Skip to main content
Back to TRANSFORMATIONS

Your Progress

0 / 112 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • TRANSFORMATIONS

Transformations practice · Easy

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 61-90 of 112 questions
61 Easy
61 of 112
Application +4 | -1
The period of the function f(θ)=sin⁡θ3+cos⁡θ2f\left( \mathrm{\theta } \right) = \sin \frac{\mathrm{\theta }}{3} + \cos \frac{\mathrm{\theta }}{2} is
View answer and explanation
Correct option: D
12π12\pi
Option D is correct because the period of the sum of two trigonometric functions is the LCM of their individual periods.
62 Easy
62 of 112
Application +4 | -1
The function f(x)=sin⁡πx2+2cos⁡πx3−tan⁡πx4f\left( x \right) = \sin \frac{{\pi x}}{2} + 2\cos \frac{{\pi x}}{3} - \tan \frac{{\pi x}}{4} is periodic with period
View answer and explanation
Correct option: D
12
Option D (12) is correct because the period of the sum of periodic functions is the least common multiple (LCM) of their individual periods, which in this case is LCM(4, 6, 4) = 12.
63 Easy
63 of 112
Application +4 | -1
The period of the function f(x)=sin⁡(sin⁡x5)f\left( x \right) = \sin \left( {\sin \frac{x}{5}} \right) is
View answer and explanation
Correct option: C
10π10\pi
Option C (10π10\pi) is correct because it is the smallest value for which f(x+10π)=f(x)f(x + 10\pi) = f(x).
64 Easy
64 of 112
Application +4 | -1
If sin⁡  (x+3α)=3 sin⁡(α−x)\sin \,\,\left( {x + 3\alpha } \right) = 3\,\sin \left( {\alpha - x} \right), then
View answer and explanation
Correct option: C
tan⁡  x=tan⁡3  α\tan \,\,x = {\tan ^3}\,\,\alpha
Option C (tan⁡ x=tan⁡3 α\tan \,x = {\tan ^3}\,\alpha) is correct because it is derived by applying componendo and dividendo and trigonometric identities to the given equation.
65 Easy
65 of 112
Application +4 | -1
If     xcos⁡  θ=ycos⁡  (θ−2 π3)=zcos(θ+2 π3),   then   x+y+z  \;\;\frac{x}{{\cos \,\,\mathrm{\theta }}} = \frac{y}{{\cos \,\,\left( {\mathrm{\theta } - \frac{{2\,\pi }}{3}} \right)}} = \frac{\mathrm{z}}{{cos\left( {\mathrm{\theta } + \frac{{2\,\pi }}{3}} \right)}},\;\,\mathrm{then}\;\,x + y + \mathrm{z}\; is equal to

