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JEE • MATHEMATICS • PROPERTIES OF TRIANGLES

Properties of triangles practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 391-420 of 434 questions

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391 Easy
391 of 434
Application +4 | -1
In △ABC,1−tan⁡B2⋅tan⁡C2\triangle A B C, 1-\tan \frac{B}{2} \cdot \tan \frac{C}{2} is equal to
View answer and explanation
Correct option: A
2aa+b+c\frac{2 a}{a+b+c}
Option A (2aa+b+c\frac{2 a}{a+b+c}) is correct because it is the simplified form of the given expression using trigonometric identities and triangle properties.
392 Easy
392 of 434
Application +4 | -1
If r1=2r2=3r3r_1=2 r_2=3 r_3 then a+b+ca+b+c is equal to
View answer and explanation
Correct option: A
3b3 b
Option B (3b) is correct because given the relationship between the ex-radii, we can express a, b, and c in terms of each other and find that a+b+c=3ba+b+c = 3b.
393 Easy
393 of 434
Application +4 | -1
If in a △ABC,acos⁡2(C2)+ccos⁡2(A2)=3b2\triangle A B C, a \cos ^2\left(\frac{C}{2}\right)+c \cos ^2\left(\frac{A}{2}\right)=\frac{3 b}{2}, then the sides a,ba, b and cc
View answer and explanation
Correct option: A
are in AP
Option A (are in AP) is correct because by substituting the half-angle formula into the given equation and simplifying, we can show that 2b=a+c2b = a+c, which means a,b,ca, b, c are in arithmetic progression.
394 Medium
394 of 434
Application +4 | -1
In a△ABC,a=1a \triangle A B C, a=1 and the perimeter is six times the AMA M of the sines of the angles. The measure of ∠A\angle A is
View answer and explanation
Correct option: C
π6\frac{\pi}{6}
Option C (π6\frac{\pi}{6}) is correct because the given condition leads to sin⁡A=12\sin A = \frac{1}{2}, which implies A=π6A = \frac{\pi}{6}.
395 Easy
395 of 434
Analyzing +4 | -1
A quadrilateral ABCDABCD in which AB=a,  BC=b,  CD=cAB = a,\;BC = b,\;CD = c and DA=dDA = d is such that one circle can be inscribed in it and another circle can be circumscribed about it, then cos⁡A\cos A is equal to
View answer and explanation
Correct option: B
ad−bcad+bc\frac{{ad - bc}}{{ad + bc}}
Option B (ad−bcad+bc\frac{{ad - bc}}{{ad + bc}}) is correct because it is the expression derived from the given conditions of a cyclic quadrilateral with an inscribed circle.
396 Easy
396 of 434
Application +4 | -1
In a △ABC\triangle A B C, if A=60∘A=60^{\circ}, then bc+a+ca+b\frac{b}{c+a}+\frac{c}{a+b} is equal to
View answer and explanation
Correct option: A
1
Option A (1) is correct because by using the Law of Cosines and simplifying, we can show that bc+a+ca+b=1\frac{b}{c+a} + \frac{c}{a+b} = 1.
397 Medium
397 of 434
Application +4 | -1
If the area of a triangle ABCA B C is given by Δ=a2−(b−c)2\Delta=a^2-(b-c)^2, then tan⁡(A2)\tan \left(\frac{A}{2}\right) is equal to
View answer and explanation
Correct option: C
14\frac{1}{4}
Option C (14\frac{1}{4}) is correct because by using the given area formula and Heron's formula, we can derive the value of tan⁡(A2)\tan(\frac{A}{2}).
398 Easy
398 of 434
Application +4 | -1
In a Δ  ABC,  a,  c  ,  A\Delta \;ABC,\;a,\;c\;,\;A are given and b1,b2{b_1},{b_2} are two values of third side bb such that b=2b1b = 2{b_1}. Then, sin⁡A\sin A is equal to
View answer and explanation
Correct option: B
9a2−c28c2\sqrt {\frac{{9{a^2} - {c^2}}}{{8{c^2}}}}
Option B (9a2−c28c2\sqrt {\frac{{9{a^2} - {c^2}}}{{8{c^2}}}}) is correct because it is derived from the quadratic equation formed using the Law of Cosines and the given relationship between the two possible values of the third side.
