +4 | -1
Consider Bohr's atomic theory of single electron system, where the transition of electron from fourth excited state to second excited state of Lithium emits radiation which knocks out the electron from fourth excited state of an atom of an element. The atomic number of the element is
View answer and explanation
Correct option: A
4
Option A (4) is correct because the energy emitted during the transition in Lithium is equal to the energy required to knock out the electron from the fourth excited state of the element.
197 Medium
197 of 248
Remembering +4 | -1
In the lowest energy level of hydrogen atom, the electron has the angular momentum
View answer and explanation
Correct option: C
h/2πh/2\pi
Option C (h/2πh/2\pi) is correct because, according to Bohr's model, the angular momentum of an electron in the lowest energy level (n=1) of a hydrogen atom is given by L=nh/2πL = nh/2\pi, where n=1.
198 Medium
198 of 248
Analyzing +4 | -1
Which of the following statements about the Bohr model of the hydrogen atom is false
View answer and explanation
Correct option: D
Potential energy of electron in n=2n = 2 orbit is less than that in n=1n = 1 orbit
Option D is correct because the potential energy of an electron becomes less negative (increases) as n increases in the Bohr model.
199 Medium
199 of 248
Understanding +4 | -1
X-rays and γ\gamma-rays of the same energies may be distinguished by
View answer and explanation
Correct option: D
Method of production
Option D (Method of production) is correct because X-rays are produced by accelerating electrons, while gamma rays are produced by nuclear transitions.
200 Medium
200 of 248
Analyzing +4 | -1
In the hydrogen atom, an electron makes a transition from n=2\mathrm{n}=2 to n=1\mathrm{n}=1. The magnetic field produced by the circulating electron at the nucleus
View answer and explanation
Correct option: D
increases 32 times
Option D (increases 32 times) is correct because the magnetic field produced by the circulating electron at the nucleus is inversely proportional to n5n^5, so when n changes from 2 to 1, the magnetic field increases by a factor of 25=322^5 = 32.
201 Medium
201 of 248
Understanding +4 | -1
In radio therapy, XX-rays are used to
View answer and explanation
Correct option: B
Treat cancer by controlled exposure
Option B (Treat cancer by controlled exposure) is correct because X-rays are used in radiotherapy to kill cancer cells through targeted radiation.
202 Medium
202 of 248
Application +4 | -1
The angular momentum of an electron in hydrogen atom is 5h2π\frac{5 h}{2 \pi}. Here hh is the Plank's constant. The potential energy of this electron is
View answer and explanation
Correct option: C
−1.088 eV-1.088 \,{eV}
Option C (-1.088 eV) is correct because the potential energy is calculated using the formula U=−27.2n2U = \frac{{-27.2}}{{n^2}} eV, where n=5.
203 Medium
203 of 248
Remembering +4 | -1
In Bohr’s model of hydrogen atom, which of the following represents the variation of nth orbit radius with n?
View answer and explanation
Correct option: D
rn∝n2{r_n} \propto {n^2}
Option D (rn∝n2{r_n} \propto {n^2}) is correct because, according to Bohr's model, the radius of the nth orbit is proportional to the square of the principal quantum number n.
204 Medium
204 of 248
Understanding +4 | -1
The Bohr model of atoms
View answer and explanation
Correct option: B
assumes that the angular momentum of electrons is quantised
Option B (assumes that the angular momentum of electrons is quantised) is correct because Bohr's model postulates that the angular momentum of electrons in atoms is quantized.
205 Medium
205 of 248
Understanding +4 | -1
Whenever a hydrogen atom emits a photon in the Balmer series
View answer and explanation
Correct option: C
It must emit another photon in the Lyman series
Option C (It must emit another photon in the Lyman series) is correct because after emitting a Balmer series photon, the electron must transition to the ground state, which involves emitting a Lyman series photon.
206 Medium
206 of 248
Analyzing +4 | -1
An ionised H{H}-molecule consist of an electron and two protons. One proton are separated by a small distance of the order of angstrom. In the ground state
View answer and explanation
Correct option: A
The electron would not move in circular orbits
Option A (The electron would not move in circular orbits) is correct because the presence of two protons separated by a small distance will result in a non-uniform electric field, preventing the electron from moving in a perfect circular orbit.
207 Medium
207 of 248
Understanding +4 | -1
An electron in the n=1n = 1 orbit of hydrogen atom is bounded by 13.6  eV13.6\,\,eV. Energy requires to ionize it is
View answer and explanation
Correct option: A
13.6  eV13.6\,\,eV
Option A (13.6 eV) is correct because the ionization energy is equal to the binding energy for an electron in the n=1 orbit.
208 Medium
208 of 248
Remembering +4 | -1
The wavelength of X-rays is of the order of
View answer and explanation
Correct option: C
Angstrom  (10−10m)Angstrom\;\left( {{{10}^{ - 10}}m} \right)
Option C (Angstrom  ({10−10m)Angstrom\;(\{{{10}}^{ - 10}m)) is correct because the wavelength of X-rays falls within the Angstrom range.
209 Medium
209 of 248
Understanding +4 | -1
For the structural analysis of crystals, XX-rays are used because
View answer and explanation
Correct option: A
XX-rays have wavelength of the order of interatomic spacing
Option A (XX-rays have wavelength of the order of interatomic spacing) is correct because X-rays with wavelengths comparable to interatomic distances are diffracted by the crystal lattice, allowing for structural analysis.
210 Medium
210 of 248
Remembering +4 | -1
The structure of solid crystals is investigated by using
View answer and explanation
Correct option: B
XX-rays
Option B (XX-rays) is correct because X-rays have wavelengths suitable for investigating the structure of solid crystals through diffraction.
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