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JEE • MATHEMATICS • TRIGONOMETRIC EQUATIONS

Trigonometric equations practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 581 questions

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271 Medium
271 of 581
Analyzing +4 | -1
If A+B=π3A+B=\frac{\pi}{3} and cos⁡A+cos⁡B=1\cos A+\cos B=1, then
View answer and explanation
Correct option: B
∣cos⁡A−cos⁡B∣=23|\cos A-\cos B|=\sqrt{\frac{2}{3}}
Option B (∣cos⁡A−cos⁡B∣=23|\cos A-\cos B|=\sqrt{\frac{2}{3}}) is correct because it is the result of applying trigonometric identities and the given conditions to simplify the expression.
272 Easy
272 of 581
Application +4 | -1
The value of xx in (0,   π2)\left( {0,\;\,\frac{\pi }{2}} \right) satisfying the equation sin⁡ x  cos   x=14\sin \,x\,\,cos\,\;x = \frac{1}{4} is
View answer and explanation
Correct option: D
π12\frac{\pi }{{12}}
Option D (π12\frac{\pi }{{12}}) is correct because by using the double angle identity for sine and solving the resulting equation, we find that x=π12x = \frac{\pi }{{12}} is the solution in the given interval.
273 Easy
273 of 581
Application +4 | -1
sin⁡47∘+sin⁡61∘−sin⁡11∘−sin⁡25∘\sin 47^{\circ}+\sin 61^{\circ}-\sin 11^{\circ}-\sin 25^{\circ} is equal to
View answer and explanation
Correct option: D
cos⁡7∘\cos 7^{\circ}
Option D (cos⁡7∘\cos 7^{\circ}) is correct because the expression simplifies to cos⁡7∘\cos 7^{\circ} using trigonometric identities.
274 Easy
274 of 581
Application +4 | -1
If tan⁡  θ+tan⁡  2θ+3  tan⁡  θ  tan⁡  2θ=3\tan \,\,\mathrm{\theta } + \tan \,\,2\mathrm{\theta } + \sqrt 3 \,\,\tan \,\,\mathrm{\theta }\,\,\tan \,\,2\mathrm{\theta } = \sqrt 3, then
View answer and explanation
Correct option: C
θ=(3 n+1)π9,  ∀  n∈I\mathrm{\theta } = \frac{{\left( {3\,n + 1} \right)\pi }}{9},\,\,\forall \;n \in I
Option D (θ=(3n+1)π9,,∀  n∈I\mathrm{\theta } = \frac{{(3n + 1)\pi }}{9},\\,\forall \;n \in I) is correct because it is derived from solving the trigonometric equation using the tangent addition formula.
275 Hard
275 of 581
Application +4 | -1
Solution set of the inequality ∣tan⁡x∣<1/3|\tan x| < 1 / \sqrt{3} is
View answer and explanation
Correct option: A
(nπ−π6,nπ+π6);n∈Z\left(n \pi-\frac{\pi}{6}, n \pi+\frac{\pi}{6}\right) ; n \in Z
Option A ((nπ−π6,nπ+π6n \pi-\frac{\pi}{6}, n \pi+\frac{\pi}{6}); n∈Zn \in Z) is correct because it represents the general solution for the inequality ∣tan⁡x∣<1/3|\tan x| < 1 / \sqrt{3}.
276 Easy
276 of 581
Application +4 | -1
If sin⁡θ\sin \theta and cos⁡θ\cos \theta are the roots of the equation ax2−bx+c=0a x^2-b x+c=0, then a,ba, b and cc satisfy the relation
View answer and explanation
Correct option: B
a2−b2+2ac=0a^2-b^2+2 a c=0
Option B (a2−b2+2ac=0a^2-b^2+2 a c=0) is correct because it is the relation derived from the given roots sin⁡θ\sin \theta and cos⁡θ\cos \theta of the quadratic equation.
277 Easy
277 of 581
Analyzing +4 | -1
The values of xx between   0\mathrm{\;0} and 2 π2\,\pi which satisfy the equation sin⁡  x 8  cos⁡2  x=1\sin \,\,x\,\sqrt {8\,\,{{\cos }^2}\,\,x} = 1 are in AP. The common difference of the AP is
View answer and explanation
Correct option: B
π4\frac{\mathrm{\pi }}{4}
Option B (π4\frac{\mathrm{\pi }}{4}) is correct because the values of x that satisfy the equation form an arithmetic progression with a common difference of π4\frac{\mathrm{\pi }}{4}.
