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JEE • MATHEMATICS • STRAIGHT LINES

Straight lines practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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511 Easy
511 of 555
Analyzing +4 | -1
The circumcentre of the triangle formed by the lines y=x,  y=2xy = x,\;y = 2x and y=3x+4y = 3x + 4 is
View answer and explanation
Correct option: B
(6,  −8)\left( {6,\; - 8} \right)
Option B ((6, -8)) is correct because it represents the circumcenter of the triangle formed by the given lines, found by solving equations derived from the circumcenter's properties.
512 Easy
512 of 555
Application +4 | -1
The number of lines that are parallel to 2  x+6  y+7=02\;x + 6\;y + 7 = 0 and have an intercept of length 10 between the coordinate axes, is
View answer and explanation
Correct option: B
2
Option B (2) is correct because there are two lines that satisfy the given conditions of being parallel and having a specific intercept length.
513 Medium
513 of 555
Application +4 | -1
If the line 2x+y=k2 x+y=k passes through the point which divides the line segment joining the points (1,1)(1,1) and (2,4)(2,4) in the ratio 3:23: 2, then kk equals
View answer and explanation
Correct option: C
6
Option C (6) is correct because substituting the coordinates of the point dividing the line segment in the given ratio into the line equation yields k=6.
514 Easy
514 of 555
Application +4 | -1
If the straight line ax+by+c=0ax + by + c = 0 always passes through (1,-2) then a,b,c are in
View answer and explanation
Correct option: A
AP
Option A (AP) is correct because substituting the point (1, -2) into the line equation results in a relationship that shows a, b, and c are in arithmetic progression.
515 Easy
515 of 555
Application +4 | -1
The image of the origin with reference to the line 4x+3y−25=0,  4x + 3y - 25 = 0,\; is
View answer and explanation
Correct option: B
(8,6)
The correct answer is B (8,6) because the image of the origin with respect to the line 4x + 3y - 25 = 0 is found using the reflection formula.
516 Medium
516 of 555
Application +4 | -1
The shortest distance between the two lines L1:x=k1L_1: x=k_1; y=k2y=k_2 and L2:x=k3;y=k4L_2: x=k_3 ; y=k_4 is equal to
View answer and explanation
Correct option: D
(k1−k3)2+(k2−k4)2\sqrt{\left(k_1-k_3\right)^2+\left(k_2-k_4\right)^2}
Option D ((k1−k3)2+(k2−k4)2\sqrt{(k_1-k_3)^2 + (k_2-k_4)^2}) is correct because it represents the Euclidean distance between two points in the xy-plane.
517 Easy
517 of 555
Application +4 | -1
The point of concurrence of the lines ax+by+c=0ax + by + c = 0 and a,b,c satisfy the relation 3a+2b+4c=03a + 2b + 4c = 0 is
View answer and explanation
Correct option: C
(34,12)\left( {\frac{3}{4},\frac{1}{2}} \right)
Option D ((34,12)\left( {\frac{3}{4},\frac{1}{2}} \right)) is correct because it satisfies the given relation 3a+2b+4c=03a + 2b + 4c = 0.
518 Easy
518 of 555
Application +4 | -1
If a circle is inscribed in an equilateral triangle of side aa, then area of the square inscribed in the circle is
View answer and explanation
Correct option: A
a26\frac{{{a^2}}}{6}
Option A (a26\frac{{{a^2}}}{6}) is correct because it is derived from calculating the inradius of the equilateral triangle and then finding the side of the inscribed square.
519 Medium
519 of 555
Analyzing +4 | -1
The sides of a rhombus ABCDA B C D are parallel to the lines, x−y+2=0x-y+2=0 and 7x−y+3=07 x-y+3=0. If the diagonals of the rhombus intersect at P(1,2)P(1,2) and the vertex AA (different from the origin) is on the yy-axis, then the ordinate of AA is
View answer and explanation
Correct option: D
52\frac{5}{2}
Option D (52\frac{5}{2}) is correct because it is the y-coordinate of point A, found by using the properties of a rhombus and angle bisectors.
520 Easy
520 of 555
Application +4 | -1
If the lines 3x−4y−13=0,8x−11y−33=03 x-4 y-13=0,8 x-11 y-33=0 and 2x−3y+λ=02 x-3 y+\lambda=0 are concurrent, then λ=\lambda=
View answer and explanation
Correct option: C
−7-7
Option C (-7) is correct because the determinant of the coefficients of the concurrent lines must be zero, leading to λ = -7.
521 Medium
521 of 555
Analyzing +4 | -1
The line LL has intercepts aa and bb on the coordinate axes. When keeping the origin fixed, the coordinate axes are rotated through a fixed angle, then the same line has intercepts pp and qq on the rotated axes. Then,
View answer and explanation
Correct option: B
1a2+1b2=1p2+1q2\frac{1}{a^2}+\frac{1}{b^2}=\frac{1}{p^2}+\frac{1}{q^2}
Option B (1a2+1b2=1p2+1q2\frac{{1}}{{a^2}}+\frac{{1}}{{b^2}}=\frac{{1}}{{p^2}}+\frac{{1}}{{q^2}}) is correct because the distance from the origin to the line remains constant under rotation.
