Skip to main content
Back to SET THEORY

Your Progress

0 / 273 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • SET THEORY

Set theory practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 241-270 of 273 questions

Preparing practice and saved progress…

241 Easy
241 of 273
Analyzing +4 | -1
Let R1, R2 are relations defined on Z such that a aR1b⇔(a−b)a{R_1}b \Leftrightarrow (a - b) is divisible by 3 and a R2 b⇔(a−b)b \Leftrightarrow (a - b) is divisible by 4. Then which of the two relations (R1∪R2),(R1∩R2)\left( {{R_1} \cup {R_2}} \right),\left( {{R_1} \cap {R_2}} \right) is an
equivalence relation?
View answer and explanation
Correct option: B
(R1∩R2)\left(R_1 \cap R_2\right) only
Option B ((R1∩R2)\left(R_1 \cap R_2\right) only) is correct because the intersection of equivalence relations is always an equivalence relation, while the union is not necessarily so.
242 Medium
242 of 273
Understanding +4 | -1
If AA and BB be two sets containing 3 and 6 elements respectively, what can be the minimum number of elements in A∪BA \cup B ?
View answer and explanation
Correct option: A
6
Option A is correct because the minimum number of elements in A ∪ B occurs when A is a subset of B, resulting in A ∪ B having the same number of elements as B, which is 6.
243 Medium
243 of 273
Understanding +4 | -1
If A={y:y=2x,x∈N},B={y:y=2x−1,x∈NA=\{y: y=2 x, x \in N\}, B=\{y: y=2 x-1, x \in N, then (A∩B)′(A \cap B)^{\prime} is
View answer and explanation
Correct option: D
UU
Option D (U) is correct because A contains all even numbers, B contains all odd numbers, their intersection is empty, and the complement of an empty set is the universal set U.
244 Medium
244 of 273
Understanding +4 | -1
Which one of the following is correct ?
View answer and explanation
Correct option: B
A−(B∪C)=(A∩B′)∩C′\mathrm{A}-(\mathrm{B} \cup \mathrm{C})=\left(\mathrm{A} \cap \mathrm{B}^{\prime}\right) \cap \mathrm{C}^{\prime}
Option B (A−(B∪C)=(A∩B′)∩C′A-(B \cup C)=(A \cap B^{\prime}) \cap C^{\prime}) is correct because it represents the set of elements in A that are not in B and not in C, which is equivalent to the intersection of A with the complements of B and C.
245 Easy
245 of 273
Understanding +4 | -1
If A={x:x=2n+1,n∈ZA=\{x: x=2 n+1, n \in Z and B={x:x=2n,n∈Z}B=\{x: x=2 n, n \in Z\}, then A∪BA \cup B is
View answer and explanation
Correct option: C
Set of integers
Option C is correct because A contains all odd integers, B contains all even integers, and their union is the set of all integers.
246 Easy
246 of 273
Analyzing +4 | -1
For any three sets A,BA, B and CC the set (A∪B∪C)∩(A∩B′∩C′)′∩C′(A \cup B \cup C) \cap\left(A \cap B^{\prime} \cap C^{\prime}\right)^{\prime} \cap C^{\prime} is equal to
View answer and explanation
Correct option: A
B∩C′B \cap C^{\prime}
