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JEE • MATHEMATICS • STATISTICS

Statistics practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 312 questions

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211 Easy
211 of 312
Application +4 | -1
For a symmetrical distribution Q1=20Q_1=20 and Q3=40Q_3=40. The value of 50 th percentile is
View answer and explanation
Correct option: B
30
Option B (30) is correct because for a symmetrical distribution, the 50th percentile (median) is the average of the first and third quartiles.
212 Easy
212 of 312
Application +4 | -1
The variance of first n natural numbers is
View answer and explanation
Correct option: B
n2−112\frac{{{n^2} - 1}}{{12}}
Option B (n2−112\frac{{{n^2} - 1}}{{12}}) is correct because it is the standard formula for the variance of the first n natural numbers.
213 Easy
213 of 312
Application +4 | -1
If the co-efficient of variation of a distribution is 60 and its standard deviation is 24, then its arithmetic mean is ____.
View answer and explanation
Correct option: A
40
Option A (40) is correct because the arithmetic mean is calculated using the coefficient of variation formula.
214 Easy
214 of 312
Application +4 | -1
If the mean deviation about median for the number 3,5,7,2k,12,16,21,243,5,7,2 k, 12,16,21,24 arranged in the ascending order, is 6 then the median is
View answer and explanation
Correct option: D
11
Option B (10) is correct because by using the given functional equation and the value of f(8), we can find f(14).
215 Easy
215 of 312
Application +4 | -1
Mean of nn items is xˉ\bar{x}. If these nn items are successively increased by 2,22,23,…,2n2,2^2, 2^3, \ldots, 2^n, then the new mean is
View answer and explanation
Correct option: B
xˉ+2n+1n−2n\bar{x}+\frac{2^{n+1}}{n}-\frac{2}{n}
Option B (xˉ+2n+1n−2n\bar{x}+\frac{2^{n+1}}{n}-\frac{2}{n}) is correct because it represents the new mean after successively increasing the items by powers of 2.
216 Easy
216 of 312
Understanding +4 | -1
If two regression lines are coincident, then which is correct?
View answer and explanation
Correct option: D
r=±1r= \pm 1
Option D (r=±1r= \pm 1) is correct because when two regression lines are coincident, it indicates a perfect positive or negative correlation, meaning the correlation coefficient is either +1 or -1.
217 Easy
217 of 312
Application +4 | -1
A sample of 35 observations has the mean as 30 and SD as 4. A second sample of 65 observations from the same population has mean as 70 and SD as 3. The SD of the combined sample is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated standard deviation of the combined sample is approximately 19.38, which is not among the given options.
218 Easy
218 of 312
Application +4 | -1
Let X={xεN:1≤x≤17}X = \left\{ {x\varepsilon N:1 \le x \le 17} \right\} and Y={ax+b:x∈X and a,b∈R,a>0}Y = \left\{ {ax + b:x \in X\,\mathrm{and}\,a,b \in R,a > 0} \right\} If mean and variance of elements of Y are 17 and 216 respectively, then a+b is equal to
View answer and explanation
Correct option: C
-7
The correct answer is C (-7) because it is found by using the given mean and variance to solve for a and b, then calculating a+b.
219 Easy
219 of 312
Application +4 | -1
If Cov⁡.(X,Y)=−16.5,Var⁡.(X)=2.89\operatorname{Cov} .({X}, {Y})=-16.5, \operatorname{Var} .({X})=2.89 and Var⁡.(Y)=\operatorname{Var} .({Y})= 100100 then coefficient of correlation ρ(X,Y)\rho(X, Y) is equal to
View answer and explanation
Correct option: B
-0.97
Option B (-0.97) is correct because it accurately calculates the correlation coefficient using the given covariance and variances.
220 Easy
220 of 312
Application +4 | -1
If the values 1,12,13,14,15,…,1n1, \frac{1}{2}, \frac{1}{3}, \frac{1}{4}, \frac{1}{5}, \ldots, \frac{1}{n} occur at frequencies 1,2,3,4,5,…,n1,2,3,4,5, \ldots, n, in a distribution, then the mean is
View answer and explanation
Correct option: D
2n+1\frac{2}{n+1}
Option D (2n+1\frac{2}{n+1}) is correct because it is the result of calculating the weighted mean of the given values and frequencies.
