Back to PARABOLA
Your Progress
0 / 586 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • PARABOLA
Parabola practice · Mixed difficulty
Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.
Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
Take a chapter quiz →
Showing 61-90 of 586 questions
Preparing practice and saved progress…
61
Medium
61 of 586
Analyzing
+4 | -1
Chords of the parabola touch the hyperbola . The locus of the point of intersection of the tangents drawn to the parabola at the extremities of such chords is
View answer and explanation
Correct option: C
An ellipse
Option C (An ellipse) is correct because the locus of the point of intersection of tangents is an ellipse.
62
Easy
62 of 586
Analyzing
+4 | -1
If the line , touches both the curves and , then is equal to
View answer and explanation
Correct option: C
Option C () is correct because it is found by using the tangent condition for both the circle and the parabola and solving for |c|.
63
Easy
63 of 586
Application
+4 | -1
Two common tangents to the circle and parabola are
View answer and explanation
Correct option: B
Option B () is correct because by finding the tangent to the parabola and then applying the condition for tangency to the circle, we arrive at this equation.
64
Easy
64 of 586
Application
+4 | -1
The mid-point of the line joining the common points of the line and is
View answer and explanation
Correct option: B
Option B ((5,6)) is correct because it is found by using the T=S' method to find the midpoint of the chord intercepted by the line and parabola.
65
Easy
65 of 586
Analyzing
+4 | -1
The normal chord of a parabola at subtends a right angle at the
View answer and explanation
Correct option: A
Focus
Option B (A parabola with vertex at ) is correct. By eliminating the parameter 't', we obtain the equation of a parabola with vertex at (2,1).
66
Easy
66 of 586
Application
+4 | -1
From an external point , pair of tangent lines are drawn to the parabola, . If are the inclinations of these tangents with the axis of such that, , then the locus of is :
View answer and explanation
Correct option: C
Option C () is correct because it represents the locus of point P derived from the condition on the inclinations of the tangents to the parabola.
67
Medium
67 of 586
Application
+4 | -1
and are two parabolas. Equation of a tangent to the parabola at a point where it intersects the parabola is:
View answer and explanation
Correct option: C
Option A () is correct because it represents the tangent to the parabola at the point where it intersects , derived from solving the system of equations and finding the tangent.
68
Medium
68 of 586
Application
+4 | -1
The locus of a foot of perpendicular drawn to the tangent of parabola from focus, is
View answer and explanation
Correct option: A
Option B () is incorrect. Option A () is correct because the locus of the foot of the perpendicular drawn to the tangent of the parabola from the focus is the tangent at the vertex, which is the y-axis.
69
Easy
69 of 586
Application
+4 | -1
The line is a normal to the parabola , if
View answer and explanation
Correct option: A
Option A () is correct because it represents the condition for the line to be a normal to the parabola .
70
Easy
70 of 586
Remembering
+4 | -1
For the parabola , the length of the latus-rectum is
View answer and explanation
Correct option: A
8
Option A (8) is correct because for the parabola , the length of the latus rectum is , and in this case, .
71
Easy
71 of 586
Application
+4 | -1
If and are segments of a focal chord of the parabola , then
View answer and explanation
Correct option: A
Option A () is correct because the semi-latus rectum of a parabola is the harmonic mean of the segments of a focal chord, and solving for k gives the correct expression.
72
Easy
72 of 586
Analyzing
+4 | -1
The focal chords of the parabola which are tangent to the circle of radius and
centre (6,0) are perpendicular, then the radius of the circle is
centre (6,0) are perpendicular, then the radius of the circle is
View answer and explanation
Correct option: B
Units
Option A () is correct because after taking the limit and simplifying the summation, the result is .
73
Medium
73 of 586
Application
+4 | -1
If two normals to the parabola intersect at right angles then the chord joining their feet passes through a fixed point whose co-ordinates are:
View answer and explanation
Correct option: C
Option C ((-6,2)) is correct because the chord joining the feet of two perpendicular normals to a parabola passes through the focus, and the focus of the given parabola is (-6, 2).
74
Medium
74 of 586
Application
+4 | -1
The equation of the parabola with focus and directrix is given by
View answer and explanation
Correct option: A
Option A () is correct because it represents the equation of the parabola with the given focus and directrix, derived using the distance formula.
