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JEE • MATHEMATICS • PROPERTIES OF TRIANGLES

Properties of triangles practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 361-390 of 434 questions

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361 Medium
361 of 434
Application +4 | -1
If A1 A2 A3 A4 A5{A_1}\,{A_2}\,{A_3}\,{A_4}\,{A_5} be a regular pentagon inscribed in a unit circle. Then (A1A2)  (A1A3)\left( {{A_1}{A_2}} \right)\,\,\left( {{A_1}{A_3}} \right) is equal to
View answer and explanation
Correct option: D
5\sqrt 5
Option D (5\sqrt 5) is correct because the product of the lengths A1A2{A_1}{A_2} and A1A3{A_1}{A_3} in a regular pentagon inscribed in a unit circle equals 5\sqrt 5.
362 Easy
362 of 434
Analyzing +4 | -1
In the ambiguous case, given a,  ba,\,\,b and AA. The difference between the two values of CC is
View answer and explanation
Correct option: C
2 a2−b2  sin⁡2  A2\,\sqrt {{a^2} - {b^2}\,\,{{\sin }^2}\,\,A}
Option C (2,a2−b2 sin⁡2 A2\\,\sqrt {{{{a^2} - {b^2}\,{{\sin }^2}\,A}}}) is correct because it represents the difference between the two possible values of side c in the ambiguous case of triangle solving, derived using the cosine rule and properties of quadratic equations.
363 Easy
363 of 434
Application +4 | -1
In a △ABC,a=2b\triangle A B C, a=2 b and ∣A−B∣=π3|A-B|=\frac{\pi}{3}. The measure of ∠C\angle C is
View answer and explanation
Correct option: B
π3\frac{\pi}{3}
Option B (π3\frac{\pi}{3}) is correct because using the tangent half-angle formula and the given conditions, the angle C is found to be π3\frac{\pi}{3}.
364 Medium
364 of 434
Application +4 | -1
If a,ba, b and AA are given in aa triangle and c1,c2c_1, c_2 are the possible values of the third side, then c12+c22−2c1c2cos⁡2Ac_1^2+c_2^2-2 c_1 c_2 \cos 2 A is equal to
View answer and explanation
Correct option: C
4a2cos⁡2A4 a^2 \cos ^2 A
Option C (4a2cos⁡2A4 a^2 \cos ^2 A) is correct because by using the cosine rule and Vieta's formulas, the expression simplifies to 4a2cos⁡2A4 a^2 \cos ^2 A.
365 Easy
365 of 434
Application +4 | -1
The angles A,  BA,\;B and CC of a Δ  ABC\Delta \;ABC are in AP. if b:c=3:2b:c = \sqrt 3 :\sqrt 2, then the angle AA is
View answer and explanation
Correct option: C
75∘75^\circ
Option C (75°) is correct because, with angles in AP and b:c = √3:√2, solving for the angles gives A = 75°.
366 Easy
366 of 434
Understanding +4 | -1
In an equilateral triangle, the ratio of the inradius, circumradius and exradius are
View answer and explanation
Correct option: D
1:2:31: 2: 3
This question is incomplete and contains errors. The explanation provided is not relevant to the question. The correct answer should relate to the ratio of inradius, circumradius, and exradius in an equilateral triangle.
367 Easy
367 of 434
Application +4 | -1
In a triangle ABCA B C, let ∠C=π2\angle C=\frac{\pi}{2}. If rr is the inradius and RR is the circumradius of the triangle ABCA B C, then 2(r+R)2(r+R) equals
View answer and explanation
Correct option: B
a+ba+b
Option B (a+b) is correct because in a right-angled triangle, 2(r+R) simplifies to a+b.
368 Hard
368 of 434
Analyzing +4 | -1
If in a triangle ABC,  cos⁡A  cos⁡B+sin⁡A  sin⁡ B  sin⁡C=1ABC,\,\,\cos A\,\,\cos B + \sin A\,\,\sin \,B\,\,\sin C = 1, then the triangle is
View answer and explanation
Correct option: C
Isosceles right angled
Option C (Isosceles right angled) is correct because by simplifying the given equation, we find that A = B and C = 90°, which means the triangle is isosceles and right-angled.
