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JEE • MATHEMATICS • TRANSFORMATIONS

Transformations practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-112 of 112 questions
91 Easy
91 of 112
Application +4 | -1
The value of (cos⁡  A+cos⁡  Bsin⁡  A−sin⁡  B)n+(sin⁡  A+sin⁡  Bcos⁡  A−cos⁡  B)n{\left( {\frac{{\cos \,\,A + \cos \,\,B}}{{\sin \,\,A - \sin \,\,B}}} \right)^n} + {\left( {\frac{{\sin \,\,A + \sin \,\,B}}{{\cos \,\,A - \cos \,\,B}}} \right)^n} (where n  n\; is an even) is
View answer and explanation
Correct option: B
2  cot⁡n  (A−B2)2\,\,{\cot ^n}\,\,\left( {\frac{{A - B}}{2}} \right)
Option B (2  cot⁡n  (A−B2)2\,\,{\cot ^n}\,\,\left( {\frac{{A - B}}{2}} \right)) is correct because the expression simplifies to this form when n is even using trigonometric identities.
92 Easy
92 of 112
Application +4 | -1
The period of the function f(x)=∣sin⁡3x∣+∣cos⁡3x∣,f\left( x \right) = \left| {\sin 3x} \right| + \left| {\cos 3x} \right|, is
View answer and explanation
Correct option: B
  π6\frac{{\;\pi }}{6}
Option B (  π6\frac{{\;\pi }}{6}) is correct because it is the smallest value for which f(x+π6)=f(x)f(x + \frac{\pi}{6}) = f(x).
93 Easy
93 of 112
Analyzing +4 | -1
The maximum value of f(x)=sin⁡  x(1+cos⁡  x)f\left( x \right) = \sin \,\,x\left( {1 + \cos \,\,x} \right) is
View answer and explanation
Correct option: A
3 34\frac{{3\,\sqrt 3 }}{4}
Option A (3,34\frac{{3\\,\sqrt 3 }}{4}) is correct because it represents the maximum value of the function f(x)=sin⁡x(1+cos⁡x)f(x) = \sin x(1 + \cos x), which is found by taking the derivative, setting it to zero, and solving for x.
94 Easy
94 of 112
Application +4 | -1
The period of the function f(x)=sin⁡43x+cos⁡43xf\left( x \right) = {\sin ^4}3x + {\cos ^4}3x is
View answer and explanation
Correct option: C
π/6\pi /6
Option C (1−x31 - {x^3}) is correct because it is the inverse function obtained by swapping x and y and solving for y.
95 Easy
95 of 112
Analyzing +4 | -1
If cos⁡  θ=cos⁡  α  cos⁡  β\cos \,\,\theta = \cos \,\,\alpha \,\,\cos \,\,\beta, then tan⁡  (θ+α2)  tan⁡  (θ−α2)\tan \,\,\left( {\frac{{\theta + \alpha }}{2}} \right)\,\,\tan \,\,\left( {\frac{{\theta - \alpha }}{2}} \right) is equal to
View answer and explanation
Correct option: B
tan⁡2  β2{\tan ^2}\,\,\frac{\beta }{2}
Option B (tan⁡2β2{\tan ^2}\frac{\beta }{2}) is correct because simplifying the given expression using trigonometric identities leads to tan⁡2β2{\tan ^2}\frac{\beta }{2}.
96 Easy
96 of 112
Analyzing +4 | -1
3  cosec    20∘−sec⁡  20∘\sqrt 3 \,\,cosec\,\,\;20^\circ - \sec \,\,20^\circ is equal to
View answer and explanation
Correct option: C
4\mathrm{4}
Option C (4) is correct because simplifying the expression using trigonometric identities leads to the value 4.
97 Easy
97 of 112
Analyzing +4 | -1
The period of the function f(x)=∣sin⁡x∣+∣cos⁡x∣f\left( x \right) = \left| {\sin x} \right| + \left| {\cos x} \right| is
View answer and explanation
Correct option: B
π2{\frac{\pi }{2}}
Option B (π2\frac{\pi}{2}) is correct because the function repeats its values after an interval of π2\frac{\pi}{2}.
