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JEE • MATHEMATICS • STATISTICS

Statistics practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 312 questions

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181 Easy
181 of 312
Application +4 | -1
The correlation between two variables xx and yy is given to be rr. The values of xx and yy change such that Cov⁡(x,y)\operatorname{Cov}(x, y) remains unaltered and Var⁡(x)\operatorname{Var}(x) and Var⁡(y)\operatorname{Var}(y) are changed to four times their original values. The new correlation coefficient is changed to
View answer and explanation
Correct option: B
16r16 \mathrm{r}
Option D (r4\frac{r}{4}) is correct because the new correlation coefficient is the original correlation coefficient divided by 4 due to the change in variances.
182 Easy
182 of 312
Analyzing +4 | -1
The number of values of a∈Na \in N such that the variance of 3,7,12,a,43−a3,7,12, a, 43-a is a natural number is :
View answer and explanation
Correct option: A
0
Option A (0) is correct because the variance calculation results in a non-natural number for all natural number values of 'a'.
183 Easy
183 of 312
Application +4 | -1
Median of 16,10,14,11,9,8,12,6,516,10,14,11,9,8,12,6,5 is
View answer and explanation
Correct option: A
10
Option A (10) is correct because after arranging the data in ascending order, the median is the middle value.
184 Easy
184 of 312
Application +4 | -1
The mean of 100 items is 49 . It was later discovered that three items taken as 40,20,5040,20,50 were actually 60 , 70,80 , respectively. The correct mean is
View answer and explanation
Correct option: C
50
Option C (50) is correct because the correct mean is calculated by adjusting the original sum with the corrected values and then dividing by the number of items.
185 Easy
185 of 312
Application +4 | -1
The marks of some students were listed out of 75. The SD of marks was found to be 9. Subsequently the marks were raised to a maximum of 100 and variance of new marks was calculated. The new variance is
View answer and explanation
Correct option: C
144
Option C (144) is correct because the variance is scaled by the square of the factor by which the marks are raised.
186 Easy
186 of 312
Application +4 | -1
The coefficient of correlation between xx and yy is 0.5 and their covariance is 16 and SD of xx is 4 , then SD of yy is
View answer and explanation
Correct option: B
8
Option B (8) is correct because it is the standard deviation of y calculated using the formula relating correlation coefficient, covariance, and standard deviations.
187 Easy
187 of 312
Application +4 | -1
If the lines of regression of Y{Y} on X{X} and X{X} on Y{Y} are respectively y=Kx+4y={K} x+4 and x=4y+5x=4 y+5, then
View answer and explanation
Correct option: B
0≤K≤140 \leq {K} \leq \frac{1}{4}
Option B (0≤K≤140 \leq {K} \leq \frac{1}{4}) is correct because the product of the regression coefficients must be less than or equal to 1, ensuring that the correlation coefficient's square is within the valid range.
188 Easy
188 of 312
Application +4 | -1
If the standard deviation of the numbers −1, 0, 1, k- 1,\,0,\,1,\,k is 5\sqrt 5 where k>0k > 0, then kk is equal to
View answer and explanation
Correct option: B
262\sqrt 6
Option B (262\sqrt 6) is correct because, using the formula for standard deviation and the given values, we can solve for k and find its value to be 262\sqrt 6.
189 Easy
189 of 312
Analyzing +4 | -1
Consider three observations a, ba,\,b and cc such that b = a + cb\, = \,a\, + \,c. If the standard deviation of a + 2, b + 2c, c + 2a\, + \,2,\,b\, + \,2c,\,c\, + \,2 is dd, then which of the following is true?
View answer and explanation
Correct option: B
b2=3(a2+c2)−9d2{b^2} = 3\left( {{a^2} + {c^2}} \right) - 9{d^2}
Option B (b2=3(a2+c2)−9d2{b^2} = 3\left( {{a^2} + {c^2}} \right) - 9{d^2}) is correct because it represents the relationship between the standard deviation and the given condition b = a + c.
