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JEE • MATHEMATICS • PARABOLA

Parabola practice · Hard

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Hard
1 of 19
Application +4 | -1
If II denotes the semi-latusrectum of the parabola y2=4ax{y^2} = 4ax and SPSP and SQSQ denote the segments of any focal chord PQ,SPQ,S being the focus, then SP,lSP,l and SQSQ are in the relation
View answer and explanation
Correct option: C
HP
Option C (HP) is correct because the semi-latus rectum ll, and the segments of the focal chord SPSP and SQSQ satisfy the harmonic progression relation, i.e., 2/l=1/SP+1/SQ2/l = 1/SP + 1/SQ.
2 Hard
2 of 19
Application +4 | -1
A common tangent is drawn to the circle x2+y2=c2x^2+y^2=c^2 and the parabola y2=4axy^2=4 a x. If the angle which this tangent makes with the axis of xx is π/4\pi / 4 then the relationship between a and c(a,c>0)c(a, c>0) is-
View answer and explanation
Correct option: A
a=2c\mathrm{a}=\sqrt{2} \mathrm{c}
Option D (2x+y−33=02 x+y-3 \sqrt{{3}}=0) is correct because it is the equation of the tangent calculated at the point where the ordinate and abscissa are equal on the curve.
3 Hard
3 of 19
Analyzing +4 | -1
The set of points on the axis of the parabola y2−4x−2y+5=0y^2-4 x-2 y+5=0 from which all the three normals to the parabola are real is
View answer and explanation
Correct option: B
(k,1);k>3(k, 1) ; k>3
Option B ((k,1);k>3(k, 1) ; k>3) is correct because completing the square gives the standard form of the parabola, and the condition for three real normals from a point on the axis leads to x > 3 and y = 1.
4 Hard
4 of 19
Application +4 | -1
If the length of the normal chord to the parabola y2=4x\mathrm{y}^2=4 \mathrm{x}, which subtends right angle at the vertex is L\mathrm{L} then the value of L2\mathrm{L}^2 is
View answer and explanation
Correct option: A
108
Option A (108) is correct because the length of the normal chord is calculated to be 636\sqrt{3}, and squaring this value gives 108.
5 Hard
5 of 19
Application +4 | -1
The chord of contact of tangents drawn from any point on x−1=0x - 1 = 0 to y2−6y+4x+9=0{y^2} - 6y + 4x + 9 = 0 passes through the point
View answer and explanation
Correct option: A
(−1,3)\left( { - 1,3} \right)
Option A ((-1,3)) is correct because the chord of contact of tangents drawn from any point on the directrix of a parabola passes through its focus.
6 Hard
6 of 19
Analyzing +4 | -1
If the 4th term in the expansion of (px+1x)n,n∈N\left(p x+\frac{1}{x}\right)^n, n \in N is 52\frac{5}{2} and three normals to the parabola y2=xy^2=x are drawn through a point (q,0)(q, 0), then
View answer and explanation
Correct option: B
q>pq>p
Option B (q>pq>p) is correct because the condition for three normals to a parabola to be drawn from a point (q,0) implies q > 2a, and we find p = 1/2 and a = 1/4, thus q > p.
7 Hard
7 of 19
Analyzing +4 | -1
Let y=f(x)y=f(x) represent a parabola with focus (−12,0)\left(-\frac{1}{2}, 0\right) and directrix y=−12y=-\frac{1}{2}. Then
S={x∈R:tan⁡−1(f(x))+sin⁡−1(f(x)+1)=π2}:S=\left\{x \in \mathbb{R}: \tan ^{-1}(\sqrt{f(x)})+\sin ^{-1}(\sqrt{f(x)+1})=\frac{\pi}{2}\right\}:
View answer and explanation
Correct option: D
Contains exactly two elements
Option D (Contains exactly two elements) is correct because solving the equation derived from the given conditions yields two real solutions for x.
8 Hard
8 of 19
Analyzing +4 | -1
The locus of the vertices of the family of parabolas y=a3x23+a2x2−2ay=\frac{a^3 x^2}{3}+\frac{a^2 x}{2}-2 a is
View answer and explanation
Correct option: A
xy=10564x y=\frac{105}{64}
Option A (xy=10564x y=\frac{105}{64}) is correct because finding the vertex of the parabola and eliminating the parameter 'a' leads to the given locus.
9 Hard
9 of 19
Application +4 | -1
The equation of the common tangent to the curves y2=8x{y^2} = 8x and xy=−1xy = - 1 is
View answer and explanation
Correct option: D
y=x+2y = x + 2
Option D (y=x+2y = x + 2) is correct because it is the common tangent to both the parabola y2=8x{y^2} = 8x and the hyperbola xy=−1xy = -1, found by equating the tangent equation of the parabola to the hyperbola and solving for the tangency condition.
10 Hard
10 of 19
Analyzing +4 | -1
