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JEE • MATHEMATICS • PERMUTATION AND COMBINATION
Permutation and combination practice · Easy
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 361-390 of 485 questions
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361
Easy
361 of 485
Application
+4 | -1
In how many ways 3 letters can be posted in 4 letter-boxes, if all the letters are not posted in the same letter-box?
View answer and explanation
Correct option: B
60
Option B (60) is correct because we subtract the cases where all letters are posted in the same box from the total possible ways of posting the letters.
362
Easy
362 of 485
Application
+4 | -1
If the permutations of and taken all together are written down in alphabetical order as in dictionary and numbered, the rank of the permutation debac is
View answer and explanation
Correct option: D
93
Option D (93) is correct because it determines the rank of the given permutation in alphabetical order.
363
Easy
363 of 485
Application
+4 | -1
Find the number of ways in which 8 different flowers can be strung to form a garland so that 4 particular flowers are never separated
View answer and explanation
Correct option: B
288
Option B (288) is correct because the 4 particular flowers are treated as one unit, and the garland can be flipped, so we divide by 2.
364
Easy
364 of 485
Application
+4 | -1
If and , then is
View answer and explanation
Correct option: D
Option D ((8,2)) is the correct answer because it satisfies both permutation equations, and .
365
Easy
365 of 485
Application
+4 | -1
If and , then value of is
View answer and explanation
Correct option: B
Option B () is correct because the equality of permutations with implies that and must be and respectively.
366
Easy
366 of 485
Understanding
+4 | -1
equals:
View answer and explanation
Correct option: A
1
Option A (1) is correct because the given expression simplifies to 1 using binomial coefficient properties.
367
Easy
367 of 485
Analyzing
+4 | -1
If , then
View answer and explanation
Correct option: A
Option A (n > 6) is correct because simplifying the inequality leads to the condition n > 6.
368
Easy
368 of 485
Understanding
+4 | -1
The number of ways of putting 5 identical balls in 10 identical boxes, if not more than one can go in a box is
View answer and explanation
Correct option: D
1
Option D (1) is correct because there is only one way to put 5 identical balls in 10 identical boxes with at most one ball per box.
369
Easy
369 of 485
Application
+4 | -1
There are 10 true-false questions in an examination. Then, these questions can be answered in
View answer and explanation
Correct option: C
1024 ways
Option C (1024 ways) is correct because each question has 2 choices (True or False), and there are 10 questions, so the total number of ways is 210.
370
Easy
370 of 485
Understanding
+4 | -1
The products of any consecutive natural numbers is always divisible by
View answer and explanation
Correct option: A
Option A () is correct because the product of any r consecutive natural numbers is always divisible by r!.
371
Easy
371 of 485
Analyzing
+4 | -1
The value of is equal to
View answer and explanation
Correct option: C
Option C () is correct because by simplifying the expression using properties of permutations and factorials, the result is .
372
Easy
372 of 485
Application
+4 | -1
Four boys picked up 30 mangoes. The number of ways in which they can divide them if all mangoes be identical, is
View answer and explanation
Correct option: A
5456
Option A (5456) is correct because it represents the number of ways to distribute 30 identical mangoes among 4 boys, allowing each boy to receive any number of mangoes.
373
Easy
373 of 485
Application
+4 | -1
Assuming the balls to be identical except for difference in colours, the number of ways in which one or more balls can be selected from 10 white, 9 green and 7 black balls, is
View answer and explanation
Correct option: B
879
Option B (879) is correct because it calculates the total number of ways to select one or more balls by considering all possible combinations of white, green, and black balls and then subtracting the case where no balls are selected.
374
Easy
374 of 485
Application
+4 | -1
If , then is equal to:
View answer and explanation
Correct option: D
3
Option D (3) is correct because substituting n=3 into the given equation satisfies the equality after simplifying the combinations and permutations.
375
Easy
375 of 485
Application
+4 | -1
The number of ways in which 3 boys and 3 girls (all are of different heights) can be arranged in a line, so that boys as well as girls among themselves are in decreasing order of height from left to right, is
View answer and explanation
Correct option: C
20
Option D (766) is correct because it is the total count of numbers less than formed using only 1 and 2.