522 Medium
522 of 555
Application +4 | -1
A variable line drawn through the point (1,3)(1,3) meets the XX-axis at AA and YY-axis at BB. If the rectangle OAPBO A P B is completed, where OO is the origin, then locus of PP is
View answer and explanation
Correct option: C
1x+3y=1\frac{1}{x}+\frac{3}{y}=1
Option C (1x+3y=1\frac{1}{x}+\frac{3}{y}=1) is correct because it represents the locus of point P, derived from the equation of a line passing through (1,3) and intersecting the X and Y axes.
523 Easy
523 of 555
Application +4 | -1
Family of lines xsec⁡2θ+ytan⁡2θ−2=0x{\sec ^2}\theta + y{\tan ^2}\theta - 2 = 0 for different θ\theta real , is
View answer and explanation
Correct option: C
Concurrent at (2,−2)\left( {2, - 2} \right)
Option C ((2,−2)\left( {2, - 2} \right)) is correct because the family of lines passes through the intersection of two lines derived from the given equation.
524 Medium
524 of 555
Application +4 | -1
Let A(2,−3)A\left( {2, - 3} \right) and B(−2,1)B\left( { - 2,1} \right) be vertices of a triangle ABCABC. If the centroid of this triangle moves on the line 2x+3y=12x + 3y = 1, then the locus of the vertex CC is the line
View answer and explanation
Correct option: A
2x+3y=92x + 3y = 9
Option A (2x+3y=92x + 3y = 9) is correct because the centroid's locus is used to find the locus of vertex C, resulting in the equation 2x+3y=92x + 3y = 9.
525 Medium
525 of 555
Application +4 | -1
The line parallel to xx-axis and passing through the point of intersection of lines ax+2by+3b=0a x+2 b y+3 b=0 and bx−2ay−3a=0b x-2 a y-3 a=0, where (a,b)≠(0,0)(a, b) \neq(0,0) is
View answer and explanation
Correct option: C
below xx-axis at a distance 3/23 / 2 from it
The correct answer is C (below x-axis at a distance 3/2) because substituting x=0 into the equations and solving for y gives y = -3/2, indicating the line is below the x-axis.
526 Easy
526 of 555
Application +4 | -1
If points (a2,0),(0,b2)\left(a^2, 0\right),\left(0, b^2\right) and (1,1)(1,1) are collinear, then
View answer and explanation
Correct option: A
1a2+1b2=1\frac{1}{a^2}+\frac{1}{b^2}=1
Option A (1a2+1b2=1\frac{1}{a^2}+ \frac{1}{b^2}=1) is correct because it represents the condition for the three points to be collinear.
527 Easy
527 of 555
Application +4 | -1
The length of perpendicular from the point (acos⁡α,  asin⁡α)\left( {a\cos \mathrm{\alpha },\;a\sin \alpha } \right) upon the straight line y=xtan⁡α+c,c>0y = x\tan \alpha + c,c > 0 is
View answer and explanation
Correct option: C
ccos⁡αc\cos \mathrm{\alpha }
Option C (ccos⁡αc\cos \mathrm{\alpha }) is correct because it is the perpendicular distance calculated from the point to the line using the perpendicular distance formula.
528 Easy
528 of 555
Application +4 | -1
If the algebraic sum of the perpendicular distances from the points (2,0),(0,2)(2,0),(0,2) and (1,1)(1,1) to a variable straight line be zero, then the line passes through the point
View answer and explanation
Correct option: B
(1,1)(1,1)
Option B ((1,1)) is correct because substituting (1,1) into the derived equation satisfies the condition that the algebraic sum of perpendicular distances is zero.
529 Easy
529 of 555
Application +4 | -1
If the points (1,2) and (3,4) were to be on the same side of the line 3x−5y+a=0,3x - 5y + a = 0, then
View answer and explanation
Correct option: D
a<7a < 7 or a>11a > 11
Option D (a<7a < 7 or a>11a > 11) is correct because the product of the expressions obtained by substituting the points into the line's equation must be positive for the points to be on the same side.
530 Medium
530 of 555
Application +4 | -1
If the coordinates of A{A} and B{B} be (1,1)(1,1) and (5,7)(5,7), then the equation of the perpendicular bisector of the line segment AB{AB} is-
View answer and explanation
Correct option: A
2x+3y=182 x+3 y=18
Option D (None of these) is correct because the correct equation of the normal line is not among the provided options. The correct equation is 2x+3y-1=0, which is the same as one of the original lines.
