Skip to main content
Back to PROBABILITY

Your Progress

0 / 822 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • PROBABILITY

Probability practice · Easy

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 601-630 of 822 questions

Preparing practice and saved progress…

601 Easy
601 of 822
Application +4 | -1
If x∈[0,5],x \in \left[ {0,5} \right], then what is the probability that x2−3  x+2≥0?{x^2} - 3\;x + 2 \ge 0?
View answer and explanation
Correct option: A
04-May
Option A (4/5) is correct because it is calculated by finding the intervals where the quadratic is non-negative and dividing by the total interval length.
602 Easy
602 of 822
Application +4 | -1
An MBA applies for a job in two firms XX and YY. The probability of his being selected in firim X{X} is 0.7 and being rejected at Y{Y} is 0.5 . The probability of at least one of his applications being rejected is 0.6 . The probability that he will be selected in one of the firms, is
View answer and explanation
Correct option: C
0.8
Option B (513\frac{5}{13}) is correct because it calculates the probability that a white ball was drawn given that A states a white ball was drawn, using Bayes' theorem.
603 Easy
603 of 822
Application +4 | -1
When a certain biased die is rolled, a particular face occurs with probability 16−x\frac{1}{6} - x and its opposite face occurs with probability 16+x\frac{1}{6} + x. All other faces occurs with probability 1/60.1/60. Note that opposite faces sum to 77 in any die. If 0 <x < 16,0\, < x\, < \,\frac{1}{6}, and the probability of obtaining total sum =7,= 7, when such a die is rolled twice is 13/96, then the value of xx is
View answer and explanation
Correct option: B
1/81/8
The correct answer is 1/81/8 because it is the solution to the equation derived from the given probability of obtaining a total sum of 7 when the biased die is rolled twice.
604 Easy
604 of 822
Application +4 | -1
A speaks truth in 60%60 \% of the cases and B in 90%90 \% of the cases. The percentage of cases they are likely to contradict each other in stating the same fact is
View answer and explanation
Correct option: C
42%42 \%
Option C (42 %) is correct because it represents the sum of the probabilities that A speaks the truth and B lies, and A lies and B speaks the truth.
605 Easy
605 of 822
Application +4 | -1
A coin is tossed 3 times. The probability of obtaining at least two heads is
View answer and explanation
Correct option: C
12\frac{1}{2}
Option C (12\frac{1}{2}) is correct because it is the sum of probabilities of getting exactly 2 heads and exactly 3 heads when tossing a coin 3 times.
606 Easy
606 of 822
Application +4 | -1
A matrix is chosen at random from the set of all 2×22 \times 2 matrices with elements 0 and 1 only. The probability that the value of the determinant of the matrix chosen is positive, is
View answer and explanation
Correct option: B
3/163/16
Option B (316\frac{3}{16}) is correct because it calculates the probability of a 2x2 matrix with elements 0 and 1 having a positive determinant by counting favorable matrices and dividing by the total number of possible matrices.
607 Easy
607 of 822
Application +4 | -1
AA speaks the truth in 70 percent cases and BB in 80 percent. The probability that they will contradict each other when describing a single event is
View answer and explanation
Correct option: B
0.38
Option B (0.38) is correct because it represents the probability that A and B contradict each other, calculated by considering the cases where one speaks the truth and the other lies.
608 Easy
608 of 822
Application +4 | -1
If four dice are thrown together. Probability that the sum of the number appearing on them is 13, is
View answer and explanation
Correct option: A
35324\frac{35}{324}
Option A (35324\frac{35}{324}) is correct because it represents the probability calculated by finding the number of favorable outcomes (sum of 13) divided by the total possible outcomes when throwing four dice.
609 Easy
609 of 822
Application +4 | -1
The numbers 1,2,3,…,n1,2,3, \ldots, n are arranged in a random order. Then, the probability that the digits 1,2,3,…, k(k<n)1,2,3, \ldots ,\,k(k < n) appears as neighbours in that order, is
View answer and explanation
Correct option: D
(n−k+1)!n!\frac{(n-k+1) !}{n !}
Option D ((n−k+1)!n!\frac{(n-k+1) !}{n !}) is correct because it calculates the probability of k digits appearing as neighbors in a specific order.
610 Easy
610 of 822
Application +4 | -1
