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JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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151 Easy
151 of 746
Application +4 | -1
The value of 2∫sin⁡x dxsin⁡(x−π4)\sqrt{2} \int \frac{\sin x \,d x}{\sin \left(x-\frac{\pi}{4}\right)} is
View answer and explanation
Correct option: B
x+log⁡∣sin⁡(x−π4)∣+Cx+\log \left|\sin \left(x-\frac{\pi}{4}\right)\right|+C
Option B (x+log⁡∣sin⁡(x−π4)∣+Cx+\log \left|\sin \left(x-\frac{{\pi}}{{4}}\right)\right|+C) is correct because it represents the result of the given integral after applying substitution and simplification.
152 Easy
152 of 746
Application +4 | -1
The value of ∫dxx+a2−x2\int \frac{d x}{x+\sqrt{a^2-x^2}}, is equal to
View answer and explanation
Correct option: A
12sin⁡−1(xa)+12log⁡∣x+a2−x2∣+C1\frac{1}{2} \sin ^{-1}\left(\frac{x}{a}\right)+\frac{1}{2} \log \left|x+\sqrt{a^2-x^2}\right|+C_1
Option A (12sin⁡−1(xa)+12log⁡∣x+a2−x2∣+C1\frac{{1}}{{2}} \sin ^{-1}(\frac{{x}}{{a}})+\frac{{1}}{{2}} \log |x+\sqrt{{a^2-x^2}}|+C_1) is correct because the integral evaluates to this expression after a trigonometric substitution and simplification.
153 Easy
153 of 746
Application +4 | -1
∫exdxcos⁡hx+sin⁡hx\int \frac{e^x d x}{\cos h x+\sin h x} is
View answer and explanation
Correct option: B
x+cx+c
Option B is correct because simplifying the denominator using the definitions of cosh x and sinh x leads to a simple exponential function, which integrates to x + c.
154 Easy
154 of 746
Application +4 | -1
If In=∫sin⁡n  x dx{I_n} = \int {\sin ^n}\,\,x\,dx,then nIn  −  (n−1)In−2n{I_n}\,\, - \,\,\left( {n - 1} \right){I_{n - 2}} equals
View answer and explanation
Correct option: C
−  sin⁡n−1  x  cos⁡x- \,\,{\sin ^{n - 1}}\,\,x\,\,\cos x
Option C is correct because it is the result of applying integration by parts to the integral of sin^n(x).
155 Easy
155 of 746
Application +4 | -1
The value of ∫dx4x−3−x2\int \frac{d x}{\sqrt{4 x-3-x^2}} is equal to
View answer and explanation
Correct option: D
sin⁡−1(x−2)+C\sin ^{-1}(x-2)+C
Option D (sin⁡−1(x−2)+C\sin ^{-1}(x-2)+C) is correct because it is the result of completing the square and using the standard integral formula for arcsine.
156 Easy
156 of 746
Analyzing +4 | -1
∫  x+  x23+  x6x (1+  x3  dx\int \,\,\frac{{x + \,\,\sqrt[3]{{{x^2}}} + \,\,\sqrt[6]{x}}}{{x\,(1 + \,\,\sqrt[3]{x}}}\,\,dx
View answer and explanation
Correct option: A
32  x2/3+  6  tan⁡−1  x1/6+  C\frac{3}{2}\,\,{x^{2/3}} + \,\,6\,\,{\tan ^{ - 1}}\,\,{x^{1/6}} + \,\,C
Option A (32 x2/3+ 6 tan⁡−1 x1/6+ C\frac{3}{2}\,{x^{2/3}} + \,6\,{\tan ^{ - 1}}\,{x^{1/6}} + \,C) is correct because after substitution and simplification, the integral can be easily solved.
157 Easy
157 of 746
Application +4 | -1
∫1log⁡a(axcos⁡ax)dx=\int \frac{1}{\log a}\left(a^x \cos a^x\right) d x=
View answer and explanation
Correct option: C
1(log⁡a)2sin⁡ax+c\frac{1}{(\log a)^2} \sin a^x+c
Option C (1(log⁡a)2sin⁡ax+c\frac{1}{(\log a)^2} \sin a^x+c) is correct because it is the result of two substitutions and applying the integral of cosine.
158 Easy
158 of 746
Application +4 | -1
The integral ∫1(x−1)3(x+2)54  dx\int {\frac{1}{{\sqrt[4]{{{{(x - 1)}^3}{{(x + 2)}^5}}}}}} \,\,dx is equal to (where CC is a constant for integration)
View answer and explanation
Correct option: C
43(x−1x+2)1/4+C\frac{4}{3}{\left( {\frac{{x - 1}}{{x + 2}}} \right)^{1/4}} + C
Option C (43(x−1x+2)1/4+C\frac{4}{3}{\left( {\frac{{x - 1}}{{x + 2}}} \right)^{1/4}} + C) is correct because it is the result of the integration after a suitable substitution.
