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JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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421 Easy
421 of 746
Application +4 | -1
I=∫1(a2−b2x2)3/2dxI=\int \frac{1}{\left(a^2-b^2 x^2\right)^{3 / 2}} d x is equal to
View answer and explanation
Correct option: B
xa2a2−b2x2+C\frac{x}{a^2 \sqrt{a^2-b^2 x^2}}+C
Option B is correct because the integral simplifies to x / (a2 * sqrt(a2 - b2 * x2)) + C after trigonometric substitution.
422 Easy
422 of 746
Application +4 | -1
∫  dxa2  sin⁡2  x  +  b2  cos⁡2  x\int \,\,\frac{{dx}}{{{a^2}\,\,{{\sin }^2}\,\,x\,\, + \,\,{b^2}\,\,{{\cos }^2}\,\,x}} is equal to
View answer and explanation
Correct option: A
1ab  tan⁡−1  (a  tan⁡  xb)  +  c\frac{1}{{ab}}\,\,{\tan ^{ - 1}}\,\,\left( {\frac{{a\,\,\tan \,\,x}}{b}} \right)\,\, + \,\,c
Option A (1ab tan⁡−1  (a  tan⁡  xb)  +  c\frac{1}{{ab}}\,{\tan ^{ - 1}}\,\,\left( {\frac{{a\,\,\tan \,\,x}}{b}} \right)\,\, + \,\,c) is correct because the integral can be solved by dividing by cos²(x) and using a suitable substitution.
423 Easy
423 of 746
Application +4 | -1
∫dx5+4cos⁡x=\int \frac{d x}{5+4 \cos x}=
View answer and explanation
Correct option: C
23tan⁡−1(13tan⁡x2)+c\frac{2}{3} \tan ^{-1}\left(\frac{1}{3} \tan \frac{x}{2}\right)+c
Option C is correct because the integral is solved using the tangent half-angle substitution, resulting in 23tan⁡−1(13tan⁡x2)+c\frac{2}{3} \tan^{-1}(\frac{1}{3} \tan \frac{x}{2})+c.
424 Easy
424 of 746
Application +4 | -1
The integral ∫(1+x−1x)ex+1xdx\int\left(1+x-\frac{1}{x}\right) e^{x+\frac{1}{x}} d x is equal to
View answer and explanation
Correct option: B
xex+1x+Cx e^{x+\frac{1}{x}}+C
Option B (xex+1x+Cx e^{x+\frac{{1}}{{x}}}+C) is correct because it represents the result of the given integral after applying integration by parts and simplification.
425 Easy
425 of 746
Application +4 | -1
∫cos⁡  2x(sin⁡  x  +  cos⁡  x)2  dx\int \frac{{\cos \,\,2x}}{{{{\left( {\sin \,\,x\,\, + \,\,\cos \,\,x} \right)}^2}}}\,\,dx is equal to
View answer and explanation
Correct option: B
log⁡(sin⁡ x  +  cos⁡  x)  +  C\log \left( {\sin \,x\,\, + \,\,\cos \,\,x} \right)\,\, + \,\,C
Option B is correct because the integral simplifies to a logarithmic function after simplification.
426 Easy
426 of 746
Application +4 | -1
∫(1xtan⁡(1x))2dx=……\int\left(\frac{1}{x} \tan \left(\frac{1}{x}\right)\right)^2 d x=\ldots \ldots
View answer and explanation
Correct option: C
1x−tan⁡(1x)+c\frac{1}{x}-\tan \left(\frac{1}{x}\right)+c
Option C (1x−tan⁡(1x)+c\frac{1}{x}-\tan \left(\frac{1}{x}\right)+c) is the correct result obtained by using substitution and integrating the resulting trigonometric function.
427 Easy
427 of 746
Application +4 | -1
∫dx(x−x2)=\int \frac{d x}{\left(x-x^2\right)}=
View answer and explanation
Correct option: A
log⁡x−log⁡(1−x)+c\log x-\log (1-x)+c
Option C (log⁡x−log⁡(1−x)+c\log x-\log (1-x)+c) is correct because the integral is solved by partial fraction decomposition.