A box B1B_1 contains 1 white ball, 3 red balls and 2 black balls. Another box B2B_2 contains 2 white balls, 3 red balls and 4 black balls. A third box B3B_3 contains 3 white balls, 4 red balls and 5 black balls. If 1 ball is drawn from each of the three boxes B1,B2B_1, B_2 and B3B_3, the probability that all 3 drawn balls are of the same colour is
View answer and explanation
Correct option: A
82648\frac{82}{648}
Option A (82648\frac{{82}}{{648}}) is correct because it calculates the probability of drawing all white, all red, or all black balls from the three boxes and sums these probabilities.
611 Easy
611 of 822
Application +4 | -1
The probability of occurrence of a multiple of 2 on one dice and a multiple of 3 on the other dice if both are thrown together, is:
View answer and explanation
Correct option: D
1136\frac{11}{36}
Option D (1136\frac{11}{36}) is correct because the probability is calculated by counting the favorable outcomes and dividing by the total possible outcomes.
612 Easy
612 of 822
Application +4 | -1
All the spades are taken out from a pack of cards. From these cards, cards are drawn one by one without replacement till the ace of spades comes. The probability that the ace comes in the 4 th draw, is
View answer and explanation
Correct option: A
113\frac{1}{13}
Option A is correct because the probability is calculated by multiplying the probabilities of not drawing the ace in the first three draws and then drawing the ace on the fourth draw.
613 Easy
613 of 822
Application +4 | -1
Let n(A−B)=25+x,n(B−A)=2xn(A-B)=25+x, n(B-A)=2 x and n(A∩B)=2xn(A \cap B)=2 x. If n(A)=2n(B)n(A)=2 n(B) then ' xx ' is
View answer and explanation
Correct option: D
5
Option D (5) is correct. The value of x is found by setting up equations based on the given information about the number of elements in different sets and solving for x.
614 Easy
614 of 822
Application +4 | -1
7 white balls and 3 black balls are placed in a row at random. The probability that no two black balls are adjacent is
View answer and explanation
Correct option: B
715\frac{7}{15}
Option B (715\frac{{7}}{{15}}) is correct because it calculates the ratio of favorable arrangements (no two black balls adjacent) to the total possible arrangements of white and black balls.
615 Easy
615 of 822
Application +4 | -1
If AA and BB are two events such that P(A)=25P(A)=\frac{2}{5} and P(A∩B)=320P(A \cap B)=\frac{3}{20}, then the conditional probability P(A/A′∪B′)P\left(A / A^{\prime} \cup B^{\prime}\right), where A′A^{\prime} denotes the complement of AA, is equal to
View answer and explanation
Correct option: C
517\frac{5}{17}
Option C (517\frac{5}{17}) is correct because it correctly applies the conditional probability formula and De Morgan's law.
616 Easy
616 of 822
Analyzing +4 | -1
Bag I contains 3 red, 4 black and 3 white balls and Bag II contains 2 red, 5 black and 2 white balls. One ball is transferred from Bag I to Bag II and then a ball is drawn from Bag II. The ball so drawn is found to be black in colour. Then the probability, that the transferred ball is red, is :
View answer and explanation
Correct option: B
518\frac{5}{18}
Option A (1) is correct because the LHS and RHS of the equation are equal only when x=0, resulting in one element in the set.
617 Easy
617 of 822
Application +4 | -1
The probability that a candidate secures a seat in Engineering through “EAMCET” is 1/10.1/10. 7 candidates are selected at random from a centre. The probability that exactly two will get seats is
View answer and explanation
Correct option: C
21  (0.1)2  (0.9)521\;{\left( {0.1} \right)^2}\;{\left( {0.9} \right)^5}
Option C (21(0.1)2(0.9)521{\left( {0.1} \right)^2}{\left( {0.9} \right)^5}) is correct because it uses the binomial probability formula with n=7, k=2, p=1/10, and q=9/10.
618 Easy
618 of 822
Application +4 | -1
The probability that the 6th day of a randomly chosen month of a year is a Sunday, is
View answer and explanation
Correct option: C
184\frac{1}{{84}}
Option C (1/84) is correct. The probability that the 6th day of a randomly chosen month is a Sunday is calculated by considering the probability of choosing a month and the probability that the month starts on a Tuesday.
619 Easy
619 of 822
Application +4 | -1
Six coins are tossed simultaneously. The probability of getting at least 4 heads is
View answer and explanation
Correct option: B
Nov-32
Option A (Nov-32) is correct because it calculates the probability of getting at least 4 heads by summing the probabilities of getting 4, 5, or 6 heads.
620 Easy
620 of 822
Application +4 | -1
