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JEE • MATHEMATICS • PROBABILITY
Probability practice · Mixed difficulty
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 121-150 of 1130 questions
121
Medium
121 of 1130
Application
+4 | -1
The chance of an event happening is the square of the chance of a second event but the odds against the first are the cube of the odds against the second. The chances of the events are
View answer and explanation
Correct option: A
Option A () is correct because it satisfies both given conditions: the chance of the first event is the square of the second, and the odds against the first are the cube of the odds against the second.
122
Medium
122 of 1130
Application
+4 | -1
The probability that in a random arrangement of the letters of the word ‘UNIVERSITY’, the two do not come together is
View answer and explanation
Correct option: A
04-May
Option A (04-May) is correct because the probability is calculated by finding the total arrangements and subtracting arrangements where the two I's are together, then dividing by the total arrangements.
123
Easy
123 of 1130
Understanding
+4 | -1
A die is thrown. If it shows a six, we draw a ball from a bag consisting 2 black balls and 6 white balls. If it does not show a six, then we toss a coin. Then, the sample space of this experiment consists of
View answer and explanation
Correct option: B
18 points
Option B (18 points) is correct because the sample space consists of 8 outcomes when a six is rolled and 10 outcomes when a six is not rolled, totaling 18.
124
Easy
124 of 1130
Application
+4 | -1
Two non-negative integers are chosen at random. The probability that the sum of the square is divisible by 5 is
View answer and explanation
Correct option: B
Option B () is correct because it represents the probability that the sum of the squares of two randomly chosen non-negative integers is divisible by 5.
125
Easy
125 of 1130
Application
+4 | -1
An unbiased die is rolled until two consecutive trails result in even numbered faces. The probability that exactly six trials are required to get two consecutive even numbered faces, is
View answer and explanation
Correct option: A
Option A (5(1/2)6) is correct because it calculates the probability of getting two consecutive even numbers on the 6th trial, with 5 possible sequences of odd and even numbers leading to this outcome.
126
Medium
126 of 1130
Application
+4 | -1
Two numbers and are chosen at random from the set . The probability that is divisible by 3 is
View answer and explanation
Correct option: D
None of these
The correct probability is , which is not among the options. is divisible by 3 if and only if both and are divisible by 3, or neither are divisible by 3.
127
Easy
127 of 1130
Application
+4 | -1
A person draws a card from a pack of playing cards, replaces it and shuffles the pack. He continues doing this until he draws a spade. The chance that he fail the first two times is
View answer and explanation
Correct option: D
Option D () is correct because it calculates the probability of failing to draw a spade in the first two attempts with replacement.
128
Easy
128 of 1130
Application
+4 | -1
Three dice are thrown. The probability that the same number will appear on each of them, is
View answer and explanation
Correct option: C
Option C (1/36) is correct because it is the probability of getting the same number on all three dice, calculated by dividing the number of favorable outcomes by the total number of outcomes.
129
Easy
129 of 1130
Application
+4 | -1
A coin is tossed 4 times. The probability that at least one head turns up, is
View answer and explanation
Correct option: D
Option A () is correct because the probability is calculated by considering the number of ways to choose 3 white balls out of 4 white balls, divided by the total number of ways to choose 3 balls out of 8 balls, considering identical balls.
130
Easy
130 of 1130
Application
+4 | -1
Probability is 0.45 that a dealer will sell at least 20 television sets during a day, and the probability is 0.74 that he will sell less than 24 televisions. The probability that he will sell , or 23 televisions during the day, is
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Correct option: A
0.19
Option A (0.19) is correct because it represents the probability of the dealer selling 20, 21, 22, or 23 televisions, calculated using the addition rule of probability.
131
Easy
131 of 1130
Understanding
+4 | -1
If and are two events such that and , then the correct statement among the following is:
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Correct option: D
The correct answer is not listed in the options. The correct answer should be since .
132
Medium
132 of 1130
Analyzing
+4 | -1
Let and Then,
View answer and explanation
Correct option: C
Option C () is correct because it correctly identifies that A and B are independent events, leading to the given relationship for their complements.
133
Easy
133 of 1130
Application
+4 | -1
From a bag containing 30 tickets numbered three tickets are selected at random without replacement. Suppose these tickets are arranged as . The probability that and , is
View answer and explanation
Correct option: A
Option A (1/29) is correct because it represents the probability of selecting three tickets such that x2 = 15 and x3 > 20, calculated by dividing the number of favorable outcomes by the total number of possible outcomes.
134
Easy
134 of 1130
Application
+4 | -1
If and be two events such that and , then is equal to
View answer and explanation
Correct option: D
Option D () is correct because it is the product of P(A/B) and P(A'/B) calculated using conditional probability and the given probabilities.
135
Easy
135 of 1130
Application
+4 | -1
A six faced die is so biased that it is twice likely to show an even number as an odd number when thrown. If the die is thrown twice the probability that sum of the numbers is even is
View answer and explanation
Correct option: D
Option D () is correct because it is the probability of getting an even sum when a biased die is thrown twice, considering the die is twice as likely to show an even number as an odd number.