For each parabola y=x2+px+qy=x^2+p x+q, meeting coordinate axes at 3-distinct points, if circles are drawn through these points, then the family of circles must pass through
View answer and explanation
Correct option: B
(0,1)(0,1)
Option B (0,1) is correct because the family of circles passing through the intersection points of the parabola and coordinate axes must pass through the point (0,1).
11 Hard
11 of 19
Understanding +4 | -1
The locus of the foot of the perpendicular from the focus upon a tangent to the parabola y2=4  ax{y^2} = 4\;ax is
View answer and explanation
Correct option: B
Tangent at the vertex
Option B (Tangent at the vertex) is correct because the locus of the foot of the perpendicular from the focus upon a tangent to the parabola is the tangent at the vertex.
12 Hard
12 of 19
Application +4 | -1
Radius of circle touching the parabola y2=4xy^2=4 x at point (1,2)(1,2) and passing through its focus is
View answer and explanation
Correct option: B
2\sqrt{2}
Option B (2\sqrt{2}) is correct because it's the radius of the circle that touches the parabola at (1,2) and passes through the focus (1,0).
13 Hard
13 of 19
Analyzing +4 | -1
In a parabola y2=4ax,y^2 = 4ax, two points PP and QQ are taken such that the tangents drawn to parabola at these points
meet at directrix in R.R. Focus of locus of circumcentre of ΔPQR\Delta PQR will be:
View answer and explanation
Correct option: C
(3a2,0)\left( {\frac{{3a}}{2},0} \right)
Option C (3a2,0)\left( \frac{{3a}}{{2}},0 \right) is correct because the locus of the circumcentre is a parabola with focus at (3a2,0)\left( \frac{{3a}}{{2}},0 \right).
14 Hard
14 of 19
Understanding +4 | -1
The circle on focal radii of a parabola as diameter touches the
View answer and explanation
Correct option: C
Tangent at the vertex
The correct answer is C (Tangent at the vertex) because the circle described on the focal radii of a parabola as diameter touches the tangent at the vertex.
15 Hard
15 of 19
Analyzing +4 | -1
If the normals from any point to the parabola x2=4yx^2=4 y cuts the line y=2y=2 in points whose abscissae are in A.P., then the slopes of the tangents at the 3 conormal points are in
View answer and explanation
Correct option: B
GPG P
Option B (G P) is correct because the slopes of the tangents at the three conormal points are in Geometric Progression.
16 Hard
16 of 19
Analyzing +4 | -1
The set of points (x,y)(x, y) whose distance from the line y=2x+2y=2 x+2 is the same as the distance from (2,0)(2,0) is a parabola. This parabola is congruent to the parabola in standard from y=kx2y=k x^2 for some kk which is equal to
View answer and explanation
Correct option: D
512\frac{\sqrt{5}}{12}
Option D (512\frac{\sqrt{5}}{12}) is correct because equating the distance from a point to a line and a fixed point results in a parabola, and transforming it to standard form reveals k = 512\frac{\sqrt{5}}{12}.
17 Hard
17 of 19
Analyzing +4 | -1
If two different tangents of y2=4xy^2=4 x are the normals to x2=4x^2=4 by, then
View answer and explanation
Correct option: A
∣b∣<122|b|<\frac{1}{2 \sqrt{2}}
Option A (∣b∣<122|b|<\frac{1}{2 \sqrt{2}}) is correct because the condition for two different tangents leads to a discriminant greater than zero, resulting in the given inequality.
18 Hard
18 of 19
Analyzing +4 | -1
If a≠0a \neq 0 and the line 2bx+3cy+4d=02 b x+3 c y+4 d=0 passes through the points of intersection of the parabolas y2=4axy^2=4 a x and x2=4ayx^2=4 a y, then
View answer and explanation
Correct option: A
d2+(2b+3c)2=0d^2+(2 b+3 c)^2=0
Option A (d2+(2b+3c)2=0d^2+(2 b+3 c)^2=0) is correct because the given line passes through the intersection points of the parabolas, leading to the condition d=0 and 2b+3c=0.
19 Hard
19 of 19
Application +4 | -1
If y=2x+3y = 2x + 3 is a tangent to the parabola, y2=24  x,{y^2} = 24\;x, then its distance from the parallel normal is
View answer and explanation
Correct option: C
15515\sqrt 5
Option C (15515\sqrt 5) is correct because it is the distance between the given tangent and its parallel normal to the parabola.
Revision notes and key takeaways

Review PARABOLA in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 19 single-correct-answer MCQs on PARABOLA.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
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