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JEE • MATHEMATICS • PROBABILITY

Probability practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 781-810 of 822 questions
781 Easy
781 of 822
Application +4 | -1
Four tickets are marked 00,01, 10 and 11 respectively, are placed in a bag. A ticket is drawn at random five times, being replaced each time. The probability that the sum of the numbers on the five tickets drawn is 24, is
View answer and explanation
Correct option: B
25512\frac{25}{512}
Option B (25512\frac{25}{512}) is correct because it is the probability calculated by dividing the number of favorable outcomes (sum of 24) by the total possible outcomes when drawing the tickets.
782 Easy
782 of 822
Application +4 | -1
There are 12 white and 12 red balls in a bag. Balls are drawn one by one with replacement from the bag. The probability that 7 th drawn ball is 4 th white, is
View answer and explanation
Correct option: B
5/325 / 32
The correct answer is 5/325 / 32 because it calculates the probability that the 7th drawn ball is the 4th white ball.
783 Easy
783 of 822
Analyzing +4 | -1
If P(B)=35,P(A/B)=12P(B)=\frac{3}{5}, P(A / B)=\frac{1}{2} and P(A∪B)=45P(A \cup B)=\frac{4}{5}, then P(A∪B)′+P(A′∪B)P(A \cup B)^{\prime}+P\left(A^{\prime} \cup B\right) is equal to
View answer and explanation
Correct option: D
1
Option D (1) is correct because the expression simplifies to 1 using the given probabilities and conditional probability formula.
784 Easy
784 of 822
Analyzing +4 | -1
Two numbers aa and bb are chosen at random from the set {1,2,3,…,5n}\{1,2,3, \ldots, 5 n\}. The probability that a4−b4a^4-b^4 is divisible by 5, is
View answer and explanation
Correct option: C
17n−55(5n−1)\frac{17 n-5}{5(5 n-1)}
Option C (17n−55(5n−1)\frac{{17 n-5}}{{5(5 n-1)}}) is correct because it represents the probability calculated by dividing the number of ways to choose two numbers such that a4−b4a^4 - b^4 is divisible by 5 by the total number of ways to choose two numbers.
785 Easy
785 of 822
Application +4 | -1
In tossing 10 coins, the probability of getting exactly 5 heads is
View answer and explanation
Correct option: B
63256\frac{63}{256}
Option B (63256\frac{{63}}{{256}}) is correct because it is calculated using the binomial probability formula for exactly 5 heads out of 10 coin tosses.
786 Easy
786 of 822
Understanding +4 | -1
Suppose AA and BB are two events such that P(A)>0P(A)>0 and P(B)≠1P(B) \neq 1, then P(A′∣B′)P\left(A^{\prime} \mid B^{\prime}\right) equals
View answer and explanation
Correct option: A
[1−P(A∪B)]/P(B′)[1-P(A \cup B)] / P\left(B^{\prime}\right)
Option A ([1−P(A∪B)]/P(B′)[1-P(A \cup B)] / P(B')) is correct because it correctly applies the definition of conditional probability and De Morgan's law.
787 Easy
787 of 822
Application +4 | -1
Let xx be a non-zero real number. A determinant is chosen from the set of all determinants of order 2 with entries xx or −x-x only. The probability that the value of the determinant is non-zero is
View answer and explanation
Correct option: C
12\frac{1}{2}
Option C (12\frac{1}{2}) is correct because it represents the probability that the value of the determinant is non-zero, given the entries are either x or -x.
788 Easy
788 of 822
Application +4 | -1
A bag contains aa white and bb black balls. Two players AA and BB alternately draw a ball from the bag replacing the ball each time after the draw till one of them draws a white ball and wins the game. AA begins the game. If the probability of AA winning the game is three times that of BB, then the ratio a:ba:b is
View answer and explanation
Correct option: C
2:12:1
Option C (2:12:1) is correct because the probability of A winning is three times that of B, which leads to the ratio a:b = 2:1 after solving the probabilities of A and B winning.
789 Easy
789 of 822
Understanding +4 | -1
Which one is not a requirement of a binomial distribution?
View answer and explanation
Correct option: C
The outcomes must be dependent on each other
Option C (The outcomes must be dependent on each other) is correct because one of the requirements of a binomial distribution is that the outcomes of each trial must be independent.
790 Easy
790 of 822
Application +4 | -1
If P(A)=0.4P(A)=0.4, and P(A∩B)=0.15P(A \cap B)=0.15, then P(A∣A′∪B′)P\left(A \mid A^{\prime} \cup B^{\prime}\right) is equal to
View answer and explanation
Correct option: C
517\frac{5}{17}
Option C (517\frac{5}{17}) is correct because it correctly uses the conditional probability formula and De Morgan's Law.
