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JEE • PHYSICS • ALTERNATING CURRENT

Alternating current practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 121-150 of 279 questions

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121 Hard
121 of 279
Application +4 | -1
The peak voltage of 220 volt AC mains (in volt) is
View answer and explanation
Correct option: C
311
Option C (311) is correct because the peak voltage is calculated by multiplying the RMS voltage by the square root of 2.
122 Medium
122 of 279
Understanding +4 | -1
A soft iron rod is inserted in the solenoid. After this what will be the effect on the brightness of the bulb?
View answer and explanation
Correct option: A
Brightness will decrease
Option A (Brightness will decrease) is correct because inserting a soft iron rod increases the inductance, which increases impedance and decreases current, thus reducing brightness.
123 Medium
123 of 279
Understanding +4 | -1
Power consumed in A.C circuit is zero then the ac source could be connected to
View answer and explanation
Correct option: D
Both (2) and (3)
Option D (Both (2) and (3)) is correct because power consumed in a purely inductive or capacitive AC circuit is zero.
124 Medium
124 of 279
Understanding +4 | -1
Statement (A): Step up transformer converts low voltage, high current to high voltage, low current.

Statement (B): Transformer works on both ac and dc.
View answer and explanation
Correct option: B
(A) is true but (B) is false
Option B ((A) is true but (B) is false) is correct because step-up transformers increase voltage and decrease current, but transformers only operate on AC due to the need for a changing magnetic field.
125 Easy
125 of 279
Understanding +4 | -1
The core of a transformer is laminated to reduce energy losses due to
View answer and explanation
Correct option: A
Eddy currents
Option A (Eddy currents) is correct because laminating the core increases resistance, reducing the magnitude of eddy currents and thus energy losses.
126 Medium
126 of 279
Application +4 | -1
A resistor of R=6Ω, an inductor of L = 1 H and a capacitor of C=17.36 μF are connected in series with an AC source. Find the Q - factor.
View answer and explanation
Correct option: B
40
Option B (40) is correct because the Q-factor is calculated using the formula Q = (1/R) * sqrt(L/C).
127 Medium
127 of 279
Application +4 | -1
A bulb rated 60 W60 \mathrm{~W} at 220 V220 \mathrm{~V} is connected across a household supply of alternating voltage of 220 V220 \mathrm{~V}. Calculate the maximum instantaneous current through the filament.
View answer and explanation
Correct option: A
0.39 A
Option A (0.39 A) is correct because it calculates the maximum instantaneous current using the power rating and voltage.
128 Medium
128 of 279
Application +4 | -1
Consider an a.c circuit having resistor of resistance RR and an inductor having reactance XL.X_L. If voltage leads the current by an angle 60∘,60^{\circ}, then
View answer and explanation
Correct option: C
XL=3RX_L=\sqrt{3} R
Option C (XL=3RX_L=\sqrt{3} R) is correct because it correctly relates the inductive reactance and resistance based on the given phase angle.
129 Medium
129 of 279
Application +4 | -1
An LC current contains inductance L=1μH\mathrm{L}=1 \mu \mathrm{H} and capacitance C=0.01μF\mathrm{C}=0.01 \mu \mathrm{F}. The wavelength of electromagnetic wave generated is nearly :-
View answer and explanation
Correct option: C
188 m188 \mathrm{~m}
Option C (188 m) is correct because the wavelength is calculated using the formula λ=c⋅2πLC\lambda = c \cdot 2 \pi \sqrt{LC}.
130 Medium
130 of 279
Application +4 | -1
A 220 V, 50 Hz ac source is connected to an inductance of 0.2 H and a resistance of 20 ohm in series. What is the current in the circuit
View answer and explanation
Correct option: D
3.33A
Option D (3.33A) is correct because the current in the series RL circuit is calculated using Ohm's law and impedance.
131 Easy
131 of 279
Application +4 | -1
Statement I: In a series R−L−CR-L-C circuit the voltage across-resistor, inductor and capacitor are 8 V,16 V8 \mathrm{~V}, 16 \mathrm{~V} and 10 V10 \mathrm{~V} respectively. The resultant emf in the circuit is 10 V10 \mathrm{~V}.

