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JEE • MATHEMATICS • TRIGONOMETRIC EQUATIONS

Trigonometric equations practice · Mixed difficulty

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241 Easy
241 of 581
Analyzing +4 | -1
General value of θ\mathrm{\theta } satisfying the equation tan⁡2  θ+sec⁡  2θ=1{\tan ^2}\,\,\mathrm{\theta } + \sec \,\,2\mathrm{\theta } = 1 is
View answer and explanation
Correct option: B
mπ,   nπ    ±  π3m\pi ,\;\,n\pi \;\,\, \pm \,\,\frac{\pi }{3}
Option B (mπ,   nπ    ±  π3m\pi ,\;\,n\pi \;\,\,\pm \,\,\frac{\pi }{3}) is correct because it represents the general solutions obtained by solving the given trigonometric equation.
242 Easy
242 of 581
Application +4 | -1
If sin⁡  (π  cot⁡  θ)=cos⁡  (π  tan⁡  θ)\sin \,\,\left( {\pi \,\,\cot \,\,\theta } \right) = \cos \,\,\left( {\pi \,\,\tan \,\,\theta } \right) then cot⁡  2  θ\cot \,\,2\;\theta is equal to where n∈Zn \in Z
View answer and explanation
Correct option: B
n+14n + \frac{1}{4}
Option B (n+14n + \frac{1}{4}) is correct because it is the simplified form of the expression after applying trigonometric identities and solving for cot⁡2θ\cot 2\theta.
243 Medium
243 of 581
Analyzing +4 | -1
The solution of trigonometric equation cos⁡4x+sin⁡4x=2cos⁡(2x+π)cos⁡(2x−π)\cos ^4 x+\sin ^4 x=2 \cos (2 x+\pi) \cos (2 x-\pi) is
View answer and explanation
Correct option: B
x=nπ4+(−1)n4sin⁡−1(±223)x=\frac{n \pi}{4}+\frac{(-1)^n}{4} \sin ^{-1}\left(\frac{ \pm 2 \sqrt{2}}{3}\right)
Option B (x=nπ4+(−1)n4sin⁡−1(±223)x=\frac{{n \pi}}{{4}}+\frac{{(-1)^n}}{{4}} \sin^{-1}(\frac{{ \pm 2 \sqrt{{2}}}}{{3}})) is correct because simplifying the given equation leads to this general solution.
244 Easy
244 of 581
Application +4 | -1
f(θ)=sin⁡2θ+sin⁡2(θ+2π3)+sin⁡2(θ+4π3)f(\theta)=\sin ^2 \theta+\sin ^2\left(\theta+\frac{2 \pi}{3}\right)+\sin ^2\left(\theta+\frac{4 \pi}{3}\right), then f(π15)f\left(\frac{\pi}{15}\right) is equal to
View answer and explanation
Correct option: B
32\frac{3}{2}
Option B (32\frac{3}{2}) is correct because simplifying the given trigonometric expression results in a constant value of 32\frac{3}{2}, independent of θ\theta.
245 Easy
245 of 581
Analyzing +4 | -1
The number of solutions of the equation 2cos⁡x=∣ sin⁡  x ∣{2^{\cos x}} = \left| {\,\sin \,\,x\,} \right| in [−2  π,  2  π]\left[ { - 2\;\pi ,\,\,2\;\pi } \right], is
View answer and explanation
Correct option: D
4\mathrm{4}
Option D (4) is correct because the graphs of the two functions, y=2cos⁡xy = {2^{\cos x}} and y = \left| {\,\sin \,x\} \right|y = \left| {\,\sin \,x\} \right|, intersect at four points within the given interval [−2π,2π][-2\pi, 2\pi].
246 Medium
246 of 581
Analyzing +4 | -1
If cos⁡22x−sin⁡4x−2cos⁡2x=λ\cos ^2 2 x-\sin ^4 x-2 \cos ^2 x=\lambda, has a solution ∀ x∈R\forall \, x \in R, then the range of λ\lambda is
View answer and explanation
Correct option: B
[−43,0]\left[-\frac{4}{3}, 0\right]
The correct answer is B ([−43,0]\left[-\frac{4}{3}, 0\right]) because it represents the range of the function after simplification and completing the square.
