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JEE • MATHEMATICS • STATISTICS

Statistics practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 465 questions
91 Medium
91 of 465
Application +4 | -1
A sample of 90 values has mean 55 and standard
deviation 3. A second sample of 110 values has mean
60 and standard deviation 2. The combined variance
is equal to (upto two decimal)
View answer and explanation
Correct option: A
12.43
Option A (12.43) is correct because the combined variance is calculated using the formula that accounts for both the individual variances and the differences between the individual means and the overall mean.
92 Medium
92 of 465
Application +4 | -1
If for a distribution ∑(x−5)=3,∑(x−5)2=43\sum(x-5)=3, \sum(x-5)^2=43 and the total number of items is 18.

Statement-I: Mean of the distribution is 4.1666.

Statement-II: Standard deviation of the distribution is 1.54.
View answer and explanation
Correct option: B
Only Statement II is true
The correct answer is None of these. The equation of tangent to 4x2−9y2=364 x^2-9 y^2=36 which are perpendicular to straight line 5x+2y−10=05 x+2 y-10=0 are not found because the roots are imaginary.
93 Easy
93 of 465
Application +4 | -1
Which of the following is correct about the series 24,38,55,69,8924,38,55,69,89 ?
View answer and explanation
Correct option: C
Mean = Median
Option C (Mean = Median) is correct because the calculated mean and median of the given series are both equal to 55.
94 Easy
94 of 465
Application +4 | -1
Karl Pearson's coefficient of skewness of a distribution is 0.32 . Its SDS D is 6.5 and mean 39.6. Then, the median of the distribution is given by
View answer and explanation
Correct option: B
38.9
Option B (38.9) is correct because it is the approximate median calculated using Karl Pearson's coefficient of skewness formula.
95 Easy
95 of 465
Application +4 | -1
The variance of first 50 even natural numbers is
View answer and explanation
Correct option: B
833
Option B (833) is correct because the variance of the first 50 even natural numbers is calculated using the formula for variance and the sum of squares.
96 Medium
96 of 465
Application +4 | -1
Coefficient of variation of two distributions are 50%50 \% and 60%60 \% and their arithmetic means are 30 and 25 respectively. Difference of standard deviation is:
View answer and explanation
Correct option: D
0
Option D (0) is correct because the difference in standard deviations is 0, as both distributions have the same standard deviation of 15.
97 Easy
97 of 465
Remembering +4 | -1
The intersecting point of two regression lines is
View answer and explanation
Correct option: D
(xˉ,yˉ)(\bar x,\bar y)
Option D ((xˉ,yˉ)(\bar x,\bar y)) is correct because the point of intersection of the two regression lines is the mean of x and y, represented as (xˉ,yˉ)(\bar x,\bar y).
98 Medium
98 of 465
Understanding +4 | -1
The 7th{7^{th}} percentile is equal to
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the 7th percentile is equal to the 70th percentile, not the 7th decile, 6th decile, or the third quartile.
99 Medium
99 of 465
Application +4 | -1
Coefficient of variation of two distributions are 60% and 75%, and their standard deviation are 18 and 15
respectively, then their arithmetic means respectively are
View answer and explanation
Correct option: B
30, 20
Option B (30, 20) is correct because it correctly calculates the arithmetic means using the given coefficients of variation and standard deviations.
100 Medium
100 of 465
Understanding +4 | -1
If xˉ\bar{x} is the mean and σ2\sigma^2 is the variance of nn observations x1,x2,…,xnx_1, x_2, \ldots, x_n, then which of the following are true for the observations ax1,ax2,ax3,…,axn?{ax}_1, {ax}_2,{ax}_3, \ldots, {ax}_n?

