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JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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511 Easy
511 of 746
Application +4 | -1
If ∫dxx5x2−3=Ktan⁡−1f(x)+C\int \frac{d x}{x \sqrt{5 x^2-3}}=K \tan ^{-1} f(x)+C then
View answer and explanation
Correct option: B
f(x)=53x2−1,K=13f(x)=\sqrt{\frac{5}{3} x^2-1}, K=\frac{1}{\sqrt{3}}
Option B (f(x)=53x2−1,K=13f(x)=\sqrt{{\frac{{5}}{{3}} x^2-1}}, K=\frac{{1}}{{\sqrt{{3}}}}) is correct because the integral can be solved by substitution, leading to an arctangent integral.
512 Easy
512 of 746
Application +4 | -1
∫(1+x−x−1)ex+x−1dx\int\left(1+x-x^{-1}\right) e^{x+x^{-1}} d x, is equal to
View answer and explanation
Correct option: A
xex+x−1+Cx e^{x+x^{-1}}+C
Option A is correct because the integral simplifies to xex+x−1+Cx e^{x+x^{-1}}+C after applying integration by parts.
513 Easy
513 of 746
Analyzing +4 | -1
The value of ∫dxcos⁡6x+sin⁡6x\int \frac{d x}{\cos ^6 x+\sin ^6 x}, is equal to
View answer and explanation
Correct option: D
tan⁡−1(−2cot⁡2x)+C\tan ^{-1}(-2 \cot 2 x)+C
Option D (tan⁡−1(−2cot⁡2x)+C\tan^{-1}(-2 \cot 2x) + C) is correct because after simplifying the integral using trigonometric identities and substitution, we arrive at this result.
514 Easy
514 of 746
Application +4 | -1
The value of ∫1x2(x4+1)3/4dx\int \frac{1}{x^2\left(x^4+1\right)^{3 / 4}} d x, is
View answer and explanation
Correct option: B
−(1+1x4)1/4-\left(1+\frac{1}{x^4}\right)^{1 / 4}
Option B is correct because the integral simplifies to -(1 + 1/x4)(1/4) + C after substitution and simplification.
515 Easy
515 of 746
Application +4 | -1
∫x1+x4dx=\int \frac{x}{1+x^4} d x=
View answer and explanation
Correct option: B
12tan⁡−1x2+c\frac{1}{2} \tan ^{-1} x^2+c
Option B is correct because substituting t=x2t = x^2 transforms the integral to 12∫11+t2dt\frac{1}{2} \int \frac{1}{1 + t^2} dt, which equals 12tan⁡−1t+c=12tan⁡−1x2+c\frac{1}{2} \tan^{-1} t + c = \frac{1}{2} \tan^{-1} x^2 + c.
516 Easy
516 of 746
Application +4 | -1
Let x2≠nπ−1,n∈Nx^2 \neq n \pi-1, n \in N. Then, the value of ∫x2sin⁡(x2+1)−sin⁡2(x2+1)2sin⁡(x2+1)+sin⁡2(x2+1)dx\int x \sqrt{\frac{2 \sin \left(x^2+1\right)-\sin 2\left(x^2+1\right)}{2 \sin \left(x^2+1\right)+\sin 2\left(x^2+1\right)}} d x is equal to
View answer and explanation
Correct option: B
log⁡∣sec⁡(x2+12)∣+C\log \left|\sec \left(\frac{x^2+1}{2}\right)\right|+C
Option B is correct because after simplifying the expression inside the square root and using a trigonometric identity, the integral can be evaluated as log⁡∣sec⁡(x2+12)∣+C\log \left|\sec \left(\frac{x^2+1}{2}\right)\right|+C.
517 Easy
517 of 746
Application +4 | -1
∫cos⁡xxdx\int \frac{\cos \sqrt{x}}{\sqrt{x}} d x is equal to
View answer and explanation
Correct option: D
2sin⁡x+c2 \sin \sqrt{x}+c
Option D is correct because substituting t=xt = \sqrt{x} simplifies the integral to 2∫cos⁡tdt2\int \cos t dt, which integrates to 2sin⁡x+c2\sin \sqrt{x} + c.
518 Easy
518 of 746
Application +4 | -1
If ∫5+x10x16dx=a(1+5x10)3/2+C\int \frac{\sqrt{5+x^{10}}}{x^{16}} d x=a\left(1+\frac{5}{x^{10}}\right)^{3 / 2}+C, then a=a=
View answer and explanation
Correct option: C
−175-\frac{1}{75}
Option C is correct because after substitution and integration, the value of 'a' is found to be -1/75.