Option A (B∩C′B \cap C^{\prime}) is the correct answer because after simplifying the set operations, the expression reduces to this intersection.
247 Easy
247 of 273
Application +4 | -1
If A={1,  2,  3,  4},A = \left\{ {1,\;2,\;3,\;4} \right\}, then the number of subsets of set A containing element 3, is
View answer and explanation
Correct option: C
8
Option C (8) is correct because there are 23 = 8 subsets that contain the element 3, formed from the remaining elements 1, 2, and 4.
248 Easy
248 of 273
Understanding +4 | -1
If XX and YY are two sets, then X∩(Y∪X)′X \cap {\left( {Y \cup X} \right)^\prime } equals
View answer and explanation
Correct option: C
ϕ\phi
Option C (ϕ\phi) is correct because X∩(Y∪X)′=X∩(Y′∩X′)=(X∩X′)∩Y′=ϕ∩Y′=ϕX \cap (Y \cup X)' = X \cap (Y' \cap X') = (X \cap X') \cap Y' = \phi \cap Y' = \phi.
249 Medium
249 of 273
Application +4 | -1
If A={1,2},B={1,3}A=\{1,2\}, B=\{1,3\}, then (A×B)∪(B×A)(A \times B) \cup(B \times A) is equal to
View answer and explanation
Correct option: A
{(1,3),(2,3),(3,1),(3,2),(1,1),(2,1),(1,2)}\{(1,3),(2,3),(3,1),(3,2),(1,1),(2,1),(1,2)\}
Option A ({ (1,3),(2,3),(3,1),(3,2),(1,1),(2,1),(1,2) }) is correct because it accurately represents the union of the Cartesian products A × B and B × A.
250 Easy
250 of 273
Application +4 | -1
In a class of 45 students, 22 can speak Hindi and 12 can speak English only. The number of students, who can speak both Hindi and English, is
View answer and explanation
Correct option: B
11
The correct answer is B (11) because it is calculated by using set theory principles including union, intersection, and complement of sets.
251 Easy
251 of 273
Application +4 | -1
A survey shows that 63% of the Americans like cheese whereas 76% like apples. If x%x\% of the Americans like both cheese and apples, then
View answer and explanation
Correct option: C
39⩽x⩽6339 \leqslant x \leqslant 63
The correct answer is C (39⩽x⩽6339 \leqslant x \leqslant 63) because the percentage of Americans who like both cheese and apples must be within the range where the total percentage does not exceed 100%.
252 Easy
252 of 273
Understanding +4 | -1
The number of non-empty subsets of the set {1,2,3,4}\{1,2,3,4\} is
View answer and explanation
Correct option: A
15
Option A (15) is correct because the number of non-empty subsets of a set with n elements is 2^n - 1.
253 Easy
253 of 273
Understanding +4 | -1
If PP is the set of all parallelograms, and TT is the set of all trapeziums, then P∩TP \cap T is
View answer and explanation
Correct option: A
PP
Option A (PP) is correct because all parallelograms are also trapeziums, making the intersection of parallelograms and trapeziums the set of parallelograms.
254 Medium
254 of 273
Understanding +4 | -1
Which of the following is/are true?