399 Easy
399 of 434
Application +4 | -1
In a Δ ABC\Delta \,ABC,

a(b2+c2)  cos⁡  A+b(c2+a2)  cos⁡  B+c(a2+b2)cos⁡  Ca\left( {{b^2} + {c^2}} \right)\,\,\cos \,\,A + b\left( {{c^2} + {a^2}} \right)\,\,\cos \,\,B + c\left( {{a^2} + {b^2}} \right)\cos \,\,C is equal to
View answer and explanation
Correct option: C
3 abc3\,abc
The correct answer is C (3abc3abc) because by using the projection rule, the given expression simplifies to 3abc3abc.
400 Medium
400 of 434
Application +4 | -1
If the area of △ABC\triangle A B C is a2−(b−c)2a^2-(b-c)^2, then find the value of tan⁡A\tan A.
View answer and explanation
Correct option: A
815\frac{8}{15}
Option A (815\frac{8}{15}) is correct because it is the value of tan⁡A\tan A calculated using the given area of the triangle and trigonometric identities.
401 Easy
401 of 434
Analyzing +4 | -1
In a Δ ABC\Delta \,ABC if c=(a+b)sin⁡  θc = \left( {a + b} \right)\sin \,\,\theta and cos⁡  θ=k aba+b\cos \,\,\theta = \frac{{k\,\sqrt {ab} }}{{a + b}}, then k=k =
View answer and explanation
Correct option: A
2  cos⁡  C22\,\,\cos \,\,\frac{C}{2}
Option A (2cos⁡C22 \cos \frac{C}{2}) is correct because using sine rule and half angle formula, we can derive that k=2cos⁡C2k = 2 \cos \frac{C}{2}.
402 Medium
402 of 434
Analyzing +4 | -1
For a triangle ABCA B C, the value of cos⁡2A+cos⁡2B+\cos 2 A+\cos 2 B+ cos⁡2C\cos 2 C is least. If its inradius is 3 and incentre is MM, then which of the following is NOT correct?
View answer and explanation
Correct option: C
Area of ΔABC\Delta A B C is 2732\frac{27 \sqrt{3}}{2}
Option C (Area of ΔABC\Delta A B C is 2732\frac{{27 \sqrt{{3}}}}{{2}}) is correct because the area of an equilateral triangle with inradius 3 is 27327\sqrt{3}, not 2732\frac{{27 \sqrt{{3}}}}{{2}}.
403 Easy
403 of 434
Application +4 | -1
If A=30∘,  a=7,  b=8A = 30^\circ ,\,\,a = 7,\,\,b = 8 in Δ ABC\Delta \,ABC, then BB has
View answer and explanation
Correct option: B
Two solutions
Option B (Two solutions) is correct because the condition b>a>bsin⁡Ab > a > b \sin A is satisfied, indicating two possible triangles.
404 Easy
404 of 434
Analyzing +4 | -1
If a Δ  ABC,if  a4+b4+c4=2c2(a2+b2)\Delta \;ABC,\mathrm{if}\;{a^4} + {b^4} + {c^4} = 2{c^2}\left( {{a^2} + {b^2}} \right), then ∠C\angle C is equal to
View answer and explanation
Correct option: B
135∘135^\circ
Option B (135∘135^\circ) is correct because it satisfies the given equation when substituting into the cosine rule.
405 Easy
405 of 434
Application +4 | -1
The horizontal distance between two tower is 60 m60 \mathrm{~m}. The angular elevation of the top of the taller tower as seen from the top of the shorter one is 30∘30^{\circ}. If the height of the taller tower is 150 m150 \mathrm{~m}, the height of the shorter one is
View answer and explanation
Correct option: A
(150−203)m(150-20 \sqrt{3}) \mathrm{m}
Option A ((150−203)m(150-20 \sqrt{3}) \mathrm{m}) is correct because it is derived using trigonometry and the given heights and distance.
