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JEE • MATHEMATICS • PROBABILITY
Probability practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 211-240 of 1130 questions
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211
Easy
211 of 1130
Application
+4 | -1
The chances to fail in physics are 20% and the chances to fail in mathematics are 10%. What are the chances to fail in at least one object?
View answer and explanation
Correct option: A
28%
Option A (28%) is correct because it calculates the probability of failing in at least one subject using the formula for the union of two events.
212
Easy
212 of 1130
Application
+4 | -1
In a three throw of two dice, the probability throwing doublets not more than twice is
View answer and explanation
Correct option: C
Option C (215/216) is correct because it calculates the probability of throwing doublets not more than twice in three throws of two dice, using the binomial distribution.
213
Easy
213 of 1130
Application
+4 | -1
Let and are two events and then is
View answer and explanation
Correct option: B
0.8
Option B (0.8) is correct because it is the probability of calculated using the given probabilities and the formula for the probability of the union of two events.
214
Easy
214 of 1130
Application
+4 | -1
If and are chosen from the set , , with replacement, the probability that the roots of the equation are real is
View answer and explanation
Correct option: A
0.84
Option A (0.84) is correct because it represents the probability calculated by finding the complement of the probability of non-real roots.
215
Easy
215 of 1130
Analyzing
+4 | -1
Let and . Then,
View answer and explanation
Correct option: B
Option B () is correct because it indicates that and are independent events, which is derived from the given equation .
216
Easy
216 of 1130
Application
+4 | -1
Three identical dice are rolled. The probability that the same number will appear on each of them, is
View answer and explanation
Correct option: B
Jan-36
Option B (Jan-36) is correct because the probability of getting the same number on each of the three dice is 1/36.
217
Medium
217 of 1130
Application
+4 | -1
From a group of 8 boys and 3 girls, a committee of 5 members to be formed. Find the probability that 2 particular girls are included in the committee
View answer and explanation
Correct option: B
Option B () is correct because it is the probability of including 2 particular girls in a committee of 5, calculated by dividing the number of favorable outcomes by the total number of possible committees.
218
Easy
218 of 1130
Application
+4 | -1
A fair coin is tossed times. If the probability that heads occurs 6 times is equal to the probability that heads occurs 8 times, then value of is
View answer and explanation
Correct option: C
14
Option C (14) is correct because equating the probabilities of getting 6 and 8 heads leads to the equation , which solves for n = 14.
219
Medium
219 of 1130
Application
+4 | -1
In a sequence of independent trials, the probability of success is . If denotes the probability that the second success occurs on the fourth trial or later trial, then is
View answer and explanation
Correct option: C
7
Option C (7) is correct because the probability that the second success occurs on the fourth trial or later is 27/32, and 32p - 20 = 7.
220
Easy
220 of 1130
Analyzing
+4 | -1
For two events and it is given that and . Then,
View answer and explanation
Correct option: B
and are independent events such that
Option B ( and are independent events such that ) is correct because the given conditions and imply that and are independent, and is indeed 3/4.
221
Easy
221 of 1130
Application
+4 | -1
A bag contains 7 red and 2 white balls and another bag contains 5 red and 4 white balls. Two balls are drawn, one from each bag. The probability that both the balls are white, is
View answer and explanation
Correct option: C
Option C () is correct because it is the product of the probabilities of drawing a white ball from each bag.
222
Hard
222 of 1130
Application
+4 | -1
A bag contains some white and some
black balls, all combinations of balls being equally likely. The
total number of balls in the bag is 10. If three balls are drawn
at random without replacement and all of them are found to
be black, the probabili ty that the bag contains 1 white and
9 black balls is
black balls, all combinations of balls being equally likely. The
total number of balls in the bag is 10. If three balls are drawn
at random without replacement and all of them are found to
be black, the probabili ty that the bag contains 1 white and
9 black balls is
View answer and explanation
Correct option: A
Option A (14/55) is correct because it is the conditional probability calculated using Bayes' theorem, given that three black balls were drawn.
223
Medium
223 of 1130
Application
+4 | -1
A complete cycle of a traffic light takes 60 s. During each cycle the light is green for 25 s, yellow for 5 s and red for 30 s. At a randomly chosen time, the probability that the light will not be green, is
View answer and explanation
Correct option: D
Option A () is correct because it is found by using the given probabilities and the formula .
224
Medium
224 of 1130
Application
+4 | -1
An experiment succeeds twice as often as it fails. Find the probability that in 4 trials there will be at least three success
View answer and explanation
Correct option: C
Option C () is correct because it calculates the probability of at least three successes in four trials, considering both 3 successes and 4 successes.
