Skip to main content
Back to INDEFINITE INTEGRATION

Your Progress

0 / 995 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Mixed difficulty

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 691-720 of 995 questions

Preparing practice and saved progress…

691 Medium
691 of 995
Application +4 | -1
∫(tan⁡  x  +  cot⁡  x)dx\int \left( {\sqrt {\tan \,\,x} \,\, + \,\,\sqrt {\cot \,\,x} } \right)dx is equal to
View answer and explanation
Correct option: A
2  sin⁡−1 (sin⁡  x  −  cos⁡  x)  +  c\sqrt 2 \,\,{\sin ^{ - 1}}\,(\sin \,\,x\,\, - \,\,\cos \,\,x)\,\, + \,\,c
Option A is correct because the integral simplifies to a form that can be solved using a trigonometric substitution, resulting in the given arcsine function.
692 Easy
692 of 995
Application +4 | -1
If In=∫  xn .  ecx   dx     for     n  ≥  1,   then  c . In  +  n . In−1{I_n} = \int \,\,{x^n}\,.\,\,{e^{cx}}\;\,dx\;\;\,\mathrm{for}\,\;\;n\,\, \ge \,\,1,\,\;\mathrm{then}\,\,c\,.\,{I_n}\,\, + \,\,n\,.\,{I_{n - 1}} is equal to

