JEE MATHEMATICS MCQ: PERMUTATIONS

1 Easy

1 of 1

Understanding +4 | -1

2 m

white counters and

2 n

red counters are arranged in a straight line with

(m+n)

counters on each side of a central mark. The number of ways of arranging the counters, so that the arrangements are symmetrical with respect to the central mark, is

View answer and explanation

Correct option: A

\frac{(m+n) !}{m ! n !}

Option A (

\frac{(m+n) !}{m ! n !}

) is correct because it represents the number of ways to arrange m white and n red counters on one side of the central mark, determining the entire symmetrical arrangement.

More Questions from PERMUTATIONS

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How many different nine digit numbers can be formed from the number 223355888 by rearranging its digits so that the odd digits occupy even positions? The number of ways in which

r

letters can be posted in

n

letterboxes in a town is The number of four-digit numbers that can be made with the digits

1,2,3,4

and 5 in which atleast two digits are identical, is The number of ways in which a pack of 52 cards can be divided equally into four groups, is Five digited numbers with distinct digits are formed by using the digits, 5, 4, 3, 2, 1, 0. The number of those numbers which are multiples of 3, is A man invites a party to

\left( {m + n} \right)

friends to dinner and places m at one round table and

n

at another. The number of ways of arranging the guests is