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376
Easy
376 of 485
Analyzing
+4 | -1
Number of positive integer less than 17, for which is an integral multiple of 49, is
View answer and explanation
Correct option: C
5
Option C (5) is the correct answer because there are five values of n less than 17 for which the given expression is divisible by 49.
377
Easy
377 of 485
Application
+4 | -1
If of 8 !, 10 ! and 12 ! and of 8 !, 10 ! and 12 !, then is equal to
View answer and explanation
Correct option: C
11880
Option C (11880) is correct because it calculates the ratio of the LCM and HCF of the given factorials.
378
Easy
378 of 485
Application
+4 | -1
The total number of factors (excluding 1) of 2160 is
View answer and explanation
Correct option: B
39
Option B (39) is correct because it calculates the total number of factors (including 1 and 2160) and then subtracts 1 to exclude the factor 1.
379
Easy
379 of 485
Application
+4 | -1
If denotes the number of permutations of things taken all at a time, the number of permutations of things taken 11 at a time and the number of permutations of things taken all at a time such that , then the value of is
View answer and explanation
Correct option: B
12
Option A (12) is correct because it is the value of x that satisfies the given permutation equation after simplification and solving the quadratic equation.
380
Easy
380 of 485
Application
+4 | -1
Total number of positive integral solutions of is equal to
View answer and explanation
Correct option: B
54
Option B (54) is correct because it accurately calculates the number of positive integral solutions by considering the distribution of prime factors of 60 among the three variables.
381
Easy
381 of 485
Analyzing
+4 | -1
The number of bijective functions , such that , is _____.
View answer and explanation
Correct option: B
Option B () is correct because we choose 17 elements out of 50 for the decreasing sequence and arrange the remaining 33 elements.
382
Easy
382 of 485
Application
+4 | -1
An examination paper contains 8 question of which 4 has 3 possible answers, 3 have 2 possible answers each and the remaining one question has 5 possible answers. The total number of possible answers to all the questions is
View answer and explanation
Correct option: D
3240
Option D (3240) is correct because it calculates the total number of possible answer combinations by multiplying the number of choices for each question.
383
Easy
383 of 485
Application
+4 | -1
There are three copies, each of 4 different books. The number of ways in which they can be arranged on a shelf, is
View answer and explanation
Correct option: A
Option A () is correct because it accounts for the repetitions of the 4 different books.
384
Easy
384 of 485
Application
+4 | -1
12 boys and 2 girls are to be seated in a row such that there are atleast 3 boys between the 2 girls. The number of ways this can be done is ! the value of is
View answer and explanation
Correct option: B
110
Option B (110) is correct because it calculates the number of arrangements where at least 3 boys are between the two girls.
385
Easy
385 of 485
Application
+4 | -1
The number of squares that we can find on a chess board is
View answer and explanation
Correct option: D
204
Option D (204) is correct because the total number of squares is the sum of squares of integers from 1 to 8.
386
Easy
386 of 485
Application
+4 | -1
The total number of proper factors of 7875 is
View answer and explanation
Correct option: C
22
Option C (22) is correct because it calculates the total number of factors and then subtracts 1 to exclude the number itself, giving the number of proper factors.
387
Easy
387 of 485
Analyzing
+4 | -1
The number of positive terms in the sequence is
View answer and explanation
Correct option: C
4
Option A (3) is correct because by substituting the limit of f(x) and simplifying, the logarithm evaluates to 3.
388
Easy
388 of 485
Application
+4 | -1
The number of ways in which 5 boys and 5 girls can sit in a row so that all girls sit together is
View answer and explanation
Correct option: C
86400
Option C (86400) is correct because it calculates the arrangements of boys and girls with all girls sitting together.
389
Easy
389 of 485
Understanding
+4 | -1
The no. of dissimilar terms in the expansion of is
View answer and explanation
Correct option: A
66
Option A (66) is correct because the number of dissimilar terms in the expansion of is calculated using the formula for combinations with repetition.
390
Easy
390 of 485
Application
+4 | -1
The total number of selections of at least one red ball from a bag containing 4 red balls and 3 green balls, balls of the same colour being identical, is
View answer and explanation
Correct option: C
16
Option C (16) is correct because it represents the total number of selections with at least one red ball.
Revision notes and key takeaways
Review PERMUTATION AND COMBINATION in your textbook or class notes, then use this set to check your understanding.
Showing 361-390 of 485 questions
