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JEE • MATHEMATICS • TRIGONOMETRIC EQUATIONS

Trigonometric equations practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 261 questions

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181 Easy
181 of 261
Application +4 | -1
3cos⁡θ+cos⁡3θ3sin⁡θ−sin⁡3θ\frac{3 \cos \theta+\cos 3 \theta}{3 \sin \theta-\sin 3 \theta} is equal to
View answer and explanation
Correct option: C
cot⁡3θ\cot ^3 \theta
Option C (cot⁡3θ\cot^3 \theta) is correct because by applying the triple angle formulas for cosine and sine, the expression simplifies to cot⁡3θ\cot^3 \theta.
182 Easy
182 of 261
Analyzing +4 | -1
The general solution of sin⁡2  θ  sec⁡  θ+3  tan⁡  θ=0{\sin ^2}\,\,\mathrm{\theta }\,\,\sec \,\,\mathrm{\theta } + \sqrt 3 \,\,\tan \,\,\mathrm{\theta } = 0 is
View answer and explanation
Correct option: B
θ=nπ,   n∈I\mathrm{\theta } = n\pi ,\;\,n \in I
Option B (θ = nπ, n ∈ I) is correct because the equation simplifies to tan θ (sin θ + √3) = 0, and since sin θ + √3 ≠ 0, we have tan θ = 0, which gives θ = nπ.
183 Easy
183 of 261
Analyzing +4 | -1
The possible values of θ∈(0,π)\theta \in(0, \pi) such that sin⁡(θ)+sin⁡(4θ)+sin⁡(7θ)=0\sin (\theta)+\sin (4 \theta)+\sin (7 \theta)=0 are
View answer and explanation
Correct option: D
2π9,π4,4π9,π2,3π4,8π9\frac{2 \pi}{9}, \frac{\pi}{4}, \frac{4 \pi}{9}, \frac{\pi}{2}, \frac{3 \pi}{4}, \frac{8 \pi}{9}
The correct answer is D because it lists all the values of θ∈(0,π)\theta \in (0, \pi) that satisfy the given trigonometric equation.
184 Easy
184 of 261
Understanding +4 | -1
If ∣x∣<3|x| < 3 and xx is a real number, then −m<x<m-m < x < m. The value of mm is
View answer and explanation
Correct option: A
3
Option A (3) is correct because the definition of absolute value implies that if ∣x∣<3|x| < 3, then −3<x<3-3 < x < 3, thus m=3m = 3.
185 Easy
185 of 261
Application +4 | -1
Let −π6<θ<−π12-\frac{\pi}{6} < \theta < -\frac{\pi}{12}. suppose α1\alpha_1 and β1\beta_1 are the roots of the equation x2−2xsec⁡θ+1=0x^2-2 x \sec \theta+1=0 and α2,β2\alpha_2, \beta_2 are the roots of the equation x2+2xtan⁡θ−1=0x^2+2 x \tan \theta-1=0. If α1>β1\alpha_1 > \beta_1 and α2>β2\alpha_2 > \beta_2, then α1+β2\alpha_1+\beta_2 equals
View answer and explanation
Correct option: C
−2tan⁡θ-2 \tan \theta
Option C (-2 tan θ) is correct because it is derived by finding the roots of the given equations and summing α_1 and β_2.
186 Easy
186 of 261
Application +4 | -1
The solution of the equation tan⁡2θtan⁡θ=1\tan 2 \theta \tan \theta=1 is
View answer and explanation
Correct option: A
θ=nπ±π6\theta=n \pi \pm \frac{\pi}{6}
Option A (θ=nπ±π6\theta=n \pi \pm \frac{{\pi}}{{6}}) is correct because it represents the general solution derived from solving the given trigonometric equation.
187 Easy
187 of 261
Application +4 | -1
If α,   β∈(0,   π2),  sin⁡  α=45\alpha ,\;\,\beta \in \left( {0,\;\,\frac{\pi }{2}} \right),\,\,\sin \,\,\alpha = \frac{4}{5} and cos⁡  (α+β)=−1213\cos \,\,\left( {\alpha + \beta } \right) = - \frac{{12}}{{13}}, then sin⁡  β\sin \,\,\beta is equal to

View answer and explanation
Correct option: A
6365\frac{{63}}{{65}}
Option A, 6365\frac{{63}}{{65}}, is correct because it is the value of sin⁡ β\sin \,\beta calculated using the given values of sin⁡ α\sin \,\alpha and cos⁡ (α+β)\cos \,\left( {\alpha + \beta } \right) and the trigonometric identity for sin⁡(α+β−α)\sin(\alpha + \beta - \alpha).
