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JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Mixed difficulty

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751 Easy
751 of 995
Application +4 | -1
∫  x  −  1x  +  1  dx\int \,\,\sqrt {\frac{{x\,\, - \,\,1}}{{x\,\, + \,\,1}}\,\,dx} is equal to
View answer and explanation
Correct option: B
x2−  1−  sin⁡−1  x+c\sqrt {{x^2} - \,\,1} - \,\,{\sin ^{ - 1}}\,\,x + c
Option B (x2− 1− sin⁡−1 x+c\sqrt {{x^2} - \,1} - \,{\sin ^{ - 1}}\,x + c) is correct because it is the result of simplifying the integrand and using appropriate integration techniques.
752 Medium
752 of 995
Application +4 | -1
If ∫  cos⁡4 x  dx=Ax  +  B  sin⁡  2 x  +  C  sin⁡  4x  +  D\int \,\,{\cos ^4}\,x\,\,dx = Ax\,\, + \,\,B\,\,\sin \,\,2\,x\,\, + \,\,C\,\,\sin \,\,4x\,\, + \,\,D , then {A,B,C} equals
View answer and explanation
Correct option: B
{38,  14,  132}\left\{ {\frac{3}{8},\,\,\frac{1}{4},\,\,\frac{1}{{32}}} \right\}
Option B ({38,,14,,132}\left\{{{\frac{3}{8},\\,\frac{1}{4},\\,\frac{1}{{32}}}}\right\}) is correct because the integral of cos⁡4x\cos^4 x is evaluated using trigonometric identities and then the coefficients are matched.
753 Medium
753 of 995
Analyzing +4 | -1
∫ (x+2x+4)2ex dx\int \,{\left( {\frac{{x + 2}}{{x + 4}}} \right)^2}{e^x}\,dx is equal to
View answer and explanation
Correct option: A
ex  (xx  +  4)  +  c{e^x}\,\,\left( {\frac{x}{{x\,\, + \,\,4}}} \right)\,\, + \,\,c
Option A is correct because the integral simplifies to ex (xx  +  4)  +  c{e^x}\,\left( {\frac{x}{{x\,\, + \,\,4}}} \right)\,\, + \,\,c after applying integration by parts and simplification.
754 Easy
754 of 995
Application +4 | -1
∫dx(x+1)  4x+3\int \frac{{dx}}{{\left( {x + 1} \right)\,\,\sqrt {4x + 3} }} is equal to
View answer and explanation
Correct option: C
2 tan⁡−1  4x+3  +  c2\,{\tan ^{ - 1}}\,\,\sqrt {4x + 3} \,\, + \,\,c
Option C (2 tan⁡−1 4x + 3 + c2\,{\tan ^{ - 1}}\,\sqrt {4x\, + \,3} \, + \,c) is correct because it is the result of the integration after substitution and simplification.
755 Easy
755 of 995
Understanding +4 | -1
∫  cos⁡  x  +  x  sin⁡  xx2  +  x  cos⁡  x    dx\int \,\,\frac{{\cos \,\,x\,\, + \,\,x\,\,\sin \,\,x}}{{{x^2}\,\, + \,\,x\,\,\cos \,\,x}}\,\,\;dx is equal to
View answer and explanation
Correct option: D
log⁡  ∣ xx  +  cos⁡  x ∣+c\log \,\,\left| {\,\frac{x}{{x\,\, + \,\,\cos \,\,x}}\,} \right| + c
Option D, \log \,\left| {\,\frac{x}{{x\,+\cos \,x}}\} \right| + c\log \,\left| {\,\frac{x}{{x\,+\cos \,x}}\} \right| + c, is correct because the integral simplifies to this form after algebraic manipulation and recognizing the derivative in the denominator.
756 Easy
756 of 995
Application +4 | -1
The value of ∫1+sin⁡x1−sin⁡xdx\int \frac{1+\sin x}{1-\sin x} d x is
View answer and explanation
Correct option: C
2tan⁡(x2+π4)−x+C2 \tan \left(\frac{x}{2}+\frac{\pi}{4}\right)-x+C
Option C (2tan⁡(x2+π4)−x+C2 \tan \left(\frac{x}{2}+\frac{\pi}{4}\right)-x+C) is correct because it is the result of integrating the given expression and simplifying using trigonometric identities.
757 Easy
757 of 995
Analyzing +4 | -1
∫cos⁡x−sin⁡xcos⁡x+sin⁡x(2+2sin⁡2x)dx\int \frac{\cos x-\sin x}{\cos x+\sin x}(2+2 \sin 2 x) d x is equal to
View answer and explanation
Correct option: A
sin⁡2x+C\sin 2 x+C
Option A (sin⁡2x+C\sin 2 x+C) is correct because the integral simplifies to 2∫cos⁡2xdx2 \int \cos 2x dx, which equals sin⁡2x+C\sin 2x + C.
