Back to PERMUTATION AND COMBINATION
Your Progress
0 / 250 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • PERMUTATION AND COMBINATION
Permutation and combination practice · Medium
Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.
Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
Take a chapter quiz →
Showing 91-120 of 250 questions
Preparing practice and saved progress…
91
Medium
91 of 250
Analyzing
+4 | -1
Garlands are formed using 6 red roses and 6 yellow roses of different sizes. The number of arrangements in garland which have red roses and yellow roses come alternately is
View answer and explanation
Correct option: C
!
Option C ( !) is correct because the yellow roses are arranged in a circle, and the red roses fill the gaps, considering the garland can be flipped.
92
Medium
92 of 250
Application
+4 | -1
A teaparty is arranged for 16 people along two sides of a large table with 8 chairs on each side. Four men want to sit on one particular side and two on the other side. The number of ways in which they can be seated, is
View answer and explanation
Correct option: B
Option B () is correct because it calculates the number of ways to seat 16 people with restrictions on where the men sit.
93
Medium
93 of 250
Analyzing
+4 | -1
In a shooting competition, a man can score 5, 4, 3, 2 or 0 points for each shot. Then, the number of different ways in which he can score 30 in seven shots, is
View answer and explanation
Correct option: C
420
Option C (420) is correct because it represents the coefficient of x30 in the generating function, accounting for all possible combinations of scores to reach 30 in 7 shots.
94
Medium
94 of 250
Application
+4 | -1
The number of ways five alphabets can be chosen from the alphabets of the word MATHEMATICS, where the chosen alphabets are not necessarily distinct, is equal to:
View answer and explanation
Correct option: D
179
Option D (179) is correct because it accounts for all possible combinations of selecting five alphabets from the word MATHEMATICS, considering repetitions.
95
Medium
95 of 250
Application
+4 | -1
There are letters letters letters . The number of ways of selecting letters out of these if is
View answer and explanation
Correct option: B
Option B () is correct because it represents the number of ways of selecting k letters out of p 'a's, q 'b's, and r 'c's, given p < k < q < r.
96
Medium
96 of 250
Analyzing
+4 | -1
If , then
View answer and explanation
Correct option: A
integer
Option A ( integer) is correct because the expression S can be simplified to (n+1)! - 1, making (S+1) equal to (n+1)!, which is divisible by n!.
97
Medium
97 of 250
Application
+4 | -1
A three digit number is such that the last two digits of it are equal and differ from the first. The number of such is
View answer and explanation
Correct option: C
81
Option C (81) is correct because there are 9 choices for the first digit (1-9) and 9 choices for the last two digits (00, 11, ..., 99) excluding the case where the first digit is equal to the last two.
98
Medium
98 of 250
Application
+4 | -1
Total number of positive integral solutions of is equal to
View answer and explanation
Correct option: A
42
Option A (42) is correct because it represents the total number of positive integral solutions for the given equation after considering the possible values of x3.
99
Medium
99 of 250
Application
+4 | -1
The number of numbers between 2,000 and 5,000 that can be formed with the digits , (repetition of digits is not allowed) and are multiple of 3 is?
View answer and explanation
Correct option: A
30
Option A (30) is correct because by considering all possible cases for the thousands digit (2, 3, or 4) and ensuring the sum of the digits is divisible by 3, we find a total of 30 such numbers.
100
Medium
100 of 250
Application
+4 | -1
The letters of the word 'VICTORY' are arranged in all possible ways, and the words thus obtained are arranged as in a dictionary. Then the rank of given word is
View answer and explanation
Correct option: A
3733
Option A (3733) is correct because it calculates the rank of the word VICTORY based on dictionary order.
101
Medium
101 of 250
Application
+4 | -1
If the words formed by using the letters of the word 'AGAIN' are arranged in the form of dictionary, then word is
View answer and explanation
Correct option: B
NAAIG
Option B (NAAIG) is correct because when the words formed by the letters of 'AGAIN' are arranged in dictionary order, the 50th word is NAAIG.
102
Medium
102 of 250
Application
+4 | -1
From 5 consonants, 4 vowels and 3 capital letters, the number of words beginning with a capital letter and containing 3 consonants and 2 vowels that can be made is
View answer and explanation
Correct option: B
21600
Option B (21600) is correct because it represents the number of words that can be made with the given constraints.
103
Medium
103 of 250
Application
+4 | -1
In how many ways can a student choose a program of 5 courses, if 9 courses are available and 2 specific courses are compulsory for every student?
View answer and explanation
Correct option: C
35
Option C (35) is correct because after fixing the 2 compulsory courses, we need to choose 3 courses out of the remaining 7, which can be done in ways.
104
Medium
104 of 250
Analyzing
+4 | -1
The number of rational numbers lying in the interval all whose digits after the decimal points are non-zero and are in decreasing order, is
View answer and explanation
Correct option: C
Option C () is correct because it represents the sum of ways to choose 1 to 9 digits from the set {1, 2, ..., 9} and arrange them in decreasing order.