188 Easy
188 of 261
Application +4 | -1
Let A=sin⁡4x+cos⁡4x,x∈RA=\sin ^4 x+\cos ^4 x, x \in \mathbf{R}, then
View answer and explanation
Correct option: A
12≤A≤1\frac{1}{2} \leq A \leq 1
The correct answer is A (12≤A≤1\frac{1}{2} \leq A \leq 1) because by simplifying the expression and using the range of sin²(2x), we can find the range of A.
189 Easy
189 of 261
Analyzing +4 | -1
If f(θ)=sin⁡4θ+cos⁡4θ+1f(\theta)=\sin ^4 \theta+\cos ^4 \theta+1, then range of f(θ)f(\theta) is
View answer and explanation
Correct option: A
[32,2]\left[\frac{3}{2}, 2\right]
Option A ([32,2]\left[\frac{3}{2}, 2\right]) is correct because it represents the range of the function after simplification using trigonometric identities.
190 Easy
190 of 261
Analyzing +4 | -1
In a △PQR\triangle P Q R, if 3sin⁡P+4cos⁡Q=63 \sin P+4 \cos Q=6 and 4sin⁡Q+3cos⁡P=14 \sin Q+3 \cos P=1, then ∠R\angle R is equal to
View answer and explanation
Correct option: B
π6\frac{\pi}{6}
Option B (π6\frac{\pi}{6}) is correct because solving the system of trigonometric equations and considering the possible values for angles in a triangle leads to this result.
191 Easy
191 of 261
Application +4 | -1
Solution to the equation tan⁡pθ−cot⁡qθ\tan p \theta-\cot q \theta is
View answer and explanation
Correct option: A
(2n+1)(p+q)π2,n∈I\frac{(2 n+1)}{(p+q)} \frac{\pi}{2}, n \in I
Option A is correct because the solution is derived by simplifying the given trigonometric equation and solving for θ\theta.
192 Easy
192 of 261
Analyzing +4 | -1
The number of solutions of the equation tan⁡  x+sec⁡  x=2  cos⁡  x\tan \,\,x + \sec \,\,x = 2\,\,\cos \,\,x and cos⁡  x≠0\cos \,\,x \ne 0 lying in the interval (0,   2π)\left( {0,\;\,2\pi } \right)is

View answer and explanation
Correct option: A
2\mathrm{2}
Option A (2) is correct because the equation has two solutions in the given interval after considering the domain restrictions.
193 Easy
193 of 261
Application +4 | -1
If cos⁡A3=cos⁡B4=15−π2<A<0\frac{\cos A}{3}=\frac{\cos B}{4}=\frac{1}{5}-\frac{\pi}{2} < A < 0 and −π2<B<0-\frac{\pi}{2} < B < 0, then the value of 2sin⁡A+4sin⁡B2 \sin A+4 \sin B is
View answer and explanation
Correct option: C
−4-4
Option C (-4) is correct because it is the result of calculating 2sin⁡A+4sin⁡B2 \sin A + 4 \sin B using the given conditions and quadrant information.
194 Easy
194 of 261
Application +4 | -1
A root of the equation sin⁡x+x−1=0\sin x+x-1=0 lies in the interval
View answer and explanation
Correct option: A
(0,π2)\left(0, \frac{\pi}{2}\right)
Option A (0,π2)\left(0, \frac{\pi}{2}\right) is correct because the equation sin⁡x+x−1=0\sin x + x - 1 = 0 has a root in this interval, which can be seen by observing the behavior of the function at the interval's endpoints.
195 Easy
195 of 261
Application +4 | -1
If cot⁡  x+cosec    x=3\cot \,\,x + \mathrm{cose}c\;\,\,x = \sqrt 3, then the principle value of (x−π6)\left( {x - \frac{\pi }{6}} \right) is
View answer and explanation
Correct option: D
π6\frac{\pi }{6}
Option D (π6\frac{\pi }{6}) is correct because solving the given trigonometric equation cot⁡x+csc⁡x=3\cot x + \csc x = \sqrt{3} leads to x=2nπ+π3x = 2n\pi + \frac{\pi}{3}, and substituting into x−π6x - \frac{\pi}{6} gives π6\frac{\pi}{6} for n=0n=0.