View answer and explanation
Correct option: A
xn ecx{x^n}\,{e^{cx}}
Option A (xn ecx{x^n}\,{e^{cx}}) is correct because integrating by parts and rearranging the terms leads to the given expression.
693 Easy
693 of 995
Analyzing +4 | -1
∫x4+1x6+1dx\int \frac{x^4+1}{x^6+1} d x is equal to
View answer and explanation
Correct option: A
tan⁡−1x+13tan⁡−1x3+C\tan ^{-1} x+\frac{1}{3} \tan ^{-1} x^3+C
Option A (tan⁡−1x+13tan⁡−1x3+C\tan ^{-1} x+\frac{1}{3} \tan ^{-1} x^3+C) is correct because by factoring the denominator and simplifying the integrand, the integral can be expressed as the sum of two standard integrals.
694 Easy
694 of 995
Application +4 | -1
∫sin⁡3x⋅cos⁡xdx=\int \sin ^3 x \cdot \cos x d x=
View answer and explanation
Correct option: B
sin⁡4x4+c\frac{\sin ^4 x}{4}+c
Option B (sin⁡4x4+c\frac{\sin ^4 x}{4}+c) is correct because it is the result of integrating the given expression using substitution.
695 Medium
695 of 995
Application +4 | -1
∫01  cot⁡−1  (1−x+x2)    dx\int \nolimits_0^1 \,\,{\cot ^{ - 1}}\,\,\left( {1 - x + {x^2}} \right)\;\,\,dx is equal to
View answer and explanation
Correct option: D
π2  −  log⁡  2\frac{\pi }{2}\,\, - \,\,\log \,\,2
Option D (π2 − log⁡ 2\frac{\pi }{2}\, - \,\log \,2) is correct because after rewriting the integral and using integration by parts, the result is π2−log⁡2\frac{\pi}{2} - \log 2.
696 Easy
696 of 995
Application +4 | -1
∫log⁡x(log⁡x+2)dx=\int \log x(\log x+2) d x=
View answer and explanation
Correct option: A
x(log⁡x)2+cx(\log x)^2+c
Option A (x(log⁡x)2+cx(\log x)^2+c) is correct because the integral evaluates to this expression after substitution and simplification.
697 Medium
697 of 995
Application +4 | -1
If ∫3sin⁡x+2cos⁡x2sin⁡x+3cos⁡xdx=lx+mlog⁡e∣2sin⁡x+3cos⁡x∣+c\int \frac{3 \sin x+2 \cos x}{2 \sin x+3 \cos x} d x=l x+m \log _e|2 \sin x+3 \cos x|+c then
View answer and explanation
Correct option: B
l=1213,m=−513l=\frac{12}{13}, m=-\frac{5}{13}
Option B (l=1213,m=−513l=\frac{{12}}{{13}}, m=-\frac{{5}}{{13}}) is correct because it is obtained by applying the formula derived from decomposing the integrand.
698 Medium
698 of 995
Application +4 | -1
If ∫(sin⁡2x−cos⁡2x)dx=12sin⁡(2x−a)+b\int(\sin 2 x-\cos 2 x) d x=\frac{1}{\sqrt{2}} \sin (2 x-a)+b, then
View answer and explanation
Correct option: D
a=−5π4,b=a=-\frac{5 \pi}{4}, b= any constant
Option B ([1,3/2]) is correct because it represents the interval where the expression inside the square root is non-negative.
699 Medium
699 of 995
Application +4 | -1
∫dxtan⁡x+cot⁡x+sec⁡x+cosec⁡x\int \frac{d x}{\tan x+\cot x+\sec x+\operatorname{cosec} x} is equal to
View answer and explanation
Correct option: C
12(sin⁡x−cos⁡x−x)+c\frac{1}{2}(\sin x-\cos x-x)+c
Option C (12(sin⁡x−cos⁡x−x)+c\frac{1}{2}(\sin x-\cos x-x)+c) is correct because after simplifying the integrand and integrating, this is the resulting expression.
700 Easy
700 of 995
Application +4 | -1
If ∫dx2sin⁡x−cos⁡x+5=Atan⁡−115f(x)+C\int \frac{\mathrm{d} x}{2 \sin x-\cos x+5}=A \tan ^{-1} \frac{1}{\sqrt{5}} f(x)+C, then
View answer and explanation
Correct option: A
A=1/5A=1 / \sqrt{5}
Option A (A=1/5A=1 / \sqrt{5}) is correct because after substitution and integration, the coefficient of the inverse tangent term is 1/51/\sqrt{5}.
701 Medium
701 of 995
Application +4 | -1
To evaluate ∫x3e3x2+5dx\int x^3 e^{3 x^2+5} d x, the simplest way is to
View answer and explanation
Correct option: B
Substitute (3x2+5)=t\left(3 x^2+5\right)=t
Option B (Substitute (3x2+5)=t\left(3 x^2+5\right)=t) is correct because this substitution simplifies the integral into a manageable form.
702 Medium
702 of 995
Application +4 | -1
∫  (2x12+  5x9)(x5+  x3+  1)3    dx\int \,\,\frac{{\left( {2{x^{12}} + \,\,5{x^9}} \right)}}{{{{\left( {{x^5} + \,\,{x^3} + \,\,1} \right)}^3}}}\,\,\;dx is equal to
View answer and explanation
Correct option: B
x102  (x5+  x3  +1)2  +  c\frac{{{x^{10}}}}{{2\,\,{{\left( {{x^5} + \,\,{x^3}\,\, + 1} \right)}^2}}}\,\, + \,\,c
Option B (x102  (x5+ x3 +1)2 + c\frac{{{x^{10}}}}{{2\,\,{{\left( {{x^5} + \,{x^3}\, + 1} \right)}^2}}}\, + \,c\) is correct because after substituting and integrating, we obtain the given result.