159 Easy
159 of 746
Application +4 | -1
The value of ∫cos⁡5x+cos⁡4x1−2cos⁡3xdx\int \frac{\cos 5 x+\cos 4 x}{1-2 \cos 3 x} d x is
View answer and explanation
Correct option: B
−12sin⁡2x−sin⁡x+c-\frac{1}{2} \sin 2 x-\sin x+c
Option B (−12sin⁡2x−sin⁡x+c-\frac{1}{2} \sin 2 x-\sin x+c) is correct because after simplifying the integrand using trigonometric identities, the integral can be easily evaluated.
160 Easy
160 of 746
Application +4 | -1
∫1+tan⁡xx+log⁡sec⁡xdx\int \frac{1+\tan x}{x+\log \sec x} d x is equal to
View answer and explanation
Correct option: A
log⁡(x+log⁡sec⁡x)+c\log (x+\log \sec x)+c
Option A is correct because the derivative of x+log⁡(sec⁡x)x + \log(\sec x) is 1+tan⁡x1 + \tan x, making the integral a simple logarithmic form.
161 Easy
161 of 746
Analyzing +4 | -1
If ∫  cos⁡  4x  +  1cos⁡  x  −  tan⁡  x    dx=A  cos⁡  4x  +  B\int \,\,\frac{{\cos \,\,4x\,\, + \,\,1}}{{\cos \,\,x\,\, - \,\,\tan \,\,x}}\,\,\;dx = A\,\,\cos \,\,4x\,\, + \,\,B,then
View answer and explanation
Correct option: B
A=−  18A = - \,\,\frac{1}{8}
The correct answer is B (A=−  18A = - \,\,\frac{1}{8}) because after simplification and integration, the coefficient of cos⁡4x\cos 4x is -1/8.
162 Easy
162 of 746
Application +4 | -1
∫elog⁡5xdx=\int e^{\log_5 x} d x=
View answer and explanation
Correct option: B
xlog⁡55elog⁡55e\frac{x^{\log_5 5e}}{\log _5 5 e}
Option B is correct because the integral of elog⁡5xe^{\log_5 x} simplifies to xlog⁡55elog⁡55e\frac{x^{\log_5 5e}}{\log_5 5 e} using properties of logarithms and integration.
163 Easy
163 of 746
Application +4 | -1
If ∫g  (x)  dx=g(x)\int g\,\,\left( x \right)\,\,dx = g\left( x \right), then ∫g  (x)  {f(x)  +  f′(x)}dx\int g\,\,\left( x \right)\,\,\left\{ {f\left( x \right)\,\, + \,\,f'\left( x \right)} \right\}dx is equal to
View answer and explanation
Correct option: C
g  (x)  f(x)  +  Cg\,\,\left( x \right)\,\,f\left( x \right)\,\, + \,\,C
Option C (g  (x)  f(x)  +  Cg\,\,( x )\,\,f( x )\,\, + \,\,C) is correct because it is derived by using integration by parts, where the integral of g(x) is g(x) itself.
164 Easy
164 of 746
Application +4 | -1
For what value of aa and bb, the equation ∫dx1+sin⁡x=tan⁡(x2+a)+b holds good.\int \frac{d x}{1+\sin x}=\tan \left(\frac{x}{2}+a\right)+b \text { holds good.}
View answer and explanation
Correct option: C
a=−π4,ba=-\frac{\pi}{4}, b is any arbitrary constant
Option C (a=−π4,ba=-\frac{\pi}{4}, b is any arbitrary constant) is correct because the integral of dx1+sin⁡x\frac{dx}{1+\sin x} simplifies to tan⁡(x2−π4)+c\tan(\frac{x}{2} - \frac{\pi}{4}) + c.
165 Easy
165 of 746
Application +4 | -1
∫e2x2+ln⁡xdx\int e^{2 x^2+\ln x} d x is equal to
View answer and explanation
Correct option: A
e2x24+c\frac{e^{2 x^2}}{4}+c
Option A (e2x24+c\frac{e^{2 x^2}}{4}+c) is correct because it is the result of integrating the given expression using substitution.