428 Easy
428 of 746
Application +4 | -1
∫2xcos⁡3x2sin⁡x2dx=\int 2 x \cos ^3 x^2 \sin x^2 d x=
View answer and explanation
Correct option: A
−14cos⁡4x2+c-\frac{1}{4} \cos ^4 x^2+c
Option A (−14cos⁡4x2+c-\frac{1}{4} \cos ^4 x^2+c) is correct because it is the result of integrating the given expression using substitution.
429 Easy
429 of 746
Application +4 | -1
∫log⁡(x+1+x2)1+x2dx=\int \frac{\log \left(x+\sqrt{1+x^2}\right)}{\sqrt{1+x^2}} d x=
View answer and explanation
Correct option: A
12[log⁡(x+1+x2)]2+c\frac{1}{2}\left[\log \left(x+\sqrt{1+x^2}\right)\right]^2+c
Option A (12[log⁡(x+1+x2)]2+c\frac{1}{2}\left[\log \left(x+\sqrt{1+x^2}\right)\right]^2+c) is correct because it is the result of the integration after using a suitable substitution.
430 Easy
430 of 746
Application +4 | -1
∫1(ex+e−x)2dx=\int \frac{1}{\left(e^x+e^{-x}\right)^2} d x=
View answer and explanation
Correct option: A
−12(e2x+1)+c-\frac{1}{2\left(e^{2 x}+1\right)}+c
Option A is correct because the integral simplifies to −12(e2x+1)+c-\frac{{1}}{{2(e^{{2x}}+1)}}+c after substitution and integration.
431 Easy
431 of 746
Application +4 | -1
∫  xe  xdx\int \,\,\sqrt x e\,{\,^{\sqrt x }}dx is equal to
View answer and explanation
Correct option: B
(2x  −  4 x+4)ex+  c\left( {2x\,\, - \,\,4\,\sqrt x + 4} \right){e^{\sqrt x }} + \,\,c
Option B ((2x − 4 x+4)ex+ c\left( {2x\, - \,4\,\sqrt x + 4} \right){e^{\sqrt x }} + \,c) is correct because it is the result of integrating the given expression using substitution and integration by parts.
432 Easy
432 of 746
Application +4 | -1
If ∫f  (x)  dx=g  (x)\int f\,\,\left( x \right)\,\,dx = \mathrm{g}\,\,\left( x \right), then f  (x)  g(x)f\,\,\left( x \right)\,\,\mathrm{g}\left( x \right) is equal to
View answer and explanation
Correct option: B
12  g2(x)\frac{1}{2}\,\,{\mathrm{g}^2}\left( x \right)
Option B (12 g2(x)\frac{1}{2}\,{\mathrm{g}^2}\left( x \right)) is correct because after applying integration by parts and simplifying, the result matches this option.
433 Easy
433 of 746
Application +4 | -1
∫1x1/5(1+x4/5)1/2dx\int \frac{1}{x^{1 / 5}\left(1+x^{4 / 5}\right)^{1 / 2}} d x, is
View answer and explanation
Correct option: B
521+x4/5+C\frac{5}{2} \sqrt{1+x^{4 / 5}}+C
Option B (521+x4/5+C\frac{{5}}{{2}} \sqrt{{1+x^{4 / 5}}}+C) is correct because it is the result of the integration after appropriate substitution.
434 Easy
434 of 746
Application +4 | -1
The value of ∫  (x  −  x3)1/3x4  dx\int \,\,\frac{{{{\left( {x\,\, - \,\,{x^3}} \right)}^{1/3}}}}{{{x^4}}}\,\,dx is
View answer and explanation
Correct option: B
−38  (1x2  −  1)4/3+  C- \frac{3}{8}\,\,{\left( {\frac{1}{{{x^2}}}\,\, - \,\,1} \right)^{4/3}} + \,\,C
Option B ( −38 (1x2  −  1)4/3+  C\ - \frac{3}{8}\,{\left( {\frac{1}{{{x^2}}}\,\, - \,\,1} \right)^{4/3}} + \,\,C) is correct because after simplifying the integrand and using substitution, the result matches this option.