A lottery sells n2n^2 tickets and declares nn prizes. If a man purchases nn tickets, the probability of his winning exactly one prize is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the provided options do not match the correct probability calculation for winning exactly one prize.
621 Easy
621 of 822
Application +4 | -1
A lot consists of 102 good pencils, 6 with minor defects and 2 with major defects. A pencil is choosen at random. The probability that this pencil is not defective is
View answer and explanation
Correct option: A
3/53/5
Option C, 4/54/5 is incorrect. The correct probability is 102/110=51/55102/110 = 51/55. The provided solution and answer are incorrect.
622 Easy
622 of 822
Application +4 | -1
A five digits number is formed by writing the digits 1, 2, 3, 4, 5 in a random order without repetitions. Then the probability that the number is divisible by 4, is
View answer and explanation
Correct option: C
15\frac{1}{5}
Option C (1/5) is correct because it calculates the probability of forming a number divisible by 4 from the given digits.
623 Easy
623 of 822
Application +4 | -1
If the probability that a person is not a swimmer is 0.3 , then the probability that out of 5 persons 4 are swimmers is
View answer and explanation
Correct option: A
5C4(0.7)4(0.3){ }^5 C_4(0.7)^4(0.3)
Option A (5C4(0.7)4(0.3){}^5 C_4(0.7)^4(0.3)) is correct because it represents the probability of exactly 4 swimmers out of 5 people, using the binomial probability formula.
624 Easy
624 of 822
Application +4 | -1
The probability that a company executive will travel by train is 23\frac{2}{3} and that he will travel by plane is 15.\frac{1}{5}. The probability of his journey by train or plane is
View answer and explanation
Correct option: B
1315\frac{{13}}{{15}}
Option B (13/15) is correct because it calculates the probability of the executive traveling by train or plane by adding their individual probabilities since the events are mutually exclusive.
625 Easy
625 of 822
Application +4 | -1
If a dice is thrown twice, the probability of occurrence of 4 at least once, is
View answer and explanation
Correct option: A
11/3611/36
Option A (11/3611/36) is correct because it represents the probability of getting at least one 4 when a dice is thrown twice.
626 Easy
626 of 822
Application +4 | -1
You are given a box with 20 cards in it. 10 of these cards have letter II printed on them. The other ten have the letter T{T} printed on them. If you pick up 3 cards at random and keep them in same order, the probability of making the word IITIIT, is
View answer and explanation
Correct option: D
538\frac{5}{38}
Option D (5/38) is correct because it is the probability of picking two I cards followed by a T card from the given set of cards.
627 Easy
627 of 822
Understanding +4 | -1
If AA and BB are arbitrary events, then
View answer and explanation
Correct option: B
P(A∪B)≤P(A)+P(B)P(A \cup B) \leq P(A)+P(B)
Option B (P(A∪B)≤P(A)+P(B)P(A \cup B) \leq P(A)+P(B)) is correct because the probability of the union of two events is always less than or equal to the sum of their individual probabilities.
628 Easy
628 of 822
Application +4 | -1
If a dice is thrown twice, the probability of occurrence of 4 at least once is
View answer and explanation
Correct option: A
1136\frac{{11}}{{36}}
Option A (1136\frac{{11}}{{36}}) is correct because it represents the probability of getting a 4 at least once in two throws of a dice.
629 Easy
629 of 822
Application +4 | -1
If AA and BB are two independent events such that P(Aˉ∩B)=2/15P(\bar{A} \cap B)=2 / 15 and P(A∩Bˉ)=1/6P(A \cap \bar{B})=1 / 6, then P(B)P(B), is
View answer and explanation
Correct option: C
45\frac{4}{5} or, 16\frac{1}{6}
Option C (45\frac{4}{5} or, 16\frac{1}{6}) is correct because it is the solution to the probability equations derived from the given independent events.
630 Easy
630 of 822
Application +4 | -1
If AA and BB are two events such that P(A∪B)=56,P\left( {A \cup B} \right) = \frac{5}{6}, P(A∩B)=13P\left( {A \cap B} \right) = \frac{1}{3} and P(Bˉ)=13,P\left( {\bar B} \right) = \frac{1}{3}, then the value of P(A)P\left( A \right) is
View answer and explanation
Correct option: C
12\frac{1}{2}
Option C (12\frac{1}{2}) is correct because it is the value of P(A) that satisfies the given probability conditions.
Revision notes and key takeaways

Review PROBABILITY in your textbook or class notes, then use this set to check your understanding.

Showing 601-630 of 822 questions

Your practice

0 / 822 answered · 822 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.