Skip to main content
Back to PAIR OF STRAIGHT LINES

Your Progress

0 / 59 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • PAIR OF STRAIGHT LINES

Pair of straight lines practice · Medium

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 31-59 of 59 questions

Preparing practice and saved progress…

31 Medium
31 of 59
Application +4 | -1
If the line L: x5+yb=1\frac{x}{5}+\frac{y}{b}=1 passes through (13,32)(13,32) and line K:xc+y3=1\mathrm{K}: \frac{x}{c}+\frac{y}{3}=1 is parallel to L\mathrm{L}, then the distance between L\mathrm{L} and K=…….\mathrm{K}=\ldots \ldots ..
View answer and explanation
Correct option: D
2317\frac{23}{\sqrt{17}}
Option D (2317\frac{{23}}{{\sqrt{{17}}}}) is correct because it represents the distance between the two parallel lines L and K.
32 Medium
32 of 59
Application +4 | -1
Area of the parallelogram whose sides are xcos⁡α+ysin⁡α=p  xcos⁡α+ysin⁡α=qx \cos \alpha+y \sin \alpha=p \,\,x \cos \alpha+y \sin \alpha=q, xcos⁡β+ysin⁡β=rx \cos \beta+y \sin \beta=r and xcos⁡β+ysin⁡β=sx \cos \beta+y \sin \beta=s is
View answer and explanation
Correct option: A
±(p−q)(r−s)cosec⁡(α−β)\pm(p-q)(r-s) \operatorname{cosec}(\alpha-\beta)
Option A (x2+y2−hx−ky=0x^2+y^2-hx-ky=0) is correct because it represents the locus of the foot of the perpendicular from the origin to a line passing through (h,k).
33 Medium
33 of 59
Application +4 | -1
Which of the following pairs of straight lines intersects at right angles?
View answer and explanation
Correct option: A
2x2=y(x+2y)2 x^2=y(x+2 y)
Option A (2x2=y(x+2y)2x^2 = y(x+2y)) is correct because the sum of the coefficients of x2x^2 and y2y^2 is zero, which is the condition for lines intersecting at right angles.
34 Medium
34 of 59
Application +4 | -1
The slope of a line is 3 times the slope of the other line and the tangent of the angle between them is 4/134 / 13, sum of their slopes is equal to
View answer and explanation
Correct option: D
8
Option D (8) is correct because solving the tangent of the angle between two lines equation leads to two possible values for the slopes, and one of them results in the sum of slopes being 8.
35 Medium
35 of 59
Application +4 | -1
If one of the lines given by ax2+2hxy+by2=0a x^2+2 h x y+b y^2=0 bisects the angle between coordinate axes, then
View answer and explanation
Correct option: A
(a+b)2=4h2(a+b)^2=4 h^2
Option A ((a+b)2=4h2(a+b)^2=4 h^2) is correct because it represents the condition when one of the lines bisects the angle between the coordinate axes.
36 Medium
36 of 59
Application +4 | -1
One diagonal of a square is the portion of the line 3x+2y=123 x+2 y=12 intercepted between the axes. The coordinates of the extremity of the other diagonals not lying in the first quadrant are
View answer and explanation
Correct option: C
(−1,1)(-1,1)
Option C ((-1,1)) is correct because it satisfies the condition that the other diagonal's extremity lies on a line derived from the square's properties and the given diagonal.
37 Medium
37 of 59
Application +4 | -1
The angle between the lines joining the origin to the points of intersection of the line 3x+y=2\sqrt{3} x+y=2 and the curve y2−x2=4y^2-x^2=4 is
View answer and explanation
Correct option: C
tan⁡−1(32)\tan ^{-1}\left(\frac{\sqrt{3}}{2}\right)
Option C (tan⁡−1(32)\tan ^{-1}(\frac{\sqrt{3}}{2})) is correct because it is obtained by homogenizing the equation and then using the formula for the angle between the lines.
38 Medium
38 of 59
Analyzing +4 | -1