703 Easy
703 of 995
Application +4 | -1
∫ex(1−sin⁡x1−cos⁡x)dx\int \mathrm{e}^{\mathrm{x}}\left(\frac{1-\sin \mathrm{x}}{1-\cos \mathrm{x}}\right) \mathrm{dx} is equal to
View answer and explanation
Correct option: B
−excot⁡(x2)+C-\mathrm{e}^{\mathrm{x}} \cot \left(\frac{\mathrm{x}}{2}\right)+\mathrm{C}
Option B (−excot⁡(x2)+C-e^{x} \cot \left(\frac{x}{2}\right)+C) is correct because it is the result of integrating the given expression after simplification using trigonometric identities.
704 Easy
704 of 995
Analyzing +4 | -1
∫555x⋅  55x⋅  5x  dx\int {5^{{5^{{5^x}}}}} \cdot \,\,{5^{{5^x}}} \cdot \,\,{5^x}\;dx is equal to
View answer and explanation
Correct option: C
555x(log⁡  5)3  +  C\frac{{{5^{{5^{{5^x}}}}}}}{{{{\left( {\log \,\,5} \right)}^3}}}\,\, + \,\,C
Option A (1\mathrm{1}) is correct because the limit is evaluated by simplifying the integral and applying the limit definition.
705 Easy
705 of 995
Analyzing +4 | -1
If ∫cos⁡θ5+7sin⁡θ−2cos⁡2θ dθ  =A  log⁡e∣B(θ)∣+C,\int {\frac{{\cos \theta }}{{5 + 7\sin \theta - 2{{\cos }^2}\theta }}} \,d\theta \,\, = A\,\,{\log _e}\left| {B(\theta )} \right| + C, where CC is constant of integration, then B(θ)A\frac{{B(\theta )}}{A} can be
View answer and explanation
Correct option: D
5(2sin⁡θ+1)sin⁡θ+3\frac{{5(2\sin \theta + 1)}}{{\sin \theta + 3}}
Option D is correct because after integrating the given expression and simplifying, the result matches the form Alog⁡e∣B(θ)∣+CA \log_e |B(\theta)| + C, leading to the correct value of B(θ)A\frac{{B(\theta)}}{A}.
706 Easy
706 of 995
Application +4 | -1
∫(x3+3x2+3x+1)(x+1)5dx=\int \frac{\left(x^3+3 x^2+3 x+1\right)}{(x+1)^5} d x=
View answer and explanation
Correct option: A
−1(x+1)+c-\frac{1}{(x+1)}+c
Option A (−1(x+1)+c-\frac{{1}}{{(x+1)}}+c) is correct because the integral simplifies to this form after simplifying the fraction.
707 Easy
707 of 995
Analyzing +4 | -1
The integral ∫2x  −  3(x2+  x  +1)2  dx\int \frac{{2x\,\, - \,\,3}}{{{{\left( {{x^2} + \,\,x\,\, + 1} \right)}^2}}}\,\,dx is equal to
View answer and explanation
Correct option: A
−  8x+7x2+x+1  −  163 3  tan⁡−1  (2x+13)+C- \,\,\frac{{8x + 7}}{{{x^2} + x + 1}}\,\, - \,\,\frac{{16}}{{3\,\sqrt 3 }}\,\,{\tan ^{ - 1}}\,\,\left( {\frac{{2x + 1}}{3}} \right) + C
Option A is the correct answer because the integral can be solved by breaking it into parts and using trigonometric substitution to evaluate the remaining integral.
708 Medium
708 of 995
Application +4 | -1
For what value of aa and bb, the equation ∫(sin⁡2x−cos⁡2x)dx=12sin⁡(2x−a)+b holds good.\int(\sin 2 x-\cos 2 x) d x=\frac{1}{\sqrt{2}} \sin (2 x-a)+b \text { holds good.}
View answer and explanation
Correct option: A
a=−5π4,ba=-\frac{5 \pi}{4}, b is any arbitrary constant
Option A (a=−5π4a = -\frac{{5 \pi}}{{4}}, b is any arbitrary constant) is correct because integrating and comparing with the given form yields the value of a.
709 Medium
709 of 995
Analyzing +4 | -1
Let g(x)g(x) be a differentiable function satisfying ddx{g(x)}=g(x)\frac{d}{d x}\{g(x)\}=g(x) and g(0)=1g(0)=1, then
∫g(x)(2−sin⁡2x1−cos⁡2x)dx\int g(x)\left(\frac{2-\sin 2 x}{1-\cos 2 x}\right) d x is equal to
View answer and explanation
Correct option: B
−g(x)cot⁡x+C-g(x) \cot x+C
The correct answer is B (−g(x)cot⁡x+C-g(x) \cot x+C) because given the properties of g(x)g(x), the integral simplifies and can be solved using integration techniques.
710 Easy
710 of 995
Application +4 | -1
∫(x3)  (1  +  x435)  dx\int \left( {\sqrt[3]{x}} \right)\,\,\left( {\sqrt[5]{{1\,\, + \,\,\sqrt[3]{{{x^4}}}}}} \right)\,\,dx is equal to
View answer and explanation
Correct option: C
58  (1  +  x43)65  +  c\frac{5}{8}\,\,{\left( {1\,\, + \,\,{x^{\frac{4}{3}}}} \right)^{\frac{6}{5}}}\,\, + \,\,c
Option C (58(1,+,x43)65+,c\frac{5}{8}\left( {1\\,\\ + \\,{x^{\frac{{4}}{{3}}}}} \right)^{\frac{{6}}{{5}}}\\ + \\,c) is correct because it is the result of integrating the given expression after a suitable substitution.
711 Easy
711 of 995
Application +4 | -1
∫dx1+ex=\int \frac{d x}{1+e^x}=
View answer and explanation
Correct option: B