758 Easy
758 of 995
Application +4 | -1
∫extan⁡2(ex)dx=\int e^x \tan ^2\left(e^x\right) d x=
View answer and explanation
Correct option: D
tan⁡(ex)−ex+c\tan \left(e^x\right)-e^x+c
Option D (tan⁡(ex)−ex+c\tan \left(e^x\right)-e^x+c) is correct because the integral simplifies to this form after substitution and integration.
759 Medium
759 of 995
Analyzing +4 | -1
Let ff be a polynomial function such that for all real x,f(x2+1)=x4+5x2+2x, f\left(x^2+1\right)=x^4+5 x^2+2, then ∫f(x)dx\int f(x) d x is
View answer and explanation
Correct option: A
x33+3x22−2x+c\frac{x^3}{3}+\frac{3 x^2}{2}-2 x+c
Option A, x33+3x22−2x+c\frac{x^3}{3}+\frac{3 x^2}{2}-2 x+c, is correct because by substituting x2+1x^2+1 into f, we can determine f(x) and then integrate it.
760 Medium
760 of 995
Analyzing +4 | -1
∫sin⁡x−cos⁡x(sin⁡x+cos⁡x)sin⁡xcos⁡x+sin⁡2xcos⁡2xdx=\int \frac{\sin x-\cos x}{(\sin x+\cos x) \sqrt{\sin x \cos x+\sin ^2 x \cos ^2 x}} d x=
View answer and explanation
Correct option: C
−Sec⁡−1(sin⁡2x+1)+c-\operatorname{Sec}^{-1}(\sin 2 x+1)+c
The correct answer is C (−Sec⁡−1(sin⁡2x+1)+c-\operatorname{Sec}^{-1}(\sin 2 x+1)+c) because the integral simplifies to a standard inverse secant form after appropriate trigonometric manipulations and substitution.
761 Medium
761 of 995
Application +4 | -1
If ∫asin⁡x+bcos⁡xcsin⁡x+dcos⁡xdx=px+qlog⁡e∣csin⁡x+dcos⁡x∣+c\int \frac{a \sin x+b \cos x}{c \sin x+d \cos x} d x=p x+q \log _e|c \sin x+d \cos x|+c where p+qp+q is equal to
View answer and explanation
Correct option: A
c(a+b)−d(a−b)c2+d2\frac{c(a+b)-d(a-b)}{c^2+d^2}
Option A (c(a+b)−d(a−b)c2+d2\frac{{c(a+b)-d(a-b)}}{{c^2+d^2}}) is correct because it represents the value of p+qp+q obtained by decomposing the integrand and integrating.
762 Easy
762 of 995
Analyzing +4 | -1
If ∫cos⁡4x+1cot⁡x−tan⁡xdx=kcos⁡4x+c\int \frac{\cos 4 x+1}{\cot x-\tan x} d x=k \cos 4 x+c then
View answer and explanation
Correct option: B
k=−1/8k=-1 / 8
Option B (k=−1/8k=-1 / 8) is correct because after simplifying the integral and solving, the value of k is found to be -1/8.
763 Easy
763 of 995
Analyzing +4 | -1
If ∫  log⁡  (1−x  +  1+x)dx=x   f(x)+Ax+B  sin⁡−1x+C\int \,\,\log \,\,\left( {\sqrt {1 - x} \,\, + \,\,\sqrt {1 + x} } \right)dx = x\,\;f\left( x \right) + Ax + B\,\,{\sin ^{ - 1}}x + C, then
View answer and explanation
Correct option: A
f(x)=log⁡  (1−x  +  1+x)f\left( x \right) = \log \,\,\left( {\sqrt {1 - x} \,\, + \,\,\sqrt {1 + x} } \right)
Option A (f(x)=log⁡  (1−x  +  1+x)f\left( x \right) = \log \,\,\left( {\sqrt {1 - x} \,\, + \,\,\sqrt {1 + x} } \right)) is correct because after integrating by parts, the function f(x) matches this logarithmic expression.
764 Easy
764 of 995
Understanding +4 | -1
∫cosec⁡2x1+cot⁡xdx=\int \frac{\operatorname{cosec}^2 x}{1+\cot x} d x=
View answer and explanation
Correct option: B
−log⁡(1+cot⁡x)+c-\log (1+\cot x)+c
Option B (log⁡(1+cot⁡x)+c\log (1+\cot x)+c) is correct because substituting t=1+cot⁡xt = 1 + \cot x leads to a simple logarithmic integral.