406 Easy
406 of 434
Application +4 | -1
If p1,  p2,  p3{p_1},\,\,{p_2},\,\,{p_3} are altitudes of a triangle ABCABC from the vertices A,  B,  CA,\,\,B,\,\,C and Δ\Delta, the area of the triangle, then p1−1+p2−1−p3−1p_1^{ - 1} + p_2^{ - 1} - p_3^{ - 1} is equal to
View answer and explanation
Correct option: C
s−cΔ\frac{{s - c}}{\Delta }
Option C (s−cΔ\frac{{s - c}}{\Delta }) is correct because by using the area formula and substituting, the expression simplifies to s−cΔ\frac{{s - c}}{\Delta }.
407 Easy
407 of 434
Analyzing +4 | -1
In a ΔABC\Delta ABC, if (3−1)a=2b,  A=3B\left( {\sqrt 3 - 1} \right)a = 2b,\;A = 3B, then ∠C\angle C is
View answer and explanation
Correct option: B
120∘120^\circ
Option B (120∘120^\circ) is correct because by using the sine rule and the given relationship between the sides and angles, we can find the angles of the triangle and determine that angle C is 120 degrees.
408 Medium
408 of 434
Application +4 | -1
In a triangle ABC,2a2+4b2+c2=4ab+2acA B C, 2 a^2+4 b^2+c^2=4 a b+2 a c, then the numerical value of cos⁡B\cos B is equal to
View answer and explanation
Correct option: D
78\frac{7}{8}
Option D (7/8) is correct because it is the result of using the cosine rule and the given equation to find the value of cos B.
409 Easy
409 of 434
Application +4 | -1
In Δ  ABC,  2R2sin⁡Asin⁡Bsin⁡C\Delta \;ABC,\;2{R^2}\sin A\sin B\sin C is equal to
View answer and explanation
Correct option: C
Δ\Delta
Option C (Δ\Delta) is correct because using the sine rule, the expression simplifies to the area of the triangle.
410 Easy
410 of 434
Analyzing +4 | -1
In a △PQR\triangle P Q R, If 3sin⁡P+4cos⁡Q=63 \sin P+4 \cos Q=6 and 4sin⁡Q+3cos⁡4 \sin Q+3 \cos P=1P=1, then the angle RR is equal to:
View answer and explanation
Correct option: B
π6\frac{\pi}{6}
Option B (π6\frac{{\pi}}{{6}}) is correct because it is the only value of angle R that satisfies the given trigonometric equations and the triangle property.
411 Easy
411 of 434
Application +4 | -1
If in a ΔABC,(s−a)(s−b)=s(s−c)\Delta ABC,\left( {s - a} \right)\left( {s - b} \right) = s\left( {s - c} \right), then angle CC is equal to
View answer and explanation
Correct option: A
90∘90^\circ
Option A (90∘90^\circ) is correct because it satisfies the given condition when using the tangent half-angle formula.
412 Medium
412 of 434
Application +4 | -1
In a Δ  ABC\Delta \;ABC, if a=2x,  b=2ya = 2x,\;b = 2y and ∠C=120∘\angle C = 120^\circ, then the area of the triangle is
View answer and explanation
Correct option: B
xy  3xy\;\sqrt 3 sq unit
Option B (xy  3xy\;\sqrt 3 sq unit) is correct because the area of the triangle is calculated using the formula 12absin⁡C\frac{1}{2}ab\sin C with the given values.
