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JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Mixed difficulty

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841 Medium
841 of 995
Analyzing +4 | -1
The value of ∫  sec⁡  x  dxsin⁡  (2x+θ)  +  sin⁡  θ\int \,\,\frac{{\sec \,\,x\,\,dx}}{{\sqrt {\sin \,\,\left( {2x + \mathrm{\theta }} \right)\,\, + \,\,\sin \,\,\mathrm{\theta }} }} is
View answer and explanation
Correct option: B
2  (tan⁡  x  +  tan⁡  θ)  sec⁡  θ+c\sqrt {2\,\,(\tan \,\,x\,\, + \,\,\tan \,\,\mathrm{\theta })\,\,\sec \,\,\mathrm{\theta }} + c
Option B (2  (tan⁡  x  +  tan⁡  θ)  sec⁡  θ+c\sqrt {2\,\,(\tan \,\,x\,\, + \,\,\tan \,\,\mathrm{\theta })\,\,\sec \,\,\mathrm{\theta }} + c) is correct because it is the result of correctly evaluating the integral after trigonometric simplification and substitution.
842 Easy
842 of 995
Analyzing +4 | -1
∫etan⁡−1x(1+x2)[(sec⁡−11+x2)2+cos⁡−1(1−x21+x2)]dx,\int \frac{e^{\tan ^{-1} x}}{\left(1+x^2\right)}\left[\left(\sec ^{-1} \sqrt{1+x^2}\right)^2+\cos ^{-1}\left(\frac{1-x^2}{1+x^2}\right)\right] d x, (x>0)(x>0) is equal to
View answer and explanation
Correct option: C
etan⁡−1x⋅(sec⁡−1(1+x2))2+Ce^{\tan ^{-1} x} \cdot\left(\sec ^{-1}\left(\sqrt{1+x^2}\right)\right)^2+C
Option C (etan⁡−1x⋅(sec⁡−1(1+x2))2+Ce^{\tan^{-1} x} \cdot (\sec^{-1}(\sqrt{{1 + x^2}}))^2 + C) is correct because the integral simplifies to this form after applying trigonometric identities and substitution.
843 Easy
843 of 995
Application +4 | -1
Correct evaluation of ∫x(x−2)(x−1)dx\int \frac{x}{(x-2)(x-1)} d x is
View answer and explanation
Correct option: A
log⁡e(x−2)2(x−1)+p\log _e \frac{(x-2)^2}{(x-1)}+p
Option A, log⁡e(x−2)2(x−1)+p\log _e \frac{(x-2)^2}{(x-1)}+p, is the correct evaluation because it results from partial fraction decomposition and integration of the given expression.
844 Medium
844 of 995
Application +4 | -1
The value of integral ∫01 1  −  x1  +  x   dx\int \nolimits_0^1 \,\sqrt {\frac{{1\,\, - \,\,x}}{{1\,\, + \,\,x}}} \;\,dx is
View answer and explanation
Correct option: B
π2  −  1\frac{\pi }{2}\,\, - \,\,1
Option B (π2−1\frac{\pi }{2}\\ - \\1) is correct because the integral can be solved by rationalizing the denominator and then using trigonometric substitution or direct integration.
845 Easy
845 of 995
Application +4 | -1
The value of ∫dx(x−a)(b−x)\int \frac{d x}{\sqrt{(x-a)(b-x)}}, is
View answer and explanation
Correct option: A
2sin⁡−1x−ab−a+C2 \sin ^{-1} \sqrt{\frac{x-a}{b-a}}+C
Option A (2sin⁡−1x−ab−a+C2 \sin ^{-1} \sqrt{\frac{x-a}{b-a}}+C) is correct because it is the result of the integral after applying the trigonometric substitution x=acos⁡2θ+bsin⁡2θx=a \cos ^2 \theta+b \sin ^2 \theta.
