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JEE • MATHEMATICS • PERMUTATION AND COMBINATION

Permutation and combination practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 481-485 of 485 questions

481 Easy

481 of 485

Application +4 | -1

The number of words that can be formed by using the letters of the word MATHEMATICS that start as well as end with T is:

View answer and explanation

Correct option: B

90720

Option B (90720) is correct because after fixing T at the beginning and end, we arrange the remaining 9 letters, accounting for repetitions of M and A, resulting in 9!/(2!2!) = 90720.

482 Easy

482 of 485

Application +4 | -1

The number of ways that 8 beads of different colours be strung as a necklace is

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Correct option: C

\frac{7 !}{2}

Option C (

\frac{7 !}{2}

) is correct because the number of ways to arrange n distinct objects in a necklace is (n-1)!/2.

483 Easy

483 of 485

Application +4 | -1

m

men and

n

women are to be seated in a row so that no two women sit together. If

m > n

, then the number of ways in which they can be seated, is

View answer and explanation

Correct option: A

\frac{{m!\left( {m + 1} \right)!}}{{\left( {m - n + 1} \right)!}}

Option A (

\frac{{m!\left( {m + 1} \right)!}}{{\left( {m - n + 1} \right)!}}

) is correct because it accounts for arranging the men and then placing the women in the gaps.

484 Easy

484 of 485

Application +4 | -1

The number of positive integers

< 1,00,000

which contain exactly one 2, one 5 and one 7 in its decimal representation is

View answer and explanation

Correct option: A

2940

Option A (2940) is correct because it accounts for the permutations of the digits 2, 5, and 7 within a 5-digit number, along with the possible choices for the remaining digits.

485 Easy

485 of 485

Application +4 | -1

The letters of the word RANDOM are written in all possible orders and these words are written out as in a dictionary, then the rank of the word RANDOM is

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Correct option: A

614

Option A (614) is correct because the rank of the word RANDOM is determined by counting the number of words that come before it in a dictionary, considering the alphabetical order of the letters.

Revision notes and key takeaways

Review PERMUTATION AND COMBINATION in your textbook or class notes, then use this set to check your understanding.

Showing 481-485 of 485 questions

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