519 Easy
519 of 746
Application +4 | -1
∫dxcos⁡6x+sin⁡6x\int \frac{d x}{\cos ^6 x+\sin ^6 x} is equal to
View answer and explanation
Correct option: C
tar⁡21(tan⁡x−cot⁡x)+c\operatorname{tar}^{21}(\tan x-\cot x)+c
Option C (tar⁡21(tan⁡x−cot⁡x)+c\operatorname{tar}^{21}(\tan x-\cot x)+c) is correct because after simplification and substitution, the integral results in the arctangent function.
520 Easy
520 of 746
Application +4 | -1
∫dxa2cos⁡2x+b2sin⁡2x(a,b>0)\int \frac{\mathrm{d} x}{a^2 \cos ^2 x+b^2 \sin ^2 x}(a, b>0) is equal to
View answer and explanation
Correct option: C
1abtan⁡−1((ba)tan⁡x)+C\frac{1}{a b} \tan ^{-1}\left(\left(\frac{b}{a}\right) \tan x\right)+C
Option C (1abtan⁡−1((ba)tan⁡x)+C\frac{{1}}{{a b}} \tan ^{-1}\left(\left(\frac{{b}}{{a}}\right) \tan x\right)+C) is correct because dividing by cos⁡2x\cos^2 x and substituting t=tan⁡xt = \tan x leads to an arctangent integral.
521 Easy
521 of 746
Application +4 | -1
If f(3x−43x+4)=x+2f\left(\frac{3 x-4}{3 x+4}\right)=x+2, then ∫f(x)dx\int f(x) d x is:
View answer and explanation
Correct option: B
−83log⁡∣1−x∣+23x+c-\frac{8}{3} \log |1-x|+\frac{2}{3} x+c
Option B is correct because the integral can be solved by substitution and partial fractions.
522 Easy
522 of 746
Application +4 | -1
If ∫f(x)x2−x+1 dx=32log⁡(x2−x+1)+\int \frac{f(x)}{x^2-x+1} \mathrm{~d} x=\frac{3}{2} \log \left(x^2-x+1\right)+ 13tan⁡−12x−13+C\frac{1}{\sqrt{3}} \tan ^{-1} \frac{2 x-1}{\sqrt{3}}+C then f(x)f(x) is equal to
View answer and explanation
Correct option: C
3x−13 x-1
The correct answer is 3x−13x-1 because differentiating the given integral and simplifying leads to f(x)=3x−1f(x) = 3x - 1.
523 Easy
523 of 746
Application +4 | -1
If ∫ex(1+x)sec⁡2(xex)dx=f(x)+\int e^x(1+x) \sec ^2\left(x e^x\right) d x=f(x)+ Constant, then f(x)f(x) is equal to
View answer and explanation
Correct option: D
tan⁡(xex)\tan \left(x e^x\right)
Option D (tan⁡(xex)\tan \left(x e^x\right)) is correct because the integral simplifies to tan⁡(xex)+C\tan(xe^x) + C, so f(x)=tan⁡(xex)f(x) = \tan(xe^x).
524 Easy
524 of 746
Application +4 | -1
If f(x)f(x) is differentibale and ∫0t2xf(x)dx=25t5\int\limits_{{0}}^{t^{2}} x f(x) d x=\frac{2}{5} t^{5} then f(425)f\left(\frac{4}{25}\right) equals
View answer and explanation
Correct option: A
2/52 / 5
Option A is correct because differentiating both sides of the equation and solving for f(4/25) yields 2/5.
525 Easy
525 of 746
Application +4 | -1
If In=∫  xn .  ecx   dx     for     n  ≥  1,   then  c . In  +  n . In−1{I_n} = \int \,\,{x^n}\,.\,\,{e^{cx}}\;\,dx\;\;\,\mathrm{for}\,\;\;n\,\, \ge \,\,1,\,\;\mathrm{then}\,\,c\,.\,{I_n}\,\, + \,\,n\,.\,{I_{n - 1}} is equal to

View answer and explanation
Correct option: A
xn ecx{x^n}\,{e^{cx}}
Option A (xn ecx{x^n}\,{e^{cx}}) is correct because integrating by parts and rearranging the terms leads to the given expression.