846 Medium
846 of 995
Application +4 | -1
The value of the integral ∫  x  sin⁡  x2 esec⁡x2cos⁡2  x2  dx\int \,\,\frac{{x\,\,\sin \,\,{x^2}\,{e^{\sec {x^2}}}}}{{{{\cos }^2}\,\,{x^2}}}\,\,dx, is
View answer and explanation
Correct option: A
12  esec⁡x2+  C\frac{1}{2}\,\,{e^{\sec {x^2}}} + \,\,C
Option A (12 esec⁡x2+ C\frac{1}{2}\,{e^{\sec {x^2}}} + \,C) is correct because it is the result of integrating the given expression using substitution.
847 Medium
847 of 995
Application +4 | -1
∫  dx1−cos⁡  x−sin⁡  x\int \,\,\frac{{dx}}{{1 - \cos \,\,x - \sin \,\,x}} is equal to
View answer and explanation
Correct option: C
log⁡  ∣1−cot⁡  x2∣+c\log \,\,\left| {1 - \cot \,\,\frac{x}{2}} \right| + c
Option C is correct because the integral simplifies to log⁡  ∣1−cot⁡  x2∣+c\log \,\,\left| {1 - \cot \,\,\frac{x}{2}} \right| + c after using trigonometric identities and substitution.
848 Easy
848 of 995
Application +4 | -1
∫  cos⁡  {2  tan⁡−1  1−x1+x }  dx\int \,\,\cos \,\,\left\{ {2\,\,{{\tan }^{ - 1}}\,\,\sqrt {\frac{{1 - x}}{{1 + x}}\,} } \right\}\,\,dx is equal to
View answer and explanation
Correct option: D
x22+c\frac{{{x^2}}}{2} + c
Option D (x22+c\frac{{{x^2}}}{2} + c) is correct because after simplifying the trigonometric expression, the integral becomes ∫xdx\int x dx, which evaluates to x22+c\frac{x^2}{2} + c.
849 Medium
849 of 995
Application +4 | -1
If the primitive of 1f(x)\frac{1}{{f\left( x \right)}} is equal to log⁡  {f(x)}2  +  c,  then  f(x)\log \,\,{\left\{ {f\left( x \right)} \right\}^2}\,\, + \,\,c,\,\,\mathrm{then}\,\,f\left( x \right) is

View answer and explanation
Correct option: B
x2  +  d\frac{x}{2}\,\, + \,\,d
Option B (x2 + d\frac{x}{2}\, + \,d) is correct because differentiating log⁡ {f(x)}2 + c\log \,{\left\{ {f\left( x \right)} \right\}^2}\, + \,c gives 1f(x)\frac{1}{{f\left( x \right)}} when f(x)=x2+df(x) = \frac{x}{2} + d.
850 Easy
850 of 995
Application +4 | -1
∫  x2+  x  −6(x−2)  (x−1)  dx\int \,\,\frac{{{x^2} + \,\,x\,\, - 6}}{{\left( {x - 2} \right)\,\,\left( {x - 1} \right)}}\,\,dx
View answer and explanation
Correct option: D
x  +  4  log⁡  (x−1)  +  cx\,\, + \,\,4\,\,\log \,\,\left( {x - 1} \right)\,\, + \,\,c
Option D (x,+,4,log⁡,(x−1),+,,cx\\,\\ + \\,4\\,\log \\,\left( {x - 1} \right)\\,\\ + \\,\\,c) is correct because the integral simplifies to a rational function that can be easily integrated after partial fraction decomposition.
851 Easy
851 of 995
Application +4 | -1
∫(x+3)ex(x+4)2dx=\int \frac{(x+3) e^x}{(x+4)^2} d x=
View answer and explanation
Correct option: C
exx+4+c\frac{e^x}{x+4}+c
Option C (exx+4+c\frac{{e^x}}{{x+4}}+c) is correct because the integral can be simplified and solved using integration by parts or by recognizing the form ∫ex[f(x)+f′(x)]dx=exf(x)+c\int e^x [f(x) + f'(x)] dx = e^x f(x) + c.
