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JEE • MATHEMATICS • SET THEORY

Set theory practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 31-60 of 78 questions
31 Medium
31 of 78
Understanding +4 | -1
If AA and BB are two disjoint sets, then which one of the following is correct?
View answer and explanation
Correct option: A
A−B=A−(A∩B)A-B=A-(A \cap B)
Option A (A−B=A−(A∩B)A-B=A-(A \cap B)) is correct because for disjoint sets, their intersection is empty, so removing the intersection from A doesn't change A.
32 Medium
32 of 78
Understanding +4 | -1
The set {x:x\{x: x is a positive integer less than 6 and 3x−13^x-1 is an even number }\} in roster form is
View answer and explanation
Correct option: A
{1,2,3,4,5}\{1,2,3,4,5\}
Option A ({1,2,3,4,5}\{1,2,3,4,5\}) is correct because 3x−13^x - 1 is an even number for all positive integers x. Therefore, all positive integers less than 6 satisfy the condition.
33 Medium
33 of 78
Application +4 | -1
20 teachers of a school either teach Mathematics or Physics. 12 of them teach Mathematics, while 4 teach both the subject. Then, the number of teachers teaching Physics only is
View answer and explanation
Correct option: B
8
Option B (8) is correct because it is calculated by subtracting the number of teachers teaching both subjects from the total number of teachers teaching Physics.
34 Medium
34 of 78
Understanding +4 | -1
The set A={x:x4−x3−x2=0A=\left\{x: x^4-x^3-x^2=0\right. and x∈N}\left.x \in N\right\} represents
View answer and explanation
Correct option: A
a null set
Option A (a null set) is correct because the equation x4−x3−x2=0x^4 - x^3 - x^2 = 0 has no natural number solutions.
35 Medium
35 of 78
Application +4 | -1
In a class of 35 students, 17 have taken Mathematics, 10 have taken Mathematics but not Economics. If each student has taken either Mathematics or Economics or both, then the number of students who have taken Economics but not Mathematics is
View answer and explanation
Correct option: C
18
The correct answer is C (18) because it is calculated by using set theory principles including union, intersection, and complement of sets.
36 Medium
36 of 78
Analyzing +4 | -1
Let P(S)P(S) denote the power set of S={1,2,3,…,10}S=\{1,2,3, \ldots, 10\}. Define the relations R1R_{1} and R2R_{2} on P(S)P(S) as AR1BA R_{1} B if (A∩BC)∪(B∩AC)=ϕ\left(A \cap B^{C}\right) \cup\left(B \cap A^{C}\right)=\phi and AR2BA R_{2} B if A∪BC=B∪AC,∀A,B∈P(S)A \cup B^{C}=B \cup A^{C}, \forall A, B \in P(S). Then
View answer and explanation
Correct option: D
Both R1R_{1} and R2R_{2} are equivalence relations
Option D is correct. Both R1R_1 and R2R_2 are equivalence relations because they both imply A=BA=B.
37 Medium
37 of 78
Analyzing +4 | -1
Let S={x∈R:x≥0S=\{x \in R: x \geq 0 and 2∣x−3∣+x(x−6)+6=02|\sqrt{x}-3|+\sqrt{x}(\sqrt{x}-6)+6=0. Then SS:
View answer and explanation
Correct option: B
Contains exactly two elements.
Option B (Contains exactly two elements) is correct because solving the equation for different intervals yields two valid solutions: x=4 and x=16.
38 Medium
38 of 78
Analyzing +4 | -1
Let A={ONGC,BHEL,SAIL,GAIL,IOCL}A = \left\{ {{\text{ONGC}},{\text{BHEL}},{\text{SAIL}},{\text{GAIL}},{\text{IOCL}}} \right\} and RR be a relation defined as “two elements of AA are related if they share exactly one letter”. The relation RR is
View answer and explanation
Correct option: C
Only symmetric
Option C (Only symmetric) is correct because the relation R is symmetric (if (a, b) is in R, then (b, a) is in R), but not reflexive, transitive, or anti-symmetric.
39 Medium
39 of 78
Application +4 | -1
In a class of 55 students, the number of students studying different subjects are 23 in mathematics, 24 in physics, 19 in chemistry, 12 in mathematics and physics, 9 in mathematics and chemistry, 7 in physics and chemistry and 4 in all the three subjects. The number of students who have taken exactly one subject is:
View answer and explanation
Correct option: D
22
The correct answer is D (22) because it is the sum of students studying exactly one subject, calculated using the principle of inclusion-exclusion.
40 Medium
40 of 78
Application +4 | -1
Let A={x∈W\mathrm{A}=\{\mathrm{x} \in \mathrm{W}, the set of whole numbers and x<3},B={x∈Nx < 3\}, B=\{x \in N, the set of natural numbers and 2≤x<4}2 \leq x < 4\} and C={3,4}C=\{3,4\}, then how manyelements will (A∪B)×C(\mathrm{A} \cup \mathrm{B}) \times \mathrm{C} contain?
View answer and explanation
Correct option: B
8
Option B (8) is correct because it represents the number of elements in the Cartesian product of the union of sets A and B with set C, calculated by finding the union and then the Cartesian product.
