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JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 331-360 of 746 questions

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331 Easy
331 of 746
Application +4 | -1
∫  e3  log⁡x(x4+1)−1  dx\int \,\,{e^{3\,\,\log x}}{\left( {{x^4} + 1} \right)^{ - 1}}\,\,dx is equal to
View answer and explanation
Correct option: B
14  log⁡  (x4+1)+  c\frac{1}{4}\,\,\log \,\,\left( {{x^4} + 1} \right) + \,\,c
Option B (14,,log⁡,(x4+1)+,c\frac{1}{4}\\,,\log \\,\left( {{{{x^4} + 1}}} \right) + \\,c) is correct because it is the result of simplifying the integral and applying a u-substitution.
332 Easy
332 of 746
Application +4 | -1
The value of ∫cos⁡xsin⁡x+cos⁡x dx\int \frac{\cos x}{\sin x+\cos x} \mathrm{~d} x is
View answer and explanation
Correct option: B
12(x+log⁡∣sin⁡x+cos⁡x∣)+C\frac{1}{2}(x+\log |\sin x+\cos x|)+C
Option B is correct because the integral can be solved by splitting the numerator and using logarithmic integration.
333 Easy
333 of 746
Application +4 | -1
∫  dx2 x  (1+x)\int \,\,\frac{{dx}}{{2\,\sqrt x \,\,\left( {1 + x} \right)}} is equal to
View answer and explanation
Correct option: B
tan⁡−1  (x)+c{\tan ^{ - 1}}\,\,\left( {\sqrt x } \right) + c
Option B (tan⁡−1  (x)+c{\tan ^{ - 1}}\,\,\left( {\sqrt x } \right) + c) is correct because it is obtained by using a simple u-substitution with u=xu = \sqrt{x}.
334 Easy
334 of 746
Analyzing +4 | -1
If ∫1x+x5dx=f(x)+C\int \frac{1}{x+x^5} d x=f(x)+C, then the value of ∫x4x+x5dx\int \frac{x^4}{x+x^5} d x is
View answer and explanation
Correct option: A
log⁡x−f(x)+C\log x-f(x)+C
The correct answer is A (log⁡x−f(x)+C\log x-f(x)+C) because by manipulating the integrand and using the given information, the integral can be expressed in terms of f(x)f(x) and log⁡x\log x.
335 Easy
335 of 746
Application +4 | -1
∫{x+x2+1}nx2+1dx\int \frac{\left\{x+\sqrt{x^2+1}\right\}^n}{\sqrt{x^2+1}} d x is equal to
View answer and explanation
Correct option: B
1n{x+x2+1}n+C\frac{1}{n}\left\{x+\sqrt{x^2+1}\right\}^n+C
Option B is correct. The integral is solved by recognizing that the derivative of x+x2+1x + \sqrt{x^2 + 1} is x+x2+1x2+1\frac{{x + \sqrt{x^2 + 1}}}{{\sqrt{x^2 + 1}}}, allowing for a direct substitution and integration.
336 Easy
336 of 746
Application +4 | -1
∫1+x4(1−x4)3/2dx\int \frac{1+x^4}{\left(1-x^4\right)^{3 / 2}} d x is equal to
View answer and explanation
Correct option: B
11x2−x2+C\frac{1}{\sqrt{\frac{1}{x^2}-x^2}}+C
Option B (11x2−x2+C\frac{{1}}{{\sqrt{{\frac{{1}}{{x^2}}-x^2}}}}+C) is correct because it is the result of the integration after appropriate substitution and simplification.
337 Easy
337 of 746
Application +4 | -1
∫  dxcos⁡  x  +  3  sin⁡  x\int \,\,\frac{{dx}}{{\cos \,\,x\,\, + \,\,\sqrt 3 \,\,\sin \,\,x}} equals
View answer and explanation
Correct option: A
12  log⁡  tan⁡  (x2  +  π12)+c\frac{1}{2}\,\,\log \,\,\tan \,\,\left( {\frac{x}{2}\,\, + \,\,\frac{\pi }{{12}}} \right) + c
Option A is correct because the integral of the given function simplifies to a logarithmic tangent function with the correct phase shift.