I. If AA is a subset of the universal set UU, then its complement A′\mathrm{A}^{\prime} is also a subset of U\mathrm{U}.

II. If U={1,2,3,….,10}\mathrm{U}=\{1,2,3, \ldots ., 10\} and A={1,3,5\mathrm{A}=\{1,3,5, 7,9}7,9\}, then (A′)′=A\left(A^{\prime}\right)^{\prime}=A.
View answer and explanation
Correct option: C
Both I and II are true
Option C (Both I and II are true) is correct because the complement of a subset of the universal set is also a subset, and the double complement of a set is the set itself.
255 Easy
255 of 273
Application +4 | -1
If A={x:x2−5x+6=0},B={2,4},C={4,5},A=\left\{x: x^2-5 x+6=0\right\}, B=\{2,4\}, C=\{4,5\}, then A×(B∩C)A \times(B \cap C) is
View answer and explanation
Correct option: A
{(2,4),(3,4)}\{(2,4),(3,4)\}
Option A ({(2,4),(3,4)}\{(2,4),(3,4)\}) is correct because it represents the Cartesian product of set A and the intersection of sets B and C.
256 Easy
256 of 273
Analyzing +4 | -1
The intersection of all the intervals having the form [1+1n,6−2n]\left[1+\frac{1}{n}, 6-\frac{2}{n}\right], where nn is a positive integer is
View answer and explanation
Correct option: C
[2,4][2,4]
Option C ([2,4]) is the correct answer because it represents the intersection of all intervals of the given form as n approaches infinity.
257 Medium
257 of 273
Understanding +4 | -1
Let S=\mathrm{S}= the set of all triangles, P=\mathrm{P}= the set of all isosceles triangles, Q=Q= the set of all equilateral triangles, R=\mathrm{R}= the set of all right-angled triangles.
What do the sets P∩QP \cap Q and R−PR-P represents respectively ?
View answer and explanation
Correct option: A
The set of isosceles triangles; the set of non- isosceles right angled triangles
Option A (The set of isosceles triangles; the set of non-isosceles right angled triangles) is correct because the intersection of isosceles and equilateral triangles is the set of isosceles triangles, and right-angled triangles excluding isosceles triangles are non-isosceles right-angled triangles.
258 Easy
258 of 273
Analyzing +4 | -1
Let S={x∈[−6,3]−{−2,2}:∣x+3∣−1∣x∣−2≥0}S=\left\{x \in[-6,3]-\{-2,2\}: \frac{|x+3|-1}{|x|-2} \geq 0\right\} and T={x∈Z:x2−7∣x∣+9≤0}T=\left\{x \in \mathbb{Z}: x^2-7|x|+9 \leq 0\right\}. Then the number of elements in S∩TS \cap T is
View answer and explanation
Correct option: D
3
Option D is correct because by solving the inequalities for S and T, we find that the intersection S ∩ T contains 3 elements.
259 Medium
259 of 273
Analyzing +4 | -1
Let ZZ denote the set of all integers and A={(a,b):a2+3b2=28,    a,  b∈Z}A = \left\{ {\left( {a,b} \right):{a^2} + 3{b^2} = 28,\;\;a,\;b \in Z} \right\} and B={(a,  b):a>b,  a,  b∈Z}B = \{ \left( {a,\;b} \right):a > b,\;a,\;b \in Z\}. Then, the number of elements in A∩BA \cap B is
View answer and explanation
Correct option: D
6
Option D (6) is correct because by finding all possible integer pairs (a, b) satisfying the equation and then filtering those where a > b, we arrive at a total of 6 elements in the intersection.
260 Medium
260 of 273
Application +4 | -1
In a town of 10,000 families it was found that 40%40 \% family buy newspaper A, 20%20 \% buy newspaper B\mathrm{B} and 10%10 \% families buy newspaper C, 5%5 \% families buy A and B, 3%3 \% buy B\mathrm{B} and C\mathrm{C} and 4%4 \% buy A\mathrm{A} and C\mathrm{C}. If 2%2 \% families buy all the three newspapers, then number of families which buy A only is
View answer and explanation
Correct option: B
3300
Option B (3300) is correct because it represents the number of families that buy newspaper A only, calculated using the principle of inclusion-exclusion.
261 Easy
261 of 273
Understanding +4 | -1
If Na={an:n∈N}N_a=\{a n: n \in N\}, then N5∩N7=N_5 \cap N_7=
View answer and explanation
Correct option: C
N35N_{35}
Option C (N35N_{35}) is correct because the intersection of multiples of 5 and multiples of 7 are the multiples of their least common multiple, which is 35.
262 Easy
262 of 273
Application +4 | -1