435 Easy
435 of 746
Analyzing +4 | -1
∫x2  (ax+  b)−2   dx\int {x^2}\,\,{\left( {ax + \,\,b} \right)^{ - 2}}\;\,dx is equal to
View answer and explanation
Correct option: B
2a2  (x  −  ba  log⁡  (ax  +  b))  −  x2a(ax  +  b)  +  c\frac{2}{{{a^2}}}\,\,\left( {x\,\, - \,\,\frac{b}{a}\,\,\log \,\,\left( {ax\,\, + \,\,b} \right)} \right)\,\, - \,\,\frac{{{x^2}}}{{a\left( {ax\,\, + \,\,b} \right)}}\,\, + \,\,c
The correct answer is D (2a2 ,  (x  +  ba , log⁡   (ax  +  b))  −   x2a(ax  +  b)  +  c\frac{2}{{{a^2}}}\,\\,\,\,\left( {x\,\, + \,\,\frac{b}{a}\,\\,\,\log \,\,\,\left( {ax\,\, + \,\,b} \right)} \right)\,\, - \,\,\,\frac{{{{{x^2}}}}}{{{{a\left( {ax\,\, + \,\,b} \right)}}}}\,\, + \,\,c) because it results from correct substitution and integration by parts.
436 Easy
436 of 746
Application +4 | -1
The integral ∫sec⁡2x(sec⁡x+tan⁡x)9/2dx\int \frac{\sec ^2 x}{(\sec x+\tan x)^{9 / 2}} d x equals (for some arbitrary constant KK)
View answer and explanation
Correct option: C
−1(sec⁡x+tan⁡x)11/2{111+17(sec⁡x+tan⁡x)2}+K-\frac{1}{(\sec x+\tan x)^{11 / 2}}\left\{\frac{1}{11}+\frac{1}{7}(\sec x+\tan x)^2\right\}+K
Option C (−1(sec⁡x+tan⁡x)11/2{111+17(sec⁡x+tan⁡x)2}+K-\frac{1}{(\sec x+\tan x)^{11 / 2}}\{\frac{1}{11}+\frac{1}{7}(\sec x+\tan x)^2\}+K) is correct because substituting t=sec⁡x+tan⁡xt = \sec x + \tan x and simplifying leads to the given result.
437 Easy
437 of 746
Application +4 | -1
∫tan⁡(3x−5)sec⁡(3x−5)dx=\int \tan (3 x-5) \sec (3 x-5) d x=
View answer and explanation
Correct option: B
13sec⁡(3x−5)+c\frac{1}{3} \sec (3 x-5)+c
Option B is correct because substituting t=3x−5t = 3x - 5 transforms the integral to 13∫tan⁡tsec⁡tdt\frac{1}{3} \int \tan t \sec t dt, which equals 13sec⁡t+c=13sec⁡(3x−5)+c\frac{1}{3} \sec t + c = \frac{1}{3} \sec(3x - 5) + c.
438 Easy
438 of 746
Application +4 | -1
∫{tan⁡x+cot⁡x}dx\int\{\sqrt{\tan x}+\sqrt{\cot x}\} d x is equal to
View answer and explanation
Correct option: B
2sin⁡−1(sin⁡x−cos⁡x)+C\sqrt{2} \sin ^{-1}(\sin x-\cos x)+C
Option B, 2sin⁡−1(sin⁡x−cos⁡x)+C\sqrt{2} \sin ^{-1}(\sin x-\cos x)+C, is correct because manipulating the integrand and using a trigonometric identity leads to this result.
