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JEE • MATHEMATICS • PROBABILITY

Probability practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 811-840 of 1130 questions

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811 Easy
811 of 1130
Application +4 | -1
A manufacture of cotter pins knows that 5% of his product is defective. He sells pins in boxes of 100 and guarantees that not more than one pin will be defective in a box. In order to find the probability that a box will fail to meet the guaranteed quality, the probability distribution one has to employ is
View answer and explanation
Correct option: B
Poisson
Option B (Poisson) is correct because the Poisson distribution is appropriate for modeling rare events like defective items in a large batch.
812 Easy
812 of 1130
Application +4 | -1
If P(A)=23,P(B)=12P(A)=\frac{2}{3}, P(B)=\frac{1}{2} and P(A∪B)=56P(A \cup B)=\frac{5}{6}, then events AA and BB are
View answer and explanation
Correct option: C
independent
Option C (independent) is correct because P(A ∩ B) = P(A) * P(B), which is the condition for independence.
813 Easy
813 of 1130
Application +4 | -1
If AA and BB are two independent events such that P(B)=27,P(A∪Bc)=0.8P\left( B \right) = \frac{2}{7},P\left( {A \cup {B^c}} \right) = 0.8, then P(A)P\left( A \right) is equal to
View answer and explanation
Correct option: C
0.3
Option C (0.3) is correct because it is the solution to the probability equation derived from the given information about independent events A and B.
814 Easy
814 of 1130
Application +4 | -1
Probability of getting positive integral roots of the equation x2−n=0{x^2} - n = 0 for the integer n,   1≤n≤40n,\;\,1 \le n \le 40 is
View answer and explanation
Correct option: C
320\frac{3}{{20}}
Option C (320\frac{3}{{20}}) is correct because only 6 values of n (1, 4, 9, 16, 25, 36) between 1 and 40 result in positive integer roots for the given equation.
815 Medium
815 of 1130
Analyzing +4 | -1
In a test, an examines either guesses or copies or knows the answer to a multiple choice questions with four choices. The probability that he makes a guess is 13\frac{1}{3} and the probability that he copies the answer is 16.\frac{1}{6}. The probability that his answer is correct given that he copies it is 18.\frac{1}{8}. The probability that his answer is correct, given that he guesses it is 14.\frac{1}{4}. The probability that they knew the answer to the questions given that he correctly answered is
View answer and explanation
Correct option: C
2429\frac{{24}}{{29}}
Option C (2429\frac{{24}}{{29}}) is correct because it is the result of applying Bayes' theorem to calculate the probability of knowing the answer given a correct answer.
816 Easy
816 of 1130
Application +4 | -1
If two dice are thrown together, then the probability that the sum of numbers appearing on them is 9, is
View answer and explanation
Correct option: A
19\frac{1}{9}
Option A (1/9) is correct because there are 4 favorable outcomes out of a total of 36 possible outcomes when throwing two dice.
817 Medium
817 of 1130
Application +4 | -1
Two number a,ba, b are chosen from the set of integers 1,2,3,….,391,2,3, \ldots ., 39, then probability that the equation 7a−9b=07 a-9 b=0 is satisfied, is
View answer and explanation
Correct option: C
4741\frac{4}{741}
The correct answer is C (4741\frac{4}{741}) because it is the probability calculated by finding the number of favorable pairs (a, b) that satisfy the equation 7a - 9b = 0 and dividing by the total number of possible pairs.
818 Easy
818 of 1130
Application +4 | -1
The probability that a student is not a car driver is 1/51 / 5. The probability that out of 5 students, exactly 4 are car drivers is
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Correct option: A
(45)4\left(\frac{4}{5}\right)^4
Option B ((5C4{}^5 C_4)(4/5)4) is correct because it represents the probability of exactly 4 out of 5 students being car drivers, using the binomial probability formula.
819 Easy
819 of 1130
Understanding +4 | -1
An unbiased die is rolled twice. Let AA denote the event that an even number appears on the first throw and BB denote the event that an odd number appears on the second throw. Then AA and BB
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Correct option: C
Are independent
Option C (Are independent) is correct because the events A and B are independent since P(A ∩ B) = P(A)P(B).
820 Easy
820 of 1130
Application +4 | -1
A letter is known to have come either from LONDON or CLIFTON; on the postmark only the two consecutive letters ON\mathrm{ON} are legible. The probability that it came from LONDON is
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Correct option: B
1217\frac{12}{17}
Option B (12/17) is correct because it represents the conditional probability of the letter coming from LONDON given that the postmark shows 'ON'.
