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JEE • MATHEMATICS • PARABOLA

Parabola practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 331-356 of 356 questions
331 Easy
331 of 356
Remembering +4 | -1
Equation ax2+2hxy+by2+2gx+2fy+c=0  a{x^2} + 2hxy + b{y^2} + 2\mathrm{g}x + 2fy + c = 0\;
(abc+2fgh−af2−bg2−ch2≠0)\left( {abc + 2f\mathrm{g}h - a{f^2} - b{\mathrm{g}^2} - c{h^2} \ne 0} \right) represents a parabola, if
View answer and explanation
Correct option: A
h2=ab{h^2} = ab
Option A (h2=ab{h^2} = ab) is correct because this is the condition for the given general equation to represent a parabola.
332 Easy
332 of 356
Application +4 | -1
The parabola y2=4ax{y^2} = 4ax passes through the point (2,−6),\left( {2, - 6} \right), then the length of its latusrectum is
View answer and explanation
Correct option: A
18
Option A (18) is correct because substituting the given point into the parabola equation allows us to solve for 'a', and then calculate the latus rectum using 4a.
333 Easy
333 of 356
Understanding +4 | -1
The locus of the point of intersection of perpendicular tangents to the parabola, is
View answer and explanation
Correct option: B
its directrix
Option B (its directrix) is correct because the locus of the point of intersection of perpendicular tangents to a parabola is its directrix.
334 Easy
334 of 356
Understanding +4 | -1
The parametric coordinates of any point on the parabola y2=4ax{y^2} = 4ax can be
View answer and explanation
Correct option: C
(asin⁡2t,−2asin⁡t)\left( {a{{\sin }^2}t, - 2a\sin t} \right)
Option A (± π2\pm \, \frac{\pi }{2}) is correct because the difference between the eccentric angles of the ends of a pair of conjugate diameters of an ellipse is ± π2\pm \, \frac{\pi }{2}.
335 Easy
335 of 356
Application +4 | -1
The tangent at (1,7)(1,7) to the curve x2=y−6x^2=y-6 touches the circle x2+y2+16x+12y+c=0x^2+y^2+16 x+12 y+c=0 at
View answer and explanation
Correct option: D
(−6,−7)(-6,-7)
Option D ((-6,-7)) is correct because the tangent to the parabola at (1,7) intersects the circle at (-6,-7).
336 Easy
336 of 356
Application +4 | -1
The equation of parabola with focus (0,0)\left( {0,0} \right) and directrix x+y=4x + y = 4, is
View answer and explanation
Correct option: A
x2+y2−2xy+8x+8y−16=0{x^2} + {y^2} - 2xy + 8x + 8y - 16 = 0
Option A (x2+y2−2xy+8x+8y−16=0{x^2} + {y^2} - 2xy + 8x + 8y - 16 = 0) is correct because it represents the equation of a parabola derived from the definition where the distance to the focus equals the distance to the directrix.
337 Easy
337 of 356
Analyzing +4 | -1
PP and QQ are two distinct points on the parabola, y2=4xy^{2}=4 x, with parameters tt and t1t_{1} respectively. If the normal at PP passes through Q\mathrm{Q}, then the minimum value of t12\mathrm{t}_{1}^{2} is :
View answer and explanation
Correct option: A
8
Option A (8) is correct because the minimum value of t12t_1^2 is found using the relationship between tt and t1t_1 and applying AM-GM inequality.
338 Easy
338 of 356
Application +4 | -1
The length of the latus rectum of the parabola 9x2−6x+36y+19=09 x^2-6 x+36 y+19=0 is
View answer and explanation
Correct option: D
4
Option D (4) is correct because the length of the latus rectum of a parabola in the form (x−h)2=4p(y−k)(x-h)^2 = 4p(y-k) is 4p4p.