75
Easy
75 of 586
Application
+4 | -1
The equation of the parabola whose focus is and directrix , is
View answer and explanation
Correct option: A
The correct answer is A () because it is derived by applying the definition of a parabola: the distance to the focus equals the distance to the directrix.
Explore Other Chapters in MATHEMATICS
View All →
76
Easy
76 of 586
Application
+4 | -1
The vertex of the parabola is
View answer and explanation
Correct option: B
Option C ((-3, -1)) is correct because the vertex of the parabola is (-3, -1) after rewriting the equation in standard form.
77
Easy
77 of 586
Application
+4 | -1
The equation of the tangent at a point where is any parameter to the parabola , is
View answer and explanation
Correct option: A
Option A () is correct because it represents the equation of the tangent at a point to the parabola .
78
Easy
78 of 586
Analyzing
+4 | -1
The curve described parametrically by the equations , is
View answer and explanation
Correct option: B
A parabola
The correct answer is B (A parabola) because the parametric equations can be reduced to a quadratic equation representing a parabola.
79
Easy
79 of 586
Application
+4 | -1
A parabola passing through the point has its vertex at the origin and -axis as its axis. The latus rectum of the parabola is
View answer and explanation
Correct option: B
8
Option B (8) is correct because substituting the given point into the parabola equation and calculating the latus rectum yields 8.
80
Medium
80 of 586
Application
+4 | -1
The eccentricity of the conic represented by the parametric equation
View answer and explanation
Correct option: A
1
Option A is correct because the eccentricity of the conic represented by the parametric equations x = t2 - t + 1 and y = t2 + t + 1 is 1, indicating a parabola.
81
Easy
81 of 586
Application
+4 | -1
The equation of the tangents to the parabola which go through the point are
View answer and explanation
Correct option: D
Option D () is correct because these are the equations of the tangents to the parabola that pass through the given point.
82
Easy
82 of 586
Application
+4 | -1
The length of the latusrectum of the parabola , is
View answer and explanation
Correct option: C
8
Option C (8) is correct because the length of the latus rectum is the coefficient of the y-term after completing the square.
83
Easy
83 of 586
Application
+4 | -1
Locus of the poles of focal chords of a parabola is
View answer and explanation
Correct option: D
The directrix
Option D (The directrix) is correct because the locus of the poles of focal chords of a parabola is the directrix.
84
Medium
84 of 586
Application
+4 | -1
If the equation of normal to the parabola having slope -2 is given by , then value of .
View answer and explanation
Correct option: D
-12
Option B (12) is correct because the length AA' is calculated using the properties of the normal at the ends of the latus rectum of the parabola.
85
Easy
85 of 586
Analyzing
+4 | -1
The locus of the mid-point of the line segment joining a point on the parabola and the point of contact of circle drawn on focal distance of the point as diameter with the tangent at the vertex, is
View answer and explanation
Correct option: D
Option D () is correct because the locus of the midpoint is the parabola .
86
Easy
86 of 586
Application
+4 | -1
A line passing through the focus of the parabola intersects the parabola in two distinct points. If m be the slope of the line , then
View answer and explanation
Correct option: C
Option C () is correct because any line passing through the focus of a parabola intersects it at two distinct points, except for the line parallel to the axis (which has a slope of 0).
87
Easy
87 of 586
Application
+4 | -1
The equation of a tangent to the hyperbola parallel to the line is
View answer and explanation
Correct option: C
Option C () is correct because it represents a tangent to the hyperbola with a slope of 1, derived using the tangent equation formula.
88
Easy
88 of 586
Application
+4 | -1
The vertex of the parabola is
View answer and explanation
Correct option: B
Option B (()) is correct because it represents the vertex of the given parabola after rewriting the equation in standard form.
89
Medium
89 of 586
Application
+4 | -1
If is a normal to the parabola , then it touches the parabola
View answer and explanation
Correct option: A
Option A () is correct because it represents the parabola that the normal line touches, derived from the normal condition and the tangent equation.
90
Medium
90 of 586
Analyzing
+4 | -1
The possible coordinate of the point on , which is closest from is :
View answer and explanation
Correct option: A
Option A ((2,-4)) is correct because it represents the point on the parabola closest to the given circle, found by minimizing the distance between the point on the parabola and the center of the circle.
Revision notes and key takeaways
Review PARABOLA in your textbook or class notes, then use this set to check your understanding.
Showing 61-90 of 586 questions