221 Easy
221 of 312
Application +4 | -1
If the arithmetic mean of 9 observations is 100 and that of 6 is 80 . Then, the combined mean of all the 15 observations will be
View answer and explanation
Correct option: D
92
Option D (92) is correct because the combined mean is calculated by weighting the means of the two groups by their respective sizes.
222 Easy
222 of 312
Application +4 | -1
The variance of the data 2, 4, 6, 8, 10 is
View answer and explanation
Correct option: C
8
Option C (8) is the correct variance. The variance is calculated by finding the average of the squared differences from the mean.
223 Easy
223 of 312
Application +4 | -1
The variance of 20 observations is 5. If each observation is multiplied by 2 then the new variance of the
resulting observations, is:
View answer and explanation
Correct option: C
20
Option C (20) is correct because when each observation is multiplied by a constant, the variance is multiplied by the square of that constant.
224 Easy
224 of 312
Application +4 | -1
The standard deviation of −1,−2,−3,−4,−5,−6,−7-1,-2,-3,-4,-5,-6,-7 is
View answer and explanation
Correct option: A
2
Option A (2) is correct because the standard deviation of the given data is calculated to be 2.
225 Easy
225 of 312
Application +4 | -1
If ∑i=19(xi−5)=9\sum\limits_{i = 1}^9 {\left( {{x_i} - 5} \right) = 9\mathrm{ }} and ∑i=19(xi−5)2=45\sum\limits_{i = 1}^9 {{{\left( {{x_i} - 5} \right)}^2} = 45}, then the standard deviation of the 9 items then the standard deviation of the 9 items x1,x2,...,x9{x_1},{x_2},...,{x_9} is
View answer and explanation
Correct option: C
2
Option C (2) is correct because the standard deviation is calculated using the given sums and remains unchanged when observations are shifted by a constant.
226 Easy
226 of 312
Understanding +4 | -1
If the correlation coefficient between xx and yy is 0.6 and if u=X−52u=\frac{{X}-5}{2} and v=Y−33v=\frac{{Y}-3}{3} then the coefficient of correlation between uu and vv is
View answer and explanation
Correct option: B
0.6
Option B (0.6) is correct because the correlation coefficient is invariant under linear transformations. Since u and v are linear transformations of X and Y, their correlation coefficient is the same as that of X and Y.
227 Easy
227 of 312
Application +4 | -1
If the mean of numbers 27,31,89,107,15627,31,89,107,156 is 82 , then the mean of 130,126,68,50,1130,126,68,50,1 is
View answer and explanation
Correct option: D
75
Option D (75) is correct because it is the arithmetic mean of the given numbers.
228 Easy
228 of 312
Application +4 | -1
The mean wage of 1000 workers in a factory running in two shifts of 700 and 300 workers is Rs. 500 . The mean wage of 700 workers working in day shift is Rs. 450 . The mean wage of workers working in the night shift is
View answer and explanation
Correct option: B
Rs. 616.67
Option B (Rs. 616.67) is correct because it represents the mean wage of workers in the night shift calculated using the weighted average formula.
229 Easy
229 of 312
Application +4 | -1
The test marks in Statistics for a class are 20, 24, 27, 38,18,42,35,21,44,18,31,36,41,26,2938,18,42,35,21,44,18,31,36,41,26,29. The median score of the class is
View answer and explanation
Correct option: C
29
Option C (29) is correct because the median is the middle value when the data is arranged in ascending order.
230 Easy
230 of 312
Understanding +4 | -1
The coefficient of correlation (r)(r) and the two regression coefficients byx,  bxy{b_{yx}},\;{b_{xy}} are related as
View answer and explanation
Correct option: D
r=(sign  byx)bxy  byxr = \left( {\mathrm{sig}n\;{b_{yx}}} \right)\sqrt {{b_{xy}}\;{b_{yx}}}
Option D is correct because the correlation coefficient r is the geometric mean of the regression coefficients, with the sign of r being the same as that of the regression coefficients.