852 Medium
852 of 995
Application +4 | -1
The value of ∫0π/2  cos⁡  θ4  −  sin⁡2  θ  dθ\int \nolimits_0^{\mathrm{\pi }/2} \,\,\frac{{\cos \,\,\mathrm{\theta }}}{{\sqrt {4\,\, - \,\,{{\sin }^2}\,\,\mathrm{\theta }} }}\,\,d\mathrm{\theta } is
View answer and explanation
Correct option: B
π6\frac{\mathrm{\pi }}{6}
Option B (π6\frac{\mathrm{\pi }}{6}) is correct because after substitution, the integral becomes a standard arcsin integral, evaluating to π6\frac{\pi}{6}.
853 Easy
853 of 995
Application +4 | -1
∫3x29−16x6dx=\int \frac{3 x^2}{\sqrt{9-16 x^6}} d x=
View answer and explanation
Correct option: A
14sin⁡−1(4x33)+c\frac{1}{4} \sin ^{-1}\left(\frac{4 x^3}{3}\right)+c
Option A is correct because the integral can be solved using substitution, resulting in 14sin⁡−1(4x33)+c\frac{1}{4} \sin^{-1}(\frac{4x^3}{3}) + c.
854 Easy
854 of 995
Application +4 | -1
∫(x2−x+1x2+1)ecot⁡−1(x)dx=f(x)⋅ecot⁡−1(x)+C\int\left(\frac{x^2-x+1}{x^2+1}\right) e^{\cot^ {-1}(x)} d x=f(x) \cdot e^{\cot^{-1}(x)}+C
where CC is constant of integration. Then f(x)f(x) is equal to:
View answer and explanation
Correct option: C
xx
Option C (xx) is correct because integrating the given expression using substitution cot⁡−1x=t\cot^{-1}x = t leads to f(x)=xf(x) = x.
855 Medium
855 of 995
Analyzing +4 | -1
∫x4−1x2x4+x2+1dx\int \frac{x^4-1}{x^2 \sqrt{x^4+x^2+1}} d x equals
View answer and explanation
Correct option: A
x4+x2+1x+c\frac{\sqrt{x^4+x^2+1}}{x}+c
Option A is correct because the integral simplifies to a form that can be solved by substitution, resulting in the given expression.
856 Easy
856 of 995
Application +4 | -1
∫sin⁡x+8cos⁡x4sin⁡x+6cos⁡xdx=\int \frac{\sin x+8 \cos x}{4 \sin x+6 \cos x} d x=
View answer and explanation
Correct option: A
x+12log⁡∣4sin⁡x+6cos⁡x∣+Cx+\frac{1}{2} \log |4 \sin x+6 \cos x|+C
Option C (x+2log⁡∣2sin⁡x+3cos⁡x∣+Cx+2 \log |2 \sin x+3 \cos x|+C) is correct because the integral is solved by expressing the numerator as a linear combination of the denominator and its derivative.
857 Easy
857 of 995
Application +4 | -1
I=∫cos⁡{2tan⁡−11−x1+x}dxI=\int \cos \left\{2 \tan ^{-1} \sqrt{\frac{1-x}{1+x}}\right\} d x is equal to
View answer and explanation
Correct option: A
12x2+C\frac{1}{2} x^2+C
Option A is correct because the integral can be simplified using trigonometric identities and a substitution.
858 Easy
858 of 995
Application +4 | -1
If f:R→Rf: \mathbb{R} \rightarrow \mathbb{R} is a function such that f(x)+2f(1x)=3x ∀x≠0f(x)+2 f\left(\frac{1}{x}\right)=3 x \,\forall x \neq 0 then ∫xf(x)dx\int x f(x) dx is equal to
View answer and explanation
Correct option: A
2x−13x3+c2x - \frac{1}{3}{x^3} + c
Option A (2x−13x3+c2x - \frac{1}{3}{x^3} + c) is correct because solving the functional equation for f(x)f(x) and then integrating xf(x)xf(x) yields this result.