439 Easy
439 of 746
Analyzing +4 | -1
∫  {1  +  2  tan⁡  x  (tan⁡  x  +  sec⁡  x)}1/2dx\int \,\,{\left\{ {1\,\, + \,\,2\,\,\tan \,\,x\,\,\left( {\tan \,\,x\,\, + \,\,\sec \,\,x} \right)} \right\}^{1/2}}dx is equal to
View answer and explanation
Correct option: C
log⁡  sec⁡  x (sec⁡  x  +  tan⁡  x  +  C)\log \,\,\sec \,\,x\,\left( {\sec \,\,x\,\, + \,\,\tan \,\,x\,\, + \,\,C} \right)
Option C is correct because the integral simplifies to \log⁡sec⁡x+log⁡(sec⁡x+tan⁡x)\log \sec x + \log (\sec x + \tan x), which can be combined to give \log⁡sec⁡x(sec⁡x+tan⁡x)\log \sec x(\sec x + \tan x).
440 Easy
440 of 746
Application +4 | -1
∫x2(x2+2)(x2+3)dx=\int \frac{x^2}{\left(x^2+2\right)\left(x^2+3\right)} d x=
View answer and explanation
Correct option: B
−2tan⁡−1x2+3tan⁡−1x3+c-\sqrt{2} \tan ^{-1} \frac{x}{\sqrt{2}}+\sqrt{3} \tan ^{-1} \frac{x}{\sqrt{3}}+c
Option B, −2tan⁡−1x2+3tan⁡−1x3+c-\sqrt{2} \tan ^{-1} \frac{x}{\sqrt{2}}+\sqrt{3} \tan ^{-1} \frac{x}{\sqrt{3}}+c, is the correct answer because it results from partial fraction decomposition and integration of the given expression.
441 Easy
441 of 746
Understanding +4 | -1
∫  ex  [f(x)+f′(x)]  dx\int \,\,{e^x}\,\,\left[ {f\left( x \right) + f'\left( x \right)} \right]\,\,dx is equal to
View answer and explanation
Correct option: A
exf  (x)+c{e^x}f\,\,\left( x \right) + c
Option A (exf (x)+c{e^x}f\,\left( x \right) + c) is correct because the integral of ex[f(x)+f′(x)]dx{e^x}[f(x) + f'(x)] dx results in exf(x)+c{e^x}f(x) + c using integration by parts.
442 Easy
442 of 746
Analyzing +4 | -1
∫1sin⁡6x+cos⁡6xdx\int \frac{1}{\sin ^6 x+\cos ^6 x} d x is equal to
View answer and explanation
Correct option: C
tan⁡−1(tan⁡x−cot⁡x)+C\tan ^{-1}(\tan x-\cot x)+C
Option C (tan⁡−1(tan⁡x−cot⁡x)+C\tan ^{-1}(\tan x-\cot x)+C) is correct because after simplifying and integrating, the result matches this option.
443 Easy
443 of 746
Application +4 | -1
∫cos⁡−1(1x)dx\int \cos ^{-1}\left(\frac{1}{x}\right) d x
View answer and explanation
Correct option: B
xsec⁡−1x−cosh⁡−1x+Cx \sec ^{-1} x-\cosh ^{-1} x+C
Option B is correct because the integral of arccos(1/x) dx is equivalent to the integral of arcsec(x) dx, which after integration by parts results in x arcsec(x) - arccosh(x) + C.
444 Easy
444 of 746
Application +4 | -1
∫dxx (xn+1)\int \frac{{dx}}{{x\,\left( {{x^n} + 1} \right)}} is equal to
View answer and explanation
Correct option: A
1n  log⁡  (xnxn+1)+c\frac{1}{n}\,\,\log \,\,\left( {\frac{{{x^n}}}{{{x^n} + 1}}} \right) + c
Option A, \frac{1}{n}\,\,\log \,\,\left( {\frac{{{{x^n}}}}{{{{x^n} + 1}}} \right) + c\frac{1}{n}\,\,\log \,\,\left( {\frac{{{{x^n}}}}{{{{x^n} + 1}}} \right) + c, is correct because it is the result of integrating the given function using substitution and partial fractions.