278 Easy
278 of 581
Application +4 | -1
If tan⁡θ=n\tan \theta=\sqrt{n} for some non-square natural number nn, then sec⁡2θ\sec 2 \theta is
View answer and explanation
Correct option: A
A rational number
Option A (A rational number) is correct because sec⁡2θ\sec 2\theta can be expressed as a ratio of integers when tan⁡θ=n\tan \theta = \sqrt{n} and nn is a non-square natural number.
279 Hard
279 of 581
Understanding +4 | -1
Consider the following statements:

I. The function f(x)=f(x)= greatest integer ≤x,x∈R\leq x, x \in R is a continuous function.

II. All trigonometric functions are continuous on RR. Which of the statements given above is/are correct?
View answer and explanation
Correct option: D
Neither I nor II
Option D is correct because neither the greatest integer function nor all trigonometric functions are continuous on R.
280 Easy
280 of 581
Analyzing +4 | -1
The value of (1+cos⁡π8)(1+cos⁡3π8)\left(1+\cos \frac{\pi}{8}\right)\left(1+\cos \frac{3 \pi}{8}\right) (1+cos⁡5π8)(1+cos⁡7π8)\left(1+\cos \frac{5 \pi}{8}\right)\left(1+\cos \frac{7 \pi}{8}\right) is
View answer and explanation
Correct option: C
18\frac{1}{8}
Option C (18\frac{1}{8}) is correct because using trigonometric identities, the expression simplifies to 18\frac{1}{8}.
281 Easy
281 of 581
Application +4 | -1
If 0≤x≤π0 \le x \le \pi and 81sin⁡2x+  81cos⁡2x=30{81^{{{\sin }^2}x}} + \,\,{81^{{{\cos }^2}x}} = 30, then xx is equal to
View answer and explanation
Correct option: A
π6\frac{\pi }{6}
Option A (π6\frac{\pi }{6}) is correct because it satisfies the given trigonometric equation after simplification and solving for x.
282 Easy
282 of 581
Application +4 | -1
The value of cot⁡54∘tan⁡36∘+tan⁡20∘cot⁡70∘\frac{\cot 54^{\circ}}{\tan 36^{\circ}}+\frac{\tan 20^{\circ}}{\cot 70^{\circ}} is
View answer and explanation
Correct option: B
2
Option B (2) is correct because the expression simplifies to 1 + 1 after applying the complementary angle identities.
283 Easy
283 of 581
Application +4 | -1
If sec⁡2θ=2(1−tan⁡2θ){\sec ^2}\theta = \sqrt 2 \left( {1 - {{\tan }^2}\theta } \right), then θ=\theta =
View answer and explanation
Correct option: C
n  π±π8,  n∈Zn\;\pi \pm \frac{\pi }{8},\,\,n \in Z
Option C (n  π±π8, n∈Zn\;\pi \pm \frac{\pi }{8},\,n \in Z) is correct because it is derived by simplifying the given equation using trigonometric identities and solving for θ\theta.
284 Medium
284 of 581
Application +4 | -1
General solution of equation ∣sin⁡x∣=cos⁡x|\sin x|=\cos x is
View answer and explanation
Correct option: C
2nπ±π4,n∈l2 \mathrm{n} \pi \pm \frac{\pi}{4}, \mathrm{n} \in \mathrm{l}
Option C (2nπ±π4,n∈l2 \mathrm{n} \pi \pm \frac{\pi}{4}, \mathrm{n} \in \mathrm{l}) is correct because it represents the general solution considering both positive and negative cases of sin⁡x\sin x within the given condition.
285 Medium
285 of 581
Application +4 | -1
The solution set of (5+4cos⁡  θ)  (2cos⁡  θ+1)=0\left( {5 + 4\cos \,\,\theta } \right)\,\,\left( {2\cos \,\,\theta + 1} \right) = 0 in the interval [0,   2π]\left[ {0,\;\,2\pi } \right] is

View answer and explanation
Correct option: C
{2 π3,   4 π3}\left\{ {\frac{{2\,\pi }}{3},\,\;\frac{{4\,\pi }}{3}} \right\}
Option C ({2,π3,;4,π3}\{\frac{{2\\,\pi }}{{3}},\\;\frac{{4\\,\pi }}{{3}}\}) is correct because these are the only solutions in the given interval that satisfy the equation.