If α,β>0\alpha, \beta>0 and α<β\alpha<\beta and αx2+4γxy+βy2+4p(x+y+1)=0\alpha x^2+4 \gamma x y+\beta y^2+4 p(x+y+1)=0 represents a pair of straight lines, then
View answer and explanation
Correct option: D
p≤αp \leq \alpha or p≥βp \geq \beta
Option D (p≤αp \leq \alpha or p≥βp \geq \beta) is correct because the condition for the equation to represent a pair of straight lines leads to the inequality (p−α)(p−β)≥0(p-\alpha)(p-\beta) \geq 0, which implies p≤αp \leq \alpha or p≥βp \geq \beta.
39 Medium
39 of 59
Application +4 | -1
The equation of the line which bisects the obtuse angle between the lines x−2y+4=0x-2 y+4=0 and 4x−3y+2=04 x-3 y+2=0, is
View answer and explanation
Correct option: A
(4−5)x−(3−25)y+(2−45)=0(4-\sqrt{5}) x-(3-2 \sqrt{5}) y+(2-4 \sqrt{5})=0
Option A ((4−5)x−(3−25)y+(2−45)=0(4-\sqrt{5}) x-(3-2 \sqrt{5}) y+(2-4 \sqrt{5})=0) is correct because it represents the equation of the bisector of the obtuse angle between the two given lines, derived using the angle bisector formula and considering the condition for obtuse angle.
40 Medium
40 of 59
Analyzing +4 | -1
A light ray coming along the line 3x+4y=53 x+4 y=5, gets reflected from the line ax+by=1a x+b y=1 and goes along the line 5x−12y=105 x-12 y=10, then
View answer and explanation
Correct option: C
a=64115,b=−8115a=\frac{64}{115}, b=-\frac{8}{115}
Option C (a=64115,b=−8115a=\frac{64}{115}, b=-\frac{8}{115}) is correct because the line ax+by=1ax + by = 1 must be one of the angle bisectors of the given lines.
41 Medium
41 of 59
Application +4 | -1
If y=mxy=m x be one of the bisectors of the angle between the lines ax2−2hxy+by2=0a x^2-2 h x y+b y^2=0, then
View answer and explanation
Correct option: C
h(1−m2)+m(a−b)=0h\left(1-m^2\right)+m(a-b)=0
Option C, h(1−m2)+m(a−b)=0h(1-m^2)+m(a-b)=0, is correct because it represents the condition when y=mxy=mx is one of the angle bisectors of the given pair of lines.
42 Medium
42 of 59
Understanding +4 | -1
Mixed term xyx y is to be removed from the general equation ax2+by2+2hxy+2gx+2fy+c=0a x^2+b y^2+2 h x y+2 g x+2 f y+c=0, one should rotate the axes through an angle θ\theta given by tan⁡2θ=\tan 2 \theta=
View answer and explanation
Correct option: D
2ha−b\frac{2 h}{a-b}
Option D (2ha−b\frac{{2h}}{{a-b}}) is correct because it represents the formula for the angle of rotation required to eliminate the xy term in a general conic equation.
43 Medium
43 of 59
Application +4 | -1
If a,x1,x2a, x_1, x_2 are in G.P. with common ratio rr, and b,y1,y2b, y_1, y_2 are in G.P. with common ratio ss where s−r=2s-r=2, then the area of the triangle with vertices (a,b)(a, b), (x1,y1)\left(x_1, y_1\right) and (x2,y2)\left(x_2, y_2\right) is
View answer and explanation
Correct option: A
∣ab(r2−1)∣\left|a b\left(r^2-1\right)\right|
Option C ((0,0)) is correct because the triangle formed by the lines is a right-angled triangle at the origin, and the orthocenter of a right-angled triangle is the vertex at the right angle.
44 Medium
44 of 59
Analyzing +4 | -1
If the system of equations ax+hy+g=0,hx+by+f=0a x+h y+g=0, h x+b y+f=0 and ax2+2hxy+by2+2gx+2fy+c+ta x^{2}+2 h x y+b y^{2}+2 g x+2 f y+c+t =0=0 has a unique solution, then
View answer and explanation
Correct option: C
t=abc+2fgh−af2−bg2−ch2h2−abt=\frac{a b c+2 f g h-a f^{2}-b g^{2}-c h^{2}}{h^{2}-a b}
Option C is correct because after rationalizing and simplifying the limit, the expression converges to 1/(4√2) as y approaches infinity.
45 Medium
45 of 59
Application +4 | -1
The value of λ\lambda so that 3x2+7xy+λy2+5x+5y+2=03 x^2+7 x y+\lambda y^2+5 x+5 y+2=0 represents a pair of straight lines is
View answer and explanation