Statement II: Resultant emf of the circuit is given by the relation E=VR2+(VL−VC)2E=\sqrt{V_R^2+\left(V_L-V_C\right)^2}.
View answer and explanation
Correct option: A
Statement I is true, Statement II is true; Statement II is
the correct explanation for Statement I
Statement I is true, and Statement II is also true and the correct explanation for Statement I because the resultant EMF is calculated using the given formula and matches the statement.
132 Easy
132 of 279
Application +4 | -1
A step-up transformer is used on a 120 V line to provide a potential difference of 2400 V. If the primary coil has 75 turns, the number of turns in the secondary coil is
View answer and explanation
Correct option: C
1500
Option C (1500) is correct because the ratio of turns in the secondary to primary coil is equal to the ratio of voltages.
133 Medium
133 of 279
Analyzing +4 | -1
Assertion(A): Two identical heaters are connected to two
different sources one DC and other AC having same
potential difference across their terminals. The heat
produced in heater supplied with DC source is greater.

Reason (R): The net impedance of an AC source is
greater than resistance.
View answer and explanation
Correct option: D
Both Assertion and Reason are true but Reason is not
true explanation of Assertion
Option D (Both Assertion and Reason are true but Reason is not true explanation of Assertion) is correct because both statements are true, but the reason doesn't explain why the DC heater produces more heat.
134 Medium
134 of 279
Understanding +4 | -1
A lamp (pure resistance) is connected in series with a capacitor

A) When a dc source is connected to the combination, the lamp will not glow in steady state

B) When ac source is connected to the combination, the brightness of glow of lamp increases with increases of frequecncy of ac.
View answer and explanation
Correct option: C
A & B are true
Option C is correct because with a DC source, the capacitor blocks current in steady state, while with an AC source, the capacitor allows current flow, and increasing frequency decreases capacitive reactance, increasing brightness.
135 Medium
135 of 279
Understanding +4 | -1
A Daniel cell is connected to the primary coil of a transformer. If the output voltage of the Daniel cell is 10 V10 \mathrm{~V}, and the ratio of secondary to primary coil turns of transformer is 2 , then the voltage in the secondary will be
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because transformers only work with alternating current (AC), and a Daniel cell provides direct current (DC).
136 Medium
136 of 279
Analyzing +4 | -1
A charged capacitor is discharged through a resistance. The time constant of the circuit is η\eta. Then, the value of time constant for the power dissipated through the resistance will be
View answer and explanation
Correct option: C
η/2\eta / 2
Option C is correct because the power dissipated is proportional to the square of the current, so the time constant for power is half the time constant for current.
137 Medium
137 of 279
Application +4 | -1
A 16  μF16\,\,\mu F capacitor is charged to a 20  volt\mathrm{20}\,\,\mathrm{volt} potential. The battery is then disconnected and pure 40  mH40\,\,mH coil is connected across the capacitor so that LC\mathrm{LC} oscillations are setup. The maximum current in the coil is
View answer and explanation
Correct option: D
0.4  A0.4\,\,A
Option D (0.4 A0.4\,A) is correct because it represents the maximum current in the LC circuit, calculated using energy conservation.
138 Medium
138 of 279
Application +4 | -1
For a series L−C−RL - C - R circuit with R=100 ΩR = 100\,\Omega, L=0.5mHL = 0.5\mathrm{ mH} and C=0.1 pFC = 0.1\,\mathrm{pF} connected across 220V−50Hz AC\mathrm{220V} - 50\mathrm{ Hz\, AC} supply, the phase angle between current and supplied voltage and the nature of the circuit is
View answer and explanation
Correct option: D
≈90o\approx {90^\mathrm{o}}, predominantly capacitive circuit
Option D (≈90o\approx {90^\mathrm{o}}, predominantly capacitive circuit) is correct because the capacitive reactance is much greater than the inductive reactance, making the circuit predominantly capacitive.
139 Medium
139 of 279
Analyzing +4 | -1
Assertion: In series LCR circuit phase difference between current and voltage is never zero.

