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JEE • MATHEMATICS • STATISTICS

Statistics practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 391-420 of 465 questions

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391 Easy
391 of 465
Application +4 | -1
The mean weight of 9 items is 15. If one more item is added to the series, the mean becomes 16. The value of 10th item is
View answer and explanation
Correct option: C
25
Option C (25) is correct because the value of the 10th item is the difference between the total weight of 10 items and the total weight of 9 items.
392 Hard
392 of 465
Application +4 | -1
If the angle α\alpha between two forces of equal magnitude is reduced to α−π3\alpha-\frac{\pi}{3}, then the magnitude of their resultant becomes 3\sqrt{3} times of the earlier one. The angle α\alpha is
View answer and explanation
Correct option: B
2π/32 \pi / 3
Option B, 2π3\frac{2 \pi}{3}, is correct because it satisfies the condition that the resultant becomes 3\sqrt{3} times the earlier one when the angle is reduced by π3\frac{\pi}{3}.
393 Easy
393 of 465
Application +4 | -1
The mean of the values 0,1,2,3,….n,  0,1,2,3, \ldots .n,\; with the corresponding weights nC0,nC1,….,    nCn^n{C_0}{,^n}{C_1}, \ldots .,\;{\;^n}{C_n} respectively, is
View answer and explanation
Correct option: D
n2\frac{n}{2}
The correct answer is D (n2\frac{n}{2}) because it represents the mean of the values with the given binomial weights.
394 Easy
394 of 465
Understanding +4 | -1
The correlation coefficient 0.5 between xx and yy means
View answer and explanation
Correct option: B
25%25 \% of variations are explained
Option B is correct because the correlation coefficient squared (r2r^2) represents the proportion of variance in one variable explained by the other. Here, r2=0.52=0.25r^2 = 0.5^2 = 0.25, so 25% of the variations are explained.
395 Easy
395 of 465
Application +4 | -1
If xx and yy are two random variables with the same standard deviation and coefficient of correlation rr, then the coefficient of correlation between xx and x+yx+y is
View answer and explanation
Correct option: B
1+r2\sqrt{\frac{1+r}{2}}
Option B (1+r2\sqrt{\frac{1+r}{2}}) is correct because it is derived from the covariance and standard deviations of x and x+y.
396 Easy
396 of 465
Application +4 | -1
All the students of a class performed poorly in Mathematics. The teacher decided to give grace marks of 10 to each of the students. Which of the following statistical measures will not change even after the grace marks were given?
View answer and explanation
Correct option: D
Variance
Option D (Variance) is correct because adding a constant to all data points does not change the variance, as the spread of the data remains the same.
397 Easy
397 of 465
Application +4 | -1
The mean age of a combined group of men and women is 25 yr. if the mean age of the group of men is 26 and that of the group of women is 21, then the percentage of men and women in the group is
View answer and explanation
Correct option: B
80, 20
Option B (80, 20) is correct because the percentage of men and women is calculated by setting up a weighted average equation for the combined mean age.
398 Medium
398 of 465
Application +4 | -1
The mean of observations is 4.4 and the variance is 8.24 . If three of the five observations are 1,2 and 6 , then find the other two observations.
View answer and explanation
Correct option: A
9,4
Option A (9,4) is correct because these values satisfy both the mean and variance equations derived from the given data.
399 Medium
399 of 465
Application +4 | -1
For a set of 100 observations, taking assumed mean as 4 , the sum of the deviations is −11 cm-11 \mathrm{~cm}, and the sum of the squares of these deviations is 275 cm2275 \mathrm{~cm}^2. The coefficient of variation is
View answer and explanation
Correct option: A
41.13%41.13 \%
Option A (41.13 %) is correct because the coefficient of variation is calculated correctly using the given data and the assumed mean.
400 Easy
400 of 465
Application +4 | -1
The AM of the series 1,  2,  4,  8,  16,  ...,2n,1,\;2,\;4,\;8,\;16,\;...,{2^n}, is
View answer and explanation
Correct option: B
2n+1−1n+1\frac{{{2^{n + 1}} - 1}}{{n + 1}}
Option B (2n+1−1n+1\frac{{{2^{n + 1}} - 1}}{{n + 1}}) is correct because it represents the sum of the geometric series divided by the number of terms.