339 Easy
339 of 356
Application +4 | -1
If the distances of points PP and QQ from the focus of a parabola y2=4axy^2=4ax are 4 and 9 respectively, then the distance of the point of intersection of tangents at PP and QQ from the focus, is
View answer and explanation
Correct option: B
6
Option B (6) is correct because the distance of the intersection point of tangents from the focus is the geometric mean of the distances of P and Q from the focus.
340 Easy
340 of 356
Application +4 | -1
The focal distance of a point on the parabola y2−12xy^2-12 x is 4. The abscissa of this point is
View answer and explanation
Correct option: A
1
Option A (1) is correct because the abscissa (x-coordinate) of the point on the parabola is 1, derived from the focal distance formula.
341 Easy
341 of 356
Application +4 | -1
If the length of the latus rectum of a parabola, whose focus is (a,a)(a, a) and the tangent at its vertex is x+y=ax+y=a, is 16 , then ∣a∣|a| is equal to :
View answer and explanation
Correct option: C
424 \sqrt{2}
Option C (424 \sqrt{2}) is correct because the length of the latus rectum is four times the distance from the focus to the tangent at the vertex.
342 Easy
342 of 356
Analyzing +4 | -1
The equations of the common tangents to the parabola y=x2y=x^2 and y=−(x−2)2y=-(x-2)^2 are
View answer and explanation
Correct option: A
y=0,y=4(x−1)y=0, y=4(x-1)
Option A (y=0,y=4(x−1)y=0, y=4(x-1)) is correct because these lines are tangent to both parabolas, as verified by solving for the tangency conditions.
343 Easy
343 of 356
Application +4 | -1
The value of cc for which the line y=2x+cy=2 x+c is a tangent to the parabola y2=4a(x+a)y^2=4 a(x+a), is
View answer and explanation
Correct option: D
5a2\frac{5 a}{2}
Option D (5a2\frac{5 a}{2}) is correct because it is the value of c that makes the discriminant of the quadratic equation zero, indicating tangency.
344 Easy
344 of 356
Application +4 | -1
The chords of contact of the pairs of tangents drawn from each point on the line 2x+y=42 x+y=4 to the parabola y2=−4xy^2=-4 x pass through the point
View answer and explanation
Correct option: D
(−2,1)(-2,1)
Option D ((-2,1)) is correct because the chords of contact pass through a fixed point which can be found by expressing the equation of the chord of contact in the form L1+λL2=0L_1 + \lambda L_2 = 0.
345 Easy
345 of 356
Application +4 | -1
The point of the parabola y2=18x{y^2} = 18x, for which the ordinate is three times the abscissa is
View answer and explanation
Correct option: D
(2,6)\left( {2,6} \right)
Option D ((2,6)) is correct because it satisfies both the equation of the parabola and the condition that the ordinate is three times the abscissa.
346 Easy
346 of 356
Application +4 | -1
If PSQ is the focal chord of the parabola y2=8xy^2=8 x such that SP=6S P=6, then the length of SQS Q is
View answer and explanation
Correct option: C
3
Option D (x+a=0x+a=0) is correct because the tangents at the ends of a focal chord intersect on the directrix, which is x = -a.
347 Easy
347 of 356
Application +4 | -1
One of the points on the parabola y2=12x{y^2} = 12x with focal distance 12, is
View answer and explanation
Correct option: B
(9,63)(9,6\sqrt {3)}
Option B ((9,63))(9,6\sqrt {3)}) is correct because when the focal distance is 12, the point on the parabola y2=12x{y^2} = 12x is (9,63))(9,6\sqrt {3)}).
348 Easy
348 of 356
Analyzing +4 | -1
Let AA and BB be two distinct points on the parabola y2=4xy^2=4 x. If The axis of the parabola touches a circle of radius rr having ABA B as its diameter, then the slope of the line joining AA and BB can be
View answer and explanation
Correct option: B
±2r\pm \frac{2}{r}
Option B (±2r\pm \frac{2}{r}) is correct because the slope of the line joining A and B can be expressed in terms of the radius r of the circle touching the axis of the parabola.
