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JEE • MATHEMATICS • STATISTICS

Statistics practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-390 of 465 questions

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361 Easy
361 of 465
Understanding +4 | -1
The best average of dealing a qualitative data is
View answer and explanation
Correct option: B
Median
Option B (Median) is correct because the median is the most appropriate measure of central tendency for qualitative data, as it is not affected by extreme values.
362 Easy
362 of 465
Application +4 | -1
If σ\sigma is the standard deviation of a random variable xx, then the standard deviation of the random variable ax+bax + b, wherea,b∈Ra,b \in R is
View answer and explanation
Correct option: B
∣a∣σ\left| a \right|\sigma
Option B (∣a∣σ\left| a \right|\sigma) is correct because the standard deviation of a linear transformation ax + b is |a| times the standard deviation of x.
363 Easy
363 of 465
Understanding +4 | -1
If regression coefficient of yy on xx is 2 , then the regression coefficient of xx on yy is
View answer and explanation
Correct option: C
≤12\leq \frac{1}{2}
Option C (≤12\leq \frac{1}{2}) is correct because the product of the regression coefficients must be less than or equal to 1. If byx=2b_{yx} = 2, then bxyb_{xy} must be less than or equal to 1/2.
364 Easy
364 of 465
Application +4 | -1
The mean weight per student in a group of seven students is
55 kg. If the individual weights of 6 students are 52, 58, 55,
53, 56 and 54; then weights of the seventh student is
View answer and explanation
Correct option: C
57 kg
Option C (57 kg) is correct because it is the weight that, when added to the weights of the other six students, results in the correct mean weight.
365 Easy
365 of 465
Understanding +4 | -1
The standard deviation for the set of numbers 1,4,51,4,5, 7,8 is 2.45 nearly. If 10 is added to each number, then new standard deviation is
View answer and explanation
Correct option: C
2.45
Option C (2.45) is correct because adding a constant to each number in a set does not change the standard deviation.
366 Medium
366 of 465
Understanding +4 | -1
A uniform rod of weight WW and length 2l2 l is resting in a smooth spherical bowl of radius rr. The rod is inclined to the horizontal at an angle of
View answer and explanation
Correct option: A
0∘0^{\circ}
Option A (0∘0^{\circ}) is correct because with a frictionless surface, the rod will rest at the minimum inclination, which is horizontal.
367 Easy
367 of 465
Application +4 | -1
The means and variance of n observations x1,x2,x3,…,xn{x_1},{x_2},{x_3}, \ldots ,{x_n} are 5 and 0 respectively. If ∑i=1nxi2=400\sum \limits_{i = 1}^n x_i^2 = 400, then the value of n is equal to
View answer and explanation
Correct option: D
16
Option D (16) is correct because the variance is 0, all observations are equal to the mean, and the sum of squares can be used to find n.
368 Easy
368 of 465
Application +4 | -1
A class of 30 boys and 15 girls is given a test in Mathematics. The average marks obtained by boys is 15 and by girls is 6 . The average of whole class is
View answer and explanation
Correct option: B
12
Option B (12) is correct because the average is calculated by weighting the average marks of boys and girls by their respective numbers.
369 Easy
369 of 465
Understanding +4 | -1
Semi-interquartile range is
View answer and explanation
Correct option: B
2σ/32 \sigma / 3
Option B (2σ/32 \sigma / 3) is correct because the semi-interquartile range is approximately equal to 2/32/3 of the standard deviation in a normal distribution.
370 Easy
370 of 465
Understanding +4 | -1
The mean of a set of number is xˉ\bar{x} if each number is increased by λ\lambda, then mean of the new set is-
View answer and explanation
Correct option: B
xˉ+λ\bar{x}+\lambda
Option B (xˉ+λ\bar{x}+\lambda) is correct because adding a constant to each number in a set increases the mean by that constant.
371 Easy
371 of 465
Application +4 | -1
5 students of a class have an average height 150 cm and variance 18cm2.18\mathrm{ }c{m^2}. A new student, whose height is 156 cm, joined them. The variance (in cm2c{m^2} )of the height of these six students is
View answer and explanation
Correct option: C
20
Option C (20) is correct because it is the variance of the heights of the six students after adding the new student, calculated using the updated mean and the given information.
372 Easy
372 of 465
Application +4 | -1
A student scores the following marks in five tests 45, 54, 41, 57, 43. His score is not known for the sixth test. If the mean score is 48 in the six tests, then the standard deviation of the marks in six tests is
View answer and explanation
Correct option: B
103\frac{{10}}{{\sqrt 3 }}
Option B (103\frac{{10}}{{\sqrt 3 }}) is correct because it is the standard deviation calculated from the given test scores and the unknown sixth test score, where the mean of the six scores is 48.