−log⁡(1+e−x)-\log \left(1+e^{-x}\right)
Option B is correct because the integral can be rewritten and solved using a substitution, resulting in −log⁡(1+e−x)-\log(1+e^{-x}).
712 Medium
712 of 995
Application +4 | -1
∫(sin⁡x+cos⁡x)(2−sin⁡2x)sin⁡22xdx=\int \frac{(\sin x+\cos x)(2-\sin 2 x)}{\sin ^2 2 x} d x=
View answer and explanation
Correct option: B
sin⁡x−cos⁡xsin⁡2x+c\frac{\sin x-\cos x}{\sin 2 x}+c
Option B (sin⁡x−cos⁡xsin⁡2x+c\frac{\sin x-\cos x}{\sin 2 x}+c) is correct because the integral simplifies to this expression after a suitable substitution.
713 Medium
713 of 995
Application +4 | -1
∫  exlog⁡a ex  dx\int \,\,{e^{x\log a}}\,{e^x}\;dx is equal to
View answer and explanation
Correct option: D
(ae)xlog⁡e  ae  +  c\frac{{{{\left( {ae} \right)}^x}}}{{{{\log }_e}\,\,ae}}\,\, + \,\,c
Option D ((ae)xlog⁡e ae + c\frac{{{{\left( {ae} \right)}^x}}}{{{{\log }_e}\,ae}}\, + \,c\) is correct because the integral of exlog⁡aexe^{x\log a}e^x simplifies to (ae)xlog⁡e ae + c\frac{{{{\left( {ae} \right)}^x}}}{{{{\log }_e}\,ae}}\, + \,c.
714 Medium
714 of 995
Application +4 | -1
If ∫x+sin⁡x1+cos⁡x dx=f(x)tan⁡x2+C\int \frac{x+\sin x}{1+\cos x} \mathrm{~d} x=f(x) \tan \frac{x}{2}+C
View answer and explanation
Correct option: B
f(x)=xf(x)=x
Option B (f(x)=xf(x)=x) is correct because after integration and simplification, the given integral equals xtan⁡x2+Cx \tan \frac{x}{2}+C.
715 Easy
715 of 995
Application +4 | -1
If ∫  1x+x5  dx=f(x)+c\int \,\,\frac{1}{{x + {x^5}}}\,\,dx = f\left( x \right) + c, then the value of ∫x4x+x5   dx\int \frac{{{x^4}}}{{x + {x^5}}}\,\;dx equals
View answer and explanation
Correct option: A
log⁡  x  −  f  (x)  +  c\log \,\,x\,\, - \,\,f\,\,\left( x \right)\,\, + \,\,c
Option A (log⁡  x  −  f  (x)  +  c\log \,\,x\,\, - \,\,f\,\,\left( x \right)\,\, + \,\,c) is correct because it is obtained by manipulating the integrand and using the given integral.
716 Easy
716 of 995
Application +4 | -1
If ∫1+cos⁡8xtan⁡2x−cot⁡2xdx=acos⁡8x+C\int \frac{1+\cos 8 x}{\tan 2 x-\cot 2 x} d x=a \cos 8 x+C, then a=a=
View answer and explanation
Correct option: C
116\frac{1}{16}
Option C (116\frac{1}{16}) is correct because after simplifying the integral, the coefficient of cos⁡8x\cos 8x is 116\frac{1}{16}.
717 Medium
717 of 995
Analyzing +4 | -1
∫xm−1xm+11−2xm+mx2mdx=f(x)mxm+c\int \frac{x^m-1}{x^{m+1} \sqrt{1-2 x^m+m x^{2 m}}} d x=\frac{f(x)}{m x^m}+c where f(x)f(x) is equal to
View answer and explanation
Correct option: A
1−2xm+mx2m\sqrt{1-2 x^m+m x^{2 m}}
Option A (1−2xm+mx2m\sqrt{{1-2 x^m+m x^{2 m}}}) is correct because the integral simplifies to this expression after substitution and algebraic manipulation.
718 Easy
718 of 995
Application +4 | -1
∫333x33x3x dx\int 3^{3^{3^x}} 3^{3^x} 3^x \mathrm{~d} x is equal to
View answer and explanation
Correct option: C
3335(log⁡3)3+C\frac{3^{3^{3^5}}}{(\log 3)^3}+C
Option C is correct because after applying the substitution t=333xt = 3^{3^{3^x}}, the integral simplifies to 333x(log⁡3)3+C\frac{3^{3^{3^x}}}{(\log 3)^3}+C.
719 Easy
719 of 995
Application +4 | -1
The integral ∫dxx2(x4+1)34\int \frac{d x}{x^2\left(x^4+1\right)^{\frac{3}{4}}} equals
View answer and explanation
Correct option: D
−(x4+1x4)14+C-\left(\frac{x^4+1}{x^4}\right)^{\frac{1}{4}}+C
Option D (−(x4+1x4)14+C-\left(\frac{{x^4+1}}{{x^4}}\right)^{\frac{{1}}{{4}}}+C) is correct because it represents the result of the given integral after applying substitution and simplification.
720 Medium
720 of 995
Analyzing +4 | -1
The value of the integral ∫  ex  (1−x1+x)2 dx\int \,\,{e^x}\,\,{\left( {\frac{{1 - x}}{{1 + x}}} \right)^2}\,dx is
View answer and explanation
Correct option: C
ex1+x2  +  c\frac{{{e^x}}}{{1 + {x^2}}}\,\, + \,\,c
Option C is correct because the integral can be solved by rewriting the integrand and using integration by parts, leading to the result e^x / (1 + x2) + c.
Revision notes and key takeaways

Review INDEFINITE INTEGRATION in your textbook or class notes, then use this set to check your understanding.

Showing 691-720 of 995 questions

Your practice

0 / 995 answered · 995 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.