190 Easy
190 of 312
Application +4 | -1
The arithmetic mean of the series 1,2,22,…,2n−11,2,2^2, \ldots, 2^{n-1} is
View answer and explanation
Correct option: B
(2n−1)/n\left(2^n-1\right) / n
Option B (2n−1n\frac{{2^n-1}}{{n}}) is correct because the arithmetic mean of a geometric series is the sum of the series divided by the number of terms.
191 Easy
191 of 312
Application +4 | -1
If the value of mode and mean is 60 and 66 respectively, then the value of median is-
View answer and explanation
Correct option: B
64
Option B (64) is correct because it is calculated using the empirical relationship between mode, median, and mean: Mode = 3 Median - 2 Mean.
192 Easy
192 of 312
Application +4 | -1
If the lines of regression are 3x+12y=19  and  3y+9x=46,  then  rxy3x + 12y = 19\;\mathrm{and}\;3y + 9x = 46,\;\mathrm{then}\;{r_{xy}}, will be
View answer and explanation
Correct option: B
−0.289- 0.289
Option B (−0.289-0.289) is correct because it is the result of calculating the correlation coefficient from the given regression lines, ensuring the correct sign.
193 Easy
193 of 312
Understanding +4 | -1
The point that lies on both the lines of regression for a bivariate distribution, is
View answer and explanation
Correct option: B
(xˉ,yˉ)(\bar{x}, \bar{y})
Option B is correct because the point of intersection of the two regression lines is always the means of the x and y variables, represented as (xˉ,yˉ)(\bar{x}, \bar{y}).
194 Easy
194 of 312
Understanding +4 | -1
Median is based on the
View answer and explanation
Correct option: D
middle 50%50 \% of items
Option D (middle 50% of items) is correct because the median represents the central value, dividing the data set into two equal halves, effectively encompassing the middle 50%.
195 Easy
195 of 312
Application +4 | -1
In a test of Statistics, marks were awarded out of 40 . The average of 15 students was 38 . Later, it was decided to give marks out of 50 . The new average marks will be
View answer and explanation
Correct option: B
47.5
Option B (47.5) is correct because the new average is calculated by multiplying the original average by the ratio of the new maximum marks to the old maximum marks.
196 Easy
196 of 312
Application +4 | -1
The mean of two samples of sizes 200 and 300 were found to be 25 and 10 respectively, their standard deviations were 3 and 4 respectively the variance of combined sample size of 500 is
View answer and explanation
Correct option: C
67.2
Option C (67.2) is correct because the combined variance is calculated using the formula σ2=n1(σ12+d12)+n2(σ22+d22)n1+n2\sigma^{2} = \frac{{n_{{1}}(\sigma_{{1}}^{{2}}+d_{{1}}^{{2}})+n_{{2}}(\sigma_{{2}}^{{2}}+d_{{2}}^{{2}})}}{{n_{{1}}+n_{{2}}}}, where did_i is the difference between the individual mean and the combined mean.
197 Easy
197 of 312
Understanding +4 | -1
The mode of the series 3,4,2,6,1,7,6,7,6,8,9,5 is
View answer and explanation
Correct option: B
6
Option B (6) is correct because the mode is the value that appears most frequently in the series, and 6 appears three times, which is more than any other number.
198 Easy
198 of 312
Application +4 | -1
The variance of the first nn natural numbers is
View answer and explanation
Correct option: A
(n2−112)\left( {\frac{{{n^2} - 1}}{{12}}} \right)
Option A ((n2−112)\left( {\frac{{{{{n^2} - 1}}}}{{{{12}}}}} \right)) is correct because it is the formula for the variance of the first n natural numbers.
199 Easy
199 of 312
Application +4 | -1
The mean of data 55,155,255,35555,155,255,355, 455 and 555 is
View answer and explanation
Correct option: B
305
Option B (305) is correct because the mean is calculated by summing the data points and dividing by the number of points.
200 Easy
200 of 312
Remembering +4 | -1
For a symmetrical distribution, the coefficient of skewness is
View answer and explanation
Correct option: B
0
Option B (0) is correct because in a symmetrical distribution, the mean, median, and mode are equal, resulting in a skewness coefficient of 0.