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136
Easy
136 of 1130
Analyzing
+4 | -1
Odds in favour of an event are 2 to 1 and odds in favour of are 3 to 1 . Consistent with this information the smallest and largest values for the probability of event are given by
View answer and explanation
Correct option: C
Option C () is correct because it represents the range of possible values for the probability of event B, derived from the given odds and the properties of probability.
137
Medium
137 of 1130
Application
+4 | -1
The probability that at least one of the events and occurs is 0.7 and they occur simultaneously with probability 0.2. Then,
View answer and explanation
Correct option: C
1.1
Option C (1.1) is correct because it is derived from the properties of probability and complementary events.
138
Easy
138 of 1130
Application
+4 | -1
A person draws a card from a pack of 52 playing cards, replaces it and shuffles the pack. He continues doing this until he draws a spade, the chance that he will fail in the first two draws is
View answer and explanation
Correct option: B
Option B (9/16) is correct because the probability of failing in the first two draws is the product of the probabilities of failing in each individual draw, since the draws are independent.
139
Easy
139 of 1130
Application
+4 | -1
A coin is biased so that the head is 3 times as likely to occur as tail. This coin is tossed until a head or three tails occur. If denotes the number of tosses of the coin, then the mean of is
View answer and explanation
Correct option: C
Option C (21/16) is correct because it is the expected value (mean) of the number of tosses calculated using probabilities of getting a head or three tails.
140
Easy
140 of 1130
Analyzing
+4 | -1
A number is chosen from the set The probability that has 3 in units place, is
View answer and explanation
Correct option: C
Option C () is correct because the units digit of powers of 3 cycle through 3, 9, 7, and 1, resulting in a probability of 1/4 for a 3 in the units place.
141
Easy
141 of 1130
Analyzing
+4 | -1
If two events and are such that and then is equal to
View answer and explanation
Correct option: C
Option C () is correct because it represents the conditional probability of event B occurring given that event A or the complement of event B has occurred, calculated using the given probabilities.
142
Easy
142 of 1130
Application
+4 | -1
A bag contains 5 red, 3 white and 2 black balls. If a ball is picked at random, the probability that it is red is
View answer and explanation
Correct option: B
Option B () is correct because the probability of picking a red ball is the number of red balls divided by the total number of balls.
143
Easy
143 of 1130
Application
+4 | -1
In a multiple choice question there are four alternative answers, of which one or more are correct. A candidate will get marks in the question only if he ticks all the correct answers. The candidate decides to tick answers at random. If he is allowed upto three chanes to answer the question, the probability that he will get marks in the question, is
View answer and explanation
Correct option: B
Option B () is correct because it represents the probability of selecting the correct answer within three attempts, considering all possible combinations.
144
Medium
144 of 1130
Application
+4 | -1
If the probability density function of a random variable is in then is equal to
View answer and explanation
Correct option: C
Option C () is correct because it calculates the conditional probability P(X > 1.5 | X > 1) by finding the individual probabilities P(X > 1.5) and P(X > 1) using integration of the probability density function.
145
Easy
145 of 1130
Application
+4 | -1
Kiran is deciding whether to visit Russia or Ukrain for the holidays. She makes her decision by rolling a regular 6-sided die. If she gets 1 or 2 she goes to Ukrain, if she rolls a 3,4 or 5 she goes to Russia. If she rolls a 6 she rolls again, the probability that she goes to Ukrain is , then is
View answer and explanation
Correct option: A
2
Option A (2) is correct because the probability that Kiran goes to Ukrain is 2/5, and therefore 5p = 5*(2/5) = 2.
146
Easy
146 of 1130
Application
+4 | -1
Out of 40 consecutive integers, two are chosen at random, the probability that their sum is odd is
View answer and explanation
Correct option: B
Option B () is correct because it calculates the probability of the sum being odd by considering the number of ways to choose one even and one odd number.
147
Easy
147 of 1130
Understanding
+4 | -1
If are arbitrary events, then
View answer and explanation
Correct option: B
Option B () is correct because , and since , it follows that .
148
Easy
148 of 1130
Application
+4 | -1
In a binomial distribution the mean is 15 and variance is 10. Then parameter is
View answer and explanation
Correct option: C
45
Option C (45) is correct because it is the value of n that satisfies the given mean and variance for a binomial distribution.
149
Medium
149 of 1130
Application
+4 | -1
If is an integer lying in , then the probability that the graph of is strictly above the -axis is
View answer and explanation
Correct option: C
Option C (2/9) is correct because the probability that the graph is strictly above the x-axis is 8/36 = 2/9, derived from the condition that the discriminant is negative.
150
Easy
150 of 1130
Application
+4 | -1
If a die is thrown and a card is selected at random from a deck of 52 playing cards, then the probability of getting an even number on the die and a spade card is
View answer and explanation
Correct option: C
Option C () is correct because it is the product of the probability of getting an even number on the die and the probability of getting a spade card.
Revision notes and key takeaways
Review PROBABILITY in your textbook or class notes, then use this set to check your understanding.
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