445 Easy
445 of 746
Application +4 | -1
∫(sin⁡  2x−cos⁡   2x)dx=12  sin⁡  (2x−a)+b\int \left( {\sin \,\,2x - \cos \,\,\,2x} \right)dx = \frac{1}{{\sqrt 2 }}\,\,\sin \,\,\left( {2x - a} \right) + b, then
View answer and explanation
Correct option: B
a=−5π4,   b∈Ra = - \frac{{5\pi }}{4},\,\;b \in R
Option B (a=−5π4,  b∈Ra = - \frac{{5\pi }}{4},\;b \in R) is correct because it is derived by integrating the given trigonometric expression and comparing it with the target form.
446 Easy
446 of 746
Application +4 | -1
The area under the curve y=x2y=x^2 and the line x=3x=3 and x\mathrm{x} axis is_____ sq. units.
View answer and explanation
Correct option: A
9
Option D (1) is correct because setting up the integral and solving for 'a' gives a value of 1.
447 Easy
447 of 746
Analyzing +4 | -1
If ∫xa3−x3dx=msin⁡−1(xa)n+C\int \sqrt{\frac{x}{a^3-x^3}} d x=m \sin ^{-1}\left(\frac{x}{a}\right)^n+C, then
View answer and explanation
Correct option: C
m=1/nm=1 / n
Option C is correct because after evaluating the integral, we find that m=23m = \frac{2}{3} and n=32n = \frac{3}{2}, which means m=1nm = \frac{1}{n}.
448 Easy
448 of 746
Application +4 | -1
∫sec⁡2x(sec⁡x+tan⁡x)9/2dx\int \frac{\sec ^2 x}{(\sec x+\tan x)^{9 / 2}} d x equals to (for some arbitrary constant KK)
View answer and explanation
Correct option: C
−1(sec⁡x+tan⁡x)11/2{111+17(sec⁡x+tan⁡x)2}+K\frac{-1}{(\sec x+\tan x)^{11 / 2}}\left\{\frac{1}{11}+\frac{1}{7}(\sec x+\tan x)^2\right\}+K
Option C (\frac{{-1}}{{(\sec x+\tan x)^{{11 / 2}}}}\left{\frac{{1}}{{11}}+\frac{{1}}{{7}}(\sec x+\tan x)^2\right\}+K\frac{{-1}}{{(\sec x+\tan x)^{{11 / 2}}}}\left{\frac{{1}}{{11}}+\frac{{1}}{{7}}(\sec x+\tan x)^2\right\}+K) is correct because it represents the result of the given integral after applying substitution and simplification.
449 Easy
449 of 746
Application +4 | -1
∫xnlog⁡xdx=\int x^n \log x d x=
View answer and explanation
Correct option: D
xn+1n+1{log⁡x−1n+1}+c\frac{x^{n+1}}{n+1}\left\{\log x-\frac{1}{n+1}\right\}+c
Option D (\frac{x^{n+1}}{n+1}\left{\log x-\frac{1}{n+1}\right}+c\frac{x^{n+1}}{n+1}\left{\log x-\frac{1}{n+1}\right}+c) is correct because it is the result of integrating xnlog⁡xx^n \log x using integration by parts.
450 Easy
450 of 746
Application +4 | -1
∫  dxx+x\int \,\,\frac{{dx}}{{x + \sqrt x }} is equal to
View answer and explanation
Correct option: B
2  log⁡  (1+x ) +c2\,\,\log \,\,\left( {1 + \sqrt x \,} \right)\, + c
Option B (2\,\log \,\left( {1 + \sqrt x \} \right)\, + c2\,\log \,\left( {1 + \sqrt x \} \right)\, + c) is correct because after substitution, the integral simplifies and evaluates to this expression.
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