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JEE • MATHEMATICS • PARABOLA

Parabola practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 571-586 of 586 questions
571 Easy
571 of 586
Application +4 | -1
The chords of contact of the pairs of tangents drawn from each point on the line 2x+y=42 x+y=4 to the parabola y2=−4xy^2=-4 x pass through the point
View answer and explanation
Correct option: D
(−2,1)(-2,1)
Option D ((-2,1)) is correct because the chords of contact pass through a fixed point which can be found by expressing the equation of the chord of contact in the form L1+λL2=0L_1 + \lambda L_2 = 0.
572 Easy
572 of 586
Application +4 | -1
The point of the parabola y2=18x{y^2} = 18x, for which the ordinate is three times the abscissa is
View answer and explanation
Correct option: D
(2,6)\left( {2,6} \right)
Option D ((2,6)) is correct because it satisfies both the equation of the parabola and the condition that the ordinate is three times the abscissa.
573 Medium
573 of 586
Analyzing +4 | -1
The equation x2+4xy+4y2−3x−6y−4=0x^2+4 x y+4 y^2-3 x-6 y-4=0 represents a
View answer and explanation
Correct option: C
a pair of straight lines
Option C (a pair of straight lines) is correct because the discriminant Δ=0\Delta = 0 and h2=abh^2 = ab, indicating a pair of parallel straight lines.
574 Easy
574 of 586
Application +4 | -1
If PSQ is the focal chord of the parabola y2=8xy^2=8 x such that SP=6S P=6, then the length of SQS Q is
View answer and explanation
Correct option: C
3
Option D (x+a=0x+a=0) is correct because the tangents at the ends of a focal chord intersect on the directrix, which is x = -a.
575 Easy
575 of 586
Application +4 | -1
One of the points on the parabola y2=12x{y^2} = 12x with focal distance 12, is
View answer and explanation
Correct option: B
(9,63)(9,6\sqrt {3)}
Option B ((9,63))(9,6\sqrt {3)}) is correct because when the focal distance is 12, the point on the parabola y2=12x{y^2} = 12x is (9,63))(9,6\sqrt {3)}).
576 Easy
576 of 586
Analyzing +4 | -1
Let AA and BB be two distinct points on the parabola y2=4xy^2=4 x. If The axis of the parabola touches a circle of radius rr having ABA B as its diameter, then the slope of the line joining AA and BB can be
View answer and explanation
Correct option: B
±2r\pm \frac{2}{r}
Option B (±2r\pm \frac{2}{r}) is correct because the slope of the line joining A and B can be expressed in terms of the radius r of the circle touching the axis of the parabola.
577 Easy
577 of 586
Analyzing +4 | -1
Two parabolas CC and DD intersect at two different points, where CC is y=x2−3y=x^2-3 and DD is y=kx2y=k x^2. The intersection at which the x\mathrm{x} value is positive is designated point AA, and x=ax=a at this intersection the tangent line ll at AA to the curve DD intersects curve CC at point BB, other than AA. If xx-value of point BB is 1 , then a is equal to
View answer and explanation
Correct option: C
3
Option C (3) is correct because solving the intersection of the two parabolas and the tangent line equation leads to a cubic equation with a root at a=3.
578 Easy
578 of 586
Application +4 | -1
The coordinates of the focus of the parabola described parametrically by x=5t2+2,  y=  10t  +  4x = 5{t^2} + 2,\;y = \;10t\; + \;4 are
View answer and explanation
Correct option: A
(7,4)\left( {7,4} \right)
Option A (7,4)\left( {7,4} \right) is correct because after converting the parametric equations to Cartesian form and comparing with the standard parabola equation, the focus is found to be at (7,4).
579 Hard
579 of 586
Application +4 | -1
If y=2x+3y = 2x + 3 is a tangent to the parabola, y2=24  x,{y^2} = 24\;x, then its distance from the parallel normal is
View answer and explanation
Correct option: C
15515\sqrt 5
Option C (15515\sqrt 5) is correct because it is the distance between the given tangent and its parallel normal to the parabola.
580 Easy
580 of 586
Analyzing +4 | -1
min⁡[(x1−x2)2+(3+(1−x12)−4x2)2],∀\min \left[\left(x_1-x_2\right)^2+\left(3+\sqrt{\left(1-x_1^2\right)}-\sqrt{4 x_2}\right)^2\right], \forall x1,x2∈Rx_1, x_2 \in R, is
View answer and explanation
Correct option: B
3−223-2 \sqrt{2}
The correct answer is B (3−223-2 \sqrt{2}) because it represents the square of the shortest distance between the circle and the parabola, found using the common normal and subtracting the radius.
581 Easy
581 of 586
Application +4 | -1
If y+b=m1(x+a)y+b=m_1(x+a) and y+b=m2(x+a)y+b=m_2(x+a) are two tangents to the parabola y2=4axy^2=4 a x, then
View answer and explanation
Correct option: C
m1m2=−1m_1 m_2=-1
Option C (m1m2=−1m_1 m_2=-1) is correct because the tangents intersect on the directrix, implying they are perpendicular.
582 Medium
582 of 586
Analyzing +4 | -1
Three distinct normals to the parabola y2=x{y^2} = x are drawn through a point (c,0)\left( {c,0} \right), then
View answer and explanation
Correct option: C
c>12c > \frac{1}{2}
Option C (c>12c > \frac{1}{2}) is correct because for three distinct normals to be drawn to the parabola, the x-coordinate of the point must be greater than half the latus rectum.
583 Easy
583 of 586
Application +4 | -1
If one end of a focal chord of the parabola y2=16x{y^2} = 16x, is at (1, 4) then the length of this focal chord is
View answer and explanation
Correct option: B
25
Option B (25) is correct because it is the length of the focal chord calculated using the formula 4acsc⁡2α4a \csc^2 \alpha after finding the slope and focus.
584 Easy
584 of 586
Application +4 | -1
The angle between the tangents drawn from the origin to the parabola y2=4  a(x−a),{y^2} = 4\;a\left( {x - a} \right), is
View answer and explanation
Correct option: A
900{90^0}
Option A (900{90^0}) is correct because the tangents drawn from the origin to the parabola intersect at right angles, as the origin lies on the directrix.
585 Easy
585 of 586
Analyzing +4 | -1
The set of points on the axis of the parabola y2=4axy^2=4 a x, from which three distinct normals can be drawn to the parabola y2=4axy^2=4 a x, is
View answer and explanation
Correct option: B
{(x,0):x>2a}\{(x, 0): x>2 a\}
Option B ({(x,0):x>2a}\{(x, 0): x>2 a\}) is correct because three distinct normals can be drawn from points on the axis of the parabola when x is greater than 2a.
586 Easy
586 of 586
Analyzing +4 | -1
The condition that the parabolas y2=4c(x−d)y^2=4 c(x-d) and y2=4axy^2=4ax have a common normal other than XX-axis (a>0,c>0)(a>0, c>0) is
View answer and explanation
Correct option: A
2a<2c+d2 a < 2 c+d
Option A (2a<2c+d2 a < 2 c+d) is correct because the condition for a common normal (other than the X-axis) is derived by equating the normal equations of the two parabolas and solving for the relationship between a, c, and d.
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