286 Medium
286 of 581
Application +4 | -1
If cot⁡(α+β)=0,  then  sin⁡(α+2β)\cot \left( {\mathrm{\alpha } + \mathrm{\beta }} \right) = 0,\mathrm{\;then}\,\,\sin \left( {\mathrm{\alpha } + 2\mathrm{\beta }} \right) is equal to

View answer and explanation
Correct option: A
sin⁡α\sin \mathrm{\alpha }
Option A (sin⁡α\sin \mathrm{\alpha }) is correct because, given the condition, the expression simplifies to sin⁡α\sin{\alpha} using trigonometric identities.
287 Easy
287 of 581
Application +4 | -1
If tan⁡2θ  tan⁡θ=1\tan 2\mathrm{\theta }\,\,\tan \mathrm{\theta } = 1, then the general value of θ\mathrm{\theta } is
View answer and explanation
Correct option: A
(  n+12)π3\left( {\;n + \frac{1}{2}} \right)\frac{\pi }{3}
Option A, (  n+12)π3\left( {\;n + \frac{{1}}{{2}}} \right)\frac{{\pi }}{{3}}, is the correct general solution for θ\theta derived from the given trigonometric equation by using trigonometric identities and solving for θ\theta.
288 Easy
288 of 581
Analyzing +4 | -1
The sum of all values of xx in [0,  2π]\left[ {0,\,\,2\pi } \right], for which sin⁡x+sin⁡2x+sin⁡3x+sin⁡4x=0\sin x + \sin 2x + \sin 3x + \sin 4x = 0, is equal to
View answer and explanation
Correct option: D
9 π9\,\pi
Option D (9π9\pi) is correct because the sum of all solutions to the trigonometric equation within the given interval [0, 2π\pi] is 9π\pi.
289 Easy
289 of 581
Application +4 | -1
The solution set of the equation 5cos⁡2θ+2cos⁡2θ2+15 \cos 2 \theta+2 \cos ^2 \frac{\theta}{2}+1 =0=0, in the interval −π<θ<π-\pi<\theta<\pi, is
View answer and explanation
Correct option: B
{π3,π−cos⁡−1(35)}\left\{\frac{\pi}{3}, \pi-\cos ^{-1}\left(\frac{3}{5}\right)\right\}
Option B is the correct solution set because it satisfies the given trigonometric equation within the specified interval.
290 Easy
290 of 581
Analyzing +4 | -1
If 0≤x<π20 \le x < \frac{\pi }{2}, then the number of values of xx for which x−sin⁡2x+sin⁡3x=0x - \sin 2x + \sin 3x = 0, is
View answer and explanation
Correct option: A
2
Option A (2) is correct because there are two values of x (0 and π3\frac{\pi}{3}) in the given interval that satisfy the equation.
291 Easy
291 of 581
Application +4 | -1
The set of real xx satisfying the inequality 5−2x3≤x6−5\frac{5-2 x}{3} \leq \frac{x}{6}-5 is [a,∞)[a, \infty). The value of aa is
View answer and explanation
Correct option: A
8
Option A (8) is correct because solving the inequality 5−2x3≤x6−5\frac{5-2x}{3} \leq \frac{x}{6} - 5 results in x≥8x \geq 8, which corresponds to the interval [8,∞)[8, \infty).
292 Easy
292 of 581
Application +4 | -1
The equation 3sin⁡2x+10cos⁡x−6=03 \sin ^2 x+10 \cos x-6=0 is satisfied if
View answer and explanation
Correct option: B
x=2nπ±cos⁡−1(13)x=2 n \pi \pm \cos ^{-1}\left(\frac{1}{3}\right)
Option B (x=2nπ±cos⁡−1(13)x=2 n \pi \pm \cos ^{-1}(\frac{1}{3})) is correct because it represents the general solution to the given trigonometric equation.
293 Easy
293 of 581
Analyzing +4 | -1
The general solution of :  sin⁡2θ  sec⁡  θ+3  tan⁡  θ=0:\,\,{\sin ^2}\theta \,\,\sec \,\,\theta + \sqrt 3 \,\,\tan \,\,\theta = 0 is
View answer and explanation
Correct option: B
θ=n  π,  n∈Z\theta = n\;\pi ,\,\,n \in Z
Option B (θ=n;π,;;n∈Z\theta = n\\;\pi ,\\;\\;n \in Z) is correct because the given equation simplifies to (sin⁡θ+3)tan⁡θ=0(\sin \theta + \sqrt 3 )\tan \theta = 0, leading to tan⁡θ=0\tan \theta = 0 and thus θ=n;π\theta = n\\;\pi.