401 Easy
401 of 465
Application +4 | -1
Mean deviation of the series a,a+d,a+2d,a+2nda, a+d, a+2 d, a+2 n d from its mean is
View answer and explanation
Correct option: C
n(n+1)d(2n+1)\frac{n(n+1) d}{(2 n+1)}
Option C (n(n+1)d(2n+1)\frac{{n(n+1) d}}{{(2 n+1)}}) is correct because it accurately calculates the mean deviation of the given series from its mean.
402 Medium
402 of 465
Application +4 | -1
If two lines of regression are3xˉ−2yˉ+1=0  and  2xˉ−yˉ−2=03\bar x - 2\bar y + 1 = 0\;and\;2\bar x - \bar y - 2 = 0, then (xˉ,  yˉ)(\bar x,\;\bar y) is
View answer and explanation
Correct option: B
(5,8)\left( {5,8} \right)
Option B ((5,8)\left( {5,8} \right)) is correct because it is the solution to the system of equations formed by the two regression lines.
403 Easy
403 of 465
Understanding +4 | -1
If both the regression lines intersect perpendicularly, then
View answer and explanation
Correct option: C
r=0r = 0
Option C (r=0r = 0) is correct because if the regression lines are perpendicular, it means there is no linear relationship between the variables, hence the correlation coefficient is zero.
404 Medium
404 of 465
Application +4 | -1
The average weight of a class of 14 students is 42 kg42 \mathrm{~kg}. If the teacher is included then average weight increases by 400 g400 \mathrm{~g}, then weight of teacher is
View answer and explanation
Correct option: B
48
Option B (48) is correct because the teacher's weight is calculated by considering the increase in the average weight when the teacher is included.
405 Easy
405 of 465
Application +4 | -1
When a particle be kept at rest under the action of the following forces
View answer and explanation
Correct option: A
↑8N,↑5N,↓13N\uparrow 8 N, \uparrow 5 N, \downarrow 13 N
Option A, ↑8N,↑5N,↓13N\uparrow 8 N, \uparrow 5 N, \downarrow 13 N, is correct because the upward forces sum to equal the downward force, resulting in equilibrium.
406 Easy
406 of 465
Application +4 | -1
The correlation coefficient of two variable xx and yy is 0.8. The regression coefficient of yy on xx is 0.2, than the regression coefficient of xx on yy is
View answer and explanation
Correct option: A
3.23.2
Option A (3.23.2) is correct because it is calculated using the formula relating the correlation coefficient and regression coefficients.
407 Hard
407 of 465
Application +4 | -1
If the mean of 4,7,2,8,64,7,2,8,6 and aa is 7 , then the mean deviation from the median of these observations is
View answer and explanation
Correct option: D
3
Option D (3) is correct. The mean deviation from the median is calculated after finding the missing observation and the median.
408 Medium
408 of 465
Application +4 | -1
If the regression coefficient of XX on YY and YY on XX are -0.4 and -0.9 respectively, then the correlation coefficient between X{X} and Y{Y} is
View answer and explanation
Correct option: A
-0.6
Option A (-0.6) is correct because the correlation coefficient is the square root of the product of the regression coefficients, and it has the same sign as the regression coefficients.
409 Easy
409 of 465
Application +4 | -1
Let σ\sigma be standard deviation of nn observations. Each observation is multiplied by a constant cc. The standard deviation of resulting numbers is
View answer and explanation
Correct option: B
cσc \sigma
Option B (cσc \sigma) is correct because multiplying each observation by a constant multiplies the standard deviation by the absolute value of that constant.
410 Medium
410 of 465
Analyzing +4 | -1
Statement-1: The variance of first nn even natural numbers is n2−14\frac{n^2-1}{4}.

Statement-2 : The sum of first nn natural numbers is n(n+1)2\frac{n(n+1)}{2} and the sum of squares of first nn natural numbers is n(n+1)(2n+1)6\frac{n(n+1)(2 n+1)}{6}.
View answer and explanation
Correct option: C
Statement- 1 is false, Statement- 2 is true.
Statement-1 is false and Statement-2 is true, therefore option C is the correct answer.