196 Easy
196 of 261
Application +4 | -1
If tan⁡(π  cos⁡ θ)=cot⁡(π  sin⁡θ)\tan \left( {\pi \,\,\cos \,\theta } \right) = \cot \left( {\pi \,\,\sin \theta } \right), then the value (s)\left( \mathrm{s} \right) of cos⁡(θ−π4)\cos \left( {\theta - \frac{\pi }{4}} \right) is, (are)
View answer and explanation
Correct option: C
±  12 2\pm \,\,\frac{1}{{2\,\sqrt 2 }}
Option C (±122\pm \frac{{1}}{{2\sqrt 2 }}) is correct because solving the given trigonometric equation leads to cos⁡(θ−π4)=±122\cos (\theta - \frac{\pi}{4}) = \pm \frac{1}{2\sqrt{2}} for specific values of n.
197 Easy
197 of 261
Analyzing +4 | -1
If cos⁡  θ=−12  \cos \,\,\mathrm{\theta } = - \frac{1}{{\sqrt {2\;} }} and tan⁡  θ=1\tan \,\,\mathrm{\theta } = 1, then the general value of θ\mathrm{\theta } is
View answer and explanation
Correct option: B
2(n+1)π+π42\left( {n + 1} \right)\mathrm{\pi } + \frac{\mathrm{\pi }}{4}
The correct answer is B (2(n+1)π+π42(n+1)\pi + \frac{\pi}{4}) because it represents the general solution that satisfies both the cosine and tangent conditions.
198 Easy
198 of 261
Application +4 | -1
If sin⁡  θ+cos⁡  θ=1\sin \,\,\mathrm{\theta } + \cos \,\,\mathrm{\theta } = 1 then the general value of θ\mathrm{\theta } is
View answer and explanation
Correct option: B
nπ+(−1)nπ4−π4n\pi + {\left( { - 1} \right)^n}\frac{\pi }{4} - \frac{\pi }{4}
Option B (nπ+(−1)nπ4−π4n\pi + {\left( { - 1} \right)^n}\frac{\pi }{4} - \frac{\pi }{4}) is correct because it represents the general solution derived from the given trigonometric equation.
199 Easy
199 of 261
Analyzing +4 | -1
The sum of solutions of the equation cos⁡x1+sin⁡x=∣tan⁡2x∣\frac{{\cos x}}{{1 + \sin x}} = \left| {\tan 2x} \right|, x∈(−π2,π2)−{π4,−π4}x \in \left( { - \frac{\pi }{2},\frac{\pi }{2}} \right) - \left\{ {\frac{\pi }{4}, - \left. {\frac{\pi }{4}} \right\}} \right. is
View answer and explanation
Correct option: A
−11π30- \frac{{11\pi }}{{30}}
Option A (−11π30- \frac{{11\pi }}{{30}}) is correct because it is the sum of the solutions to the given equation within the specified interval.
200 Easy
200 of 261
Application +4 | -1
If cos⁡  p  θ=cos⁡  q  θ,  p≠q\cos \,\,p\;\theta = \cos \,\,q\;\theta ,\,\,p \ne q then
View answer and explanation
Correct option: B
θ=2  n  πp±q,  n∈Z\theta = \frac{{2\;n\;\pi }}{{p \pm q}},\,\,n \in Z
Option B (θ=2  n  πp±q,, n∈Z\theta = \frac{{2\;n\;\pi }}{{p \pm q}},\\,\,n \in Z) is correct because it represents the general solution for the given trigonometric equation using the properties of cosine function.
201 Easy
201 of 261
Application +4 | -1
Total number of solutions of sin⁡2x−sin⁡x−1=0\sin 2 x-\sin x-1=0 in [−2π,2π][-2 \pi, 2 \pi] is equal to
View answer and explanation
Correct option: B
4
Option B (4) is correct. By simplifying the equation to sin⁡x=1−52\sin x = \frac{{1 - \sqrt{{5}}}}{{2}}, we find that there are 4 solutions for xx in the interval [−2π,2π][-2\pi, 2\pi].
202 Easy
202 of 261
Application +4 | -1
Number of values of x∈[0,4π]x \in[0,4 \pi] and satisfying 2sec⁡x+tan⁡x=1\sqrt{2} \sec x+\tan x=1 is
View answer and explanation
Correct option: C
2
The correct answer is C (2) because solving the trigonometric equation 2sec⁡x+tan⁡x=1\sqrt{2} \sec x + \tan x = 1 within the interval [0,4π][0, 4\pi] yields 2 distinct solutions.