338 Easy
338 of 746
Application +4 | -1
∫  axx  dx\int \,\,\frac{{{a^{\sqrt x }}}}{{\sqrt x }}\,\,dx is equal to
View answer and explanation
Correct option: B
2axlog⁡  a  +  C\frac{{2{a^{\sqrt x }}}}{{\log \,\,a}}\,\, + \,\,C
The correct answer is B (2axlog⁡  a +  C\frac{{2{a^{\sqrt x }}}}{{\log \,\,a}}\, + \,\,C) because after applying the substitution method and integrating, the result matches option B.
339 Easy
339 of 746
Application +4 | -1
If I=∫x51+x3dx\mathrm{I}=\int \frac{\mathrm{x}^5}{\sqrt{1+\mathrm{x}^3}} \mathrm{dx}, then I\mathrm{I} is equal to:
View answer and explanation
Correct option: B
29(1+x3)3/2−23(1+x3)1/2+C\frac{2}{9}\left(1+x^3\right)^{3 / 2}-\frac{2}{3}\left(1+x^3\right)^{1 / 2}+C
Option B is correct because the integral is solved by substitution, letting 1+x3=t21+x^3 = t^2 and simplifying the resulting expression.
340 Easy
340 of 746
Application +4 | -1
If ∫x3(1+x43)1/7dx=α(1+x43)β+c\int \sqrt[3]{x}\left(1+\sqrt[3]{x^4}\right)^{1 / 7} d x=\alpha\left(1+\sqrt[3]{x^4}\right)^\beta+c, then α+β−1\alpha+\beta^{-1} is
View answer and explanation
Correct option: D
4932\frac{49}{32}
Option D (4932\frac{49}{32}) is correct because after evaluating the integral and comparing coefficients, α+β−1\alpha+\beta^{-1} equals this value.
341 Easy
341 of 746
Analyzing +4 | -1
∫dx(x  +  1)5  (x  + 2)34\int \frac{{dx}}{{\sqrt[4]{{{{\left( {x\,\, + \,\,1} \right)}^5}\,\,{{\left( {x\,\, + \,2} \right)}^3}}}}} is equal to
View answer and explanation
Correct option: C
− 4   (x  +  2x  +  1)1/4+  c- \,4\,\;{\left( {\frac{{x\,\, + \,\,2}}{{x\,\, + \,\,1}}} \right)^{1/4}} + \,\,c
Option C (− 4  (x + 2x + 1)1/4+ c- \,4\;{\left( {\frac{{x\, + \,2}}{{x\, + \,1}}} \right)^{1/4}} + \,c) is correct because it is the result of the integration after a suitable substitution.
342 Easy
342 of 746
Application +4 | -1
∫axxdx=\int \frac{a^{\sqrt{x}}}{\sqrt{x}} d x=
View answer and explanation
Correct option: B
2axlog⁡ae+c2 a^{\sqrt{x}} \log _a e+c
Option B (2axlog⁡ae+c2 a^{\sqrt{{x}}} \log _a e+c) is correct because the integral can be solved by substitution and using the formula ∫axdx=axlog⁡ea+C=axlog⁡ae+C\int a^x dx = \frac{{a^x}}{{\log_e a}} + C = a^x \log_a e + C.
343 Easy
343 of 746
Application +4 | -1
∫(1+x−x−1)ex+x−1dx=\int\left(1+x-x^{-1}\right) e^{x+x^{-1}} d x=
View answer and explanation
Correct option: D
xex+x−1+Cx e^{x+x^{-1}}+C
Option D (xex+x−1+Cx e^{x+x^{-1}}+C) is correct because integrating by parts simplifies the expression, leading to the given result.
344 Easy
344 of 746
Application +4 | -1
∫  log⁡  (x  +  1+x2)1  +  x2    dx\int \,\,\frac{{\log \,\,\left( {x\,\, + \,\,\sqrt {1 + {x^2}} } \right)}}{{\sqrt {1\,\, + \,\,{x^2}} }}\;\,\,dx is equal to
View answer and explanation
Correct option: D
12  [log⁡  (x  +  1  +  x2)]2+  c\frac{1}{2}\,\,{\left[ {\log \,\,\left( {x\,\, + \,\,\sqrt {1\,\, + \,\,{x^2}} } \right)} \right]^2} + \,\,c
Option D is correct because the integral is solved using substitution, resulting in 12 [log⁡ (x + 1 +x2)]2 + c\frac{1}{2}\,{\left[ {\log \,\left( {x\,+\,\sqrt {1\,+{x^2}} } \right)} \right]^2}\,+\,c.