If A1,A2,…,A100{A_1},{A_2}, \ldots ,{A_{100}} are sets such that n(Ai)=i+2,A1⊂A2⊂A3…⊂A100n\left( {{A_i}} \right) = i + 2,{A_1} \subset {A_2} \subset {A_3} \ldots \subset {A_{100}} and ∩i=3100Ai=A,\cap _{i = 3}^{100}{A_i} = A, then n(A)=n\left( A \right) =
View answer and explanation
Correct option: C
5
Option C (5) is correct because the intersection of nested sets from A3 to A100 is A3, and n(A3) = 3 + 2 = 5.
263 Easy
263 of 273
Application +4 | -1
If A={x∈C:x2=1}A=\left\{x \in \mathbb{C}: x^2=1\right\} and B={x∈C:x4=1}B=\left\{x \in \mathbb{C}: x^4=1\right\}, then AΔBA \Delta B is equal to
View answer and explanation
Correct option: C
{−i,i}\{-i, i\}
Option C ({−i,i}\left\{-i, i\right\}) is correct because it represents the symmetric difference between sets A and B, which includes elements in B but not in A.
264 Easy
264 of 273
Understanding +4 | -1
If A⊆BA \subseteq B, then B∪AB \cup A is equal to
View answer and explanation
Correct option: C
BB
Option C (BB) is correct because if A is a subset of B, then the union of B and A is equal to B.
265 Medium
265 of 273
Understanding +4 | -1
Which of the following is a singleton set?
View answer and explanation
Correct option: A
{x:∣x∣=5,x∈N}\{x:|x|=5, x \in N\}
Option A (x:∣x∣=5,x∈N\\{x:|x|=5, x \in N\\}) is correct because it results in a set with only one element, x = 5, satisfying the condition.
266 Easy
266 of 273
Understanding +4 | -1
If the sets AA and BB are defined as:
A={(x,y):y=ex,x∈R}B={(x,y):y=x,x∈R}, then \begin{aligned} & A=\left\{(x, y): y=e^x, x \in R\right\} \\ & B=\{(x, y): y=x, x \in R\}, \text { then } \end{aligned}
View answer and explanation
Correct option: C
A∩B=ϕA \cap B=\phi
Option C (A∩B=ϕA \cap B = \phi) is correct because the graphs of y=exy = e^x and y=xy = x do not intersect, meaning there are no common points.
267 Medium
267 of 273
Application +4 | -1
In a school, there are 20 teachers who teach Mathematics or Physics of these, 12 teach Mathematics and 4 teach both Maths and Physics. Then the number of teachers teaching only Physics are
View answer and explanation
Correct option: B
8
Option B (8) is correct because it represents the number of teachers teaching only Physics, calculated by subtracting the number of teachers teaching both subjects from the total number of Physics or Mathematics teachers.
268 Easy
268 of 273
Application +4 | -1
In a town of 10,000 families it was found that 40% families buy newspaper A,20% families buy newspaper B and 10% families buy newspaper C,5% families buy A and B, 3% buy B and C and 4% buy A and C. If 2% families buy all the three newspapers, then the number of families which buy A only is
View answer and explanation
Correct option: B
3300
Option B (3300) is correct because it is found by using the principle of inclusion-exclusion to find the number of families that buy newspaper A only.
269 Easy
269 of 273
Understanding +4 | -1
Let A={2,3,4}{A}=\{2,3,4\} and X={0,1,2,3,4}{X}=\{0,1,2,3,4\}, then which of the following statements is correct
View answer and explanation
Correct option: C
{0}⊂A′\{0\} \subset {A}^{\prime} w.r.t X{X}
Option C (\{0\} ⊂ {A}^{′}w.r.tw.r.t{X}$) is correct because the set containing 0 is a subset of the complement of A with respect to X.
270 Medium
270 of 273
Application +4 | -1
If U={1,2,3,4,5,6,7,8,9},A={2,4,6,8}U=\{1,2,3,4,5,6,7,8,9\}, A=\{2,4,6,8\} and B={2,3,5,7B=\left\{2,3,5,7\right., then (A∪B)′,(A′∩B′)(AΔB)(A \cup B)^{\prime},\left(A^{\prime} \cap B^{\prime}\right)(A \Delta B) is equal to
View answer and explanation
Correct option: B
{1,9},{1,9},{3,4,5,6,7,8}\{1,9\},\{1,9\},\{3,4,5,6,7,8\}
Option B ({1,9},{1,9},{3,4,5,6,7,8}) is correct because it accurately calculates the complement of the union of A and B, the intersection of the complements of A and B, and the symmetric difference of A and B.
Revision notes and key takeaways

Review SET THEORY in your textbook or class notes, then use this set to check your understanding.

Showing 241-270 of 273 questions

Your practice

0 / 273 answered · 273 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.