247 Easy
247 of 581
Understanding +4 | -1
If sin⁡  A=sin⁡  B,  cos⁡  A=cos⁡  B\sin \,\,A = \sin \,\,B,\,\,\cos \,\,A = \cos \,\,B, then the value of AA in terms of BB is
View answer and explanation
Correct option: C
2  n  π+B2\;n\;\pi + B
Option C (2  n  π+B2\;n\;\pi + B) is correct because it satisfies both the sine and cosine relations for all integers n.
248 Easy
248 of 581
Application +4 | -1
The number of solutions of 5cos⁡2θ−3sin⁡2θ+6sin⁡θcos⁡θ=75 \cos ^2 \theta-3 \sin ^2 \theta+6 \sin \theta \cos \theta=7 in the interval [0,2π][0,2 \pi] is
View answer and explanation
Correct option: C
0
Option C (0) is correct because by rewriting the equation using trigonometric identities, we find that the equation has no solutions in the given interval.
249 Easy
249 of 581
Application +4 | -1
The general solution of sin⁡  x−3  sin⁡  2x+sin⁡  3x=cos⁡  x −3  cos⁡  2x+cos⁡  3x\sin \,\,x - 3\,\,\sin \,\,2x + \sin \,\,3x = \cos \,\,x\, - 3\,\,\cos \,\,2x + \cos \,\,3x is
View answer and explanation
Correct option: B
nπ2+π8  \frac{{n\pi }}{2} + \frac{\pi }{8}\;
Option B is correct because by rearranging the equation and factoring, we can find the general solution for x.
250 Easy
250 of 581
Application +4 | -1
The value of tan⁡40∘+tan⁡20∘+3tan⁡20∘tan⁡40∘\tan 40^{\circ}+\tan 20^{\circ}+\sqrt{3} \tan 20^{\circ} \tan 40^{\circ} is
View answer and explanation
Correct option: D
3\sqrt{3}
Option D (3\sqrt{3}) is correct because the expression simplifies to 3\sqrt{3} using the tangent addition formula.
251 Easy
251 of 581
Application +4 | -1
The set of all xx in (−π,π)(-\pi, \pi) satisfying ∣4sin⁡x−1∣<5|4 \sin x-1| < \sqrt{5} is given by
View answer and explanation
Correct option: B
(π10,3π10)\left(\frac{\pi}{10}, \frac{3 \pi}{10}\right)
Option B (π10,3π10)\left(\frac{\pi}{10}, \frac{3 \pi}{10}\right) is correct because solving the inequality ∣4sin⁡x−1∣<5|4 \sin x - 1| < \sqrt{5} for xx in the interval (−π,π)(-\pi, \pi) yields this solution set.
252 Easy
252 of 581
Application +4 | -1
If sin⁡  θ=3  cos⁡  θ,  π<θ<0\sin \,\,\mathrm{\theta } = \sqrt 3 \,\,\cos \,\,\mathrm{\theta },\mathrm{\;\pi } < \mathrm{\theta } < 0, then θ\mathrm{\theta } is equal to

View answer and explanation
Correct option: B
−  4π6- \,\,\frac{{4\mathrm{\pi }}}{6}
Option A (− 4π6- \,\frac{{4\mathrm{\pi }}}{{6}}) is correct because it satisfies the given equation sin⁡θ=3cos⁡θ\sin \theta = \sqrt{3} \cos \theta and the condition π<θ<0\mathrm{\pi } < \mathrm{\theta } < 0.
253 Easy
253 of 581
Analyzing +4 | -1
The solution of the equation 4sin⁡4x+cos⁡4x=14{\sin ^4}x + {\cos ^4}x = 1 is
View answer and explanation
Correct option: D
None of the above
Option D (None of the above) is correct because the solution to the equation 4sin⁡4x+cos⁡4x=14{\sin ^4}x + {\cos ^4}x = 1 is x=nπx = n\pi, which is not represented by the other options.
254 Medium
254 of 581
Understanding +4 | -1
Assertion: The inequality ax+by<0a x+b y < 0 is strict inequality.

Reason: The inequality ax+b≥0a x+b \geq 0 is slack inequality.
View answer and explanation
Correct option: B
Assertion is correct, reason is correct; reason is not a
correct explanation for assertion
Option B (Assertion is correct, reason is correct; reason is not a correct explanation for assertion) is correct because both statements are true, but the reason doesn't explain the assertion.