765 Easy
765 of 995
Application +4 | -1
∫ex(1−cot⁡x+cot⁡2x)dx=\int e^x\left(1-\cot x+\cot ^2 x\right) d x=
View answer and explanation
Correct option: B
−excot⁡x+C-e^x \cot x+C
Option B (−excot⁡x+C-e^x \cot x+C) is correct because the integral simplifies to this form by recognizing the derivative of −cot⁡x-\cot x is 1+cot⁡2x=csc⁡2x1 + \cot^2 x = \csc^2 x.
766 Easy
766 of 995
Application +4 | -1
∫1xcos⁡2(1+log⁡x)dx=\int \frac{1}{x \cos ^2(1+\log x)} d x=
View answer and explanation
Correct option: A
tan⁡(1+log⁡x)+c\tan (1+\log x)+c
Option A, tan⁡(1+log⁡x)+c\tan (1+\log x)+c, is the correct answer because it results from a direct substitution and integration of the given expression.
767 Medium
767 of 995
Application +4 | -1
If Fn(x)=∫(log⁡x)ndxF_n(x)=\int(\log x)^n d x and ϕn=Fn+nFn−1\phi_n=F_n+n F_{n-1}, then ϕn(e)−ϕn(1)\phi_n(e)-\phi_n(1) is equal to
View answer and explanation
Correct option: D
ee
Option D is correct because by using integration by parts, we find that φ_n(x) = x(log x)^n + c, and then φ_n(e) - φ_n(1) = e.
768 Easy
768 of 995
Analyzing +4 | -1
If ∫sec⁡4/3xcosec⁡8/3x dx=a(tan⁡x)−5/3+b(tan⁡x)1/3+C,\int \sec ^{4 / 3} x \operatorname{cosec}^{8 / 3} x \,d x=a(\tan x)^{-5 / 3}+b(\tan x)^{1 / 3}+C, then 5a+b=5 a+b=
View answer and explanation
Correct option: C
0
Option C is correct because after simplifying and integrating, we find that 5a+b=05a + b = 0.
769 Medium
769 of 995
Application +4 | -1
Let ff be a real-valued function defined on the interval (−1, 1)\left( { - 1,\,1} \right) such that e−x  f  (x)=2  +  ∫0x  t4  +  1  dt{e^{ - x}}\,\,f\,\,\left( x \right) = 2\,\, + \,\,\int \nolimits_0^x \,\,\sqrt {{t^4}\,\, + \,\,1} \,\,dt, for all x∈(−1,  1)x \in \left( { - 1,\,\,1} \right) and let f−1{f^{ - 1}} be the inverse function of ff. Then, (f−1)′  (2){\left( {{f^{ - 1}}} \right)^\prime }\,\,\left( 2 \right) is equal to
View answer and explanation
Correct option: B
13\frac{1}{3}
Option B (1/3) is correct because after differentiating and using the inverse function property, the derivative of the inverse function at 2 is found to be 1/3.
770 Easy
770 of 995
Application +4 | -1
If ∫  ex  (1−  sin⁡  x1  −  cos⁡  x)  dx=f(x)  +  constant\int \,\,{e^x}\,\,\left( {\frac{{1 - \,\,\sin \,\,x}}{{1\,\, - \,\,\cos \,\,x}}} \right)\,\,dx = f\left( x \right)\,\, + \,\,\mathrm{constant}, then f(x)f\left( x \right) is equal to
View answer and explanation
Correct option: C
− ex  cot⁡  (x2)  +  c- \,{e^x}\,\,\cot \,\,\left( {\frac{x}{2}} \right)\,\, + \,\,c
Option C ( −,ex cot⁡,(x2)+,c\ - \\,{e^x}\\\,\cot \\,\left( {\frac{x}{2}} \right)\\ + \\,c) is correct because the integral is solved by using trigonometric identities to simplify the integrand and then recognizing a pattern for integration.
771 Easy
771 of 995
Application +4 | -1
The value of I=2∫sin⁡xsin⁡(x−π/4)dxI=\sqrt{2} \int \frac{\sin x}{\sin (x-\pi / 4)} d x is
View answer and explanation
Correct option: C
x+log⁡∣sin⁡(x−π/4)∣+Cx+\log |\sin (x-\pi / 4)|+C
Option C is correct because the integral can be solved by using a substitution and trigonometric identities.
772 Easy
772 of 995
Application +4 | -1
∫log⁡xdxx3=\int \frac{\log x d x}{x^3}=
View answer and explanation
Correct option: B
−14x2(2log⁡x+1)+c-\frac{1}{4 x^2}(2 \log x+1)+c
Option B (−14x2(2log⁡x+1)+c-\frac{{1}}{{4 x^2}}(2 \log x+1)+c) is correct because it is the result of integrating the given expression using integration by parts.