413 Easy
413 of 434
Application +4 | -1
In a Δ  ABC\Delta \;ABC, if sin⁡A+sin⁡B+sin⁡C)(sin⁡A+sin⁡B−sin⁡C)=3sin⁡Asin⁡B\sin A + \sin B + \sin C)\left( {\sin A + \sin B - \sin C} \right) = 3\sin A\sin B, then the angle CC is equal to
View answer and explanation
Correct option: B
π3\frac{\pi }{3}
Option B (π3\frac{\pi }{3}) is correct because using sine rule and cosine rule, the given equation simplifies to cos⁡C=12\cos C = \frac{1}{2}, which implies C=π3C = \frac{\pi }{3}.
414 Medium
414 of 434
Application +4 | -1
If a2+b2+c2=1a^2+b^2+c^2=1, then ab+bc+caa b+b c+c a lies in the interval :
View answer and explanation
Correct option: A
[−12,1]\left[-\frac{1}{2}, 1\right]
Option A ([−12,1]\left[-\frac{1}{2}, 1\right]) is correct because it defines the interval in which the expression ab+bc+caa b+b c+c a lies, given the constraint a2+b2+c2=1a^2+b^2+c^2=1.
415 Medium
415 of 434
Application +4 | -1
The sides of two angles of a triangle are equal to 513\frac{5}{13} and 99101\frac{99}{101}. The cosine of the third angle is
View answer and explanation
Correct option: C
2551313\frac{255}{1313}
Option C (2551313\frac{255}{1313}) is correct because it is the result of applying the cosine subtraction formula after finding the sines and cosines of the given angles.
416 Easy
416 of 434
Application +4 | -1
In a ΔABC,a,c,A\Delta ABC,a,c,A are given and b1,b2{b_1},{b_2} are two values, if the third side bb such that b2=2b1{b_2} = 2{b_1}, then sin⁡A\sin A is equal to
View answer and explanation
Correct option: B
9a2−c28c2\sqrt {\frac{{9{a^2} - {c^2}}}{{8{c^2}}}}
Option B 9a2−c28c2\sqrt {\frac{{9{a^2} - {c^2}}}{{8{c^2}}}} is correct because it is derived by using the cosine rule and the given condition b2=2b1{b_2} = 2{b_1}.
417 Easy
417 of 434
Application +4 | -1
If in a triangle ABC,  b+c11=c+a12=a+b13ABC,\,\,\frac{{b + c}}{{11}} = \frac{{c + a}}{{12}} = \frac{{a + b}}{{13}} then cos⁡  A\cos \,\,A is equal to
View answer and explanation
Correct option: A
1/51/5
Option A (1/5) is correct because by setting up ratios and solving for the sides of the triangle, we can use the cosine rule to find cos A.
418 Medium
418 of 434
Application +4 | -1
If the angles of a triangle be in the ratio 1:2:7, then the ratio of its greatest side to the least side is
View answer and explanation
Correct option: C
(5+1):(5−1)\left( {\sqrt 5 + 1} \right):\left( {\sqrt 5 - 1} \right)
Option C ((5+1):(5−1)\left( {\sqrt 5 + 1} \right):\left( {\sqrt 5 - 1} \right)) is correct because it represents the ratio of the sines of the greatest and least angles, which corresponds to the ratio of the greatest and least sides.
419 Medium
419 of 434
Application +4 | -1
If in a △ABC,CD\triangle A B C, C D is the angle bisector of the ∠ABC\angle A B C, then CDC D is equal to
View answer and explanation
Correct option: C
2aba+bcos⁡C2\frac{2 a b}{a+b} \cos \frac{C}{2}
Option C (2aba+bcos⁡C2\frac{2ab}{a+b} \cos \frac{C}{2}) is correct because the length of the angle bisector can be expressed in terms of the sides and the angle.
420 Easy
420 of 434
Application +4 | -1
The angles A,BA,B and CC of a Δ  ABC\Delta \;ABC are in A.P. If AB=6,BC=7,AB = 6,BC = 7, then AC=AC =
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the calculated value of AC is 43\sqrt{43}, which is not among the given options.
Revision notes and key takeaways

Review PROPERTIES OF TRIANGLES in your textbook or class notes, then use this set to check your understanding.

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