Correct option: C
2
Option C (2) is correct because when λ=2\lambda = 2, the determinant of the matrix formed by the coefficients of the given equation is zero, indicating that the equation represents a pair of straight lines.
46 Medium
46 of 59
Application +4 | -1
Given, a straight lines and a fixed point OO, a straight line is drawn through OO meeting lines in the points R1,R2,R3,…,RnR_1, R_2, R_3, \ldots, R_n and on it a point RR is taken such that nOR=1OR1+1OR2+…+1ORn\frac{n}{O R}=\frac{1}{O R_1}+\frac{1}{O R_2}+\ldots+\frac{1}{O R_n}, then the locus of RR is
View answer and explanation
Correct option: A
a straight line
Option A (a straight line) is correct because the locus of R, derived from the given harmonic mean condition, results in a linear equation.
47 Medium
47 of 59
Analyzing +4 | -1
The equation 3x2+7xy+2y2+5x+5y+2=03 x^2+7 x y+2 y^2+5 x+5 y+2=0 represents
View answer and explanation
Correct option: A
a pair of straight lines
Option A (a pair of straight lines) is correct because the discriminant abc+2fgh−af2−bg2−ch2=0abc + 2fgh - af^2 - bg^2 - ch^2 = 0 for the given equation.
48 Medium
48 of 59
Application +4 | -1
The straight lines 7x−2y+10=07 x-2 y+10=0 and 7x+2y−10=07 x+2 y-10=0 forms and isosceles triangle with the line y=2y=2, area of this triangle is equal to
View answer and explanation
Correct option: B
107\frac{10}{7} squnits
Option C (187\frac{18}{7} sq units) is correct because the area of the isosceles triangle is calculated using the base and height, which are determined by the intersection points of the lines.
49 Medium
49 of 59
Application +4 | -1
If the lines x=k;k=1,2…,nx=k ; k=1,2 \ldots, n meet the line y=3x+4y=3 x+4 at the points Ak(xk,yk),k=1,2,…,nA_k\left(x_k, y_k\right), k=1,2, \ldots, n then the ordinate of the centre of Mean position of the points AkA_k, k=1,2,…,nk=1,2, \ldots, n is
View answer and explanation
Correct option: B
3n+112\frac{3 n+11}{2}
Option B (3n+112\frac{{3 n+11}}{{2}}) is correct because it represents the ordinate of the center of the mean position of the points AkA_k, calculated using the summation of the ordinates divided by nn.
50 Medium
50 of 59
Application +4 | -1
The equation of the lines which are passing through the origin and which are perpendicular to the pair of straight lines x2−3xy+2y2=0x^2-3 x y+2 y^2=0 is
View answer and explanation
Correct option: C
2x2+3xy+y2=02 x^2+3 x y+y^2=0
Option C (2x2+3xy+y2=02 x^2+3 x y+y^2=0) is correct because it represents the equation of the lines passing through the origin and perpendicular to the given pair of straight lines.
51 Medium
51 of 59
Application +4 | -1
The area of the triangle formed by the lines 4x2−9xy−9y2=04 x^2-9 x y-9 y^2=0 and x=2x=2 is equal to
View answer and explanation
Correct option: C
103\frac{10}{3} sq units
Option C (103\frac{10}{3} sq units) is correct because it is the area of the triangle formed by the given lines, calculated using the intersection points.
52 Medium
52 of 59
Analyzing +4 | -1
If the pairs of lines x2+2xy+λy2=0x^2+2 x y+\lambda y^2=0 and λx2+2xy+y2=0\lambda x^2+2 x y+y^2=0 have exactly one line in common, then the joint equation of the other two lines is given by
View answer and explanation
Correct option: B
3x2+10xy+3y2=03 x^2+10 x y+3 y^2=0
Option B (3x2+10xy+3y2=03 x^2+10 x y+3 y^2=0) is correct because it represents the joint equation of the other two lines after finding the common line and the value of λ.
53 Medium
53 of 59
Analyzing +4 | -1
If the straight lines ax2+2hxy+by2a x^2+2 h x y+b y^2 +2gx+2fy+c=0+2 g x+2 f y+c=0 intersect on the XX-axis, then