98 Easy
98 of 112
Analyzing +4 | -1
If α,   β,   γ,  δ\alpha ,\,\;\beta ,\,\;\gamma ,\,\,\delta are the smallest positive angles in ascending order of magnitude which have their sines equal to the positive quantity kk, then the value of

4sin⁡  α2+3sin⁡  β2+2sin⁡  γ2+sin⁡  δ24\sin \,\,\frac{\alpha }{2} + 3\sin \,\,\frac{\beta }{2} + 2\sin \,\,\frac{\gamma }{2} + \sin \,\,\frac{\delta }{2} is equal to
View answer and explanation
Correct option: B
2 1+k2\,\sqrt {1 + k}
Option B (2 1+k2\,\sqrt {1 + k}) is correct because by using the properties of sine and trigonometric identities, we can simplify the expression to 21+k2\sqrt{1+k}.
99 Easy
99 of 112
Application +4 | -1
If cos⁡  A=34\cos \,\,A = \frac{3}{4}, then 32  sin⁡  (A2)  sin⁡  (5 A2)=32\,\,\sin \,\,\left( {\frac{A}{2}} \right)\,\,\sin \,\,\left( {\frac{{5\,A}}{2}} \right) =
View answer and explanation
Correct option: C
11
Option C (11) is correct because by using product-to-sum identities and substituting the given value of cos⁡A\cos A, the expression simplifies to 11.
100 Easy
100 of 112
Application +4 | -1
If xcos⁡  θ=ycos⁡  (θ−2π3)=zcos⁡  (θ+2π3)\frac{x}{{\cos \,\,\theta }} = \frac{y}{{\cos \,\,\left( {\theta - \frac{{2\pi }}{3}} \right)}} = \frac{z}{{\cos \,\,\left( {\theta + \frac{{2\pi }}{3}} \right)}} then x+y+z=x + y + z =
View answer and explanation
Correct option: B
0
Option B (0) is correct because the sum of the cosines in the denominator simplifies to zero, making x + y + z = 0.
101 Easy
101 of 112
Analyzing +4 | -1
If in a Δ ABC\Delta \,ABC,
(sin⁡  A+sin⁡  B+sin⁡C)  (sin⁡  A+sin⁡  B−sin⁡  C)=3  sin⁡  A  sin⁡  B\left( {\sin \,\,A + \sin \,\,B + \sin C} \right)\,\,\left( {\sin \,\,A + \sin \,\,B - \sin \,\,C} \right) = 3\,\,\sin \,\,A\,\,\sin \,\,B
View answer and explanation
Correct option: C
C=60∘C = 60^\circ
Option C (C=60∘C = 60^\circ) is correct because by simplifying the given equation using trigonometric identities, we find that cos⁡C=1/2\cos C = 1/2, which implies C=60∘C = 60^\circ.
102 Easy
102 of 112
Application +4 | -1
If sin⁡  θ=sin⁡  15∘+sin⁡  45∘\sin \,\,\theta = \sin \,\,15^\circ + \sin \,\,45^\circ ,where 0∘<θ<90∘0^\circ < \theta < 90^\circ, then θ\theta is equal to0
View answer and explanation
Correct option: D
75∘75^\circ
Option D (75∘75^\circ) is correct because sin⁡θ=sin⁡15∘+sin⁡45∘\sin \theta = \sin 15^\circ + \sin 45^\circ simplifies to sin⁡θ=sin⁡75∘\sin \theta = \sin 75^\circ, leading to θ=75∘\theta = 75^\circ.
103 Easy
103 of 112
Application +4 | -1
96cos⁡π33cos⁡2π33cos⁡4π33cos⁡8π33cos⁡16π3396 \cos \frac{\pi}{33} \cos \frac{2 \pi}{33} \cos \frac{4 \pi}{33} \cos \frac{8 \pi}{33} \cos \frac{16 \pi}{33} is equal to
View answer and explanation
Correct option: A
3
Option A (3) is correct because it involves using the identity for the product of cosines and simplifying the expression.
104 Easy
104 of 112
Application +4 | -1
If   sin⁡  A−sin⁡  Ccos⁡  C−cos⁡  A=cot⁡  B,   then   A, B,C\;\frac{{\sin \,\,A - \sin \,\,C}}{{\cos \,\,C - \cos \,\,A}} = \cot \,\,B,\,\;\mathrm{then}\;\,A,\,B,C are in

View answer and explanation
Correct option: A
AP
Option A (AP) is correct because the given condition implies that BB is the arithmetic mean of AA and CC, which is the definition of an arithmetic progression.
