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JEE • MATHEMATICS • PARABOLA
Parabola practice · Easy
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 61-90 of 356 questions
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61
Easy
61 of 356
Application
+4 | -1
The equation of the directrix of the parabola is
View answer and explanation
Correct option: B
Option B () is correct because it represents the directrix of the given parabola after rewriting it in standard form.
62
Easy
62 of 356
Analyzing
+4 | -1
Let be three points on the parabola such that tangents at these points taken in pairs form a triangle . Then, area : area
View answer and explanation
Correct option: B
Option B (2:1) is correct. The ratio of the area of the triangle formed by three points on a parabola to the area of the triangle formed by the tangents at those points is always 2:1.
63
Easy
63 of 356
Application
+4 | -1
The point of intersection of the normals to the parabola at the ends of its latus rectum is :
View answer and explanation
Correct option: B
Option B () is correct because the point of intersection of the normals to the parabola at the ends of its latus rectum is (3a, 0).
64
Easy
64 of 356
Application
+4 | -1
Vertex of the parabola is and equation of the directrix is Then length of the latusrectum is
View answer and explanation
Correct option: B
8
Option B (8) is correct because the length of the latus rectum of a parabola is 4a, where a is the distance from the vertex to the directrix, and in this case, 4a = 8.
65
Easy
65 of 356
Application
+4 | -1
If a chord which is not a tangent, of the parabola has the equation , and mid-point , then which of the following is (are) possible value (s) of and ?
View answer and explanation
Correct option: D
Option D () is correct because these values satisfy the equation derived from the chord's midpoint and the parabola's equation.
66
Easy
66 of 356
Application
+4 | -1
If the vertex of the parabola lies on -axis, then the value of is
View answer and explanation
Correct option: C
64
Option C (64) is correct because when k=64, the equation becomes a perfect square, indicating the vertex lies on the x-axis.
67
Easy
67 of 356
Analyzing
+4 | -1
Consider the two curves
Then
Then
View answer and explanation
Correct option: B
and touch each other exactly at two point
Option B is correct. The curves and touch each other exactly at two points, which are (1, 2) and (1, -2), as they have the same tangent at these points.
68
Easy
68 of 356
Analyzing
+4 | -1
The slope of a chord of the parabola which is normal at one end and which subtends a right angle at the origin, is
View answer and explanation
Correct option: B
Option B () is correct because the slope of the normal chord is when it subtends a right angle at the origin.
69
Easy
69 of 356
Application
+4 | -1
If tangents at extremities of a focal chord of the parabola intersect at a point , then is equal to
View answer and explanation
Correct option: C
Option C () is correct because the tangents at the extremities of a focal chord of a parabola intersect at right angles.
70
Easy
70 of 356
Analyzing
+4 | -1
Let be a conic. Let be the focus and be the point on the axis of the conic such that where is any point on the conic. If is the ordinate of the centroid of the then is equal to
View answer and explanation
Correct option: D
The correct answer is D () because it is the limit of the ordinate of the centroid of the triangle SAB as t approaches 1, calculated using the properties of the conic and the given geometric conditions.
71
Easy
71 of 356
Analyzing
+4 | -1
The number of distinct normals that can be drawn from to the parabola , is
View answer and explanation
Correct option: A
1
Option A (1) is correct because only one normal can be drawn from the point (-2, 1) to the given parabola.
72
Easy
72 of 356
Application
+4 | -1
The centre of the conic is
View answer and explanation
Correct option: A
Option A (2,3) is correct because it is found by solving the partial derivatives of the conic equation with respect to x and y.
73
Easy
73 of 356
Application
+4 | -1
The coordinates of the extremities of the latus rectum of the parabola are
View answer and explanation
Correct option: B
Option B () is correct because these are the coordinates of the endpoints of the latus rectum for the given parabola.
74
Easy
74 of 356
Application
+4 | -1
If the common tangent to the parabolas and also touches the circle , then is equal to
View answer and explanation
Correct option: A
Option A () is correct because the common tangent's distance from the origin equals the radius of the circle, leading to c = .
75
Easy
75 of 356
Application
+4 | -1
The area of the triangle inscribed in the parabola the ordinates of whose vertices are 1,2 and 4 is
View answer and explanation
Correct option: D
sq. units
Option D ( sq. units) is correct because it is the area of the triangle calculated using the formula for the area of a triangle inscribed in a parabola.