821 Easy
821 of 1130
Analyzing +4 | -1
For two events AA and BB, if P(A)=P(A/B)=14P(A)=P(A / B)=\frac{1}{4} and P(B/A)=12P(B / A)=\frac{1}{2}, then
View answer and explanation
Correct option: D
all of the above
Option D (all of the above) is correct because the given probabilities satisfy the conditions for independence, and the conditional probabilities P(A'/B) and P(B'/A') can be derived from them.
822 Easy
822 of 1130
Application +4 | -1
Four numbers are multiplied together. Then the probability that the product will be divisible by 5 or 10, is
View answer and explanation
Correct option: A
369625\frac{369}{625}
Option A (369625\frac{{369}}{{625}}) is correct because it calculates the probability that the product is divisible by 5 or 10 by finding the complement probability and subtracting from 1.
823 Easy
823 of 1130
Application +4 | -1
Seven balls are drawn simultaneously from a bag containing 5 white and 6 green balls. The probability of drawing 3 white and 4 green balls is
View answer and explanation
Correct option: C
  5C2  6C2  11C7\frac{{{\;^5}{C_2}{\;^6}{C_2}}}{{{\;^{11}}{C_7}}}
The correct answer is C (  5C2  6C2  11C7\frac{{{\;^5}{C_2}{\;^6}{C_2}}}{{{\;^{11}}{C_7}}}) because it represents the number of ways to choose 3 white balls from 5 and 4 green balls from 6, divided by the total number of ways to choose 7 balls from 11.
824 Easy
824 of 1130
Application +4 | -1
Let A={1,3,5,7,9},B={2,4,6,8}A=\{1,3,5,7,9\}, B=\{2,4,6,8\}, if a Cartesian product A×BA \times B is choosen at random, the probability of a+b=9a+b=9 is
View answer and explanation
Correct option: D
1/51 / 5
Option D (1/5) is correct because it calculates the probability of a+b=9 by dividing the number of favorable outcomes by the total number of outcomes in the Cartesian product.
825 Easy
825 of 1130
Application +4 | -1
A bag contains 6 white and 4 black balls. Two balls are drawn at random. The probability that they are of the same colours, is
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Correct option: D
715\frac{7}{{15}}
Option D (715\frac{7}{{15}}) is correct because it is the sum of the probabilities of drawing two white balls and drawing two black balls.
826 Easy
826 of 1130
Application +4 | -1
Six dice are thrown simultaneously. The probability that all of them show the different faces, is
View answer and explanation
Correct option: B
6!66\frac{6 !}{6^6}
Option B (6!66\frac{6 !}{6^6}) is correct because it represents the probability of all six dice showing different faces, calculated as the number of permutations of 6 faces divided by the total possible outcomes.
827 Medium
827 of 1130
Application +4 | -1
A fair die is rolled. The probability that the first time 1 occurs at the even throw, is
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Correct option: B
511\frac{5}{11}
Option B (5/11) is correct because it represents the sum of an infinite geometric series where the first 1 occurs on an even throw.
828 Easy
828 of 1130
Application +4 | -1
If x∈[0,5],x \in \left[ {0,5} \right], then what is the probability that x2−3  x+2≥0?{x^2} - 3\;x + 2 \ge 0?
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Correct option: A
04-May
Option A (4/5) is correct because it is calculated by finding the intervals where the quadratic is non-negative and dividing by the total interval length.
829 Easy
829 of 1130
Application +4 | -1
An MBA applies for a job in two firms XX and YY. The probability of his being selected in firim X{X} is 0.7 and being rejected at Y{Y} is 0.5 . The probability of at least one of his applications being rejected is 0.6 . The probability that he will be selected in one of the firms, is
View answer and explanation
Correct option: C
0.8
Option B (513\frac{5}{13}) is correct because it calculates the probability that a white ball was drawn given that A states a white ball was drawn, using Bayes' theorem.
830 Easy
830 of 1130
Application +4 | -1
When a certain biased die is rolled, a particular face occurs with probability 16−x\frac{1}{6} - x and its opposite face occurs with probability 16+x\frac{1}{6} + x. All other faces occurs with probability 1/60.1/60. Note that opposite faces sum to 77 in any die. If 0 <x < 16,0\, < x\, < \,\frac{1}{6}, and the probability of obtaining total sum =7,= 7, when such a die is rolled twice is 13/96, then the value of xx is
View answer and explanation
Correct option: B
1/81/8
The correct answer is 1/81/8 because it is the solution to the equation derived from the given probability of obtaining a total sum of 7 when the biased die is rolled twice.