Reason: Voltage and current are never in phase.
View answer and explanation
Correct option: D
If both Assertion & Reason are false
Option D is correct because both the assertion and reason are false; the phase difference can be zero at resonance, and voltage and current can be in phase.
140 Medium
140 of 279
Application +4 | -1
A capacitor of capacitance 100 μF100 \, \mu \mathrm{F} and a coil of resistance 50 Ω50 \, \Omega and inductance 0.5 H0.5 \, \mathrm{H} are connected in series with a 110 V,50 Hz110 \mathrm{~V}, 50 \mathrm{~Hz} AC source. Find the rms value of the current.
View answer and explanation
Correct option: A
0.82 A0.82 \mathrm{~A}
Option A (0.82 A) is correct because the RMS current is calculated by dividing the RMS voltage by the impedance of the series RLC circuit.
141 Medium
141 of 279
Application +4 | -1
A 500μH500 \mu \mathrm{H} inductor, 80π2pF\frac{80}{\pi^2} \mathrm{pF} capacitor and a 628 Ω628 ~\Omega resistor are connected to form a series LCR circuit. Calculate the resonant frequency and QQ-factor of this circuit at resonance
View answer and explanation
Correct option: B
ff=2500 kHz,Q=12.5f_f=2500 \mathrm{~kHz}, Q=12.5
Option A (ff=2500 kHz,Q=10f_f=2500 \mathrm{~kHz}, Q=10) is incorrect. Option B (ff=2500 kHz,Q=12.5f_f=2500 \mathrm{~kHz}, Q=12.5) is correct because the resonant frequency and Q-factor are calculated using the standard formulas for a series LCR circuit.
142 Medium
142 of 279
Analyzing +4 | -1
Voltage and current in an ac circuit are given by V=5sin⁡(100πt−π6)V=5 \sin \left(100 \pi t-\frac{\pi}{6}\right) and I=4sin⁡(100πt+π6)I=4 \sin \left(100 \pi t+\frac{\pi}{6}\right)
View answer and explanation
Correct option: C
Current leads the voltage by 60∘60^{\circ}
Option C (Current leads the voltage by 60∘60^{\circ}) is correct because the phase angle of the current is π6\frac{\pi}{6} and the phase angle of the voltage is −π6-\frac{\pi}{6}, so the current leads by π3\frac{\pi}{3} which is 60∘60^{\circ}.
143 Medium
143 of 279
Application +4 | -1
AA radio set operates at 6 V6 \mathrm{~V} DC. A transformer with 18 turns in the secondary coil is used to step down the input 220 V AC emf to 6 V AC emf. This AC emf is then rectified by another circuit to give 6 V DC which is fed to the radio. Find the number of turns in the primary.
View answer and explanation
Correct option: A
660
Option A (660) is correct because the number of turns in the primary coil is calculated using the transformer equation.
144 Medium
144 of 279
Understanding +4 | -1
The power in ac circuit is given by P=ErmsIrmscos⁡ϕ.P = {E_{rms}}{I_{rms}}\cos \phi . The value of cos⁡ϕ\cos \phi in series LCR circuit at resonance is
View answer and explanation
Correct option: B
1
Option B (1) is correct because at resonance in a series LCR circuit, the impedance is equal to the resistance, making the power factor (cos⁡ϕ\cos \phi) equal to 1.
145 Medium
145 of 279
Understanding +4 | -1
Power factor of series LCR circuit at resonance is
View answer and explanation
Correct option: C
1
Option C (1) is correct because at resonance, the impedance is purely resistive, and the phase angle between voltage and current is zero, resulting in a power factor of 1.
146 Medium
146 of 279
Application +4 | -1
A transformer steps up an A.C. voltage from 230 v to 2300 v. If the number of turns in the secondary coil is 1000, the number of turns in the primary coil will be
View answer and explanation
Correct option: A
100
Option A (100) is correct because the number of turns in the primary coil is inversely proportional to the voltage in a transformer.
147 Easy
147 of 279
Understanding +4 | -1
In an ideal choke, ratio of its inductance L to its DC resistance R is
View answer and explanation
Correct option: A
Infinity
Option A (Infinity) is correct because an ideal choke has zero DC resistance, making the ratio of inductance to resistance infinite.
148 Medium
148 of 279
Application +4 | -1
By what percent the impedance in an series LCR, AC circuit should be increased so that the power factor changes from (1/2)\left( {1/2} \right) to (1/4) ?\left( {1/4} \right)\,? (assume resistance RR remains constant)
View answer and explanation
Correct option: B
100  %100\,\,\%
Option B (100  %100\,\,\% ) is correct because the impedance doubles when the power factor changes from 1/2 to 1/4, indicating a 100% increase.
149 Medium
149 of 279
Analyzing +4 | -1
Assertion: When capacitive reactance is smaller then the inductive reactance in series LCR circuit, voltage leads the current.

Reason: In series LCR circuit inductive reactance is always greater then capacitive reactance.
View answer and explanation
Correct option: C
If Assertion is True but the Reason is False
Option C is correct because the assertion is true (voltage leads current when capacitive reactance is smaller), but the reason is false (inductive reactance is not always greater).
150 Medium
150 of 279
Understanding +4 | -1
A resistance R, inductance L and capacitor C are connected in series to an oscillator of frequency ff. If resonant frequency is ff, then current will lag the voltage when
View answer and explanation
Correct option: D
f>frf > {f_r}
Option D is correct. Current lags the voltage when the frequency is greater than the resonant frequency, indicating an inductive circuit.
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