I. Mean of the observations is xˉa\frac{\bar{x}}{{a}}.

II. Variance of the observations is σ2a2\frac{\sigma^2}{{a}^2}.

III. Mean of the observations is axˉa \bar{x}.

IV. Variance of the observations is a2σ2a^2 \sigma^2.
View answer and explanation
Correct option: D
III and IV are true
Option D (III and IV are true) is correct because multiplying each observation by a constant 'a' multiplies the mean by 'a' and the variance by a squared.
101 Easy
101 of 465
Application +4 | -1
The AM of the series 1,2,4,8,16,…,2n,1,2,4,8,16, \ldots ,{2^n}, is
View answer and explanation
Correct option: B
2n+1−1n+1\frac{{{2^{n + 1}} - 1}}{{n + 1}}
Option B (2n+1−1n+1\frac{{{2^{n + 1}} - 1}}{{n + 1}}) is correct because it represents the arithmetic mean of a geometric series with the given terms.
102 Easy
102 of 465
Application +4 | -1
The mode of a moderately symmetrical series is 18 and mean is 24 . The median is
View answer and explanation
Correct option: C
22
Option C (22) is correct because it is the median calculated using the empirical relationship between mean, median, and mode for a moderately symmetrical series.
103 Easy
103 of 465
Application +4 | -1
The mean of a set of 30 observations is 75 . If each other observation is multiplied by a non-zero number λ\lambda and then each of them is decreased by 25 , their mean remains the same. The λ\lambda is equal to
View answer and explanation
Correct option: B
43\frac{4}{3}
Option B (43\frac{4}{3}) is correct because setting up the equation for the new mean and solving for λ\lambda gives λ=43\lambda = \frac{4}{3}.
104 Easy
104 of 465
Application +4 | -1
The coefficient of variation of two series are 70 and 90 and their standard deviation are 17.5 and 18 , respectively. The mean of two series are
View answer and explanation
Correct option: A
25,20
Option A (25,20) is correct because the means are calculated by rearranging the coefficient of variation formula.
105 Easy
105 of 465
Application +4 | -1
The mean of the numbers a,  b,  8,  5,  10a,\,\,b,\,\,8,\,\,5,\,\,10 is 6 and their variance is 6.8. If MM is the mean deviation of the numbers about the mean, then 25M25 M is equal to:
View answer and explanation
Correct option: A
60
Option C (5) is correct because it is the remainder when (2021)2023 is divided by 7, calculated using modular arithmetic.
106 Easy
106 of 465
Application +4 | -1
If the two regression coefficients are 0.8 and 0.2 , then the coefficient of correlation is
View answer and explanation
Correct option: A
0.4
Option A (0.4) is correct because the correlation coefficient is the geometric mean of the two regression coefficients.
107 Medium
107 of 465
Application +4 | -1
If the s.d. of a set of observations is 4 and if each observation is divided by 4, the s.d. of the new set of observations will be
View answer and explanation
Correct option: D
1
Option D (1) is correct because dividing each observation by a constant also divides the standard deviation by the same constant.
108 Medium
108 of 465
Application +4 | -1
The mean and the standard deviation (s.d.) of five observations are 9 and 0 , respectively.
If one of the observations is changed such that the mean of the new set of five observations becomes 10 , then their d. is?
View answer and explanation
Correct option: C
2
Option C (2) is correct. Since the initial standard deviation is 0, all observations are equal. After changing one observation, the new standard deviation can be calculated.
109 Easy
109 of 465
Application +4 | -1
Mean of 100 observation is 45. If it was later found that two observations 19 and 31 were incorrectly recorded as 91 and 13. The correct mean is
View answer and explanation
Correct option: C
44.46
Option C (44.46) is correct because the correct mean is calculated by subtracting the incorrect observations and adding the correct observations before dividing by the total number of observations.
110 Medium
110 of 465
Application +4 | -1
If the variance of 1,2,3,4,5,…,10 is 9912\frac{{99}}{{12}}, then the standard derivation of 3,6,9,12,…., 30 is
View answer and explanation
Correct option: B
3233\frac{3}{2}\sqrt {33}
