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JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 931-960 of 995 questions

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931 Easy
931 of 995
Application +4 | -1
∫1x(1+x3)2dx\int \frac{1}{x(1+\sqrt[3]{x})^2} d x is equal to
View answer and explanation
Correct option: A
3{log⁡(x1/31+x1/3)+11+x3}+C3\left\{\log \left(\frac{x^{1 / 3}}{1+x^{1 / 3}}\right)+\frac{1}{1+\sqrt[3]{x}}\right\}+C
Option A, 3\left{\log \left(\frac{x^{1 / 3}}{1+x^{1 / 3}}\right)+\frac{1}{1+\sqrt[3]{x}}\right\}+C3\left{\log \left(\frac{x^{1 / 3}}{1+x^{1 / 3}}\right)+\frac{1}{1+\sqrt[3]{x}}\right\}+C, is correct because it is the result of integrating the given expression after a suitable substitution and partial fraction decomposition.
932 Easy
932 of 995
Application +4 | -1
The value of ∫ex(x5+  5x4+  1)dx\int {e^x}\left( {{x^5} + \,\,5{x^4} + \,\,1} \right)dx is
View answer and explanation
Correct option: B
ex  .  x5  +  ex+  c{e^x}\,\,.\,\,{x^5}\,\, + \,\,{e^x} + \,\,c
Option B (ex . x5 + ex+ c{e^x}\,.\,{x^5}\, + \,{e^x} + \,c) is the correct result of integrating the given expression using integration by parts.
933 Easy
933 of 995
Application +4 | -1
∫dx2x−x2=\int \frac{d x}{\sqrt{2 x-x^2}}=
View answer and explanation
Correct option: B
sin⁡−1(x−1)+c\sin ^{-1}(x-1)+c
Option B is correct because the integral can be rewritten and solved using a trigonometric substitution, resulting in sin⁡−1(x−1)+c\sin^{-1}(x-1)+c.
934 Easy
934 of 995
Application +4 | -1
If ∫  dxx2+2x+2=f (x)+c\int \,\,\frac{{dx}}{{{x^2} + 2x + 2}} = f\,\left( x \right) + c, then f(x)f\left( x \right) is equal to
View answer and explanation
Correct option: A
tan⁡−1  (x+1){\tan ^{ - 1}}\,\,\left( {x + 1} \right)
Option A (tan⁡−1  (x+1){\tan ^{ - 1}}\,\,\left( {x + 1} \right)) is correct because completing the square and using the standard integral formula for arctangent yields this result.
935 Medium
935 of 995
Analyzing +4 | -1
∫dxcos⁡6x+sin⁡6x\int \frac{d x}{\cos ^6 x+\sin ^6 x} equals
View answer and explanation
Correct option: B
13Tan⁡−1(tan⁡x−cot⁡x)3+c\frac{1}{\sqrt{3}} \operatorname{Tan}^{-1} \frac{(\tan x-\cot x)}{\sqrt{3}}+c
Option B is correct because the integral simplifies to an arctangent form after trigonometric manipulation and substitution.
936 Medium
936 of 995
Analyzing +4 | -1
∫ex(x3−x+2)(x2+1)2dx=\int e^x \frac{\left(x^3-x+2\right)}{\left(x^2+1\right)^2} d x=
View answer and explanation
Correct option: B
(x+1)exx2+1+c\frac{(x+1) e^x}{x^2+1}+c
Option C (ex(x+1x+2)+ce^x\left(\frac{{x+1}}{{x+2}}\right)+c) is correct because the integral can be expressed in the form ∫ex[f(x)+f′(x)]dx\int e^x [f(x) + f'(x)] dx, where f(x)=x+1x+2f(x) = \frac{{x+1}}{{x+2}} and its derivative is 1(x+2)2\frac{{1}}{{(x+2)^2}}.