791 Easy
791 of 822
Analyzing +4 | -1
Let E1,E2E_1, E_2 and E3E_3 be any pairwise independent events with P(E1)>0P\left(E_1\right)>0 and P(E1∩E2∩E3)=0P\left(E_1 \cap E_2 \cap E_3\right)=0, then P(Eˉ2∩Eˉ3/E1)P\left(\bar{E}_2 \cap \bar{E}_3 / E_1\right) is equal to
View answer and explanation
Correct option: A
P(Eˉ3)−P(E2)P\left(\bar{E}_3\right)-P\left(E_2\right)
Option A (P(Eˉ3)−P(E2)P(\bar{E}_3)-P(E_2)) is correct because it simplifies the conditional probability using pairwise independence and the given condition P(E1∩E2∩E3)=0P(E_1 \cap E_2 \cap E_3) = 0.
792 Easy
792 of 822
Application +4 | -1
Two cards are drawn without replacement from a well-shuffled pack. The probability that one of them is an ace of heart, is
View answer and explanation
Correct option: B
126\frac{1}{{26}}
Option B, 126\frac{1}{{26}} is correct because it considers the two possible scenarios: the ace of hearts is drawn first or second.
793 Easy
793 of 822
Application +4 | -1
The mean and variance of a binomial distribution are α\alpha and α3\frac{\alpha}{3} respectively. If P(X=1)=4243P(X=1)=\frac{4}{243}, then P(X=4P(X=4 or 5)) is equal to :
View answer and explanation
Correct option: C
1627\frac{16}{27}
Option C (1627\frac{{16}}{{27}}) is correct because after finding n=6, the probability P(X=4 or 5) is calculated correctly using the binomial distribution formula.
794 Easy
794 of 822
Analyzing +4 | -1
Four dice are thrown simultaneously and the numbers shown on these dice are recorded in 2×22 \times 2 matrices. The probability that such formed matrices have all different entries and are non-singular, is
View answer and explanation
Correct option: D
43162\frac{{43}}{{162}}
Option D (43162\frac{{43}}{{162}}) is correct because it involves calculating the total possible matrices, identifying singular matrices with distinct entries, and subtracting to find the non-singular matrices before calculating the probability.
795 Easy
795 of 822
Understanding +4 | -1
A die is thrown.

I. The probability of a prime number will appear is 12\frac{1}{2}.

II. The probability of a number more than 6 will appear is 1.1.
View answer and explanation
Correct option: A
Only I is correct
Option A (Only I is correct) is correct because the probability of a prime number appearing on a die is 1/2, while the probability of a number more than 6 is 0.
796 Easy
796 of 822
Application +4 | -1
In an experiment the success is twice that of failure. If the experiment is repeated 6 times, the probability that at least 4 times favourable is
View answer and explanation
Correct option: D
496729\frac{{496}}{{729}}
Option D (496/729) is correct because it calculates the probability of at least 4 successes in 6 trials using the binomial probability formula.
797 Easy
797 of 822
Application +4 | -1
If the probability distribution of a random variable X\mathrm{X} is as given below:
X=x:−2−10123P(X=x):110k152k310k\begin{array}{cccccccccccccccccccc} {X = x:}&{ - 2}&{ - 1}&0&1&2&3 \\ {P(X = x):}&{\frac{1}{{10}}}&k&{\frac{1}{5}}&{2k}&{\frac{3}{{10}}}&k \end{array}
Then the value of kk, is
View answer and explanation
Correct option: A
110\frac{1}{10}
Option A (110\frac{1}{10}) is correct because the sum of probabilities in a probability distribution must equal 1, allowing us to solve for k.
798 Easy
798 of 822
Application +4 | -1
One mapping is selected at random from all mappings of the set S={1,2,….,n}S=\{1,2, \ldots ., n\} to itself. If the probability that the mapping is one-one is 5324\frac{5}{324} then the value of nn equals (n∈N)(n \in N)
View answer and explanation
Correct option: A
6
The correct answer is A (6) because the probability that a mapping from a set of size n to itself is one-to-one is n!nn\frac{n!}{n^n}, and solving n!nn=5324\frac{n!}{n^n} = \frac{5}{324} gives n = 6.
799 Easy
799 of 822
Application +4 | -1
A box contains 15 green and 10 yellow balls. If 10 balls are randomly drawn, one-by-one, with replacement, then the variance of the number of green balls drawn, is
View answer and explanation
Correct option: A
125\frac{12}{5}
Option A (125\frac{12}{5}) is correct because it is the variance calculated using the formula npq with the given parameters n=10 and p=3/5.