345 Easy
345 of 746
Application +4 | -1
If I=∫cos⁡2x−cos⁡2αsin⁡x−sin⁡αdxI=\int \frac{\cos 2 x-\cos 2 \alpha}{\sin x-\sin \alpha} d x, then II equals
View answer and explanation
Correct option: B
2cos⁡x−2xsin⁡α+C2 \cos x-2 x \sin \alpha+C
Option B (2cos⁡x−2xsin⁡α+C2 \cos x-2 x \sin \alpha+C) is correct because after simplifying the integral using trigonometric identities, the result matches this option.
346 Easy
346 of 746
Application +4 | -1
∫01  x71  −  x4    dx\int \nolimits_0^1 \,\,\frac{{{x^7}}}{{\sqrt {1\,\, - \,\,{x^4}} }}\;\,\,dx is equal to
View answer and explanation
Correct option: B
13\frac{1}{3}
Option B (13\frac{1}{3}) is correct because it is the result of evaluating the definite integral using substitution and the Gamma function.
347 Easy
347 of 746
Understanding +4 | -1
Let f(x)=1xln⁡(xex)f(x)=\frac{1}{x} \ln \left(\frac{x}{e^x}\right) then its primitive w.r.t. xx is
View answer and explanation
Correct option: C
12ln⁡2x−x+C\frac{1}{2} \ln ^2 \mathrm{x}-\mathrm{x}+\mathrm{C}
Option C (12ln⁡2x−x+C\frac{1}{2} \ln ^2 \mathrm{x}-\mathrm{x}+\mathrm{C}) is correct because it is the result of integrating the given function after simplification using logarithm properties.
348 Easy
348 of 746
Analyzing +4 | -1
The value of I=∫dx(a+bx2)b−ax2I=\int \frac{d x}{\left(a+b x^2\right) \sqrt{b-a x^2}}, is
View answer and explanation
Correct option: A
1a(a2+b2)tan⁡−1(xa2+b2ab−ax2)+C\frac{1}{\sqrt{a\left(a^2+b^2\right)}} \tan ^{-1}\left(\frac{x \sqrt{a^2+b^2}}{a \sqrt{b-a x^2}}\right)+C
Option A is correct because the integral evaluates to 1a(a2+b2)tan⁡−1(xa2+b2ab−ax2)+C\frac{1}{\sqrt{a(a^2+b^2)}} \tan ^{-1}\left(\frac{x \sqrt{a^2+b^2}}{a \sqrt{b-a x^2}}\right)+C after using a trigonometric substitution and simplification.
349 Easy
349 of 746
Application +4 | -1
The value of ∫ℓn∣x∣x1+ℓn∣x∣dx\int \frac{\ell n |x|}{x \sqrt{1+\ell n |x|}} d x equals:
View answer and explanation
Correct option: A
231+ℓn∣x∣(ℓn∣x∣−2)+C\frac{2}{3} \sqrt{1+\ell n|x|}(\ell n|x|-2)+C
Option A (231+ℓn∣x∣(ℓn∣x∣−2)+C\frac{2}{3} \sqrt{1+\ell n|x|}(\ell n|x|-2)+C) is correct because it results from a u-substitution and subsequent integration.
350 Easy
350 of 746
Application +4 | -1
∫sec⁡xlog⁡(sec⁡x+tan⁡x)dx=\int \sec x \log (\sec x+\tan x) d x=
View answer and explanation
Correct option: B
12[log⁡(sec⁡x+tan⁡x)]2+c\frac{1}{2}[\log (\sec x+\tan x)]^2+c
Option B is correct because the integral evaluates to 12[log⁡(sec⁡x+tan⁡x)]2+c\frac{1}{2}[\log (\sec x+\tan x)]^2+c after a simple substitution.
351 Easy
351 of 746
Analyzing +4 | -1
If ∫cos⁡2xsin⁡4xcos⁡4x(1+cos⁡22x)dx=2log⁡e(1+cos⁡2x)−log⁡e(1+cos⁡22x)+f(x)+c\int \frac{\cos 2 x \sin 4 x}{\cos ^4 x\left(1+\cos ^2 2 x\right)} d x=2 \log _e(1+\cos 2 x)-\log _e\left(1+\cos ^2 2 x\right)+f(x)+\mathrm{c} then f(x)f(x) is
View answer and explanation
Correct option: A
sec⁡2x\sec ^2 x
Option A is correct because the integral can be solved by trigonometric manipulation and partial fractions, leading to the given expression for f(x).