937 Medium
937 of 995
Application +4 | -1
The value of ∫x7(1−x2)5dx\int \frac{x^7}{\left(1-x^2\right)^5} d x, is
View answer and explanation
Correct option: B
18x8(1−x2)4+C\frac{1}{8} \frac{x^8}{\left(1-x^2\right)^4}+C
Option D (None of these) is correct because the integral evaluates to 18x8(1−x2)4+C\frac{1}{8} \frac{x^8}{(1-x^2)^4}+C, but the explanation provided uses a substitution that changes the variable to theta and then back to x, which is not necessary.
938 Medium
938 of 995
Understanding +4 | -1
If fn(x)=log⁡log⁡…log⁡xf_n(x)=\log \log \ldots \log x (log is repeated nn times) then ∫[xf1(x)f2(x)…fn(x)]−1 dx\int\left[x f_1(x) f_2(x) \ldots f_n(x)\right]^{-1} \mathrm{~d} x is equal to
View answer and explanation
Correct option: A
fn+1(x)+Cf_{n+1}(x)+C
Option A (fn+1(x)+Cf_{n+1}(x)+C) is correct because it is the result of applying the substitution method and integrating.
939 Easy
939 of 995
Understanding +4 | -1
∫  ∣ x ∣  dx\int \,\,\left| {\,x\,} \right|\,\,dx is equal to
View answer and explanation
Correct option: D
12  x  ∣ x ∣  +  c\frac{1}{2}\,\,x\,\,\left| {\,x\,} \right|\,\, + \,\,c
Option D (\frac{1}{2}\,x\,\left| {\,x\} \right|\, + \,c\frac{1}{2}\,x\,\left| {\,x\} \right|\, + \,c) is correct because the integral of ∣x∣|x| is 12x∣x∣+c\frac{1}{2}x|x| + c.
940 Easy
940 of 995
Application +4 | -1
∫(2x+1)ex(2x+3)2dx\int \frac{(2 x+1) e^x}{(2 x+3)^2} d x is equal to
View answer and explanation
Correct option: D
ex2x+3+c\frac{e^x}{2 x+3}+c
Option D is correct because the integral can be rewritten in the form ∫ex[f(x)+f′(x)]dx\int e^x [f(x) + f'(x)] dx, which simplifies to exf(x)+ce^x f(x) + c.
941 Easy
941 of 995
Understanding +4 | -1
If polynomials PP and QQ satisfies
∫((3x−1)cos⁡x+(1−2x)sin⁡x)dx\int((3 x-1) \cos x+(1-2 x) \sin x) d x
=Pcos⁡x+Qsin⁡x=P \cos x+Q \sin x
(ignoring the constant of integration) then
View answer and explanation
Correct option: D
Q=3(x−1)Q=3(x-1)
Option D (Q=3(x−1)Q=3(x-1)) is correct because after integrating by parts and comparing coefficients, Q is found to be 3(x-1).
942 Easy
942 of 995
Application +4 | -1
The value of ∫(x+1x)3/2(x2−1x2)dx\int\left(x+\frac{1}{x}\right)^{3 / 2}\left(\frac{x^2-1}{x^2}\right) d x, is
View answer and explanation
Correct option: B
25(x+1x)5/2+C\frac{2}{5}\left(x+\frac{1}{x}\right)^{5 / 2}+C
Option B is correct because the integral simplifies to (2/5)(x + 1/x)(5/2) + C after recognizing the derivative pattern.
943 Medium
943 of 995
Analyzing +4 | -1
∫esec⁡x⋅sec⁡3x(sin⁡2x+cos⁡x+sin⁡x+sin⁡xcos⁡x)dx=\int e^{\sec x} \cdot \sec ^3 x \left(\sin ^2 x+\cos x+\sin x+\sin x \cos x\right) d x=
View answer and explanation
Correct option: A
esec⁡x(sec⁡x+tan⁡x)+e^{\sec x}(\sec x+\tan x)+
The correct answer is A (esec⁡x(sec⁡x+tan⁡x)+ce^{\sec x}(\sec x+\tan x)+c) because the integral simplifies to this expression after applying integration by parts and simplification.