View answer and explanation
Correct option: B
0\mathrm{0}
Option B (0\mathrm{0}) is correct because the sum of the cosines in the denominator simplifies to zero, making the entire expression equal to zero.
66 Easy
66 of 112
Application +4 | -1
In Δ ABC\Delta \,ABC, if sin⁡2A+sin⁡2B+sin⁡2C=2{\sin ^2}A + {\sin ^2}B + {\sin ^2}C = 2, then the triangle is
View answer and explanation
Correct option: A
Right angled, but need not be isosceles
Option A (Right angled, but need not be isosceles) is correct because the given condition sin⁡2A+sin⁡2B+sin⁡2C=2{\sin ^2}A + {\sin ^2}B + {\sin ^2}C = 2 implies that one of the angles is 90 degrees, making the triangle right-angled.
67 Easy
67 of 112
Analyzing +4 | -1
If the equation sin⁡4  θ+cos⁡4  θ=a{\sin ^4}\,\,\theta + {\cos ^4}\,\,\theta = a has a real solution then
View answer and explanation
Correct option: C
12≤a≤1\frac{1}{2} \le a \le 1
Option C (1/2 ≤ a ≤ 1) is correct because the given equation has a real solution only when a lies between 1/2 and 1, inclusive.
68 Easy
68 of 112
Application +4 | -1
If α+β−γ=π\alpha + \beta - \gamma = \pi, then sin⁡2  α+sin⁡2  β−sin⁡2  γ {\sin ^2}\,\,\alpha + {\sin ^2}\,\,\beta - {\sin ^2}\,\,\gamma \, is equal to
View answer and explanation
Correct option: A
2  sin⁡  α  sin⁡  β  cos⁡  γ2\,\,\sin \,\,\alpha \,\,\sin \,\,\beta \,\,\cos \,\,\gamma
Option A (2  sin⁡  α  sin⁡  β  cos⁡  γ2\,\,\sin \,\,\alpha \,\,\sin \,\,\beta \,\,\cos \,\,\gamma) is the correct answer because it is derived using trigonometric identities and the given condition α+β−γ=π\alpha + \beta - \gamma = \pi.
69 Easy
69 of 112
Application +4 | -1
The maximum value of cos⁡2  (π3−x)−cos⁡2  (π3+x)  {\cos ^2}\,\,\left( {\frac{\pi }{3} - x} \right) - {\cos ^2}\,\,\left( {\frac{\pi }{3} + x} \right)\; is
View answer and explanation
Correct option: C
32\frac{{\sqrt 3 }}{2}
Option C (32\frac{{\sqrt 3 }}{2}) is correct because the maximum value of the expression is achieved when sin⁡2x=1\sin 2x = 1, resulting in 32\frac{{\sqrt 3 }}{2}.
70 Easy
70 of 112
Application +4 | -1
The value of   sin⁡  20∘  sin⁡  40∘  sin⁡  60∘  sin⁡  80∘  \mathrm{\;}\sin \,\,20^\circ \,\,\sin \,\,40^\circ \,\,\sin \,\,60^\circ \,\,\sin \,\,80^\circ \mathrm{\;} is equal to
View answer and explanation
Correct option: C
316\frac{3}{{16}}
Option C (316\frac{3}{{16}}) is correct because the given trigonometric expression simplifies to 316\frac{3}{{16}} using trigonometric identities.
71 Easy
71 of 112
Analyzing +4 | -1
The value of cos⁡  π7+cos⁡  2 π7+cos⁡  3 π7+cos⁡  4 π7+cos⁡  5 π7+cos6π7+cos⁡  7π7\cos \,\,\frac{\pi }{7} + \cos \,\,\frac{{2\,\pi }}{7} + \cos \,\,\frac{{3\,\pi }}{7} + \cos \,\,\frac{{4\,\pi }}{7} + \cos \,\,\frac{{5\,\pi }}{7} + \mathrm{cos}\frac{{6\pi }}{7} + \cos \,\,\frac{{7\pi }}{7}, is
View answer and explanation
Correct option: B
−1- 1
Option B (-1) is correct because the sum of the given cosine series simplifies to -1.
72 Easy
72 of 112
Application +4 | -1
The value of sin⁡  50∘−sin⁡70∘+sin⁡10∘\sin \,\,50^\circ - \sin 70^\circ + \sin 10^\circ is
View answer and explanation
Correct option: A
0
Option A (0) is correct because the expression simplifies to 0 using trigonometric identities.
73 Easy
73 of 112
Analyzing +4 | -1
The range of the function,
f(x)=log⁡5(3+cos⁡(3π4+x)+cos⁡(π4+x)+cos⁡(π4−x)−cos⁡(3π4−x))f(x) = {\log _{\sqrt 5 }}\left( {3 + \cos \left( {\frac{{3\pi }}{4} + x} \right) + \cos \left( {\frac{\pi }{4} + x} \right) + \cos \left( {\frac{\pi }{4} - x} \right) - \cos \left( {\frac{{3\pi }}{4} - x} \right)} \right) is
View answer and explanation
Correct option: D
[0,  2][0,\,\,2]
Option D ([0, 2]) is correct because it represents the range of the function after simplifying the trigonometric expression and applying logarithmic properties.
74 Easy
74 of 112
Understanding +4 | -1
The smallest value of 5  cos⁡  θ+125\,\,\cos \,\,\theta + 12 is
View answer and explanation
Correct option: C
7
Option C (7) is correct because the minimum value of cos θ is -1, so the minimum value of the expression is 5*(-1) + 12 = 7.
75 Easy
75 of 112
Analyzing +4 | -1
If sin⁡  α=sin⁡  β\sin \,\,\alpha = \sin \,\,\beta and cos⁡  α=cos⁡  β\cos \,\,\alpha = \cos \,\,\beta, then
View answer and explanation
Correct option: C
sin⁡  α−β2=0\sin \,\,\frac{{\alpha - \beta }}{2} = 0
Option C (sin⁡α−β2=0\sin \frac{{\alpha - \beta }}{2} = 0) is correct because the given conditions sin⁡α=sin⁡β\sin \alpha = \sin \beta and cos⁡α=cos⁡β\cos \alpha = \cos \beta imply that sin⁡α−β2=0\sin \frac{{\alpha - \beta }}{2} = 0.
76 Easy
76 of 112
Application +4 | -1
If   α+β−γ=π,   then  sin⁡2  α+sin⁡2  β−sin⁡2  γ  \;\alpha + \beta - \gamma = \pi ,\,\;\mathrm{then}\,\,{\sin ^2}\,\,\alpha + {\sin ^2}\,\,\beta - {\sin ^2}\,\,\gamma \; is equal to