231 Easy
231 of 312
Application +4 | -1
Let the six numbers a1,a2,a3,a4,a5,a6a_{1}, a_{2}, a_{3}, a_{4}, a_{5}, a_{6} be in A.P. and a1+a3=10a_{1}+a_{3}=10. If the mean of these six numbers is 192\frac{19}{2} and their variance is σ2\sigma^{2}, then 8σ28 \sigma^{2} is equal to:
View answer and explanation
Correct option: D
210
Option D (210) is correct because it involves finding the variance of an arithmetic progression.
232 Easy
232 of 312
Understanding +4 | -1
The mean of the squares of first nn natural numbers is
View answer and explanation
Correct option: D
16(n+1)(2n+1)\frac{1}{6}(n+1)(2 n+1).
Option D (16(n+1)(2n+1)\frac{1}{6}(n+1)(2 n+1)) is correct because the mean of the squares of the first n natural numbers is given by the formula ∑i=1ni2n=n(n+1)(2n+1)6n=(n+1)(2n+1)6\frac{{\sum_{i=1}^{n} i^2}}{{n}} = \frac{{n(n+1)(2n+1)}}{{6n}} = \frac{{(n+1)(2n+1)}}{{6}}.
233 Easy
233 of 312
Understanding +4 | -1
The arithmetic mean of the squares of the first nn natural numbers is
View answer and explanation
Correct option: B
(n+1)(2n+1)/6(n+1)(2 n+1) / 6
Option B ((n+1)(2n+1)/6(n+1)(2 n+1) / 6) is correct because it is the arithmetic mean of the squares of the first nn natural numbers.
234 Easy
234 of 312
Understanding +4 | -1
The means of a set of numbers is Xˉ{\bar X} . If each number is divided by 3, then the new mean is
View answer and explanation
Correct option: D
Xˉ3\frac{{\bar X}}{3}
Option D (Xˉ3\frac{{\bar X}}{3}) is correct because if each number is divided by 3, the new mean is simply the original mean divided by 3.
235 Easy
235 of 312
Application +4 | -1
Mean of 25 observations was found to be 78.4. But later on it was found that 96 was misread 69 . The correct mean is
View answer and explanation
Correct option: B
79.48
Option B (79.48) is correct because the correct mean is calculated by adjusting the incorrect sum of observations.
236 Easy
236 of 312
Application +4 | -1
For observation set xx data obtained is xi={11,12,13,…41}x_i=\{11,12,13, \ldots 41\}

For another observation set yy data obtained is yi={61,62,63,…91}y_i=\{61,62,63, \ldots 91\}

Then value of xˉ+yˉ+σ2\bar{x}+\bar{y}+\sigma^2 where xˉ,yˉ\bar{x}, \bar{y} are means of respective data set while σ2\sigma^2 is variance of combined data is
View answer and explanation
Correct option: C
807
Option C (807) is correct because it is the sum of the means of the two data sets and the variance of the combined data set, calculated using statistical formulas.
237 Easy
237 of 312
Application +4 | -1
If the mean of n observation 12,22,32,….,n2    is    46n11{1^2},{2^2},{3^2}, \ldots .,{n^2}\;\;\mathrm{is}\;\;\frac{{46n}}{{11}}, then n is equal to
View answer and explanation
Correct option: A
11
Option A (11) is correct because solving the equation for the mean of squares yields n=11 as the valid solution.
238 Easy
238 of 312
Understanding +4 | -1
If μ\mu is the mean of a distribution, then ∑fi(yi−μ)\sum f_i\left(y_i-\mu\right) is equal to
View answer and explanation
Correct option: C
0
Option C (0) is correct because the sum of the deviations from the mean, weighted by their frequencies, is always zero.
239 Easy
239 of 312
Understanding +4 | -1
The best average of dealing a qualitative data is
View answer and explanation
Correct option: B
Median
Option B (Median) is correct because the median is the most appropriate measure of central tendency for qualitative data, as it is not affected by extreme values.
240 Easy
240 of 312
Application +4 | -1
If σ\sigma is the standard deviation of a random variable xx, then the standard deviation of the random variable ax+bax + b, wherea,b∈Ra,b \in R is
View answer and explanation
Correct option: B
∣a∣σ\left| a \right|\sigma
Option B (∣a∣σ\left| a \right|\sigma) is correct because the standard deviation of a linear transformation ax + b is |a| times the standard deviation of x.
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