203 Easy
203 of 261
Application +4 | -1
If the distance between the points (acos⁡θ,asin⁡θ)\left( {a\cos \mathrm{\theta },a\sin \mathrm{\theta }} \right) and (acos⁡ϕ,asin⁡ϕ)\left( {a\cos \phi ,a\sin \phi } \right) is 2a2a, then θ\mathrm{\theta } is equal to
View answer and explanation
Correct option: A
2nπ±π+ϕ,n∈Z2n\pi \pm \pi + \phi ,n \in Z
Option A (2nπ±π+ϕ,n∈Z2n\pi \pm \pi + \phi ,n \in Z) is correct because it represents the general solution for θ\theta derived from the given distance condition between the two points.
204 Easy
204 of 261
Application +4 | -1
If 0≤x≤π0 \le x \le \pi and 81sin⁡2x+  81cos⁡2x=30{81^{{{\sin }^2}x}} + \,\,{81^{{{\cos }^2}x}} = 30, then xx is equal to
View answer and explanation
Correct option: A
π6,  π3\frac{\pi }{6},\,\,\frac{\pi }{3}
Option A (π6, π3\frac{\pi }{6},\,\frac{\pi }{3}) is correct because these values satisfy the given trigonometric equation within the specified interval.
205 Easy
205 of 261
Application +4 | -1
The most general values of θ\mathrm{\theta } satisfying tan⁡  θ+tan⁡  (3 π4+θ)=2\tan \,\,\mathrm{\theta } + \tan \,\,\left( {\frac{{3\,\pi }}{4} + \mathrm{\theta }} \right) = 2 is / are\mathrm{is}\,\mathrm{/}\,\mathrm{are}
View answer and explanation
Correct option: A
nπ  ±  π3,  n∈In\pi \,\, \pm \,\,\frac{\pi }{3},\,\,n \in I
Option A (nπ;±;π3,;n∈In\pi \\; \pm \\; \frac{\pi }{{3}},\\;n \in I) is correct because it represents the general solution of the trigonometric equation after simplification.
206 Easy
206 of 261
Application +4 | -1
The most general value of θ\theta satisfying
tan⁡  θ+tan⁡(3  π4+θ)=2    are\tan \,\,\theta + \tan \left( {\frac{{3\;\pi }}{4} + \theta } \right) = 2\;\,\,are
View answer and explanation
Correct option: A
n  π  ±  π3,  n∈Zn\;\pi \,\, \pm \,\,\frac{\pi }{3},\,\,n \in Z
Option A (n;π,±,π3,,n∈Zn\\;\pi \\, \pm \\, \frac{\pi }{{3}},\\,n \in Z) is correct because solving the trigonometric equation leads to tan⁡2θ=3\tan^2 \theta = 3, which gives the general solution θ=nπ±π3\theta = n\pi \pm \frac{\pi}{3}.
207 Easy
207 of 261
Analyzing +4 | -1
If the values of xx and yy satisfy the equation tan⁡2(x+y)+cot⁡2(x+y)=1−2x−x2\tan ^2(x+y)+\cot ^2(x+y)=1-2 x-x^2, then the value of x2−3x+2x^2-3 x+2 is _____.
View answer and explanation
Correct option: A
6
Option C (3) is incorrect. The correct answer is 6 because the given equation is valid only when both sides are equal to 2, leading to x = -1, and thus x2−3x+2=6x^2 - 3x + 2 = 6.
208 Easy
208 of 261
Application +4 | -1
The number of solutions of sin⁡  x=sin⁡  2x\sin \,\,x = \sin \,\,2x between −π2\frac{{ - \pi }}{2} and π2\frac{\pi }{2} is
View answer and explanation
Correct option: A
3
The correct answer is A (3) because solving the trigonometric equation sin⁡x=sin⁡2x\sin x = \sin 2x within the given interval yields three solutions: 0, π3\frac{\pi}{3}, and −π3-\frac{\pi}{3}.
209 Easy
209 of 261
Application +4 | -1
The solution of the equation cos⁡2θ+sin⁡θ+1=0\cos ^2 \theta+\sin \theta+1=0 lies in the interval
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the solution to the equation cos⁡2θ+sin⁡θ+1=0\cos^2 \theta + \sin \theta + 1 = 0 is θ=2nπ−π2\theta = 2n\pi - \frac{\pi}{2}, and none of the given intervals contain this solution.
210 Easy
210 of 261
Understanding +4 | -1
The equation sin⁡x+sin⁡y+sin⁡z=−3\sin x+\sin y+\sin z=-3 for 0≤x≤2π0 \leq x \leq 2 \pi. 0≤y≤2π,0≤z≤2π0 \leq y \leq 2 \pi, 0 \leq z \leq 2 \pi, has
View answer and explanation
Correct option: A
One solution
Option A (One solution) is correct because the maximum value of sin⁡x\sin x is 1, so for the sum to be -3, each term must be -1, leading to a unique solution.
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