JEE MATHEMATICS MCQ: PAIR OF STRAIGHT LINES

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Application +4 | -1

Area of the parallelogram whose sides are

x \cos \alpha+y \sin \alpha=p \,\,x \cos \alpha+y \sin \alpha=q

x \cos \beta+y \sin \beta=r

and

x \cos \beta+y \sin \beta=s

View answer and explanation

Correct option: A

\pm(p-q)(r-s) \operatorname{cosec}(\alpha-\beta)

Option A (

x^2+y^2-hx-ky=0

) is correct because it represents the locus of the foot of the perpendicular from the origin to a line passing through (h,k).

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