349 Easy
349 of 356
Analyzing +4 | -1
Two parabolas CC and DD intersect at two different points, where CC is y=x2−3y=x^2-3 and DD is y=kx2y=k x^2. The intersection at which the x\mathrm{x} value is positive is designated point AA, and x=ax=a at this intersection the tangent line ll at AA to the curve DD intersects curve CC at point BB, other than AA. If xx-value of point BB is 1 , then a is equal to
View answer and explanation
Correct option: C
3
Option C (3) is correct because solving the intersection of the two parabolas and the tangent line equation leads to a cubic equation with a root at a=3.
350 Easy
350 of 356
Application +4 | -1
The coordinates of the focus of the parabola described parametrically by x=5t2+2,  y=  10t  +  4x = 5{t^2} + 2,\;y = \;10t\; + \;4 are
View answer and explanation
Correct option: A
(7,4)\left( {7,4} \right)
Option A (7,4)\left( {7,4} \right) is correct because after converting the parametric equations to Cartesian form and comparing with the standard parabola equation, the focus is found to be at (7,4).
351 Easy
351 of 356
Analyzing +4 | -1
min⁡[(x1−x2)2+(3+(1−x12)−4x2)2],∀\min \left[\left(x_1-x_2\right)^2+\left(3+\sqrt{\left(1-x_1^2\right)}-\sqrt{4 x_2}\right)^2\right], \forall x1,x2∈Rx_1, x_2 \in R, is
View answer and explanation
Correct option: B
3−223-2 \sqrt{2}
The correct answer is B (3−223-2 \sqrt{2}) because it represents the square of the shortest distance between the circle and the parabola, found using the common normal and subtracting the radius.
352 Easy
352 of 356
Application +4 | -1
If y+b=m1(x+a)y+b=m_1(x+a) and y+b=m2(x+a)y+b=m_2(x+a) are two tangents to the parabola y2=4axy^2=4 a x, then
View answer and explanation
Correct option: C
m1m2=−1m_1 m_2=-1
Option C (m1m2=−1m_1 m_2=-1) is correct because the tangents intersect on the directrix, implying they are perpendicular.
353 Easy
353 of 356
Application +4 | -1
If one end of a focal chord of the parabola y2=16x{y^2} = 16x, is at (1, 4) then the length of this focal chord is
View answer and explanation
Correct option: B
25
Option B (25) is correct because it is the length of the focal chord calculated using the formula 4acsc⁡2α4a \csc^2 \alpha after finding the slope and focus.
354 Easy
354 of 356
Application +4 | -1
The angle between the tangents drawn from the origin to the parabola y2=4  a(x−a),{y^2} = 4\;a\left( {x - a} \right), is
View answer and explanation
Correct option: A
900{90^0}
Option A (900{90^0}) is correct because the tangents drawn from the origin to the parabola intersect at right angles, as the origin lies on the directrix.
355 Easy
355 of 356
Analyzing +4 | -1
The set of points on the axis of the parabola y2=4axy^2=4 a x, from which three distinct normals can be drawn to the parabola y2=4axy^2=4 a x, is
View answer and explanation
Correct option: B
{(x,0):x>2a}\{(x, 0): x>2 a\}
Option B ({(x,0):x>2a}\{(x, 0): x>2 a\}) is correct because three distinct normals can be drawn from points on the axis of the parabola when x is greater than 2a.
356 Easy
356 of 356
Analyzing +4 | -1
The condition that the parabolas y2=4c(x−d)y^2=4 c(x-d) and y2=4axy^2=4ax have a common normal other than XX-axis (a>0,c>0)(a>0, c>0) is
View answer and explanation
Correct option: A
2a<2c+d2 a < 2 c+d
Option A (2a<2c+d2 a < 2 c+d) is correct because the condition for a common normal (other than the X-axis) is derived by equating the normal equations of the two parabolas and solving for the relationship between a, c, and d.
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