View answer and explanation
Correct option: A
2  sin⁡  α  sin⁡β  cos⁡  γ2\,\,\sin \,\,\alpha \,\,\sin \beta \,\,\cos \,\,\gamma
Option A, 2 sin⁡ α sin⁡β cos⁡ γ2\,\sin \,\alpha \,\sin \beta \,\cos \,\gamma, is correct because it is the simplified form of the given expression using trigonometric identities and the given condition   α+β−γ=π\;\alpha + \beta - \gamma = \pi.
77 Easy
77 of 112
Application +4 | -1
If cos⁡  x=3  cos⁡  y\cos \,\,x = 3\,\,\cos \,\,y, then 2  tan⁡  y−x22\,\,\tan \,\,\frac{{y - x}}{2} is equal to
View answer and explanation
Correct option: D
cot⁡  (x+y2)\cot \,\,\left( {\frac{{x + y}}{2}} \right)
Option D (cot⁡  (x+y2)\cot \,\,\left( {\frac{{x + y}}{2}} \right)) is correct because it is derived by applying componendo and dividendo and using trigonometric identities.
78 Easy
78 of 112
Analyzing +4 | -1
If in a Δ ABC,  cos⁡  A+2  cos⁡  B+cos⁡  C=2\Delta \,ABC,\,\,\cos \,\,A + 2\,\,\cos \,\,B + \cos \,\,C = 2, then a,  b,  ca,\,\,b,\,\,c are in
View answer and explanation
Correct option: A
A.P.
Option A (A.P.) is correct because the given condition leads to the relationship a + c = 2b, which defines an arithmetic progression.
79 Easy
79 of 112
Application +4 | -1
If A+B+C+D=πA+B+C+D=\pi, then the value of Σcos⁡Acos⁡C−Σsin⁡Asin⁡C=\Sigma \cos A \cos C-\Sigma \sin A \sin C=
View answer and explanation
Correct option: D
0
Option D (0) is correct because the given expression simplifies to cos⁡(A+C)+cos⁡(A+D)+cos⁡(B+C)+cos⁡(B+D)+cos⁡(A+B)+cos⁡(C+D)=0\cos(A+C) + \cos(A+D) + \cos(B+C) + \cos(B+D) + \cos(A+B) + \cos(C+D) = 0 given A+B+C+D=πA+B+C+D = \pi.
80 Easy
80 of 112
Application +4 | -1
The value of sin⁡  π14  sin⁡  3 π14  sin⁡  5 π14  sin⁡  7π14\sin \,\,\frac{\pi }{{14}}\,\,\sin \,\,\frac{{3\,\pi }}{{14}}\,\,\sin \,\,\frac{{5\,\pi }}{{14}}\,\,\sin \,\,\frac{{7\pi }}{{14}}, is
View answer and explanation
Correct option: C
1 / 8\mathrm{1}\,\mathrm{/}\,\mathrm{8}
Option C (1/8) is correct because the product of sines can be simplified using trigonometric identities to obtain the value 1/8.
81 Easy
81 of 112
Application +4 | -1
The minimum value of cos⁡  2θ+cos⁡  θ\cos \,\,2\theta + \cos \,\,\theta for real values of θ\theta, is
View answer and explanation
Correct option: A
− 9/8- \,9/8
Option A (− 9/8- \,9/8) is correct because the minimum value of cos⁡ 2θ+cos⁡θ\cos \,2\theta + \cos \theta is − 9/8- \,9/8 when θ\theta is a real number.
82 Easy
82 of 112
Application +4 | -1
sin⁡  12∘  sin⁡  48∘  sin⁡  54∘\sin \,\,12^\circ \,\,\sin \,\,48^\circ \,\,\sin \,\,54^\circ is equal to
View answer and explanation
Correct option: C
1 / 8\mathrm{1}\,\mathrm{/}\,\mathrm{8}
Option C (1 / 8\mathrm{1}\,\mathrm{/}\,\mathrm{8}) is correct because by using product-to-sum identities, the expression simplifies to 18\frac{1}{8}.
83 Easy
83 of 112
Application +4 | -1
The period of the function f(x)=cosec23x+cot⁡4xf\left( x \right) = \mathrm{cose}{\mathrm{c}^2}3x + \cot 4x is
View answer and explanation
Correct option: D
π\pi
Option D (π\pi) is correct because it is the least common multiple of the periods of the individual functions, which are π3\frac{\pi}{3} and π4\frac{\pi}{4}.
84 Easy
84 of 112
Application +4 | -1
Maximum value of sin⁡θ+cos⁡θ\sin \theta + \cos \theta in [0,   π2]\left[ {0,\;\,\frac{\pi }{2}} \right] is