531 Medium
531 of 555
Analyzing +4 | -1
The number of points on the line 3x+4y=53x + 4y = 5, which are at a distance of sec2  θ+2cossec2  θ,  θ∈R\mathrm{se}{\mathrm{c}^2}\;\mathrm{\theta } + 2\mathrm{cosse}{\mathrm{c}^2}\mathrm{\;\theta },\mathrm{\;\theta } \in R, from the point (1, 3) is
View answer and explanation
Correct option: B
2
Option B (2) is correct because there are two points on the line at the specified distance from the given point.
532 Easy
532 of 555
Analyzing +4 | -1
The coordinates of the point PP on the line 2x+3y+1=02 x+3 y+1=0, such that ∣PA−PB∣|P A-P B| is maximum, where AA is (2,0)(2,0) and BB is (0,2)(0,2) is
View answer and explanation
Correct option: B
(7,−5)(7,-5)
Option B ((7,-5)) is correct because the maximum value of |PA - PB| occurs when P, A, and B are collinear, and solving the equations of the lines gives the coordinates of P.
533 Easy
533 of 555
Application +4 | -1
The value of xx, so that 2 is the slope of the line through (2,5)(2,5) and (x,3)(x, 3), is
View answer and explanation
Correct option: A
1
Option A (1) is correct because setting the slope formula equal to 2 and solving for x yields x = 1.
534 Medium
534 of 555
Application +4 | -1
Point P(2,4)P(2,4) is translated through a distance 323 \sqrt{2} units measured parallel to the line y−x−1=0y-x-1=0, in the direction of decreasing ordinates, to reach at QQ. If RR is the image of QQ with respect to the line y−x−1=0y-x-1=0, then coordinates of RR are
View answer and explanation
Correct option: D
(0,0)(0,0)
Option D ((0,0)) is correct because after translating point P and reflecting the result across the given line, the final coordinates are (0,0).
535 Easy
535 of 555
Application +4 | -1
If A(0,0),B(12,0),C(12,2),D(6,7)A\left( {0,0} \right),B\left( {12,0} \right),C\left( {12,2} \right),D\left( {6,7} \right) and E(0,5)E\left( {0,5} \right) are the vertices of the pendagon ABCDEABCDE, then its area in square units, is
View answer and explanation
Correct option: D
63
Option D (63) is correct because it is the area of the pentagon calculated using the coordinate geometry formula.
536 Easy
536 of 555
Application +4 | -1
The distance of the point (1, 2) from the line x+y+5=0x + y + 5 = 0 measured along the line parallel to 3x−y=73x - y = 7 is equal to
View answer and explanation
Correct option: C
40\sqrt {40}
Option C (40\sqrt{40}) is correct because it is the distance calculated between the point (1,2) and the intersection point (-1,-4) along the specified parallel line.
537 Easy
537 of 555
Application +4 | -1
Acute angle between the lines represented by (x2+y2)3=4xy\left(x^2+y^2\right) \sqrt{3}=4 x y is
View answer and explanation
Correct option: A
π/6\pi / 6
Option A (π/6\pi / 6) is correct because the acute angle between the lines is calculated to be 30 degrees, which is equivalent to π/6\pi/6 radians.
538 Easy
538 of 555
Application +4 | -1
The measure of the angle between the lines x=yx=y and y−0y-0 is
View answer and explanation
Correct option: D
π4\frac{\pi}{4}
Option D (π4\frac{\pi}{4}) is correct because the angle between the lines is calculated using the slopes of the lines.
539 Medium
539 of 555
Remembering +4 | -1
Consider the following statements.

I. Let A(x1,y1),B(x2,y2)A\left(x_1, y_1\right), B\left(x_2, y_2\right) and C(x3,y3){C}\left(x_3, y_3\right) be the vertices of a triangle then centroid is (x1+x2+x33,y1+y2+y33)\left(\frac{x_1+x_2+x_3}{3}, \frac{y_1+y_2+y_3}{3}\right)

II. If the point P(x,y)P(x, y) divides the line joining the points A(x1,y1)A\left(x_1, y_1\right) and B(x2,y2)B\left(x_2, y_2\right) in the ratio m:nm: n (internally), then x=mx2+nx1m+n,y=my2+ny1m+nx=\frac{m x_2+n x_1}{m+n}, y=\frac{m y_2+n y_1}{m+n}

Choose the correct option.
View answer and explanation
Correct option: C
Both are true
Option C (Both are true) is correct because both the centroid formula and the section formula (internal division) are stated accurately.
540 Easy
540 of 555
Application +4 | -1
If (sin⁡θ,cos⁡θ),θ∈[0,2π](\sin \theta, \cos \theta), \theta \in[0,2 \pi] and (1,4)(1,4) lie on the same side or on the line 3x−y+1=0\sqrt{3} x-y+1=0, then the maximum value of sin⁡θ\sin \theta will be ______.
View answer and explanation
Correct option: A
0
Option A (0) is correct because the maximum value of sin⁡θ\sin \theta is 0 when θ\theta lies in the interval [4π3,2π][\frac{{4\pi}}{{3}}, 2\pi] based on the given inequality.
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