Option B (3233\frac{3}{2}\sqrt {33}) is correct because the standard deviation of the new series is 3 times the standard deviation of the original series.
111 Medium
111 of 465
Application +4 | -1
Three forces P,Q,RP, Q, R are acting at a point in a plane. The angle between P,QP, Q and Q,RQ, R are 150∘150^{\circ} and 120∘120^{\circ} respectively, then for equilibrium; forces P,Q,RP, Q, R are in the ratio
View answer and explanation
Correct option: D
3:2:1\sqrt{3}: 2: 1
Option D, 3:2:1\sqrt{3}: 2: 1, is correct because it represents the ratio of the forces when they are in equilibrium, calculated using Lami's theorem.
112 Medium
112 of 465
Application +4 | -1
A batsman scores sums in 10 innings 38, 70, 48, 34, 42, 55, 46, 63, 54 and 44, then the deviation from median is
View answer and explanation
Correct option: A
8.6
Option A (8.6) is correct because it is the mean of the absolute deviations from the median of the given data.
113 Medium
113 of 465
Application +4 | -1
A particle is acted upon by three forces P,QP, Q and RR. It cannot be in equilibrium, if P:Q:R=P: Q: R=
View answer and explanation
Correct option: A
1:3:51: 3: 5
Option A, 1:3:51: 3: 5, is correct because the sum of the two smaller forces (1 and 3) is less than the largest force (5), violating the triangle inequality and preventing equilibrium.
114 Easy
114 of 465
Application +4 | -1
If mode of a data is 27 and mean is 24 , then median is
View answer and explanation
Correct option: B
25
Option B (25) is correct because the median is calculated correctly using the empirical relationship between mean, median, and mode.
115 Medium
115 of 465
Application +4 | -1
An aeroplane flies around a square, the sides of which measure 100 miles each. The aeroplane covers at a speed of 100 m/h100 \mathrm{~m} / \mathrm{h} the first side, at 200 m/h200 \mathrm{~m} / \mathrm{h} the seoond side, at 300 m/h300 \mathrm{~m} / \mathrm{h} the third side and 400 m/h400 \mathrm{~m} / \mathrm{h} the fourth side. The average speed of acroplane around the square is
View answer and explanation
Correct option: C
192mh192 \mathrm{mh}
Option C (192 mh) is correct because the average speed is calculated using the harmonic mean of the speeds over equal distances.
116 Easy
116 of 465
Remembering +4 | -1
Quartile deviation is nearly equal to
View answer and explanation
Correct option: C
2/3σ2 / 3 \sigma
Option C (2/3σ2 / 3 \sigma) is correct because the quartile deviation is approximately 2/3 of the standard deviation.
117 Easy
117 of 465
Application +4 | -1
In a moderately skewed distribution, the values of mean and median are 5 and 6 , respectively. The value of mode for such distribution is
View answer and explanation
Correct option: A
8
Option A (8) is correct because the mode is calculated using the empirical relationship between mean, median, and mode in a moderately skewed distribution.
118 Medium
118 of 465
Application +4 | -1
The mean weight of 120120 students in the second year class of a college is 56 kg56 {~kg}. If the mean weights of the boys and that of the girls in the class are 60 kg60 {~kg} and 50 kg50 {~kg} respectively, then the number of boys and girls separately in the class are
View answer and explanation
Correct option: C
72,48
Option C (72,48) is correct because it solves the system of equations to find the number of boys and girls based on their mean weights.
119 Medium
119 of 465
Application +4 | -1
The mean of a data set consisting of 20 observations is 40 . If one observation 53 was wrongly recorded as 33 , then the correct mean will be:
View answer and explanation
Correct option: A
41
Option A (41) is the closest correct answer. The correct mean is calculated by subtracting the incorrect value and adding the correct value, then dividing by the number of observations.
120 Easy
120 of 465
Application +4 | -1
If the variance of 1, 2, 3, 4, 5, ..., 10 is 9912\frac{{99}}{{12}}, then the standard derivation of 3, 6, 9, 12, ..., 30 is
View answer and explanation
Correct option: B
3233\frac{3}{2}\sqrt {33}
Option B (3233\frac{3}{2}\sqrt {33}) is correct because the standard deviation of the new series is 3 times the standard deviation of the original series.
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