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JEE • MATHEMATICS • SET THEORY

Set theory practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-194 of 194 questions
181 Easy
181 of 194
Understanding +4 | -1
If PP is the set of all parallelograms, and TT is the set of all trapeziums, then P∩TP \cap T is
View answer and explanation
Correct option: A
PP
Option A (PP) is correct because all parallelograms are also trapeziums, making the intersection of parallelograms and trapeziums the set of parallelograms.
182 Easy
182 of 194
Application +4 | -1
If A={x:x2−5x+6=0},B={2,4},C={4,5},A=\left\{x: x^2-5 x+6=0\right\}, B=\{2,4\}, C=\{4,5\}, then A×(B∩C)A \times(B \cap C) is
View answer and explanation
Correct option: A
{(2,4),(3,4)}\{(2,4),(3,4)\}
Option A ({(2,4),(3,4)}\{(2,4),(3,4)\}) is correct because it represents the Cartesian product of set A and the intersection of sets B and C.
183 Easy
183 of 194
Analyzing +4 | -1
The intersection of all the intervals having the form [1+1n,6−2n]\left[1+\frac{1}{n}, 6-\frac{2}{n}\right], where nn is a positive integer is
View answer and explanation
Correct option: C
[2,4][2,4]
Option C ([2,4]) is the correct answer because it represents the intersection of all intervals of the given form as n approaches infinity.
184 Easy
184 of 194
Analyzing +4 | -1
Let S={x∈[−6,3]−{−2,2}:∣x+3∣−1∣x∣−2≥0}S=\left\{x \in[-6,3]-\{-2,2\}: \frac{|x+3|-1}{|x|-2} \geq 0\right\} and T={x∈Z:x2−7∣x∣+9≤0}T=\left\{x \in \mathbb{Z}: x^2-7|x|+9 \leq 0\right\}. Then the number of elements in S∩TS \cap T is
View answer and explanation
Correct option: D
3
Option D is correct because by solving the inequalities for S and T, we find that the intersection S ∩ T contains 3 elements.
185 Easy
185 of 194
Understanding +4 | -1
If Na={an:n∈N}N_a=\{a n: n \in N\}, then N5∩N7=N_5 \cap N_7=
View answer and explanation
Correct option: C
N35N_{35}
Option C (N35N_{35}) is correct because the intersection of multiples of 5 and multiples of 7 are the multiples of their least common multiple, which is 35.
186 Easy
186 of 194
Application +4 | -1
If A1,A2,…,A100{A_1},{A_2}, \ldots ,{A_{100}} are sets such that n(Ai)=i+2,A1⊂A2⊂A3…⊂A100n\left( {{A_i}} \right) = i + 2,{A_1} \subset {A_2} \subset {A_3} \ldots \subset {A_{100}} and ∩i=3100Ai=A,\cap _{i = 3}^{100}{A_i} = A, then n(A)=n\left( A \right) =
View answer and explanation
Correct option: C
5
Option C (5) is correct because the intersection of nested sets from A3 to A100 is A3, and n(A3) = 3 + 2 = 5.
187 Easy
187 of 194
Application +4 | -1
If A={x∈C:x2=1}A=\left\{x \in \mathbb{C}: x^2=1\right\} and B={x∈C:x4=1}B=\left\{x \in \mathbb{C}: x^4=1\right\}, then AΔBA \Delta B is equal to
View answer and explanation
Correct option: C
{−i,i}\{-i, i\}
Option C ({−i,i}\left\{-i, i\right\}) is correct because it represents the symmetric difference between sets A and B, which includes elements in B but not in A.
188 Easy
188 of 194
Understanding +4 | -1
If A⊆BA \subseteq B, then B∪AB \cup A is equal to
View answer and explanation
Correct option: C
BB
Option C (BB) is correct because if A is a subset of B, then the union of B and A is equal to B.
189 Easy
189 of 194
Understanding +4 | -1
If the sets AA and BB are defined as:
A={(x,y):y=ex,x∈R}B={(x,y):y=x,x∈R}, then \begin{aligned} & A=\left\{(x, y): y=e^x, x \in R\right\} \\ & B=\{(x, y): y=x, x \in R\}, \text { then } \end{aligned}
View answer and explanation
Correct option: C
A∩B=ϕA \cap B=\phi
Option C (A∩B=ϕA \cap B = \phi) is correct because the graphs of y=exy = e^x and y=xy = x do not intersect, meaning there are no common points.
190 Easy
190 of 194
Application +4 | -1
In a town of 10,000 families it was found that 40% families buy newspaper A,20% families buy newspaper B and 10% families buy newspaper C,5% families buy A and B, 3% buy B and C and 4% buy A and C. If 2% families buy all the three newspapers, then the number of families which buy A only is
View answer and explanation
Correct option: B
3300
Option B (3300) is correct because it is found by using the principle of inclusion-exclusion to find the number of families that buy newspaper A only.
191 Easy
191 of 194
Understanding +4 | -1
Let A={2,3,4}{A}=\{2,3,4\} and X={0,1,2,3,4}{X}=\{0,1,2,3,4\}, then which of the following statements is correct
View answer and explanation
Correct option: C
{0}⊂A′\{0\} \subset {A}^{\prime} w.r.t X{X}
Option C (\{0\} ⊂ {A}^{′}w.r.tw.r.t{X}$) is correct because the set containing 0 is a subset of the complement of A with respect to X.
192 Easy
192 of 194
Understanding +4 | -1
The set of intelligent students in a class is:
View answer and explanation
Correct option: D
Not a well defined collection
Option D (Not a well defined collection) is correct because "intelligent students" is subjective and lacks a clear, objective criterion for membership, making it not a well-defined set.
193 Easy
193 of 194
Application +4 | -1
In a city 20% of the population travels by car, 50% travels by bus and 10% travels by both car and bus. Then, persons travelling by car or bus is
View answer and explanation
Correct option: C
60%60\%
Option C (60%60\%) is correct because it is the result of adding the individual percentages and subtracting the overlap, representing the total percentage traveling by car or bus.
194 Easy
194 of 194
Understanding +4 | -1
For any three sets A,BA, B and C,C, A×(B′∪C′)′A \times\left(B^{\prime} \cup C^{\prime}\right)^{\prime} equals
View answer and explanation
Correct option: A
(A×B)∩(A×C)(A \times B) \cap(A \times C)
Option A ((A×B)∩(A×C)(A \times B) \cap (A \times C)) is correct because it correctly applies De Morgan's law and the properties of Cartesian products to simplify the expression.
Revision notes and key takeaways

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