944 Easy
944 of 995
Understanding +4 | -1
If ∫dxx  log⁡  x=f(x)+\int \frac{{dx}}{{x\,\,\log \,\,x}} = f\left( x \right) + constant, then f(x)f\left( x \right) is equal to
View answer and explanation
Correct option: C
log⁡  log⁡  x\log \,\,\log \,\,x
Option C (log⁡ log⁡ x\log \, \log \, x) is correct because the integral of 1x log⁡x\frac{1}{x \, \log x} is log⁡(log⁡x)\log(\log x).
945 Hard
945 of 995
Application +4 | -1
Let f  (x)f\,\,\left( x \right) be a function satisfying f′  (x)=f(x)f'\,\,\left( x \right) = f\left( x \right) with f(0)=1f\left( 0 \right) = 1 and g  (x)g\,\,\left( x \right) be a function that satisfies f  (x)+g(x)=x2f\,\,\left( x \right) + g\left( x \right) = {x^2}. Then, the value of the integral ∫01 f(x)    g  (x)   dx\int \limits_0^1 \,f\left( x \right)\;\,\,g\,\,\left( x \right)\;\,dx, is
View answer and explanation
Correct option: D
e  −  e22  −  32e\,\, - \,\,\frac{{{e^2}}}{2}\,\, - \,\,\frac{3}{2}
Option D (e  −  e22  −  32e\,\, - \,\,\frac{{{{{e^2}}}}}{2}\,\, - \,\,\frac{3}{2}) is correct because it is the result of evaluating the definite integral after finding the functions f(x) and g(x).
946 Medium
946 of 995
Application +4 | -1
∫xtan⁡−1xdx=\int x \tan ^{-1} x d x=
View answer and explanation
Correct option: A
12(x2+1)tan⁡−1x−12x+c\frac{1}{2}\left(x^2+1\right) \tan ^{-1} x-\frac{1}{2} x+c
Option A is correct because the integral is solved using integration by parts, simplifying the resulting expression to match the given form.
947 Easy
947 of 995
Application +4 | -1
∫cos⁡xdx=\int \cos \sqrt{x} d x=
View answer and explanation
Correct option: A
2[xsin⁡x+cos⁡x]+c2[\sqrt{x} \sin \sqrt{x}+\cos \sqrt{x}]+c
Option A (2[xsin⁡x+cos⁡x]+c2[\sqrt{x} \sin \sqrt{x}+\cos \sqrt{x}]+c) is correct because it is the result of integrating the given expression using substitution and integration by parts.
948 Medium
948 of 995
Analyzing +4 | -1
∫  cos⁡  x  −  cos⁡3 x1  −  cos⁡3  x  dx\int \,\,\sqrt {\frac{{\cos \,\,x\,\, - \,\,{{\cos }^3}\,x}}{{1\,\, - \,\,{{\cos }^3}\,\,x}}} \,\,dx is equal to
View answer and explanation
Correct option: C
23  cos⁡−1  (cos⁡3/2  x)+C\frac{2}{3}\,\,{\cos ^{ - 1}}\,\,\left( {{{\cos }^{3/2}}\,\,x} \right) + C
Option C (23,cos⁡−1,(\frac{2}{3}\\,{\cos ^{ - 1}}\\,\left( {{{{}}}} \right.\cos }}^{3/2}}\\,x} \right) + C}}^{3/2}}\\,x} \right) + C) is correct because it represents the result of the integration after simplification and substitution.
949 Easy
949 of 995
Application +4 | -1
∫  tan⁡  xsin⁡  x  cos⁡  x  dx\int \,\,\frac{{\sqrt {\tan \,\,x} }}{{\sin \,\,x\,\,\cos \,\,x}}\,\,dx is equal to
View answer and explanation
Correct option: A
2 tan⁡  x  +  C2\,\sqrt {\tan \,\,x} \,\, + \,\,C
Option A (2 tan⁡ x + C2\,\sqrt {\tan \,x} \, + \,C) is correct because it is the result of a direct u-substitution and integration.