41 Medium
41 of 78
Application +4 | -1
Let S={θ∈[0,2π]:2cos⁡2θ+3sin⁡θ=0}S=\left\{\theta \in[0,2 \pi]: 2 \cos ^2 \theta+3 \sin \theta=0\right\} then number of elements of SS is
View answer and explanation
Correct option: A
2
Option A (2) is correct because solving the trigonometric equation 2cos⁡2θ+3sin⁡θ=02 \cos^2 \theta + 3 \sin \theta = 0 in the interval [0,2π][0, 2\pi] yields two solutions.
42 Medium
42 of 78
Analyzing +4 | -1
If A={θ:2cos⁡2θ+sin⁡θ≤2}A=\left\{\theta: 2 \cos ^2 \theta+\sin \theta \leq 2\right\} and B={θ:π2≤θ≤3π2}B=\left\{\theta: \frac{\pi}{2} \leq \theta \leq \frac{3 \pi}{2}\right\}, then A∩BA \cap B is equal to
View answer and explanation
Correct option: C
{θ:π2≤θ≤5π6\left\{\theta: \frac{\pi}{2} \leq \theta \leq \frac{5 \pi}{6}\right. or π≤θ≤3π2}\left.\pi \leq \theta \leq \frac{3 \pi}{2}\right\}
Option C (f(x)=tan⁡xf(x)=\tan x on [0,π][0, \pi]) is correct because tan⁡x\tan x is not continuous on the interval [0,π][0, \pi], thus Rolle's theorem is not applicable.
43 Medium
43 of 78
Analyzing +4 | -1
If A={p∈N:p  is  a  prime  and  p=7n2+3n+3n  for  some  n∈N},A = \left\{ {p \in N:p\;\mathrm{is\;}a\mathrm{\;prime\;and\;}p = \frac{{7{n^2} + 3n + 3}}{n}\mathrm{\;for\;some}\;n \in N} \right\}, then the number of elements in the set AA, is
View answer and explanation
Correct option: A
1
The correct answer is A (1) because the given condition leads to n=1, resulting in only one prime number.
44 Medium
44 of 78
Understanding +4 | -1
AA and BB are any two non-empty sets and AA is proper subset of BB. If n(A)=5,n\left( A \right) = 5, then find the minimum possible value of n(AΔB)n\left( {A\Delta B} \right)
View answer and explanation
Correct option: A
Is 1
Option A (Is 1) is correct because the minimum number of elements in B that are not in A is 1, given that A is a proper subset of B and n(A) = 5.
45 Medium
45 of 78
Application +4 | -1
If S{S} and T{T} are two sets such that S{S} has 21 elements, T{T} has 32 elements, and S∩T{S} \cap {T} has 11 elements, then number of elements S∪T{S} \cup {T} has
View answer and explanation
Correct option: A
42
Option A (42) is correct because it correctly uses the inclusion-exclusion principle to find the number of elements in the union of sets S and T.
46 Medium
46 of 78
Application +4 | -1
20 teachers of a school either teach mathematics or physics. 12 of them teach mathematics while 4 teach both the subjects. Then the number of teachers teaching physics only is
View answer and explanation
Correct option: B
8
Option B (8) is correct because it is calculated by subtracting the number of teachers teaching mathematics and both subjects from the total number of teachers.
47 Medium
47 of 78
Application +4 | -1
There are 600 student in a school. If 400 of them can speak Telugu, 300 can speak Hindi, then the number of students who can speak both Telugu and Hindi is:
View answer and explanation
Correct option: A
100
Option A (100) is correct because it is calculated using the formula for the number of elements in the union of two sets: n(A ∪ B) = n(A) + n(B) - n(A ∩ B).
48 Medium
48 of 78
Understanding +4 | -1
The cardinality of the set P{P[P(ϕ)]}\mathrm{P}\{\mathrm{P}[\mathrm{P}(\phi)]\} is
View answer and explanation
Correct option: D
4
Option D (4) is correct because the power set of the power set of the power set of the empty set has 4 elements.
49 Medium
49 of 78
Analyzing +4 | -1
A={x/x∈R,∣x∣<1}B={x/x∈R,∣x−1∣≥1}A=\{x / x \in R,|x|<1\} \quad B=\{x / x \in R,|x-1| \geq 1\} and A∪B=R−DA \cup B=R-D Then D=D=
View answer and explanation
Correct option: B
{x/1≤x<2}\{x / 1 \leq x<2\}
The correct answer cannot be determined without the options. Please provide the options to determine the correct answer.
50 Medium
50 of 78
Application +4 | -1
If A={1,2,3}A=\{1,2,3\} and B={3,8}B=\{3,8\}, then (A∪B)×(A∩B)(A \cup B) \times(A \cap B) is equal to
View answer and explanation
Correct option: D
{(1,3),(2,3),(3,3),(8,3)}\{(1,3),(2,3),(3,3),(8,3)\}
Option D ({(1,3),(2,3),(3,3),(8,3)}\left\{(1,3),(2,3),(3,3),(8,3)\right\}) is correct because it represents the Cartesian product of the union of sets A and B with the intersection of sets A and B.