411 Medium
411 of 465
Application +4 | -1
The quartile deviation of daily wages (in Rs.) of 7 persons given below is
12,7,15,10,17,17,2512,7,15,10,17,17,25
View answer and explanation
Correct option: B
2.5
Option B (2.5) is correct because it is the quartile deviation calculated as half the difference between the third and first quartiles.
412 Easy
412 of 465
Application +4 | -1
If the heights of 5 persons are 144 cm,153 cm,150 cm,158 cm144 \mathrm{~cm}, 153 \mathrm{~cm}, 150 \mathrm{~cm}, 158 \mathrm{~cm} and 155 cm155 \mathrm{~cm} respectively, then mean height is-
View answer and explanation
Correct option: C
152 cm152 \mathrm{~cm}
Option C (152 cm152 \text{{ cm}}) is correct because the mean height is calculated by summing the heights and dividing by the number of persons.
413 Medium
413 of 465
Application +4 | -1
The mean and standard deviation of the marks of 20 students were found to be 40 and 15 respectively. Later, it was discovered that a score of 60 was wrongly read as 40 , then the correct variance will be
View answer and explanation
Correct option: D
244
Option D (244) is correct because it calculates the corrected variance after accounting for the error in the student's score.
414 Easy
414 of 465
Application +4 | -1
In an experiment with 15 observations onx, the following results were available ∑x2=2830,  ∑x=170\sum {x^2} = 2830,\;\sum x = 170. One observation that was 20, was found to be wrong and was replaced by the correct value 30. Then, the corrected variance is
View answer and explanation
Correct option: A
78.078.0
Option A (78.078.0) is correct because it is the corrected variance calculated after replacing the incorrect observation with the correct value and using the variance formula.
415 Easy
415 of 465
Application +4 | -1
If the first item is increased by 1, second by 2 and so on, then the new mean is
View answer and explanation
Correct option: C
Xˉ+n+12\bar X + \frac{{n + 1}}{2}
Option C (Xˉ+n+12\bar X + \frac{{n + 1}}{2}) is correct because it represents the new mean after increasing each item by its position in the series.
416 Easy
416 of 465
Application +4 | -1
The quartile deviation of daily wages of 7 persons which are Rs. 12,7,15,10,17,17,25 is
View answer and explanation
Correct option: D
3.5
Option D (3.5) is correct because the quartile deviation is calculated as half the difference between the third and first quartiles.
417 Easy
417 of 465
Application +4 | -1
Coefficient of variance of a distribution is 60%60 \% and the standard deviation is 25 . The arithmetic mean of the distribution is
View answer and explanation
Correct option: C
1253\frac{125}{3}
Option C (1253\frac{125}{3}) is correct because the coefficient of variance is defined as the ratio of the standard deviation to the mean, allowing us to solve for the mean.
418 Medium
418 of 465
Application +4 | -1
The average rate of (i) motion in the case of a person who rides the first mile at 10 m/h10 \mathrm{~m} / \mathrm{h}, the next mile at 8 m/h8 \mathrm{~m} / \mathrm{h} and the third mile at 6 m/h6 \mathrm{~m} / \mathrm{h} (ii) increase in population which is the first decade has increased 20%20 \% in the next 25%25 \% and in the third 44%44 \% are (where, log⁡20=1.3010\log 20=1.3010, log⁡25=1.3979,log⁡28.02=1.4475\log 25=1.3979, \log 28.02=1.4475, log⁡44=1.6435\log 44=1.6435 )
View answer and explanation
Correct option: C
7.66,28.027.66,28.02
Option C (7.66, 28.02) is correct because it calculates the harmonic mean for the speeds and the geometric mean for the population increases.
419 Easy
419 of 465
Application +4 | -1
If the frequencies of first four numbers out of 1,2,4,6,81,2,4,6,8 are 2 , 3,3,23,3,2, respectively, then the frequency of 8 , if their AM is 5 , is
View answer and explanation
Correct option: C
6
Option C (6) is correct because it is the frequency of 8 that results in the given arithmetic mean of 5.
420 Easy
420 of 465
Application +4 | -1
The mean marks of 120 students is 20. It was later
discovered that two marks were wrongly taken as 50
and 80 instead of 15 and 18. The correct mean of
marks is
View answer and explanation
Correct option: A
19.19
Option A (19.19) is correct because it represents the corrected mean after accounting for the wrongly taken marks.
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