View answer and explanation
Correct option: A
2\sqrt 2
Option A (2\sqrt 2) is correct because the maximum value of sin⁡θ+cos⁡θ\sin \theta + \cos \theta is 2\sqrt 2 and occurs at θ=π4\theta = \frac{\pi}{4} within the given interval.
85 Easy
85 of 112
Application +4 | -1
The value of sin⁡  55∘−cos⁡  55∘sin⁡  10∘\frac{{\sin \,\,55^\circ - \cos \,\,55^\circ }}{{\sin \,\,10^\circ }} is
View answer and explanation
Correct option: D
2\sqrt 2
Option D (2\sqrt{2}) is correct because the expression simplifies to 2\sqrt{2} after applying the sine subtraction formula and using the value of cos⁡45∘\cos 45^\circ.
86 Easy
86 of 112
Analyzing +4 | -1
The value of sin⁡  12∘  sin⁡  24∘  sin⁡  48∘  sin⁡  84∘\sin \,\,12^\circ \,\,\sin \,\,24^\circ \,\,\sin \,\,48^\circ \,\,\sin \,\,84^\circ, is
View answer and explanation
Correct option: A
cos⁡  20∘  cos⁡  40∘  cos⁡  60∘  cos⁡   80∘\cos \,\,20^\circ \,\,\cos \,\,40^\circ \,\,\cos \,\,60^\circ \,\,\cos \,\,\,80^\circ
Option A (cos⁡ 20∘ cos⁡ 40∘ cos⁡ 60∘ cos⁡ 80∘\cos \,20^\circ \,\cos \,40^\circ \,\cos \,60^\circ \,\cos \,80^\circ) is correct because it is equal to the given expression after applying trigonometric identities.
87 Easy
87 of 112
Application +4 | -1
If sin⁡  (x+y)sin⁡  (x−y)=a+ba−b\frac{{\sin \,\,\left( {x + y} \right)}}{{\sin \,\,\left( {x - y} \right)}} = \frac{{a + b}}{{a - b}}, then tan⁡  xtan⁡  y\frac{{\tan \,\,x}}{{\tan \,\,y}} is equal to
View answer and explanation
Correct option: B
ab\frac{a}{b}
Option B (ab\frac{a}{b}) is correct because it is derived by applying the componendo and dividendo rule and simplifying the trigonometric ratios.
88 Easy
88 of 112
Application +4 | -1
If sin⁡A=nsin  B\sin A = nsin\;B, then n−1n+1  tan⁡  A+B2\frac{{n - 1}}{{n + 1}}\,\,\tan \,\,\frac{{A + B}}{2} is equal to
View answer and explanation
Correct option: B
tan⁡  A−B2\tan \,\,\frac{{A - B}}{2}
Option B tan⁡  A−B2\tan \,\,\frac{{A - B}}{2} is correct because applying componendo and dividendo to n1=sin⁡Asin⁡B\frac{n}{1} = \frac{{\sin A}}{{\sin B}} and simplifying leads to the given expression being equal to tan⁡  A−B2\tan \,\,\frac{{A - B}}{2}.
89 Easy
89 of 112
Analyzing +4 | -1
If A+B+C=180∘A + B + C = 180^\circ, then ∑  tan⁡  A2  tan⁡  B2\sum \,\,\tan \,\,\frac{A}{2}\,\,\tan \,\,\frac{B}{2} is
View answer and explanation
Correct option: B
1
Option B (1) is correct because the given condition A+B+C=180∘A + B + C = 180^\circ leads to the trigonometric identity ∑tan⁡A2tan⁡B2=1\sum \tan \frac{A}{2} \tan \frac{B}{2} = 1.
90 Easy
90 of 112
Application +4 | -1
If 5  cos⁡x+12  cos⁡y=135\,\,\cos x + 12\,\,\cos y = 13, then the maximum value of 5  sin⁡x+12  sin⁡y5\,\,\sin x + 12\,\,\sin y is
View answer and explanation
Correct option: B
120\sqrt {120}
Option B is correct because it represents the maximum value obtained by using the given equation and trigonometric identities.
Revision notes and key takeaways

Review TRANSFORMATIONS in your textbook or class notes, then use this set to check your understanding.

Showing 61-90 of 112 questions
0 /112
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.