225
Medium
225 of 1130
Application
+4 | -1
There are 10 pairs of shoes in a cupboard, from which 4 shoes are picked at random. If is the probability that there is at least one pair, then -97 is equal to
View answer and explanation
Correct option: A
2
Option A (2) is correct because the probability of at least one pair is 99/323, and 323p - 97 = 2.
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226
Easy
226 of 1130
Application
+4 | -1
If and , then is equal to
View answer and explanation
Correct option: A
Option A (0.6976) is correct because it is calculated by subtracting the probability of missing the plane with all four shots from 1.
227
Easy
227 of 1130
Application
+4 | -1
If and , then is equal to
View answer and explanation
Correct option: D
0.96
Option D (0.96) is correct because it is the result of calculating using the given probabilities and the formula .
228
Easy
228 of 1130
Application
+4 | -1
Four persons can hit a target correctly with probabilities and respectively. If all hit at the target independently, then the probability that the target would be hit, is
View answer and explanation
Correct option: B
Option B () is correct because it represents the probability that the target is hit, calculated as 1 minus the probability that none of the four persons hit the target.
229
Medium
229 of 1130
Application
+4 | -1
If and are events such that and , then,
I.
II.
III.
I.
II.
III.
View answer and explanation
Correct option: A
Only I and II are correct
Option A is correct because statements I and II are true based on the given probabilities, while statement III is false as the calculated probability of A or B is 0.74, not 0.47.
230
Easy
230 of 1130
Application
+4 | -1
If the probability of hitting a target by a shooter in any shot, is , then the minimum number of independent shots at the target required by him so that the probability of hitting the target at least once is greater than , is
View answer and explanation
Correct option: C
5
Option C (5) is correct because it is the minimum number of trials required for the probability of hitting the target at least once to be greater than 5/6, calculated using binomial distribution.
231
Easy
231 of 1130
Application
+4 | -1
Three natural numbers are taken at random one by one with replacement from the set . The probability that the of the number is 25 is
View answer and explanation
Correct option: C
Option C () is correct because it represents the number of favorable outcomes (combinations of three numbers summing to 75) divided by the total possible outcomes (1003).
232
Medium
232 of 1130
Application
+4 | -1
Seven chits are numbered 1 to 7. Four chits are drawn one by one with replacement. The probability that the least number appearing on any selected chit is 5, is
View answer and explanation
Correct option: A
Option A () is correct because it represents the probability that each of the four drawn chits has a number greater than or equal to 5.
233
Easy
233 of 1130
Application
+4 | -1
In a school 80 students like chocolate, 40 like coffee if the number of students doesn't like any of them is equal to the number of students who like both of them then what is the total number of students in the school?
View answer and explanation
Correct option: C
120
Option C (120) is correct because it represents the total number of students calculated using the principle of inclusion-exclusion and the given conditions.
234
Easy
234 of 1130
Application
+4 | -1
In a game called "odd man out" each person in a group of persons tosses a coin to determine who will buy refreshment for the entire group. The odd man out is the one whose outcome is different from the rest of the persons. The probability that there is a loser in the game is
View answer and explanation
Correct option: A
Option A () is correct because it represents the probability of having exactly one person with a different outcome than the others.
235
Easy
235 of 1130
Understanding
+4 | -1
If and are any two events, then is equal to
View answer and explanation
Correct option: D
Option D () is correct because it represents the probability of A occurring without B occurring.
236
Easy
236 of 1130
Application
+4 | -1
The Probability of solving a problem by three students is respectively. The probability that the problem will be solved is
View answer and explanation
Correct option: C
Option C () is correct because it calculates the probability that the problem will be solved by finding the complement, which is the probability that none of them solve it.
237
Easy
237 of 1130
Application
+4 | -1
For a random variable and Then, variable of is
View answer and explanation
Correct option: C
2
Option C (2) is correct because it is calculated using the formula for variance: Var(X) = E(X²) - [E(X)]².
238
Medium
238 of 1130
Analyzing
+4 | -1
Let be the maximum value of the product of two positive integers when their sum is 66 . Let the sample space and the event is a multiple of 3. Then is equal to
View answer and explanation
Correct option: B
Option B () is correct because we first find the maximum product M, then determine the sample space S and event A, and finally calculate the probability P(A).
239
Easy
239 of 1130
Understanding
+4 | -1
The event is independent of itself if and only if is
View answer and explanation
Correct option: A
0 or 1
Option A (0 or 1) is correct because for an event A to be independent of itself, P(A) must be either 0 or 1.
240
Easy
240 of 1130
Analyzing
+4 | -1
Let and be two events such that and , where stands for the complement of the event . Then the events and are
View answer and explanation
Correct option: A
independent but not equally likely
Option A (independent but not equally likely) is correct because and .
Revision notes and key takeaways
Review PROBABILITY in your textbook or class notes, then use this set to check your understanding.
Showing 211-240 of 1130 questions