859 Easy
859 of 995
Application +4 | -1
∫e−xcosec⁡2(2e−x+5)dx=\int e^{-x} \operatorname{cosec}^2\left(2 e^{-x}+5\right) d x=
View answer and explanation
Correct option: A
12cot⁡(2e−x+5)+c\frac{1}{2} \cot \left(2 e^{-x}+5\right)+c
Option A (12cot⁡(2e−x+5)+c\frac{1}{2} \cot \left(2 e^{-x}+5\right)+c) is correct because it is the result of integrating the given expression using substitution.
860 Easy
860 of 995
Application +4 | -1
∫x−1(x−3)(x−2)dx=\int \frac{x-1}{(x-3)(x-2)} d x=
View answer and explanation
Correct option: B
log⁡(x−3)2−log⁡(x−2)+c\log (x-3)^2-\log (x-2)+c
Option B (log⁡(x−3)2−log⁡(x−2)+c\log (x-3)^2-\log (x-2)+c) is correct because the integral is solved by partial fraction decomposition.
861 Medium
861 of 995
Application +4 | -1
If f(x−4x+2)=2x+1,(x∈R={1,−2})f\left(\frac{x-4}{x+2}\right)=2 x+1,(x \in R=\{1,-2\}), then ∫f(x)dx\int f(x) d x is equal to (where CC is a constant of integration)
View answer and explanation
Correct option: B
−12log⁡e∣1−x∣−3x+c-12 \log _e|1-x|-3 x+c
Option B (−12log⁡e∣1−x∣−3x+c-12 \log _e|1-x|-3 x+c) is correct because it is the result of integrating f(x) after finding the expression for f(x) by substituting y=x−4x+2y = \frac{x-4}{x+2}.
862 Easy
862 of 995
Application +4 | -1
Let n≥2n \ge 2 be a natural number and 0<θ<π2.0 < \theta < \frac{\pi }{2}. Then ∫(sin⁡nθ−sin⁡θ)1ncos⁡θsin⁡n+1θdθ\int \frac{{{{({{\sin }^n}\theta - \sin \theta )}^{\frac{1}{n}}}\cos \theta }}{{{{\sin }^{n + 1}}\theta }}d\theta is equal to (where C is a constant of integration)
View answer and explanation
Correct option: C
nn2−1(1−1sin⁡n−1θ)n+1n+C\frac{n}{{{n^2} - 1}}{\left( {1 - \frac{1}{{{{\sin }^{n - 1}}\theta }}} \right)^{\frac{{n + 1}}{n}}} + C
Option D (1356) is correct because it is the sum of all two-digit numbers that leave a remainder of 2 or 5 when divided by 7.
863 Easy
863 of 995
Application +4 | -1
The value of ∫1xn(1+xn)1/ndx,(n∈N)\int \frac{1}{x^n\left(1+x^n\right)^{1 / n}} d x,(n \in N), is
View answer and explanation
Correct option: A
11−n{1+1xn}1−1n+C\frac{1}{1-n}\left\{1+\frac{1}{x^n}\right\}^{1-\frac{1}{n}}+C
Option A is correct because the integral is solved using a substitution method, resulting in the given expression with a fractional exponent.
864 Easy
864 of 995
Application +4 | -1
If ∫excos⁡4x dx=Ae5x(sin⁡4x+54cos⁡4x)+C\int e^x \cos 4 x \mathrm{~d} x=A e^{5 x}\left(\sin 4 x+\frac{5}{4} \cos 4 x\right)+C then AA is equal to
View answer and explanation
Correct option: A
441\frac{4}{41}
Option A is correct because after integrating by parts twice and solving for the integral, the coefficient A is found to be 441\frac{4}{41}.