352 Easy
352 of 746
Application +4 | -1
∫32x3(log⁡x)2dx\int 32 x^3(\log x)^2 d x is equal to
View answer and explanation
Correct option: A
x4{8(log⁡x)2−4(log⁡x)+1}+cx^4\left\{8(\log x)^2-4(\log x)+1\right\}+c
Option A (x4{8(log⁡x)2−4(log⁡x)+1}+cx^4\left\{8(\log x)^2-4(\log x)+1\right\}+c) is correct because it is the result of integrating the given expression using integration by parts twice.
353 Easy
353 of 746
Application +4 | -1
∫(x+1)(x+log⁡x)2xdx=\int \frac{(x+1)(x+\log x)^2}{x} d x=
View answer and explanation
Correct option: C
13(x+log⁡x)3+c\frac{1}{3}(x+\log x)^3+c
Option C is correct because the integral simplifies to 13(x+log⁡x)3+c\frac{1}{3}(x + \log x)^3 + c after applying the substitution method.
354 Easy
354 of 746
Application +4 | -1
∫  3x9x  −  1    dx\int \,\,\frac{{{3^x}}}{{\sqrt {{9^x}\,\, - \,\,1} }}\,\,\;dx is equal to
View answer and explanation
Correct option: A
1log⁡  3  log⁡  ∣ 3x  +  9x−1 ∣  +  c\frac{1}{{\log \,\,3}}\,\,\log \,\,\left| {\,{3^x}\,\, + \,\,\sqrt {{9^x} - 1\,} } \right|\,\, + \,\,c
Option A is correct because the integral can be solved by substituting 3x=t{3^x} = t and using the standard integral formula.
355 Easy
355 of 746
Application +4 | -1
∫ax1−a2xdx=\int \frac{a^x}{\sqrt{1-a^{2 x}}} d x=
View answer and explanation
Correct option: A
1log⁡asin⁡−1ax+c\frac{1}{\log a} \sin ^{-1} a^x+c
Option A is correct because the integral can be solved using substitution.
356 Easy
356 of 746
Application +4 | -1
∫  ex  (x−1)x2    dx\int \,\,{e^x}\,\,\frac{{\left( {x - 1} \right)}}{{{x^2}}}\;\,\,dx is equal to
View answer and explanation
Correct option: C
exx  +  c\frac{{{e^x}}}{x}\,\, + \,\,c
Option C (exx + c\frac{{{e^x}}}{x}\, + \,c) is correct because the integral can be simplified and solved using the property ∫ex[f(x)+f′(x)]dx=exf(x)+c\int e^x [f(x) + f'(x)] dx = e^x f(x) + c.
357 Easy
357 of 746
Application +4 | -1
∫1xtan⁡4xsec⁡2xdx=\int \frac{1}{\sqrt{x}} \tan ^4 \sqrt{x} \sec ^2 \sqrt{x} d x=
View answer and explanation
Correct option: C
25tan⁡5x+c\frac{2}{5} \tan ^5 \sqrt{x}+c
Option C is correct because the integral can be solved using substitution.
358 Easy
358 of 746
Application +4 | -1
The value of the integral ∫24  x2−  4x4  dx\int \limits_2^4 \,\,\frac{{\sqrt {{x^2} - \,\,4} }}{{{x^4}}}\,\,dx, is
View answer and explanation
Correct option: B
332\frac{{\sqrt 3 }}{{32}}
Option B (332\frac{{\sqrt 3 }}{{32}}) is correct because it is the result of evaluating the definite integral using trigonometric substitution.
359 Easy
359 of 746
Application +4 | -1
∫ex(1+tan⁡x+tan⁡2x)dx=\int e^x\left(1+\tan x+\tan ^2 x\right) d x=
View answer and explanation
Correct option: C
extan⁡x+ce^x \tan x+c
Option C is correct because the integral simplifies to extan⁡x+ce^x \tan x + c by recognizing the form ∫ex[f(x)+f′(x)]dx=exf(x)+c\int e^x [f(x) + f'(x)] dx = e^x f(x) + c.
360 Easy
360 of 746
Application +4 | -1
∫tan⁡xcos⁡xdx\int {\frac{{\tan x}}{{\sqrt {\cos x} }}dx} is equal to
View answer and explanation
Correct option: B
2cos⁡x+c\frac{2}{{\sqrt {\cos x} }} + c
Option B (2cos⁡x+c\frac{2}{{\sqrt {\cos x} }} + c) is correct because the integral of the given function simplifies to this expression after substitution.
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