369 Easy
369 of 434
Application +4 | -1
If α,β\alpha, \beta and γ\gamma are the altitudes of a △ABC\triangle A B C and 2s2 s denotes its perimeter, then α−1+β−1+γ−1\alpha^{-1}+\beta^{-1}+\gamma^{-1} is equal to
View answer and explanation
Correct option: B
sΔ\frac{s}{\Delta}
Option B (sΔ\frac{s}{\Delta}) is correct because it is derived by expressing the reciprocals of altitudes in terms of sides and area of the triangle.
370 Easy
370 of 434
Application +4 | -1
In the angles A,BA,B and CC of a triangular are in the arithmetic progression and if a,ba,b and cc denotes the lengths of the sides opposite to A,BA,B and CC respectively, then the value of the expression acsin⁡  2C+casin⁡  2A\frac{a}{c}\sin \;2C + \frac{c}{a}\sin \;2A is
View answer and explanation
Correct option: D
3\sqrt 3
Option D (3\sqrt{3}) is correct because the expression simplifies to 2sinB, and since B = 60 degrees, the value is 3\sqrt{3}.
371 Medium
371 of 434
Application +4 | -1
If in a △ABC,a2+b2+c2=8R2\triangle A B C, a^2+b^2+c^2=8 R^2, where R=R= circumradius, the the triangle is
View answer and explanation
Correct option: C
right angled
Option C (right angled) is correct because the given condition a2+b2+c2=8R2a^2 + b^2 + c^2 = 8R^2 implies that sin⁡2A+sin⁡2B+sin⁡2C=2\sin^2 A + \sin^2 B + \sin^2 C = 2, which leads to one of the angles being π2\frac{{\pi}}{{2}}.
372 Easy
372 of 434
Application +4 | -1
If in a triangle ABC,  b+c=3aABC,\,\,b + c = 3a, then tan⁡ (B2)tan⁡(C2)\tan \,\left( {\frac{B}{2}} \right)\tan \left( {\frac{C}{2}} \right) is equal to
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the correct value of tan⁡(B2)tan⁡(C2)\tan \left( {\frac{B}{2}} \right)\tan \left( {\frac{C}{2}} \right) is 12\frac{1}{2}, which is not among the given options.
373 Easy
373 of 434
Application +4 | -1
Angles A,BA,B and CC of a Δ  ABC\Delta \;ABC are in AP. If bc=32\frac{b}{c} = \frac{{\sqrt 3 }}{{\sqrt 2 }}, then angle AA is equal to
View answer and explanation
Correct option: C
5π12\frac{{5\pi }}{{12}}
Option C (5π12\frac{{5\pi }}{{12}}) is correct because by using the sine rule and the given ratio of sides, we can find angle A to be 75 degrees, which is 5π12\frac{{5\pi }}{{12}} radians.
374 Easy
374 of 434
Analyzing +4 | -1
If in a ΔABC,  r1<r2<r3\Delta ABC,\;{r_1} < {r_2} < {r_3}, then
View answer and explanation
Correct option: A
a<b<ca < b < c
Option A (a < b < c) is correct because the given inequality r1<r2<r3{r_1} < {r_2} < {r_3} implies that (s−a)>(s−b)>(s−c)\left( {s - a} \right) > \left( {s - b} \right) > \left( {s - c} \right), which leads to a<b<ca < b < c.
375 Medium
375 of 434
Analyzing +4 | -1
sin⁡A:sin⁡C=sin⁡(A−B):sin⁡(B−C)\sin A:\sin C = \sin \left( {A - B} \right):\sin \left( {B - C} \right), then a2,  b2,  c2{a^2},\;{b^2},\;{c^2} are in
View answer and explanation
Correct option: A
AP
Option A (AP) is correct because the given condition leads to the relationship a2+c2=2b2{a^2} + {c^2} = 2{b^2}, which is the condition for a2,b2,c2{a^2}, {b^2}, {c^2} to be in arithmetic progression.