105 Easy
105 of 112
Application +4 | -1
16sin⁡(20∘)sin⁡(40∘)sin⁡(80∘)16\sin \left( {20^\circ } \right)\sin \left( {40^\circ } \right)\sin \left( {80^\circ } \right) is equal to:
View answer and explanation
Correct option: B
232\sqrt 3
Option B (232\sqrt 3) is correct because the expression simplifies using the trigonometric identity 4sin⁡θsin⁡(60°−θ)sin⁡(60°+θ)=sin⁡3θ4\sin \theta \sin(60°-\theta)\sin(60°+\theta) = \sin 3\theta.
106 Easy
106 of 112
Application +4 | -1
The value of 2  cos⁡  x−cos⁡  3x−cos⁡  5x  2\,\,\cos \,\,x - \cos \,\,3x - \cos \,\,5x\mathrm{\;} is equal to
View answer and explanation
Correct option: A
16  cos⁡3 x  sin⁡2 x16\,\,{\cos ^3}\,x\,\,{\sin ^2}\,x
Option A (16  cos⁡3 x  sin⁡2 x16\,\,{\cos ^3}\,x\,\,{\sin ^2}\,x) is correct because by using trigonometric identities and factoring, the expression simplifies to 16  cos⁡3 x  sin⁡2 x16\,\,{\cos ^3}\,x\,\,{\sin ^2}\,x.
107 Easy
107 of 112
Application +4 | -1
The least value of cosec2 x+25  sec⁡2 x\mathrm{cose}{\mathrm{c}^2}\,x + 25\,\,{\sec ^2}\,x is
View answer and explanation
Correct option: D
38
Option D (38) is correct because the minimum value of the expression is obtained by completing the square and finding the minimum value of the squared term.
108 Easy
108 of 112
Understanding +4 | -1
The function f(x)=∣cos⁡x∣f\left( x \right) = \left| {\cos x} \right| is periodic with period
View answer and explanation
Correct option: B
π\pi
Option B (π\pi) is correct because the period of ∣cos⁡x∣|\cos x| is π\pi.
109 Easy
109 of 112
Analyzing +4 | -1
In aΔ ABC,  cos⁡(B+2C+3A2)+cos⁡(A−B2)\Delta \,ABC,\,\,\cos \left( {\frac{{B + 2C + 3A}}{2}} \right) + \cos \left( {\frac{{A - B}}{2}} \right) is equal to
View answer and explanation
Correct option: B
0
Option B (0) is correct because by using the identity A+B+C=πA+B+C = \pi and simplifying the expression, we can show that the sum of the cosines equals 0.
110 Easy
110 of 112
Application +4 | -1
The sum   S=sin  θ+sin⁡  2θ+...+sin⁡  nθ  \mathrm{\;S} = \mathrm{sin}\,\,\mathrm{\theta } + \sin \,\,2\mathrm{\theta } + ... + \sin \,\,n\mathrm{\theta \;} equals
View answer and explanation
Correct option: A
sin⁡  12  (n+1)  θ  sin⁡  nθ2/sin⁡  θ2\sin \,\,\frac{1}{2}\,\,\left( {n + 1} \right)\,\,\mathrm{\theta }\,\,\sin \,\,\frac{{n\mathrm{\theta }}}{2}/\sin \,\,\frac{\mathrm{\theta }}{2}
Option A (sin⁡12(n+1)θsin⁡nθ2/sin⁡θ2\sin \frac{1}{2}\left( {n + 1} \right)\theta \sin \frac{{n\theta }}{2}/\sin \frac{{\theta }}{2}) is correct because it represents the sum of a sine series using the appropriate trigonometric formula.
111 Easy
111 of 112
Application +4 | -1
The maximum value of cos⁡2A+cos⁡2B−cos⁡2C{\cos ^2}A + {\cos ^2}B - {\cos ^2}C, is
View answer and explanation
Correct option: D
2
Option D (2) is correct because the maximum value is attained when cos²A and cos²B are maximized (equal to 1) and cos²C is minimized (equal to 0).
112 Easy
112 of 112
Analyzing +4 | -1
The equation sin⁡4θ+cos⁡4θ=a{\sin ^4}\theta + {\cos ^4}\theta = a has a real solution if
View answer and explanation
Correct option: A
a∈[1/2,1]a \in \left[ {1/2,1} \right]
Option A is correct because it finds the range of 'a' for which the equation has real solutions by using trigonometric identities and the range of cosine function.
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