526 Easy
526 of 746
Analyzing +4 | -1
∫x4+1x6+1dx\int \frac{x^4+1}{x^6+1} d x is equal to
View answer and explanation
Correct option: A
tan⁡−1x+13tan⁡−1x3+C\tan ^{-1} x+\frac{1}{3} \tan ^{-1} x^3+C
Option A (tan⁡−1x+13tan⁡−1x3+C\tan ^{-1} x+\frac{1}{3} \tan ^{-1} x^3+C) is correct because by factoring the denominator and simplifying the integrand, the integral can be expressed as the sum of two standard integrals.
527 Easy
527 of 746
Application +4 | -1
∫sin⁡3x⋅cos⁡xdx=\int \sin ^3 x \cdot \cos x d x=
View answer and explanation
Correct option: B
sin⁡4x4+c\frac{\sin ^4 x}{4}+c
Option B (sin⁡4x4+c\frac{\sin ^4 x}{4}+c) is correct because it is the result of integrating the given expression using substitution.
528 Easy
528 of 746
Application +4 | -1
∫log⁡x(log⁡x+2)dx=\int \log x(\log x+2) d x=
View answer and explanation
Correct option: A
x(log⁡x)2+cx(\log x)^2+c
Option A (x(log⁡x)2+cx(\log x)^2+c) is correct because the integral evaluates to this expression after substitution and simplification.
529 Easy
529 of 746
Application +4 | -1
If ∫dx2sin⁡x−cos⁡x+5=Atan⁡−115f(x)+C\int \frac{\mathrm{d} x}{2 \sin x-\cos x+5}=A \tan ^{-1} \frac{1}{\sqrt{5}} f(x)+C, then
View answer and explanation
Correct option: A
A=1/5A=1 / \sqrt{5}
Option A (A=1/5A=1 / \sqrt{5}) is correct because after substitution and integration, the coefficient of the inverse tangent term is 1/51/\sqrt{5}.
530 Easy
530 of 746
Application +4 | -1
∫ex(1−sin⁡x1−cos⁡x)dx\int \mathrm{e}^{\mathrm{x}}\left(\frac{1-\sin \mathrm{x}}{1-\cos \mathrm{x}}\right) \mathrm{dx} is equal to
View answer and explanation
Correct option: B
−excot⁡(x2)+C-\mathrm{e}^{\mathrm{x}} \cot \left(\frac{\mathrm{x}}{2}\right)+\mathrm{C}
Option B (−excot⁡(x2)+C-e^{x} \cot \left(\frac{x}{2}\right)+C) is correct because it is the result of integrating the given expression after simplification using trigonometric identities.
531 Easy
531 of 746
Analyzing +4 | -1
∫555x⋅  55x⋅  5x  dx\int {5^{{5^{{5^x}}}}} \cdot \,\,{5^{{5^x}}} \cdot \,\,{5^x}\;dx is equal to
View answer and explanation
Correct option: C
555x(log⁡  5)3  +  C\frac{{{5^{{5^{{5^x}}}}}}}{{{{\left( {\log \,\,5} \right)}^3}}}\,\, + \,\,C
Option A (1\mathrm{1}) is correct because the limit is evaluated by simplifying the integral and applying the limit definition.
532 Easy
532 of 746
Analyzing +4 | -1
If ∫cos⁡θ5+7sin⁡θ−2cos⁡2θ dθ  =A  log⁡e∣B(θ)∣+C,\int {\frac{{\cos \theta }}{{5 + 7\sin \theta - 2{{\cos }^2}\theta }}} \,d\theta \,\, = A\,\,{\log _e}\left| {B(\theta )} \right| + C, where CC is constant of integration, then B(θ)A\frac{{B(\theta )}}{A} can be
View answer and explanation
Correct option: D
5(2sin⁡θ+1)sin⁡θ+3\frac{{5(2\sin \theta + 1)}}{{\sin \theta + 3}}
Option D is correct because after integrating the given expression and simplifying, the result matches the form Alog⁡e∣B(θ)∣+CA \log_e |B(\theta)| + C, leading to the correct value of B(θ)A\frac{{B(\theta)}}{A}.
533 Easy
533 of 746
Application +4 | -1
∫(x3+3x2+3x+1)(x+1)5dx=\int \frac{\left(x^3+3 x^2+3 x+1\right)}{(x+1)^5} d x=
View answer and explanation
Correct option: A
−1(x+1)+c-\frac{1}{(x+1)}+c
Option A (−1(x+1)+c-\frac{{1}}{{(x+1)}}+c) is correct because the integral simplifies to this form after simplifying the fraction.