773 Medium
773 of 995
Application +4 | -1
Let f(x)=∫x(1+x)2dx(x≥0)f(x)=\int \frac{\sqrt{x}}{(1+x)^2} d x(x \geq 0). Then f(3)−f(1)f(3)-f(1) is equal to :
View answer and explanation
Correct option: D
π12+12−34\frac{\pi}{12}+\frac{1}{2}-\frac{\sqrt{3}}{4}
Option D π12+12−34\frac{\pi}{12}+\frac{1}{2}-\frac{\sqrt{3}}{4} is correct because it is the result of evaluating the definite integral after appropriate substitution and simplification.
774 Easy
774 of 995
Analyzing +4 | -1
If x is any arbitrary constant, then ∫  222x  .  22x  .  2x  dx\int \,\,{2^{{2^{{2^x}}}}}\,\,.\,\,{2^{{2^x}}}\,\,.\,\,{2^x}\,\,dx is equal to
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the integral evaluates to 222x(log⁡ 2)3 + c\frac{{{2^{{2^{{2^x}}}}}}}{{{{\left( {\log \,2} \right)}^3}}}\, + \,c, which is not any of the given options.
775 Easy
775 of 995
Application +4 | -1
∫  1+x1−x  dx\int \,\,\sqrt {\frac{{1 + x}}{{1 - x}}} \,\,dx is equal to
View answer and explanation
Correct option: C
sin⁡−1  x  −  1  −  x2 +  c{\sin ^{ - 1}}\,\,x\,\, - \,\,\sqrt {1\,\, - \,\,{x^2}} \, + \,\,c
Option C (sin⁡−1 x − 1 − x2 + c{\sin ^{ - 1}}\,x\, - \,\sqrt {1\, - \,{x^2}} \, + \,c) is correct because after simplifying the integral and using substitution, we arrive at this result.
776 Easy
776 of 995
Application +4 | -1
∫etan⁡−1x1+x2dx=\int \frac{e^{\tan ^{-1} x}}{1+x^2} d x=
View answer and explanation
Correct option: C
etan⁡−1x+ce^{\tan ^{-1} x}+c
Option C is correct because the integral can be solved using a simple substitution.
777 Easy
777 of 995
Analyzing +4 | -1
If ∫2x+59x2+6x+2dx=a9x2+6x+2+blog⁡e(3x+1+9x2+6x+2)+c\int \frac{2 x+5}{\sqrt{9 x^2+6 x+2}} d x =a \sqrt{9 x^2+6 x+2}+b \log _e\left(3 x+1+\sqrt{9 x^2+6 x+2}\right)+c then 9(a+b)9(a+b) is equal to
View answer and explanation
Correct option: C
41
Option C (41) is correct because after evaluating the integral and comparing coefficients, 9(a+b) equals 41.
778 Medium
778 of 995
Application +4 | -1
∫sin⁡xsin⁡x−cos⁡xdx\int \frac{\sin x}{\sin x-\cos x} d x equals
View answer and explanation
Correct option: A
12log⁡e∣sin⁡x−cos⁡x∣+x2+c\frac{1}{2} \log _e|\sin x-\cos x|+\frac{x}{2}+c
Option A is correct because the integral is solved by rewriting the numerator and separating the integral into simpler parts, resulting in (1/2)log_e|sinx-cosx| + x/2 + c.
779 Easy
779 of 995
Application +4 | -1
∫x−2/3(1+x1/3)1/2dx\int x^{-2 / 3}\left(1+x^{1 / 3}\right)^{1 / 2} d x is equal to
View answer and explanation
Correct option: B
2(1+x1/3)3/2+c2\left(1+x^{1 / 3}\right)^{3 / 2}+c
Option B (2(1+x1/3)3/2+c2(1+x^{1/3})^{3/2}+c) is correct because it is the result of integrating the given expression using substitution.
780 Easy
780 of 995
Analyzing +4 | -1
The value of ∫ ex  1  +  nxn−1  −  x2n(1  −  xn)  1  −  x2n  dx\int \,{e^x}\,\,\frac{{1\,\, + \,\,n{x^{n - 1}}\,\, - \,\,{x^{2n}}}}{{\left( {1\,\, - \,\,{x^n}} \right)\,\,\sqrt {1\,\, - \,\,{x^{2n}}} }}\,\,dx is equal to
View answer and explanation
Correct option: D
ex 1−x2n1−xn  +  c\frac{{{e^x}\,\sqrt {1 - {x^{2n}}} }}{{1 - {x^n}}}\,\, + \,\,c
Option D (ex 1−x2n1−xn + c\frac{{{e^x}\,\sqrt {1 - {x^{2n}}} }}{{1 - {x^n}}}\, + \,c) is correct because it is the result of integrating the given expression by recognizing the form of ex[f(x)+f′(x)]e^x[f(x) + f'(x)].
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