831 Easy
831 of 1130
Application +4 | -1
A speaks truth in 60%60 \% of the cases and B in 90%90 \% of the cases. The percentage of cases they are likely to contradict each other in stating the same fact is
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Correct option: C
42%42 \%
Option C (42 %) is correct because it represents the sum of the probabilities that A speaks the truth and B lies, and A lies and B speaks the truth.
832 Easy
832 of 1130
Application +4 | -1
A coin is tossed 3 times. The probability of obtaining at least two heads is
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Correct option: C
12\frac{1}{2}
Option C (12\frac{1}{2}) is correct because it is the sum of probabilities of getting exactly 2 heads and exactly 3 heads when tossing a coin 3 times.
833 Easy
833 of 1130
Application +4 | -1
A matrix is chosen at random from the set of all 2×22 \times 2 matrices with elements 0 and 1 only. The probability that the value of the determinant of the matrix chosen is positive, is
View answer and explanation
Correct option: B
3/163/16
Option B (316\frac{3}{16}) is correct because it calculates the probability of a 2x2 matrix with elements 0 and 1 having a positive determinant by counting favorable matrices and dividing by the total number of possible matrices.
834 Easy
834 of 1130
Application +4 | -1
AA speaks the truth in 70 percent cases and BB in 80 percent. The probability that they will contradict each other when describing a single event is
View answer and explanation
Correct option: B
0.38
Option B (0.38) is correct because it represents the probability that A and B contradict each other, calculated by considering the cases where one speaks the truth and the other lies.
835 Easy
835 of 1130
Application +4 | -1
If four dice are thrown together. Probability that the sum of the number appearing on them is 13, is
View answer and explanation
Correct option: A
35324\frac{35}{324}
Option A (35324\frac{35}{324}) is correct because it represents the probability calculated by finding the number of favorable outcomes (sum of 13) divided by the total possible outcomes when throwing four dice.
836 Medium
836 of 1130
Application +4 | -1
In a lottery three were 90 tickets numbered 1 to 90. Five tickets were drawn at random. The probability that two of the tickets drawn numbers 15 and 89, is
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Correct option: A
2/801
Option A (2/801) is correct because it represents the probability of selecting two specific tickets (15 and 89) out of 90 when drawing five tickets at random.
837 Easy
837 of 1130
Application +4 | -1
The numbers 1,2,3,…,n1,2,3, \ldots, n are arranged in a random order. Then, the probability that the digits 1,2,3,…, k(k<n)1,2,3, \ldots ,\,k(k < n) appears as neighbours in that order, is
View answer and explanation
Correct option: D
(n−k+1)!n!\frac{(n-k+1) !}{n !}
Option D ((n−k+1)!n!\frac{(n-k+1) !}{n !}) is correct because it calculates the probability of k digits appearing as neighbors in a specific order.
838 Easy
838 of 1130
Application +4 | -1
A box B1B_1 contains 1 white ball, 3 red balls and 2 black balls. Another box B2B_2 contains 2 white balls, 3 red balls and 4 black balls. A third box B3B_3 contains 3 white balls, 4 red balls and 5 black balls. If 1 ball is drawn from each of the three boxes B1,B2B_1, B_2 and B3B_3, the probability that all 3 drawn balls are of the same colour is
View answer and explanation
Correct option: A
82648\frac{82}{648}
Option A (82648\frac{{82}}{{648}}) is correct because it calculates the probability of drawing all white, all red, or all black balls from the three boxes and sums these probabilities.
839 Easy
839 of 1130
Application +4 | -1
The probability of occurrence of a multiple of 2 on one dice and a multiple of 3 on the other dice if both are thrown together, is:
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Correct option: D
1136\frac{11}{36}
Option D (1136\frac{11}{36}) is correct because the probability is calculated by counting the favorable outcomes and dividing by the total possible outcomes.
840 Easy
840 of 1130
Application +4 | -1
All the spades are taken out from a pack of cards. From these cards, cards are drawn one by one without replacement till the ace of spades comes. The probability that the ace comes in the 4 th draw, is
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Correct option: A
113\frac{1}{13}
Option A is correct because the probability is calculated by multiplying the probabilities of not drawing the ace in the first three draws and then drawing the ace on the fourth draw.
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