534 Easy
534 of 746
Analyzing +4 | -1
The integral ∫2x  −  3(x2+  x  +1)2  dx\int \frac{{2x\,\, - \,\,3}}{{{{\left( {{x^2} + \,\,x\,\, + 1} \right)}^2}}}\,\,dx is equal to
View answer and explanation
Correct option: A
−  8x+7x2+x+1  −  163 3  tan⁡−1  (2x+13)+C- \,\,\frac{{8x + 7}}{{{x^2} + x + 1}}\,\, - \,\,\frac{{16}}{{3\,\sqrt 3 }}\,\,{\tan ^{ - 1}}\,\,\left( {\frac{{2x + 1}}{3}} \right) + C
Option A is the correct answer because the integral can be solved by breaking it into parts and using trigonometric substitution to evaluate the remaining integral.
535 Easy
535 of 746
Application +4 | -1
∫(x3)  (1  +  x435)  dx\int \left( {\sqrt[3]{x}} \right)\,\,\left( {\sqrt[5]{{1\,\, + \,\,\sqrt[3]{{{x^4}}}}}} \right)\,\,dx is equal to
View answer and explanation
Correct option: C
58  (1  +  x43)65  +  c\frac{5}{8}\,\,{\left( {1\,\, + \,\,{x^{\frac{4}{3}}}} \right)^{\frac{6}{5}}}\,\, + \,\,c
Option C (58(1,+,x43)65+,c\frac{5}{8}\left( {1\\,\\ + \\,{x^{\frac{{4}}{{3}}}}} \right)^{\frac{{6}}{{5}}}\\ + \\,c) is correct because it is the result of integrating the given expression after a suitable substitution.
536 Easy
536 of 746
Application +4 | -1
∫dx1+ex=\int \frac{d x}{1+e^x}=
View answer and explanation
Correct option: B
−log⁡(1+e−x)-\log \left(1+e^{-x}\right)
Option B is correct because the integral can be rewritten and solved using a substitution, resulting in −log⁡(1+e−x)-\log(1+e^{-x}).
537 Easy
537 of 746
Application +4 | -1
If ∫  1x+x5  dx=f(x)+c\int \,\,\frac{1}{{x + {x^5}}}\,\,dx = f\left( x \right) + c, then the value of ∫x4x+x5   dx\int \frac{{{x^4}}}{{x + {x^5}}}\,\;dx equals
View answer and explanation
Correct option: A
log⁡  x  −  f  (x)  +  c\log \,\,x\,\, - \,\,f\,\,\left( x \right)\,\, + \,\,c
Option A (log⁡  x  −  f  (x)  +  c\log \,\,x\,\, - \,\,f\,\,\left( x \right)\,\, + \,\,c) is correct because it is obtained by manipulating the integrand and using the given integral.
538 Easy
538 of 746
Application +4 | -1
If ∫1+cos⁡8xtan⁡2x−cot⁡2xdx=acos⁡8x+C\int \frac{1+\cos 8 x}{\tan 2 x-\cot 2 x} d x=a \cos 8 x+C, then a=a=
View answer and explanation
Correct option: C
116\frac{1}{16}
Option C (116\frac{1}{16}) is correct because after simplifying the integral, the coefficient of cos⁡8x\cos 8x is 116\frac{1}{16}.
539 Easy
539 of 746
Application +4 | -1
∫333x33x3x dx\int 3^{3^{3^x}} 3^{3^x} 3^x \mathrm{~d} x is equal to
View answer and explanation
Correct option: C
3335(log⁡3)3+C\frac{3^{3^{3^5}}}{(\log 3)^3}+C
Option C is correct because after applying the substitution t=333xt = 3^{3^{3^x}}, the integral simplifies to 333x(log⁡3)3+C\frac{3^{3^{3^x}}}{(\log 3)^3}+C.
540 Easy
540 of 746
Application +4 | -1
The integral ∫dxx2(x4+1)34\int \frac{d x}{x^2\left(x^4+1\right)^{\frac{3}{4}}} equals
View answer and explanation
Correct option: D
−(x4+1x4)14+C-\left(\frac{x^4+1}{x^4}\right)^{\frac{1}{4}}+C
Option D (−(x4+1x4)14+C-\left(\frac{{x^4+1}}{{x^4}}\right)^{\frac{{1}}{{4}}}+C) is correct because it represents the result of the given integral after applying substitution and simplification.
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