166 Easy
166 of 746
Application +4 | -1
If ∫1x2+2x+2dx=f(x)+C\int \frac{1}{x^2+2 x+2} d x=f(x)+C, then f(x)=f(x)=
View answer and explanation
Correct option: A
tan⁡−1(x+1)\tan ^{-1}(x+1)
Option A, tan⁡−1(x+1)\tan^{-1}(x+1), is the correct answer because the integral of 1x2+2x+2\frac{1}{x^2+2x+2} is indeed tan⁡−1(x+1)+C\tan^{-1}(x+1) + C.
167 Easy
167 of 746
Application +4 | -1
∫  log⁡  x3x    dx\int \,\,\frac{{\log \,\,\sqrt x }}{{3x}}\,\,\;dxis equal to
View answer and explanation
Correct option: A
13  (log⁡   x)2+c\frac{1}{3}\,\,{\left( {\log \,\,\,\sqrt x } \right)^2} + c
Option A (13 (log⁡  x)2+c\frac{1}{3}\,{\left( {\log \,\,\sqrt x } \right)^2} + c) is correct because it results from direct integration after substitution.
168 Easy
168 of 746
Analyzing +4 | -1
The value of ∫esec⁡x  ⋅  sec⁡3  x  (sin⁡2  x  +  cos⁡  x  +  sin⁡  x  +  sin⁡  x  cos⁡  x)dx\int {e^{\sec x}}\,\, \cdot \,\,{\sec ^3}\,\,x\,\,\left( {{{\sin }^2}\,\,x\,\, + \,\,\cos \,\,x\,\, + \,\,\sin \,\,x\,\, + \,\,\sin \,\,x\,\,\cos \,\,x} \right)dx is
View answer and explanation
Correct option: C
esec⁡x  (sec⁡  x  +  tan⁡  x)  +  C{e^{\sec x}}\,\,\left( {\sec \,\,x\,\, + \,\,\tan \,\,x} \right)\,\, + \,\,C
Option C (esec⁡x  (sec⁡  x  +  tan⁡  x)  +  C{e^{\sec x}}\,\,\left( {\sec \,\,x\,\, + \,\,\tan \,\,x} \right)\,\, + \,\,C) is correct because it results from integrating the given expression using integration by parts and simplification.
169 Easy
169 of 746
Application +4 | -1
If I=∫−32(∣x+1∣+∣x+2∣+∣x−1∣)dx\mathrm{I}=\int_{-3}^2(|\mathrm{x}+1|+|\mathrm{x}+2|+|\mathrm{x}-1|) \mathrm{dx}, then I\mathrm{I} equals:
View answer and explanation
Correct option: A
312\frac{31}{2}
Option A is correct because the integral is solved by using a trigonometric substitution, which simplifies the expression and allows for direct integration.
170 Easy
170 of 746
Application +4 | -1
∫sin⁡xdx(a+bcos⁡x)2=\int \frac{\sin x d x}{(a+b \cos x)^2}=
View answer and explanation
Correct option: B
1b(a+bcos⁡x)+c\frac{1}{b(a+b \cos x)}+c
Option B (1b(a+bcos⁡x)+c\frac{1}{b(a+b \cos x)}+c) is correct because it is the result of a u-substitution and applying the power rule for integration.
171 Easy
171 of 746
Application +4 | -1
If ∫  2x1  −  4x  dx=K  sin⁡−1  (2x)  +  C\int \,\,\frac{{{2^x}}}{{\sqrt {1\,\, - \,\,{4^x}} }}\,\,dx = K\,\,{\sin ^{ - 1}}\,\,\left( {{2^x}} \right)\,\, + \,\,C, then KK is equal to
View answer and explanation
Correct option: D
1log⁡  2\frac{1}{{\log \,\,2}}
Option D (1log⁡ 2\frac{1}{{\log \,2}}) is correct because it results from applying a u-substitution and integrating the arcsine function.
172 Easy
172 of 746
Application +4 | -1
∫(3x2tan⁡1x−xsec⁡21x)dx\int\left(3 x^2 \tan \frac{1}{x}-x \sec ^2 \frac{1}{x}\right) d x is equal to
View answer and explanation
Correct option: C
x3tan⁡1x+cx^3 \tan \frac{1}{x}+c
Option C (x3tan⁡1x+cx^3 \tan \frac{{1}}{{x}}+c) is correct because the integral is solved using integration by parts and simplification.
173 Easy
173 of 746
Analyzing +4 | -1
If ∫dxx3(1+x6)2/3=xf(x)(1+x6)13+C\int \frac{{dx}}{{{x^3}{{(1 + {x^6})}^{2/3}}}} = xf(x){(1 + {x^6})^{\frac{1}{3}}} + C where, CC is a constant of integration, then the function f(x)f(x) is equal to
View answer and explanation
Correct option: B
−12x3- \frac{1}{{2{x^3}}}
Option B (−12x3- \frac{1}{{2{x^3}}}) is correct because after performing the integration and comparing with the given form, f(x)f(x) is found to be −12x3- \frac{1}{{2{x^3}}}.