376 Medium
376 of 434
Application +4 | -1
In a Δ ABC\Delta \,ABC, if c=2,  A=120∘,  a=6c = 2,\,\,A = 120^\circ ,\,\,a = \sqrt 6, then C=C =
View answer and explanation
Correct option: C
45∘45^\circ
Option C is correct because using the sine rule, we can find the angle C to be 45 degrees.
377 Medium
377 of 434
Analyzing +4 | -1
If PP is a point on the altitude ADA D of the △ABC\triangle A B C such that ∠CDP=B3\angle C D P=\frac{B}{3}, then APA P is equal to
View answer and explanation
Correct option: C
2csin⁡B32 c \sin \frac{B}{3}
Option C (2csin⁡B32 c \sin \frac{B}{3}) is correct because by applying the sine rule in triangle ABP, AP can be expressed as 2csin⁡B32 c \sin \frac{B}{3}.
378 Hard
378 of 434
Application +4 | -1
If the angles A,BA, B and CC of triangle ABCA B C are in arithmetic progression and a,b,ca, b, c represents length of sides opposite to angles A,BA, B and CC respectively, then the value of a+c(a2−ac+c2)\frac{a+c}{\sqrt{\left(a^2-a c+c^2\right)}} is:
View answer and explanation
Correct option: D
2cos⁡A−C22 \cos \frac{A-C}{2}
Option D is correct because using the given conditions and trigonometric identities, the expression simplifies to 2cos⁡A−C22 \cos \frac{{A-C}}{{2}}.
379 Easy
379 of 434
Analyzing +4 | -1
In Δ  ABC\Delta\; ABC, if sin⁡2A2,sin⁡2B2,sin⁡2C2{\sin ^2}\frac{A}{2},{\sin ^2}\frac{B}{2},{\sin ^2}\frac{C}{2} be in HP, then a,  b,  ca,\;b,\;c will be in
View answer and explanation
Correct option: C
HP
Option C (HP) is correct because if the sines squared are in HP, then the sides a, b, c are also in HP.
380 Easy
380 of 434
Analyzing +4 | -1
If a,ba, b and cc are the sides of a triangle such that b⋅c=λ2b \cdot c=\lambda^2, for some positive λ\lambda, then
View answer and explanation
Correct option: C
a≥2λsin⁡A2a \geq 2 \lambda \sin \frac{A}{2}
Option C (a≥2λsin⁡A2a \geq 2 \lambda \sin \frac{A}{2}) is correct because it is derived from the AM-GM inequality and the sine rule applied to the triangle.
381 Medium
381 of 434
Application +4 | -1
The area of the segment of a circle of radius aa subtending an angle of 2α2\alpha at the centre is
View answer and explanation
Correct option: D
a2α{a^2}\mathrm{\alpha }
The correct answer is a2α{a^2}\mathrm{\alpha } because the area of the segment is calculated as the area of the sector minus the area of the triangle, which simplifies to a2α{a^2}\mathrm{\alpha }.
382 Easy
382 of 434
Application +4 | -1
If in a ΔABC,  4sin⁡A=4sin⁡B=3sin⁡C\Delta ABC,\;4\sin A = 4\sin B = 3\sin C, then cos⁡C\cos C is equal to
View answer and explanation
Correct option: B
1/91/9
Option B (19\frac{1}{9}) is correct because it is the value of cos⁡C\cos C calculated using the given ratios of sines and the cosine rule.