View answer and explanation
Correct option: C
af=gha f=g h
Option C (af=gha f=g h) is correct because it represents the condition when the lines intersect on the X-axis.
54 Medium
54 of 59
Application +4 | -1
Two lines represented by the equation x2−y2−2x+1=0x^2-y^2-2 x+1=0 are rotated about the point (1,0)(1,0), the line making the bigger angle with the positive direction of the xx-axis being turned by 45∘45^{\circ} in the clockwise sense and the other line being turned by 15∘15^{\circ} in the anticlockwise sense. The combined equation of the pair of lines in their new position, is
View answer and explanation
Correct option: B
3x2−xy−23x+y+3=0\sqrt{3} x^2-x y-2 \sqrt{3} x+y+\sqrt{3}=0
Option B (3x2−xy−23x+y+3=0\sqrt{3} x^2-x y-2 \sqrt{3} x+y+\sqrt{3}=0) is correct because it represents the combined equation of the rotated lines after adjusting their angles with the x-axis.
55 Medium
55 of 59
Application +4 | -1
The equation x2−3xy+λy2+3x−5y+2=0x^2-3 x y+\lambda y^2+3 x-5 y+2=0 when λ\lambda is a real number, represents a pair of straight lines. If θ\theta is the angle between the lines, then cosec⁡2θ=\operatorname{cosec}^2 \theta=
View answer and explanation
Correct option: C
10
Option C (10) is correct because by substituting λ = 2 into the equation and using the formula for the angle between lines, we find that cosec⁡2θ=10\operatorname{cosec}^2 \theta = 10.
56 Medium
56 of 59
Application +4 | -1
Distance between the lines represented by the equation x2+23xy+3y2−3x−33y−4=0x^2+2 \sqrt{3} x y+3 y^2-3 x-3 \sqrt{3} y-4=0 is
View answer and explanation
Correct option: A
5/25/2
Option A (5/2) is correct because the lines are parallel, and the distance is calculated using the formula for distance between parallel lines.
57 Medium
57 of 59
Application +4 | -1
If the distance of two lines passing through origin from the point (x1,y1)\left(x_1, y_1\right) is 'dd', then the equation of lines is
View answer and explanation
Correct option: A
(xy1−yx1)2=d2(x2+y2)\left(x y_1-y x_1\right)^2=d^2\left(x^2+y^2\right)
Option A ((xy1−yx1)2=d2(x2+y2)x y_1-y x_1)^2=d^2(x^2+y^2)) is correct because it represents the equation of the pair of lines passing through the origin, given the distance 'd' from the point (x1, y1).
58 Medium
58 of 59
Application +4 | -1
A line is drawn perpendicular to the line y=5xy=5 x, meeting the coordinate axes at AA and BB. If the area of △OAB\triangle O A B is 10 sq units, where OO is the origin, then equation of drawn line is
View answer and explanation
Correct option: A
x+5y=10x+5 y=10
The correct answer is x+5y=10x+5y=10 because it represents a line perpendicular to y=5xy=5x that forms a triangle with the axes having an area of 10 square units.
59 Medium
59 of 59
Analyzing +4 | -1
If the lines joining origin to the points of intersection of the line fx−gy=λf x-g y=\lambda and the curve x2+hxy−y2+gx+fy=0x^2+h x y-y^2+g x+f y=0 are mutually perpendicular, then
View answer and explanation
Correct option: D
λ\lambda may have any value
Option D (λ\lambda may have any value) is correct because the condition for perpendicularity is always satisfied regardless of the value of λ\lambda.
Revision notes and key takeaways

Review PAIR OF STRAIGHT LINES in your textbook or class notes, then use this set to check your understanding.

Showing 31-59 of 59 questions

Your practice

0 / 59 answered · 59 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Answer feedback and difficulty

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.