51 Medium
51 of 78
Understanding +4 | -1
Which of the following is the empty set?
View answer and explanation
Correct option: B
{x:x\left\{x: x\right. is a real number and x2+1=0}\left.x^2+1=0\right\}
Option B ({x:x\{x: x is a real number and x2+1=0}\left.x^2+1=0\right\}) is the empty set because there is no real number whose square plus 1 equals 0.
52 Medium
52 of 78
Understanding +4 | -1
Let A={1,2},B={3,4}\mathrm{A}=\{1,2\}, \mathrm{B}=\{3,4\}. Then, number of subsets of A×B\mathrm{A} \times \mathrm{B} is
View answer and explanation
Correct option: D
16
Option D (16) is correct because the number of subsets of a set with n elements is 2^n. A x B has 4 elements.
53 Medium
53 of 78
Understanding +4 | -1
If A={(x,y):x2+y2=4;  x,y∈R}A = \left\{ {\left( {x,y} \right):{x^2} + {y^2} = 4;\;x,y \in R} \right\} and
B={(x,y):x2+y2=9;x,y∈R}B = \left\{ {\left( {x,y} \right):{x^2} + {y^2} = 9;x,y \in R} \right\}, then
View answer and explanation
Correct option: B
B−A=BB - A = B
Option B (B−A=BB - A = B) is correct because A and B represent circles centered at the origin with radii 2 and 3 respectively. Since A is contained within B, their intersection is empty, and removing A from B leaves B.
54 Medium
54 of 78
Application +4 | -1
Let XX be the universal set for sets AA and BB. If n(A)=200,n(B)=300n(A)=200, n(B)=300 and n(A∩B)=100n(A \cap B)=100, then n(A′∩B′)n\left(A^{\prime} \cap B^{\prime}\right) is equal to 300 , provided (X)(X) is equal to
View answer and explanation
Correct option: B
700
Option B (700) is correct because it is calculated using the formula for the union of two sets and De Morgan's law to find the size of the universal set.
55 Medium
55 of 78
Understanding +4 | -1
If A,BA, B and CC are three finite sets, then what is [(A∪B)∩C][(A \cup B) \cap C] equal to?
View answer and explanation
Correct option: C
A′∩B′∪C′A^{\prime} \cap B^{\prime} \cup C^{\prime}
Option C (A′∩B′∪C′A^{\prime} \cap B^{\prime} \cup C^{\prime}) is correct because it correctly applies De Morgan's law and the complement properties to simplify the expression.
56 Medium
56 of 78
Application +4 | -1
If XX and YY are two sets such that (X∪Y)(X \cup Y) has 60 elements, XX has 38 elements and YY has 42 elements, how many elements does (X∩Y)(\mathrm{X} \cap \mathrm{Y}) have?
View answer and explanation
Correct option: B
20
Option B (20) is correct because it is calculated using the formula for the number of elements in the union of two sets: n(X ∪ Y) = n(X) + n(Y) - n(X ∩ Y).
57 Medium
57 of 78
Analyzing +4 | -1
If A∪B=A∪CA \cup B=A \cup C and A∩B=A∩CA \cap B=A \cap C, then
View answer and explanation
Correct option: C
B=CB=C
Option A (A′A^{\prime}) is correct because the expression (A∪B)′∪(A′∩B)(A \cup B)^{\prime} \cup (A^{\prime} \cap B) simplifies to A′A^{\prime} using set identities.
58 Medium
58 of 78
Analyzing +4 | -1
Let P={θ:sin⁡θ−cos⁡θ=2cos⁡θ}P=\{\theta: \sin \theta-\cos \theta=\sqrt{2} \cos \theta\} and Q={θ:sin⁡θ+Q=\{\theta: \sin \theta+ cos⁡θ=2sin⁡θ}\cos \theta=\sqrt{2} \sin \theta\} be two sets. Then:
View answer and explanation
Correct option: C
P=Q{P}={Q}
Option C (P=Q) is correct because by manipulating the first equation, it can be shown to be equivalent to the second equation, indicating that both sets contain the same elements.
59 Medium
59 of 78
Application +4 | -1
If n(A)=4n(A)=4 and n(B)=7n(B)=7, then the minimum and maximum value of n(A∪B)n(A \cup B) are, respectively
View answer and explanation
Correct option: C
7 and 11
Option C (7 and 11) is correct because the minimum value of n(A ∪ B) occurs when A is a subset of B, and the maximum value occurs when A and B are disjoint.
60 Medium
60 of 78
Understanding +4 | -1
Let A={x:xA=\{x: x is a digit in the number 3591}\}, B={r:x∈N,x<10}B=\{r: x \in N, x<10\}.
Which of the following is false?
View answer and explanation
Correct option: D
A∪B={1,2,3,5,9}A \cup B=\{1,2,3,5,9\}
Option D (A∪B={1,2,3,5,9}A \cup B = \{1,2,3,5,9\}) is false because the union of A and B should include all elements from both sets, which is not accurately represented in this option.
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