201 Easy
201 of 312
Application +4 | -1
The algebraic sum of the deviation of 20 observations measured from 30 is 2. Then, mean of observations is
View answer and explanation
Correct option: B
30.130.1
Option B (30.130.1) is correct because it is the mean of the observations calculated using the given algebraic sum of deviations.
202 Easy
202 of 312
Application +4 | -1
The mean marks of students of a school is 56 . The mean marks of girls is 60 and that of boys is 50. If number of boys and girls are nn and mm respectively, then 9nm\frac{9 n}{m} equals
View answer and explanation
Correct option: D
6
Option D (6) is correct because it is derived from setting up a weighted average equation for the mean marks of the school and solving for the ratio n/m.
203 Easy
203 of 312
Application +4 | -1
If in a moderately skewed distribution the values of mode and mean are 6  λ  and  9λ6\;\lambda \;and\;9\lambda respectively, then the value of the median is
View answer and explanation
Correct option: A
8  λ8\;\lambda
Option A (8;λ8\\;\lambda) is correct because the median is calculated using the relationship between mean, median, and mode in a moderately skewed distribution.
204 Easy
204 of 312
Application +4 | -1
The mean of the series x1,x2,…,xn{x_1},{x_2}, \ldots ,{x_n} is Xˉ.\bar X. If x2{x_2} is replaced by λ\lambda, then the new mean is
View answer and explanation
Correct option: D
n  Xˉ−x2+λn\frac{{n\;\bar X - {x_2} + \lambda }}{n}
Option D (n  Xˉ−x2+λn\frac{{n\;\bar X - {x_2} + \lambda }}{n}) is correct because it represents the new mean after replacing one of the values in the series.
205 Easy
205 of 312
Application +4 | -1
The mean and SD of the marks of 200 candidates were found to be 40 and 15 , respectively. Later, it was discovered that a score of 40 was wrongly read as 50 . The correct mean and SD\mathrm{SD} are respectively
View answer and explanation
Correct option: B
39.95,14.9839.95,14.98
Option B (39.95,14.9839.95,14.98) is correct because the corrected mean is 39.95 and the corrected standard deviation is approximately 14.98.
206 Easy
206 of 312
Application +4 | -1
In a set of 2n2 n distinct observations, each of the observations below the median of all the observations is increased by 5 and each of the remaining observations is decreased by 3 . Then the mean of the new set of observations:
View answer and explanation
Correct option: A
increases by 1
Option A (increases by 1) is correct because increasing the lower half by 5 and decreasing the upper half by 3 results in a net increase of 2 per observation, which averages to 1.
207 Easy
207 of 312
Application +4 | -1
If a variable takes the discrete values α+4,α−72,α−52,α−3,α−2,α+12,α−12\alpha+4, \alpha-\frac{7}{2}, \alpha-\frac{5}{2}, \alpha-3, \alpha-2, \alpha+\frac{1}{2}, \alpha-\frac{1}{2}, α+5(α>0)\alpha+5(\alpha > 0), then the median is
View answer and explanation
Correct option: A
α−54\alpha-\frac{5}{4}
Option A (α−54\alpha-\frac{5}{4}) is correct because it is the median of the given discrete values after arranging them in ascending order.
208 Easy
208 of 312
Application +4 | -1
The mean and variance of 7 observations are 8 and 16 respectively. If two observations are 6 and 8, then the variance of the remaining 5 observations is
View answer and explanation
Correct option: C
53625\frac{{536}}{25}
Option C (53625\frac{{536}}{{25}}) is correct because it is the variance calculated after removing the two observations and adjusting for the new mean.
209 Easy
209 of 312
Application +4 | -1
The two lines of regression are 13x−10y+11=013 x-10 y+11=0 and 2x−y−1=02 x-y-1=0, then mean of xx and yy series are
View answer and explanation
Correct option: B
3,5
Option C (4) is correct because the standard deviation of y is calculated using the regression coefficients and the variance of x.
210 Easy
210 of 312
Remembering +4 | -1
The sum of absolute deviations about median is
View answer and explanation
Correct option: A
Least
Option A (Least) is correct because the sum of absolute deviations is minimized when taken about the median.
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