950 Easy
950 of 995
Analyzing +4 | -1
∫sin⁡4xsin⁡4x+cos⁡4xdx\int \frac{\sin ^4 x}{\sin ^4 x+\cos ^4 x} d x is equal to
View answer and explanation
Correct option: C
12{x−122log⁡∣2+sin⁡2x2−sin⁡2x∣}+C\frac{1}{2}\left\{x-\frac{1}{2 \sqrt{2}} \log \left|\frac{\sqrt{2}+\sin 2 x}{\sqrt{2}-\sin 2 x}\right|\right\}+C
The correct answer is C (12{x−122log⁡∣2+sin⁡2x2−sin⁡2x∣}+C\frac{1}{2}\left\{x-\frac{1}{2 \sqrt{2}} \log \left|\frac{\sqrt{2}+\sin 2 x}{\sqrt{2}-\sin 2 x}\right|\right\}+C) because after applying trigonometric identities and simplification, the integral can be evaluated.
951 Easy
951 of 995
Application +4 | -1
If ∫dx4−3cos⁡2x+5sin⁡2x=13f(3tan⁡x)+C\int \frac{\mathrm{d} x}{4-3 \cos ^2 x+5 \sin ^2 x}=\frac{1}{3} f(3 \tan x)+C, then f(x)f(x) is equal to
View answer and explanation
Correct option: D
tan⁡−1x\tan ^{-1} x
Option D (\tan-1 x\\) is correct. Dividing by \cos2 x and substituting \t=tan⁡xt = \tan x simplifies the integral to a standard arctangent form.
952 Medium
952 of 995
Application +4 | -1
∫ex(1−x)2(1+x2)2dx=\int e^x \frac{(1-x)^2}{\left(1+x^2\right)^2} d x=
View answer and explanation
Correct option: C
ex(11+x2)+ce^x\left(\frac{1}{1+x^2}\right)+c
Option C (ex(11+x2)+ce^x\left(\frac{1}{1+x^2}\right)+c) is correct because the integral is solved using the form ∫ex[f(x)+f′(x)]dx=exf(x)+c\int e^x [f(x) + f'(x)] dx = e^x f(x) + c.
953 Easy
953 of 995
Analyzing +4 | -1
If ∫1(sin⁡  x  +  4) (sin⁡  x−1)  dx\int \frac{1}{{(\sin \,\,x\,\, + \,\,4)\,(\sin \,\,x - 1)}}\,\,dx
=A1tan⁡  x2−1+Btan⁡−1(f(x))+C= A\frac{1}{{\tan \,\,\frac{x}{2} - 1}} + B{\tan ^{ - 1}}\left( {f\left( x \right)} \right) + C, then
View answer and explanation
Correct option: D
A=25,   B=− 25 15,   f(x)=4tan⁡  x/2+115A = \frac{2}{5},\;\,B = \frac{{ - \,2}}{{5\,\sqrt {15} }},\;\,f\left( x \right) = \frac{{4\tan \,\,x/2 + 1}}{{\sqrt {15} }}
Option D (A=25,;B=−,25;15,; f(x)=4tan⁡,x2+,115A = \frac{2}{5},\\;B = \frac{{ - \\,2}}{{5\\;\sqrt {15} }},\\;\,f\left( x \right) = \frac{{4\tan \\,\frac{x}{2}\\ + \\,1}}{{\sqrt {15} }}) is correct because it represents the correct partial fraction decomposition and integration of the given expression.
954 Medium
954 of 995
Application +4 | -1
The value of ∫x(xx)x  (2  log⁡  x  +  1)  dx\int x{\left( {{x^x}} \right)^x}\,\,\left( {2\,\,\log \,\,x\,\, + \,\,1} \right)\,\,dx is
View answer and explanation
Correct option: A
(xx)x  +  c{\left( {{x^x}} \right)^x}\,\, + \,\,c
Option A ((xx)x+c{\left( {{x^x}} \right)^x}\\ + \\ c) is correct because the integral is solved by recognizing the derivative of (x^x)^x and using substitution.
