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JEE MATHEMATICS MCQ: PERMUTATIONS

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Application +4 | -1
The number of ways in which 6 men can be arranged in a row so that three particular men are consecutive is
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Correct option: B
4P4×3P3{ }^{4} P_{4} \times{ }^{3} P_{3}
Option B (4P4×3P3{ }^{4} P_{4} \times{ }^{3} P_{3}) is correct because it treats the three consecutive men as a single unit and then arranges them internally.

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