373 Easy
373 of 465
Application +4 | -1
If the S.D. of a variable XX is σ\sigma, then the S.D. of a  X+bc(a,b,c  are  constant),\frac{{a\;X + b}}{c}\left( {a,b,c\;\mathrm{are\;constant}} \right), is
View answer and explanation
Correct option: B
∣ac∣σ\left| {\frac{a}{c}} \right|\sigma
Option B (∣ac∣σ\left| {\frac{a}{c}} \right|\sigma) is correct because the standard deviation of a linear transformation of a variable is the absolute value of the coefficient times the original standard deviation.
374 Easy
374 of 465
Application +4 | -1
If the standard deviation of numbers 2, 4, 5 and 6 is a constant α\alpha, then the standard deviation of the numbers 4, 6, 7 and 8 is
View answer and explanation
Correct option: C
α\alpha
Option C (α\alpha) is correct because the standard deviation is independent of the change of origin.
375 Easy
375 of 465
Application +4 | -1
The geometric mean of observations 2,4,162,4,16 and 32 is
View answer and explanation
Correct option: C
8
Option C (8) is correct because the geometric mean of the given observations is 8.
376 Easy
376 of 465
Analyzing +4 | -1
Suppose a population AA has 100 observations 101,102,….,200 and another population B has 100 observations 151,152,….,250 if VA  and  VB{V_A}\;and\;{V_B} represent the variances of the two populations respectively, then VA  /  VB{V_A}\;/\;{V_B} is
View answer and explanation
Correct option: D
1
Option D (1) is correct because variance is independent of the change of origin, so the variances of both populations are equal, making their ratio 1.
377 Easy
377 of 465
Application +4 | -1
The correlation coefficient between x  and  yx\;and\;y from the following data ∑x=40,  \sum x = 40,\; ∑y=50,  ∑xy=220,  ∑x2=200,  ∑y2=262,  n=10\sum y = 50,\;\sum xy = 220,\;\sum {x^2} = 200,\;\sum {y^2} = 262,\;n = 10 is
View answer and explanation
Correct option: C
0.910.91
Option C (0.910.91) is correct because it is the calculated correlation coefficient using the provided data and the correlation coefficient formula.
378 Medium
378 of 465
Application +4 | -1
If the mean deviation of number 1,1+d,1+2d,…..,1+100d1,1 + d,1 + 2d, \ldots ..,1 + 100d from their mean is 255, then the d is equal to
View answer and explanation
Correct option: C
10.1
Option C (10.1) is correct because the value of d is calculated using the formula for mean deviation and the given mean deviation value.
379 Medium
379 of 465
Understanding +4 | -1
Consider any set of observations x1,x2,x3,…,x101x_1, x_2, x_3, \ldots, x_{101}; it being given that x1<x2<x3<…<x100<x101x_1 < x_2 < x_3 < \ldots < x_{100} < x_{101}, then the mean deviation of this set of observations about a point kk is minimum, when kk equals
View answer and explanation
Correct option: B
x51x_{51}
Option B (x51x_{51}) is correct because the mean deviation is minimized when calculated about the median, which is x51x_{51} in this ordered set.
380 Easy
380 of 465
Application +4 | -1
If xx and yy are deviations from arithmetic mean, r=0.8r=0.8&nbsp; Σxy=60,σy=2.5\Sigma x y=60, \sigma_y=2.5 and Σx2=90\Sigma x^2=90, then the number of items in the series, is
View answer and explanation
Correct option: A
10
Option A (10) is correct because the number of items is calculated using the correlation coefficient, covariance, and standard deviations.
381 Medium
381 of 465
Application +4 | -1
If xˉ{\bar x} is the arithmetic mean of n independent variates x1,x2,x3,…,xn{x_1},{x_2},{x_3}, \ldots ,{x_n} each of the standard derivation σ, then variance (xˉ)\left( {\bar x} \right) is
View answer and explanation
Correct option: A
σ2n\frac{{{\sigma ^2}}}{n}
Option A (σ2n\frac{{\sigma ^2}}{n}) is correct because the variance of the mean of n independent variates is the variance of the individual variates divided by n.