255 Medium
255 of 581
Application +4 | -1
If in any △ABC\triangle A B C, the value of ∠A\angle A is obtained from the equation 3cos⁡A+2=03 \cos A+2=0, then the equation whose roots are sin⁡A\sin A and tan⁡A\tan A, is
View answer and explanation
Correct option: A
6x2+5x−5=06 x^2+\sqrt{5} x-5=0
Option A (6x2+5x−5=06 x^2+\sqrt{5} x-5=0) is correct because it represents the quadratic equation whose roots are sin⁡A\sin A and tan⁡A\tan A, derived from the given trigonometric relationship.
256 Easy
256 of 581
Application +4 | -1
The maximum and minimum values of 7cos⁡θ+24sin⁡θ7 \cos \theta+24 \sin \theta are
View answer and explanation
Correct option: A
25 and −25
Option A (25 and -25) is correct because the maximum and minimum values of acos⁡θ+bsin⁡θa \cos \theta + b \sin \theta are a2+b2\sqrt{{a^2 + b^2}} and −a2+b2-\sqrt{{a^2 + b^2}} respectively.
257 Easy
257 of 581
Analyzing +4 | -1
The number of solutions of the pair of equations 2sin⁡2θ−cos⁡  2θ=02{\sin ^2}\theta - \cos \,\,2\theta = 0 and 2cos⁡2θ−3sin⁡  θ=02{\cos ^2}\theta - 3\sin \,\,\theta = 0 in the interval [0,   2π]\left[ {0,\,\;2\pi } \right] is

View answer and explanation
Correct option: C
Two
Option C (Two) is correct because solving the given equations yields sin⁡θ=12\sin \theta = \frac{1}{2}, which has two solutions in the interval [0,2π][0, 2\pi].
258 Medium
258 of 581
Analyzing +4 | -1
The general solution of sin⁡3x+sin⁡x−3sin⁡2x\sin 3 x+\sin x-3 \sin 2 x =cos⁡3x+cos⁡x−3cos⁡2x=\cos 3 x+\cos x-3 \cos 2 x is
View answer and explanation
Correct option: A
nπ2+π8\frac{n \pi}{2}+\frac{\pi}{8} for nn integer
Option A is correct because the general solution is found by simplifying the trigonometric equation and solving for x.
259 Medium
259 of 581
Analyzing +4 | -1
The number of x∈[0,2π]x \in[0,2 \pi] for which
∣2sin⁡4x+18cos⁡2x−2cos⁡4x+18sin⁡2x∣=1 is \left|\sqrt{2 \sin ^{4} x+18 \cos ^{2} x}-\sqrt{2 \cos ^{4} x+18 \sin ^{2} x}\right|=1 \text { is }
View answer and explanation
Correct option: D
8
Option D (8) is correct because squaring both sides and solving the equation gives 8 solutions in the interval [0, 2π\pi].
260 Easy
260 of 581
Application +4 | -1
If 5  cos⁡  2  θ+2  cos⁡2  θ2+1=0, −π<θ<π5\,\,\cos \,\,2\;\theta + 2\,\,{\cos ^2}\,\,\frac{\theta }{2} + 1 = 0,\, - \pi < \theta < \pi, then θ=\theta =
View answer and explanation
Correct option: D
π3,  π−cos⁡−1  (3/5)\frac{\pi }{3},\,\,\pi - {\cos ^{ - 1}}\,\,\left( {3/5} \right)
Option D (π3, π−cos⁡−1  (3/5)\frac{\pi }{3},\,\pi - {\cos ^{ - 1}}\,\,\left( {3/5} \right)) is correct because these are the solutions to the given trigonometric equation within the specified interval.
261 Medium
261 of 581
Analyzing +4 | -1
If 2tan⁡2x−5sec⁡x2 \tan ^2 x-5 \sec x is equal to 1 for exactly 7 distinct values of x∈[0,nπ2]n∈Nx \in\left[0, \frac{n \pi}{2}\right] n \in N, then the greatest value of nn is
View answer and explanation
Correct option: D
15
Option D (15) is correct because the equation simplifies to sec(x) = 3, which yields 7 distinct solutions within the given interval, resulting in n=15.
262 Medium
262 of 581
Application +4 | -1
Find the value of cos⁡(29π/3)\cos (29 \pi / 3).
View answer and explanation
Correct option: D
1/21 / 2
Option D (1/2) is correct because by simplifying the angle and using trigonometric identities, cos⁡(29π/3)\cos (29 \pi / 3) can be reduced to cos⁡(π/3)\cos (\pi/3) which equals 1/2.