865 Medium
865 of 995
Application +4 | -1
∫  dx(sin⁡  x  −  2  cos⁡  x) (2  sin⁡  x  +  cos⁡  x)\int \,\,\frac{{dx}}{{(\sin \,\,x\,\, - \,\,2\,\,\cos \,\,x)\,(2\,\,\sin \,\,x\,\, + \,\,\cos \,\,x)}} is equal to
View answer and explanation
Correct option: A
log⁡e  tan⁡  x  −  22tan⁡  x  +  15  +  c{\log _e}\,\,\sqrt[5]{{\frac{{\tan \,\,x\,\, - \,\,2}}{{2\tan \,\,x\,\, + \,\,1}}}}\,\, + \,\,c
Option A (log⁡etan⁡,x−22tan⁡,x+15+c{\log _e}\sqrt[5]{{\frac{{\tan \\,x - 2}}{{2\tan \\,x + 1}}}}\\ + \\ c) is correct because the integral is solved by dividing by cos2(x) and using partial fractions.
866 Easy
866 of 995
Application +4 | -1
∫log⁡(x+1)dx=\int \log (x+1) d x=
View answer and explanation
Correct option: A
(x+1)log⁡(x+1)−x+c(x+1) \log (x+1)-x+c
Option A ((x+1)log⁡(x+1)−x+c(x+1) \log (x+1)-x+c) is correct because it is the result of integrating log⁡(x+1)\log(x+1) using integration by parts.
867 Easy
867 of 995
Analyzing +4 | -1
∫dxcos⁡(2x)cos⁡(4x)\int \frac{d x}{\cos (2 x) \cos (4 x)} is equal to
View answer and explanation
Correct option: A
122log⁡∣1+2sin⁡2x1−2sin⁡2x∣−12(log⁡∣sec⁡2x−tan⁡2x∣)+C\frac{1}{2 \sqrt{2}} \log \left|\frac{1+\sqrt{2} \sin 2 x}{1-\sqrt{2} \sin 2 x}\right|-\frac{1}{2}(\log |\sec 2 x-\tan 2 x|)+C
Option A is correct because after using trigonometric identities and integrating, the result matches the given expression.
868 Easy
868 of 995
Analyzing +4 | -1
The value of ∫(1+x2)dx(1−x2)1+x2+x4\int \frac{\left(1+x^2\right) d x}{\left(1-x^2\right) \sqrt{1+x^2+x^4}}, is
View answer and explanation
Correct option: A
−123log⁡∣x4+x2+1−3xx4+x2+1+3x∣+C-\frac{1}{2 \sqrt{3}} \log \left|\frac{\sqrt{x^4+x^2+1}-\sqrt{3} x}{\sqrt{x^4+x^2+1}+\sqrt{3} x}\right|+C
Option A (−123log⁡∣x4+x2+1−3xx4+x2+1+3x∣+C-\frac{1}{2 \sqrt{3}} \log \left|\frac{\sqrt{x^4+x^2+1}-\sqrt{3} x}{\sqrt{x^4+x^2+1}+\sqrt{3} x}\right|+C) is correct because the integral simplifies to this logarithmic form after appropriate substitutions.
869 Easy
869 of 995
Analyzing +4 | -1
If ∫f(x)dx=f(x)\int f(x) d x=f(x), then ∫{f(x)}2dx\int\{f(x)\}^2 d x is equal to
View answer and explanation
Correct option: A
12{f(x)}2\frac{1}{2}\{f(x)\}^2
Option A (12f(x)2\frac{1}{2}{f(x)}^2) is correct because if ∫f(x)dx=f(x)\int f(x) dx = f(x), then f(x)=Cexf(x) = Ce^x, and ∫f(x)2dx=12f(x)2\int {f(x)}^2 dx = \frac{1}{2}{f(x)}^2.
870 Easy
870 of 995
Application +4 | -1
If ∫f(x)dx=f(x)\int f(x) d x=f(x), then ∫{f(x)}2dx\int\{f(x)\}^2 d x is equal to
View answer and explanation
Correct option: A
12{f(x)}2\frac{1}{2}\{f(x)\}^2
Option A (12{f(x)}2\frac{1}{2}\{f(x)\}^2) is correct because the integral of the square of the function is half the square of the function, given the initial condition.
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