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76
Easy
76 of 356
Application
+4 | -1
The equation of the parabola whose vertex and focus are on the positive side of the -axis at distances and respectively from the origin, is
View answer and explanation
Correct option: A
Option A () is correct because it represents a parabola with the given vertex and focus, with the correct latus rectum length.
77
Easy
77 of 356
Application
+4 | -1
If is the vertex and -axis the directrix of a parabola, then its focus is
View answer and explanation
Correct option: C
Option C () is correct because the focus is equidistant from the vertex as the directrix, but on the opposite side.
78
Easy
78 of 356
Application
+4 | -1
is any focal chord of the parabola . The length of can never be less than
View answer and explanation
Correct option: C
32 units
Option C (32 units) is correct because the shortest focal chord is the latus rectum, and for the parabola , the length of the latus rectum is .
79
Easy
79 of 356
Application
+4 | -1
The equation of the parabola whose vertex is , axis is vertical, and which passes through the point , is
View answer and explanation
Correct option: A
Option A () is correct because substituting the vertex and the given point into the parabola equation yields this result.
80
Easy
80 of 356
Application
+4 | -1
If the line is a tangent to the parabola , then the point of contact is
View answer and explanation
Correct option: A
Option A ((0,1)) is correct because it's the only point that satisfies both the line and parabola equations, indicating it's the point of contact.
81
Easy
81 of 356
Application
+4 | -1
The equation of a common tangent to and the curve can be
View answer and explanation
Correct option: B
Option B () is correct because it is a common tangent to both the parabola and the ellipse, found by comparing the tangent equations of both curves.
82
Easy
82 of 356
Application
+4 | -1
Two perpendicular tangents and are drawn to , minimum length of is equal to
View answer and explanation
Correct option: B
Option B (4 a) is correct because the chord of contact of mutually perpendicular tangents to a parabola is a focal chord, and the minimum length of a focal chord is the latus rectum, which is 4a.
83
Easy
83 of 356
Application
+4 | -1
The ends of a line segment are and is a point on the line segment such that . If is an interior point of the parabola , then
View answer and explanation
Correct option: A
Option A () is correct because the point R lies inside the parabola only when the ratio is between 0 and 1.
84
Easy
84 of 356
Application
+4 | -1
The axis of the parabola , is
View answer and explanation
Correct option: A
Option A () is correct because it represents the axis of symmetry for the given parabola after completing the square.
85
Easy
85 of 356
Application
+4 | -1
If is a normal to the parabola then the value of is
View answer and explanation
Correct option: A
Option A () is correct because this is the standard form for the constant term in the normal equation to the given parabola.
86
Easy
86 of 356
Application
+4 | -1
The equation of the common tangent to the parabolas and , is
View answer and explanation
Correct option: B
Option A () is correct because it is derived by equating the tangent equations of the two parabolas and solving for the common tangent.
87
Easy
87 of 356
Application
+4 | -1
The line is a normal to the parabola at the point.
View answer and explanation
Correct option: C
Option C ((2,4)) is correct because the slope of the normal is -1, and substituting this into the parabola's normal equation gives the point (2,4).
88
Easy
88 of 356
Analyzing
+4 | -1
Consider the parabola . Let be the area of the triangle formed by the end points of its latus rectum and the point on the parabola, and be the area of the triangle formed by drawing tangents at and at the end-points of the latus rectum. Then, , is
View answer and explanation
Correct option: B
2
Option B (2) is correct because the area of a triangle formed by three points on a parabola is twice the area of the triangle formed by tangents at those points.
89
Easy
89 of 356
Application
+4 | -1
The focus of the parabola is
View answer and explanation
Correct option: C
Option D ((-,0)) is correct because it represents the focus of the given parabola after completing the square and transforming the equation.
90
Easy
90 of 356
Analyzing
+4 | -1
The normals at the ends of the latusrectum of the parabola intersect at angle of
View answer and explanation
Correct option: D
Option D () is correct because the normals at the ends of the latus rectum are perpendicular to each other.
Revision notes and key takeaways
Review PARABOLA in your textbook or class notes, then use this set to check your understanding.
Showing 61-90 of 356 questions