955 Easy
955 of 995
Application +4 | -1
Let ∫  ex  (f  (x)−f′(x))  dx=ϕ  (x)\int \,\,{e^x}\,\,\left( {f\,\,\left( x \right) - f'\left( x \right)} \right)\,\,dx = \phi \,\,\left( x \right)

Then, ∫  ex f(x)  dx\int \,\,{e^x}\,f\left( x \right)\,\,dx is equal to
View answer and explanation
Correct option: C
12  [ϕ(x)  +  exf  (x)]\frac{1}{2}\,\,\left[ {\phi \left( x \right)\,\, + \,\,{e^x}f\,\,\left( x \right)} \right]
Option C (12 [ϕ(x) + exf  (x)]\frac{1}{2}\,\left[ {\phi \left( x \right)\, + \,{e^x}f\,\,\left( x \right)} \right]) is correct because it is derived from integration by parts and the given equation.
956 Easy
956 of 995
Application +4 | -1
The integral ∫2x12+5x9(x5+x3+1)3dx\int {\frac{{2{x^{12}} + 5{x^9}}}{{{{\left( {{x^5} + {x^3} + 1} \right)}^3}}}dx} is equl to
View answer and explanation
Correct option: B
x102(x5+x3+1)2+C\frac{{{x^{10}}}}{{2{{\left( {{x^5} + {x^3} + 1} \right)}^2}}} + C
Option B is correct because the integral simplifies to a form that can be solved by substitution, resulting in the given expression.
957 Easy
957 of 995
Analyzing +4 | -1
Integral of 1+2cot⁡x(cot⁡x+cosec⁡x)\sqrt{1+2 \cot x(\cot x+\operatorname{cosec} x)} w.r.t. xx, is
View answer and explanation
Correct option: B
2ln⁡sin⁡x2+C2 \ln \sin \frac{x}{2}+C
Option B (2ln⁡sin⁡x2+C2 \ln \sin \frac{x}{2}+C) is correct because simplifying the expression inside the square root leads to an integral that can be directly evaluated to this result.
958 Easy
958 of 995
Application +4 | -1
If f(x)=x21+x2f(x)=\frac{x^2}{1+x^2} and g(x)=sin⁡xg(x)=\sin x then ∫fog(x)cos⁡x dx\int f o g(x) \cos x \mathrm{~d} x is
View answer and explanation
Correct option: A
sin⁡x−tan⁡−1(sin⁡x)+C\sin x-\tan ^{-1}(\sin x)+C
Option A (\sin x - \tan-1(\sin x) + C\\) is correct. By substituting \t=sin⁡xt = \sin x, the integral simplifies to \∫t21+t2dt\int \frac{t^2}{1+t^2} dt, which can be easily integrated.
959 Easy
959 of 995
Application +4 | -1
∫  1  +  x1  +  x3  dx\int \,\,\frac{{1\,\, + \,\,x}}{{1\,\, + \,\,\sqrt[3]{x}}}\,\,dx is equal to
View answer and explanation
Correct option: A
35  x5/3  −  34x4/3  +  x  +  C\frac{3}{5}\,\,{x^{5/3}}\,\, - \,\,\frac{3}{4}{x^{4/3}}\,\, + \,\,x\,\, + \,\,C
Option A (35⋅x5/3−34x4/3+x+C\frac{3}{5}\cdot{x^{5/3}}\\ - \frac{3}{4}{x^{4/3}}\\ + \\ x\\ + \\ C) is correct because after integrating the simplified expression, we obtain this result.
960 Easy
960 of 995
Application +4 | -1
∫sec⁡  xsec⁡  x  +  tan⁡x    dx\int \frac{{\sec \,\,x}}{{\sec \,\,x\,\, + \,\,\tan x}}\,\,\;dx
is equal to
View answer and explanation
Correct option: A
tan⁡  x−sec⁡  x+c\tan \,\,x - \sec \,\,x + c
Option A (tan⁡ x−sec⁡ x+c\tan \,x - \sec \,x + c) is correct because it is obtained by multiplying the numerator and denominator by (sec⁡x−tan⁡x)(\sec x - \tan x) and then integrating the resulting expression.
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