382 Easy
382 of 465
Application +4 | -1
The number of observations in a group is 40 . If the average of first 10 is 4.5 and that of the remaining 30 is 3.5 , then the average of the whole group is
View answer and explanation
Correct option: A
154\frac{15}{4}
Option A (154\frac{15}{4}) is correct because it is the weighted average of the two groups.
383 Easy
383 of 465
Application +4 | -1
The regression coefficient of yy on xx is 23\frac{2}{3} and xx on yy is 43\frac{4}{3}. If the acute angle between the regression line is θ\theta, then tan⁡θ\tan \theta is equal to
View answer and explanation
Correct option: C
118\frac{1}{18}
Option C (118\frac{1}{18}) is correct because it is the tangent of the acute angle between the regression lines, calculated using the given regression coefficients.
384 Easy
384 of 465
Application +4 | -1
If a variable takes values 0,1,2,3…0,1,2,3 \ldots with frequencies proportional to e−λ,e−λλ,e−λλ22!,e−λλ33!,…e^{-\lambda}, e^{-\lambda} \lambda, \frac{e^{-\lambda} \lambda^2}{2 !}, \frac{e^{-\lambda} \lambda^3}{3 !}, \ldots then the mean of the distribution is
View answer and explanation
Correct option: B
λ\lambda
Option B (λ) is correct because the mean of the Poisson distribution is equal to its parameter λ.
385 Easy
385 of 465
Application +4 | -1
If the two lines of regression are 4x+3y+7=0    and  3x+4y+8=0,4x + 3y + 7 = 0\;\;and\;3x + 4y + 8 = 0, then the means of x  and  yx\;and\;y are
View answer and explanation
Correct option: A
−47,−117\frac{{ - 4}}{7},\frac{{ - 11}}{7}
Option A (−47,−117\frac{{ - 4}}{7},\frac{{ - 11}}{7}) is correct because the means of x and y are found by solving the system of regression equations.
386 Medium
386 of 465
Understanding +4 | -1
If xˉ1\bar{x}_1 and xˉ2\bar{x}_2 are means of two distribution such that xˉ1<xˉ2\bar{x}_1 < \bar{x}_2 and xˉ\bar{x} is the mean of the joint distribution, then
View answer and explanation
Correct option: D
xˉ1<xˉ<xˉ2\bar{x}_1 < \bar{x} < \bar{x}_2
Option D (xˉ1<xˉ<xˉ2\bar{x}_1 < \bar{x} < \bar{x}_2) is correct because the mean of the joint distribution lies between the means of the individual distributions when xˉ1<xˉ2\bar{x}_1 < \bar{x}_2.
387 Easy
387 of 465
Application +4 | -1
The mean of series 1,2,4,8,….,2n1,2,4,8, \ldots ., 2^n is
View answer and explanation
Correct option: B
2n+1−1n+1\frac{2^{n+1}-1}{n+1}
Option B (2n+1−1n+1\frac{{2^{{n+1}}-1}}{{n+1}}) is correct because it represents the sum of a geometric series divided by the number of terms.
388 Medium
388 of 465
Application +4 | -1
The greatest and least magnitude of the resultant of two forces of constant magnitude are FF and GG. When the forces act an angle 2α2 \alpha, the resultant in magnitudes is equal to
View answer and explanation
Correct option: A
F2cos⁡2α+G2sin⁡2α\sqrt{F^2 \cos ^2 \alpha+G^2 \sin ^2 \alpha}
Option A, F2cos⁡2α+G2sin⁡2α\sqrt{F^2 \cos ^2 \alpha+G^2 \sin ^2 \alpha}, is correct because it represents the magnitude of the resultant when the forces act at an angle 2α2 \alpha, given the greatest and least magnitudes F and G.
389 Easy
389 of 465
Application +4 | -1
The number of children in 25 families of a locality are recorded as follows:
3,1,4,0,2,1,1,2,3,3,2,2,2,5,0,1,4,1,2,1,2,3,0,1,43,1,4,0,2,1,1,2,3,3,2,2,2,5,0,1,4,1,2,1,2,3,0,1,4
Then, mean number of children per family is
View answer and explanation
Correct option: A
2
Option A (2) is correct because the mean is calculated by summing the number of children in each family and dividing by the total number of families.
390 Medium
390 of 465
Application +4 | -1
Mean and variance of 10 positive observations is 7 and 8. If we add 5 to each number then sum of mean
and variance of new data is
View answer and explanation
Correct option: B
20
Option B (20) is correct because adding a constant to each observation increases the mean by that constant, while the variance remains unchanged. Therefore, the sum of the new mean and variance is 7 + 5 + 8 = 20.
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