294 Easy
294 of 581
Application +4 | -1
If nn is any integer, then the general solution of the equation cos⁡  θ−sin⁡  θ=12\cos \,\,\theta - \sin \,\,\theta = \frac{1}{{\sqrt 2 }} is
View answer and explanation
Correct option: C
θ=2 nπ+π12\theta = 2\,n\pi + \frac{\pi }{{12}} or θ=2 nπ−7π12\theta = 2\,n\pi - \frac{{7\pi }}{{12}}
Option D is correct because by rewriting the equation and using trigonometric identities, we can find the general solution for θ\theta.
295 Easy
295 of 581
Application +4 | -1
The number of values of xx in [0,  5  π]\left[ {0,\,\,5\;\pi } \right] satisfying the equation 3  cos⁡  2x−10  cos⁡  x+7=03\,\,\cos \,\,2x - 10\,\,\cos \,\,x + 7 = 0 is
View answer and explanation
Correct option: C
8
Option A (5) is incorrect. The correct answer is 8 because there are 3 solutions for cos(x) = 1 and 5 solutions for cos(x) = 2/3 in the given interval.
296 Easy
296 of 581
Application +4 | -1
In △ABC\triangle A B C, if ∠C=2π3\angle C=\frac{2 \pi}{3}, then the value of cos⁡2A+cos⁡2B−cos⁡Acos⁡B\cos ^2 A+\cos ^2 B-\cos A \cos B is
View answer and explanation
Correct option: A
34\frac{3}{4}
Option A (34\frac{3}{4}) is correct because by using the given angle and trigonometric identities, the expression simplifies to 34\frac{3}{4}.
297 Easy
297 of 581
Application +4 | -1
If cot⁡α\cot \alpha equals the integral solution of the inequality 4x2−16x+15<04 x^2-16 x+15<0 and sin⁡β\sin \beta equals to the slope of the bisector of the first quadrant, then sin⁡(α+β)sin⁡(α−β)\sin (\alpha+\beta) \sin (\alpha-\beta) is equal to
View answer and explanation
Correct option: B
−4/5-4 / 5
Option B (-4/5) is correct because by solving the inequality and using the given information, we can find the values of cot⁡α\cot \alpha and sin⁡β\sin \beta, and then calculate sin⁡(α+β)sin⁡(α−β)\sin(\alpha+\beta)\sin(\alpha-\beta) using trigonometric identities.
298 Hard
298 of 581
Application +4 | -1
The general solution of e−1/2  (esin⁡x+  ecos⁡x)=2{e^{ - 1/\sqrt 2 }}\,\,\left( {{e^{\sin x}} + \,\,{e^{\cos x}}} \right) = 2 is
View answer and explanation
Correct option: B
x=(4m+1)π4x = \frac{{\left( {4m + 1} \right)\pi }}{4}
Option B is correct because it satisfies the given equation by ensuring that both sin⁡x\sin x and cos⁡x\cos x are equal, leading to the minimum value of the expression.
299 Easy
299 of 581
Application +4 | -1
If cos⁡−1(x/2)+cos⁡−1(y/3)=θ\cos ^{-1}(x / 2)+\cos ^{-1}(y / 3)=\theta, then 9x2−12xycos⁡θ9 x^2-12 x y \cos \theta +4y2+4 y^2 is equal to
View answer and explanation
Correct option: C
36sin⁡2θ36 \sin ^2 \theta
Option C, 36sin⁡2θ36 \sin^2 \theta, is correct because by using the cosine addition formula and simplifying, we can derive that 9x2−12xycos⁡θ+4y2=36sin⁡2θ9x^2 - 12xy \cos \theta + 4y^2 = 36 \sin^2 \theta.
300 Medium
300 of 581
Application +4 | -1
If sin⁡A+cos⁡A=2\sin A+\cos A=\sqrt{2}, then the value of cos⁡2A\cos ^2 A is
View answer and explanation
Correct option: B
1/21 / 2
Option B (1/2) is correct because by solving the given equation for A, we find A = π/4\pi/4, and then cos⁡2A\cos^2 A can be easily calculated.
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