105
Medium
105 of 250
Application
+4 | -1
Two straight lines intersect at a point . Points are taken on one line and points on the other. If the point is not to be used, then the number of triangles that can be drawn using these points as vertices, is
View answer and explanation
Correct option: C
Option C () is correct because it represents the total number of triangles formed by subtracting the degenerate cases (3 points on the same line) from the total possible combinations.
Explore Other Chapters in MATHEMATICS
View All →
106
Medium
106 of 250
Application
+4 | -1
The number of ways of selecting 4 letters from the word EXAMINATION, is
View answer and explanation
Correct option: A
136
Option A (136) is correct because it represents the total number of ways to select 4 letters considering repetitions of A, I, and N in the word EXAMINATION.
107
Medium
107 of 250
Application
+4 | -1
There are 5 boys and 3 girls. In how many ways can they be seated in a row, so that all the three girls do not sit together?
View answer and explanation
Correct option: D
Option D () is correct because it calculates the number of ways to seat 5 boys and 3 girls such that the 3 girls do not sit together by subtracting the arrangements where they sit together from the total arrangements.
108
Medium
108 of 250
Analyzing
+4 | -1
The total number of six-digit numbers that can be formed, having the property that every succeeding digit is greater than the preceding digit, is
View answer and explanation
Correct option: A
Option A () is correct because selecting 6 distinct digits from 1 to 9 uniquely determines the six-digit number with increasing digits.
109
Medium
109 of 250
Application
+4 | -1
Value of when is . The value of is
View answer and explanation
Correct option: A
6
Option A (6) is correct because when and , equals 30, which is .
110
Medium
110 of 250
Analyzing
+4 | -1
The number of ways in which the letters of the word ARRANGE be arranged so that "two A's are together but not two R's
View answer and explanation
Correct option: A
240
Option A (240) is correct because it calculates the arrangements with two A's together and subtracts the arrangements with both A's and both R's together.
111
Medium
111 of 250
Application
+4 | -1
The number of ways of arranging six persons (having and among them) in a row so that and are always in order (not necessarily together) is
View answer and explanation
Correct option: C
30
Option C (30) is correct because it represents the number of ways to arrange the six persons with the specified order constraint.
112
Medium
112 of 250
Analyzing
+4 | -1
If , where , then the ordered pair is
View answer and explanation
Correct option: A
Option A ((9,10)) is the correct answer because the given expression can be simplified and expressed in the form where a=9 and b=10.
113
Medium
113 of 250
Application
+4 | -1
The number of ways in which a score of 11 can be made from a through by three persons, each throwing a single die once, is
View answer and explanation
Correct option: C
27
Option C (27) is correct because it calculates the number of ways three dice can sum to 11.
114
Medium
114 of 250
Application
+4 | -1
The number of proper divisors of 1260 , is
View answer and explanation
Correct option: C
34
Option C (34) is correct because it represents the number of proper divisors of 1260.
115
Medium
115 of 250
Application
+4 | -1
is equal to
View answer and explanation
Correct option: D
None of these
None of these is correct because the sum evaluates to , which is not listed as an option.
116
Medium
116 of 250
Application
+4 | -1
The total number of 3 digit even numbers that can be composed from the digitis . , 9 when the repetition of digits is not allowed, is
View answer and explanation
Correct option: A
224
Option A (224) is correct because the total number of 3-digit even numbers is calculated by considering the possible choices for each digit.
117
Medium
117 of 250
Application
+4 | -1
Let and . If is an one-one function and holds only for one value of , then the number of such possible function is
View answer and explanation
Correct option: C
45
Option D (44) is incorrect. Option A (40) is incorrect. Option B (36) is incorrect. Option C (45) is correct because it is the number of one-to-one functions where f(x) = x for only one value.
118
Medium
118 of 250
Application
+4 | -1
If number of numbers greater than 3000 , which can be formed by using the digits without repetition, is then is equal to
View answer and explanation
Correct option: A
6
Option A (6) is correct because the number of numbers greater than 3000 formed using the given digits without repetition is 1380, and 1380/230 = 6.
119
Medium
119 of 250
Application
+4 | -1
The number of words which can be formed out of letters taken 3 together, each containing one vowel at least is
View answer and explanation
Correct option: B
96
Option B (96) is correct because it represents the number of 3-letter words formed from the given letters, each containing at least one vowel.
120
Medium
120 of 250
Application
+4 | -1
Ajay writes letters to his five friends and addresses the corresponding. The number of ways can the letters be placed in the envelopes so that at least two of them are in the wrong envelopes is
View answer and explanation
Correct option: C
119
Option C (119) is correct because it calculates the total number of ways to arrange the letters minus the case where all letters are in the correct envelopes.
Revision notes and key takeaways
Review PERMUTATION AND COMBINATION in your textbook or class notes, then use this set to check your understanding.
Showing 91-120 of 250 questions