174 Easy
174 of 746
Analyzing +4 | -1
If ∫  2 1+sin⁡  x   dx=− 4  cos⁡  (ax+  b)+c\int \,\,\sqrt 2 \,\sqrt {1 + \sin \,\,x\,\;} dx = - \,4\,\,\cos \,\,\left( {ax + \,\,b} \right) + c, then the value of a,  ba,\,\,b are respectively
View answer and explanation
Correct option: A
12,  π4\frac{1}{2},\,\,\frac{\pi }{4}
Option A (12, π4\frac{1}{2},\,\frac{\pi }{4}) is correct because after simplifying the integral, the values of a and b can be identified by comparing the result with the given form.
175 Easy
175 of 746
Application +4 | -1
If ∫f(x)cos⁡xdx=12f2(x)+c\int f(x) \cos x d x=\frac{1}{2} f^2(x)+c, then f(x)f(x) can be
View answer and explanation
Correct option: D
sin⁡x\sin x
Option D (sin⁡x\sin x) is correct because when f(x)=sin⁡xf(x) = \sin x, the integral ∫f(x)cos⁡xdx\int f(x) \cos x dx results in 12f2(x)+c\frac{1}{2}f^2(x) + c.
176 Easy
176 of 746
Application +4 | -1
If I=∫etan⁡−1x(1+x2){(sec⁡−11+x2)2+cos⁡−1(1−x21+x2)}dx.I=\int \frac{e^{\tan ^{-1}} x}{\left(1+x^2\right)}\left\{\left(\sec ^{-1} \sqrt{1+x^2}\right)^2+\cos ^{-1}\left(\frac{1-x^2}{1+x^2}\right)\right\} d x. Then,
View answer and explanation
Correct option: B
I=etan⁡−1x(sec⁡−11+x2)2+CI=e^{\tan ^{-1} x}\left(\sec ^{-1} \sqrt{1+x^2}\right)^2+C
Option B is correct because the integral simplifies to etan⁡−1x(sec⁡−11+x2)2+Ce^{\tan ^{-1} x}\left(\sec ^{-1} \sqrt{1+x^2}\right)^2+C after a suitable substitution and simplification using trigonometric identities.
177 Easy
177 of 746
Application +4 | -1
∫1log⁡xedx=\int \frac{1}{\log _x e} d x=
View answer and explanation
Correct option: C
xlog⁡(xe)+cx \log \left(\frac{x}{e}\right)+c
Option D (None of these) is incorrect. Option C (xlog⁡(xe)+cx \log (\frac{x}{e})+c) is correct because it is the result of integrating 1log⁡xe\frac{1}{\log_x e} using integration by parts and properties of logarithms.
178 Easy
178 of 746
Analyzing +4 | -1
If In=∫cot⁡nx dxI_n=\int \cot ^n x\, d x, then I0+I1+2I_0+I_1+2 (I2+I3+…+I8)+I9+I10\left(I_2+I_3+\ldots+I_8\right)+I_9+I_{10} equals to (where u=cot⁡x)\left.u=\cot x\right)
View answer and explanation
Correct option: B
−(u+u22+…+u99)-\left(u+\frac{u^2}{2}+\ldots+\frac{u^9}{9}\right)
Option B (-(u+u22+…+u99u+\frac{u^2}{2}+\ldots+\frac{u^9}{9})) is correct because using the reduction formula for the integral of cot^n(x) and summing the series leads to this expression.
179 Easy
179 of 746
Application +4 | -1
∫sec⁡2x−7sin⁡7xdx\int \frac{\sec ^2 x-7}{\sin ^7 x} d x is equal to
View answer and explanation
Correct option: D
tan⁡xcosec⁡7x+c\tan x \operatorname{cosec}^7 x+c
Option D (tan⁡xcosec⁡7x+c\tan x \operatorname{cosec}^7 x+c) is correct because the integral simplifies to this expression after applying integration by parts and simplification.
180 Easy
180 of 746
Understanding +4 | -1
To find the value of ∫1+log⁡xxdx\int \frac{1+\log x}{x} d x, the proper substitution is
View answer and explanation
Correct option: B
1+log⁡x=t1+\log x=t
Option B (1+log⁡x=t1+\log x=t) is correct because it simplifies the integral by making the derivative of the substitution equal to the remaining part of the integrand.
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