263 Medium
263 of 581
Application +4 | -1
If the solutions for θ, cos⁡pθ+cos⁡qθ=0,   p>0,   q>0\mathrm{\theta },\,\cos p\mathrm{\theta } + \cos q\mathrm{\theta } = 0,\;\,p > 0,\;\,q > 0 are in AP, then the numerically smallest common difference of AP is
View answer and explanation
Correct option: B
2πp+q\frac{{2\pi }}{{p + q}}
Option B (2πp+q\frac{{2\pi }}{{p + q}}) is correct because it represents the smallest common difference of the arithmetic progression formed by the solutions of the given trigonometric equation.
264 Easy
264 of 581
Application +4 | -1
If 2  sin⁡2θ+3  cos⁡  θ+1=02\,\,{\sin ^2}\theta + \sqrt 3 \,\,\cos \,\,\theta + 1 = 0, then the value of θ\theta is
View answer and explanation
Correct option: C
5 π6\frac{{5\,\pi }}{6}
Option C is correct because it is the solution to the given trigonometric equation within the possible range of values.
265 Easy
265 of 581
Analyzing +4 | -1
If (sec⁡  θ−1)=(2−1)tan⁡  θ\left( {\sec \,\,\theta - 1} \right) = \left( {\sqrt 2 - 1} \right)\tan \,\,\theta, then θ=\theta =
View answer and explanation
Correct option: B
2  n  π,  2  n  π+π4,  n∈Z2\;n\;\pi ,\,\,2\;n\;\pi + \frac{\pi }{4},\,\,n \in Z
Option B (2  n  π, 2  n  π+π4, n∈Z2\;n\;\pi ,\,2\;n\;\pi + \frac{\pi }{4},\,n \in Z) is correct because it represents the general solutions obtained by solving the given trigonometric equation.
266 Easy
266 of 581
Analyzing +4 | -1
The minimum value of the expression sin⁡α+sin⁡β+sin⁡γ\sin \alpha+\sin \beta+\sin \gamma, where α,β\alpha, \beta and γ\gamma are real numbers satisfying α+β+γ=π\alpha+\beta+\gamma=\pi, is
View answer and explanation
Correct option: C
Negative
Option C (Negative) is correct because the minimum value of the expression can be negative when α, β, and γ are real numbers satisfying α+β+γ=π.
267 Medium
267 of 581
Application +4 | -1
The general value of xx for which cos⁡  2x,  12    and  sin⁡  2x\cos \,\,2x,\,\,\frac{1}{2}\;\,\,\mathrm{and}\,\,\sin \,\,2x are in AP, are given by
View answer and explanation
Correct option: B
nπ,   nπ+π4n\pi ,\;\,n\pi + \frac{\pi }{4}
Option B (-1) is correct because the sum telescopes to cos⁡π\cos \pi which equals -1.
268 Easy
268 of 581
Analyzing +4 | -1
The equation sin⁡  x  cos⁡  x=2\sin \,\,x\,\,\cos \,\,x = 2 has
View answer and explanation
Correct option: D
No solution
Option D (No solution) is correct because the equation simplifies to sin⁡2x=4\sin 2x = 4, which is impossible since the range of the sine function is [-1, 1].
269 Medium
269 of 581
Application +4 | -1
If 0≤x≤π20 \leq x \leq \frac{\pi}{2} and 81sin⁡2x+81cos⁡2x=3081^{\sin ^2 x}+81^{\cos ^2 x}=30, then xx is equal to
View answer and explanation
Correct option: A
π6,π3\frac{\pi}{6}, \frac{\pi}{3}
Option A (π6,π3\frac{\pi}{6}, \frac{\pi}{3}) is correct because solving the given equation by substituting y=81sin⁡2xy = 81^{\sin^2 x} leads to finding the values of sin⁡x\sin x and hence xx.
270 Medium
270 of 581
Application +4 | -1
The solution of tan⁡x+tan⁡2x+tan⁡3x=tan⁡xtan⁡2xtan⁡3x\tan x+\tan 2 x+\tan 3 x=\tan x \tan 2 x \tan 3 x is
View answer and explanation
Correct option: C
x=nπ3,n∈Ix=\frac{n \pi}{3}, n \in I
Option C (x=nπ3,n∈Ix=\frac{{n \pi}}{{3}}, n \in I) is correct because it is derived by using the tangent addition formula and simplifying the given equation.
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