800 Easy
800 of 822
Application +4 | -1
A and B throw a dice. The probability that A's throw is not greater than B's, is
View answer and explanation
Correct option: B
712\frac{7}{12}
Option B (712\frac{7}{12}) is correct because it represents the probability that A's throw is less than or equal to B's throw, calculated by summing the probabilities for each possible outcome of B's throw.
801 Easy
801 of 822
Application +4 | -1
The probability that a year chosen at random has 53 Sundays, is
View answer and explanation
Correct option: D
528\frac{5}{28}
Option D (528\frac{5}{28}) is correct because it calculates the weighted average of the probability of 53 Sundays in a leap year and a non-leap year.
802 Easy
802 of 822
Application +4 | -1
If P(A)=310,P(B)=25P(A)=\frac{3}{10}, P(B)=\frac{2}{5} and P(A∪B)=35P(A \cup B)=\frac{3}{5}, then P(B/A)+P(A/B)P(B / A)+P(A / B) equals to
View answer and explanation
Correct option: D
712\frac{7}{12}
Option D (712\frac{7}{12}) is correct because it is the result of calculating P(B/A)+P(A/B)P(B / A)+P(A / B) using the given probabilities and the formula for conditional probability.
803 Easy
803 of 822
Application +4 | -1
In a survery, it was found that 21 persons liked product AA, 26 liked product BB and 29 liked product CC. If 14 persons liked products AA and B,B, 12 liked products CC and A,A, 13 persons liked products BB and CC and 8 liked all the three products then
(i) Find the number of persons who liked the product CC only
(ii) The number of persons who like the products A{A} and B{B} but not C{C}
View answer and explanation
Correct option: A
12; 6
The correct answer is A (12; 6) because it correctly calculates the number of people who liked product C only and the number of people who liked products A and B but not C using set theory principles.
804 Easy
804 of 822
Remembering +4 | -1
In a poisson distribution mean is 16, then standard deviation is
View answer and explanation
Correct option: D
4
Option D (4) is correct because in a Poisson distribution, the variance is equal to the mean, and the standard deviation is the square root of the variance. Since the mean is 16, the standard deviation is 16=4\sqrt{16} = 4.
805 Easy
805 of 822
Understanding +4 | -1
A three digit number is selected at random from the set of all three-digit numbers. The probability that the number selected has all the three digits same, is
View answer and explanation
Correct option: D
1/1001 / 100
Option D (1/1001 / 100) is correct because there are 900 three-digit numbers, and only 9 of them have all three digits the same (111, 222, ..., 999). The probability is therefore 9/900 = 1/100.
806 Easy
806 of 822
Application +4 | -1
Bag P\mathrm{P} contains 6 red and 4 blue balls and bag Q\mathrm{Q} contains 5 red and 6 blue balls. A ball is transferred from bag P to bag Q\mathrm{Q} and then a ball is drawn from bag QQ. What is the probability that the ball drawn is blue?
View answer and explanation
Correct option: B
815\frac{8}{15}
Option B (815\frac{8}{15}) is correct because it is the probability of drawing a blue ball from bag Q after transferring a ball from bag P.
807 Easy
807 of 822
Application +4 | -1
A number is selected at random from the first twenty-five natural numbers. If it is a composite number, then it is divided by 5 . But if it is not a composite number, then it is divided by 2 . The probability that there will be no remainder in the division, is
View answer and explanation
Correct option: C
0.20.2
Option D is correct because the probability is 0.2, calculated by finding the number of composite numbers divisible by 5 and non-composite numbers divisible by 2, then dividing by the total number of selections.
808 Easy
808 of 822
Application +4 | -1
It is given that the events AA and BB are such that P(A)=14,P(A/B)=12P(A)=\frac{1}{4}, P(A / B)=\frac{1}{2} and P(B/A)=23P(B / A)=\frac{2}{3}. Then, P(B)P(B) is
View answer and explanation
Correct option: D
13\frac{1}{3}
Option D (13\frac{1}{3}) is correct because it uses the conditional probability formulas to find P(B).
809 Easy
809 of 822
Application +4 | -1
If the numbers appeared on the two throws of a fair six faced die are α\alpha and β\beta, then the probability that x2+αx+β>0x^2+\alpha x+\beta>0, for all x∈Rx \in R, is :
View answer and explanation
Correct option: A
1736\frac{17}{36}
Option A (17/36) is correct because it represents the probability calculated by finding favorable outcomes where the discriminant is negative.
810 Easy
810 of 822
Application +4 | -1
A pair of dice is thrown 5 times. For each throw, a total of 5 is considered a success. If the probability of at least 4 successes is k311\frac{k}{3^{11}}, then kk is equal to
View answer and explanation
Correct option: D
123
Option D (123) is correct because it is the numerator of the probability of at least 4 successes, calculated using binomial probability.
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