383 Easy
383 of 434
Application +4 | -1
In a Δ ABC,  A=2  π3,  b−c=3 3  cm\Delta \,ABC,\,\,A = \frac{{2\;\pi }}{3},\,\,b - c = 3\,\sqrt 3 \;\mathrm{cm} and Δ=9 32  cm2\Delta = \frac{{9\,\sqrt 3 }}{2}\,\,\mathrm{c}{\mathrm{m}^2}. Then, a=a =
View answer and explanation
Correct option: B
9   cm9\;\,\mathrm{cm}
Option B, 9   cm9\;\,\mathrm{cm}, is correct because it is the length of side 'a' calculated using the cosine rule and the given area and angle.
384 Easy
384 of 434
Application +4 | -1
In a △ABC,tan⁡A2=56,tan⁡C2=25\triangle A B C, \tan \frac{A}{2}=\frac{5}{6}, \tan \frac{C}{2}=\frac{2}{5}, then
View answer and explanation
Correct option: B
a,b,ca, b, c are in AP
Option B (a,b,ca, b, c are in AP) is correct because the given trigonometric ratios lead to the condition a+c=2ba + c = 2b, which defines an arithmetic progression.
385 Easy
385 of 434
Understanding +4 | -1
In a triangle r1>r2>r3{r_1} > {r_2} > {r_3}, then
View answer and explanation
Correct option: A
a>b>ca > b > c
Option A (a>b>ca > b > c) is correct because the inradii r1,r2,r3r_1, r_2, r_3 are inversely proportional to s−a,s−b,s−cs-a, s-b, s-c respectively.
386 Medium
386 of 434
Application +4 | -1
In any triangle ABC\mathrm{ABC}, acot⁡A+bcot⁡B+ccot⁡C=\mathrm{a} \cot \mathrm{A}+\mathrm{b} \cot \mathrm{B}+\mathrm{c} \cot \mathrm{C}=
View answer and explanation
Correct option: C
2(r+R)2(\mathrm{r}+\mathrm{R})
Option C (2(r+R)2(r+R)) is correct because, for an equilateral triangle, the expression simplifies to a value that matches the given relationship between inradius and circumradius.
387 Easy
387 of 434
Analyzing +4 | -1
If the data given to construct a triangle ABCABC are a=5,  b=7,  sin⁡A=3/4a = 5,\,\,b = 7,\,\,\sin A = 3/4, then it is possible to construct
View answer and explanation
Correct option: D
No triangles
Option D (No triangles) is correct because the value of sin B is greater than 1, which is impossible for any angle in a triangle.
388 Easy
388 of 434
Application +4 | -1
The longest side of a triangle is 3 times the shortest side and the third side is 2 cm2 \mathrm{~cm} shorter than the longest side. If the perimeter of the triangle is at least 61 cm61 \mathrm{~cm}, find the minimum length of the shortest side.
View answer and explanation
Correct option: A
9
Option A (9) is correct because setting up the inequality based on the problem statement and solving for the shortest side (x) results in x≥9x \geq 9.
389 Easy
389 of 434
Application +4 | -1
In ΔABC,2(a  sin⁡2C2+c  sin⁡2A2)\Delta ABC,2\left( {a\;{{\sin }^2}\frac{C}{2} + c\;{{\sin }^2}\frac{A}{2}} \right) is equal to
View answer and explanation
Correct option: B
c+a−bc + a - b
Option B (c+a−bc + a - b) is correct because the expression simplifies to this using trigonometric identities and the semi-perimeter formula.
390 Easy
390 of 434
Application +4 | -1
If c2=a2+b2,  2  s=a+b+c{c^2} = {a^2} + {b^2},\,\,2\;s = a + b + c, then 4s  (s−a)  (s−b)  (s−c)=4s\,\,\left( {s - a} \right)\,\,\left( {s - b} \right)\,\,\left( {s - c} \right) =
View answer and explanation
Correct option: C
c2 a2{c^2}\,{a^2}
Option D (a2 b2{a^2}\,{b^2}) is correct because using the given condition c2=a2+b2{c^2} = {a^2} + {b^2} and the area of the triangle, we can deduce that 4s(s−a)(s−b)(s−c)=a2b24s(s-a)(s-b)(s-c) = a^2b^2.
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