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JEE • MATHEMATICS • INDEFINITE INTEGRATION

Indefinite integration practice · Mixed difficulty

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Showing 631-660 of 995 questions

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631 Medium
631 of 995
Application +4 | -1
∫3x2+2xx6+2x5+x4−2x3−2x2+5dx\int \frac{3 x^2+2 x}{\sqrt{x^6+2 x^5+x^4-2 x^3-2 x^2+5}} d x equals
View answer and explanation
Correct option: A
sinh⁡−1(x3+x2−12)+c\sinh ^{-1}\left(\frac{x^3+x^2-1}{2}\right)+c
Option A (sinh⁡−1(x3+x2−12)+c\sinh ^{-1}\left(\frac{x^3+x^2-1}{2}\right)+c) is correct because it results from completing the square and using the inverse hyperbolic sine integral.
632 Easy
632 of 995
Understanding +4 | -1
Let ff and gg be two polynomials then ∫(f(x)g′′(x)−f′′(x)g(x))dx\int\left(f(x) g^{\prime \prime}(x)-f^{\prime \prime}(x) g(x)\right) \mathrm{d} x is equal to (ignoring the constant of integration)
View answer and explanation
Correct option: C
f(x)g′(x)−f′(x)g(x)f(x) g^{\prime}(x)-f^{\prime}(x) g(x)
Option C (f(x)g′(x)−f′(x)g(x)f(x) g^{\prime}(x)-f^{\prime}(x) g(x)) is correct because it is the result of applying integration by parts twice to the given integral.
633 Easy
633 of 995
Application +4 | -1
∫  [ea  log⁡  x  +  ex  log⁡  a]  dx  =...+  c  ;  a,  x  >1\int \,\,\left[ {{e^{a\,\,\log \,\,x}}\,\, + \,\,{e^{x\,\,\log \,\,a}}} \right]\,\,dx\,\, = ... + \,\,c\,\,;\,\,a,\,\,x\,\, > 1
View answer and explanation
Correct option: A
xa+1a+1  +  axlog⁡  a\frac{{{x^{a + 1}}}}{{a + 1}}\,\, + \,\,\frac{{{a^x}}}{{\log \,\,a}}
Option A is correct because the integral of the given expression simplifies to the sum of a power function and an exponential function, which matches option A.
634 Easy
634 of 995
Analyzing +4 | -1
If I1=∫sin⁡−1x dx{I_1} = \int {\sin ^{ - 1}}x\,dx and I2=∫sin⁡−1  1  −  x2  dx{I_2} = \int {\sin ^{ - 1}}\,\,\sqrt {1\,\, - \,\,{x^2}} \;dx, then
View answer and explanation
Correct option: C
I1+  I2=π2  x{I_1} + \,\,{I_2} = \frac{\pi }{2}\,\,x
Option C (I1+ I2=π2 x{I_1} + \, {I_2} = \frac{\pi }{2}\,x) is correct because the sum of the integrals simplifies to an integral involving the constant π2\frac{\pi}{2}.
635 Easy
635 of 995
Application +4 | -1
If ∫f(x)dx=F(x)\int f(x) d x=F(x), then ∫x3f(x2)dx\int x^3 f\left(x^2\right) d x is equal to
View answer and explanation
Correct option: B
12[x2F(x2)−∫F(x2)d(x2)]\frac{1}{2}\left[x^2 F\left(x^2\right)-\int F\left(x^2\right) d\left(x^2\right)\right]
Option B (12[x2F(x2)−∫F(x2)d(x2)]\frac{1}{2}[x^2 F(x^2)-\int F(x^2) d(x^2)] ) is correct because it is the result of applying integration by parts to the integral ∫x3f(x2)dx\int x^3 f(x^2) dx with a suitable substitution.
636 Easy
636 of 995
Analyzing +4 | -1
∫x2−1xx4+3x2+1dx\int \frac{x^2-1}{x \sqrt{x^4+3 x^2+1}} d x is equal to
View answer and explanation
Correct option: A
log⁡e∣x+1x+x2+1x2+3∣+C\log _e\left|x+\frac{1}{x}+\sqrt{x^2+\frac{1}{x^2}+3}\right|+C
Option A (log⁡e∣x+1x+x2+1x2+3∣+C\log _e\left|x+\frac{1}{x}+\sqrt{x^2+\frac{1}{x^2}+3}\right|+C) is correct because after dividing by x2x^2 and completing the square, the integral can be solved using a standard logarithmic form.
637 Medium
637 of 995
Analyzing +4 | -1
∫ex1+10x9−x20(1−x10)1−x20dx\int e^x \frac{1+10 x^9-x^{20}}{\left(1-x^{10}\right) \sqrt{1-x^{20}}} d x is equal to: (where cc is an integral constant)
View answer and explanation
Correct option: C
ex(1+x101−x10)+c\quad e^x\left(\sqrt{\frac{1+x^{10}}{1-x^{10}}}\right)+c
Option C (ex(1+x101−x10)+ce^x\left(\sqrt{{\frac{{1+x^{{10}}}}{{1-x^{{10}}}}}}\right)+c) is correct because the integral can be expressed in the form ∫ex(f(x)+f′(x))dx=exf(x)+c\int e^x (f(x) + f'(x)) dx = e^x f(x) + c.
638 Easy
638 of 995
Application +4 | -1
∫exsin⁡xdx=\int e^x \sin x d x=
View answer and explanation
Correct option: B
12ex(sin⁡x−cos⁡x)+c\frac{1}{2} e^x(\sin x-\cos x)+c
Option B (12ex(sin⁡x−cos⁡x)+c\frac{1}{2} e^x(\sin x-\cos x)+c) is correct because it is the result of applying integration by parts twice to the integral of exsin⁡xe^x \sin x.
639 Easy
639 of 995
Analyzing +4 | -1
The integral ∫2x12+5x9(x5+x3+1)3dx\int \frac{2 x^{12}+5 x^9}{\left(x^5+x^3+1\right)^3} d x is equal to
where, CC is an arbitrary constant.
View answer and explanation
Correct option: B
x102(x5+x3+1)2+C\frac{x^{10}}{2\left(x^5+x^3+1\right)^2}+C
Option B is correct because after substitution and simplification, the integral evaluates to the given expression.
640 Easy
640 of 995
Application +4 | -1
The value of ∫1+xxdx\int \frac{\sqrt{1+x}}{x} d x, is
View answer and explanation
Correct option: A
21+x+log⁡∣1+x−11+x+1∣+C2 \sqrt{1+x}+\log \left|\frac{\sqrt{1+x}-1}{\sqrt{1+x}+1}\right|+C
Option A is correct because the integral is solved using a substitution method, resulting in the given expression with a logarithmic term.
641 Easy
641 of 995
Application +4 | -1
∫  1x(xn+1)  dx\int \,\,\frac{1}{{x\left( {{x^n} + 1} \right)}}\,\,dx is equal to
View answer and explanation
Correct option: A
1n  log⁡  (xnxn+1)  +  C\frac{1}{n}\,\,\log \,\,\left( {\frac{{{x^n}}}{{{x^n} + 1}}} \right)\,\, + \,\,C
Option A (1n  log⁡  (xnxn+1) + C\frac{1}{n}\,\,\log \,\,\left( {\frac{{{x^n}}}{{{x^n} + 1}}} \right)\, + \,C) is correct because the integral is solved using substitution and partial fractions.
642 Easy
642 of 995
Understanding +4 | -1
∫ex(1x−1x2)dx=\int e^x\left(\frac{1}{x}-\frac{1}{x^2}\right) d x=
View answer and explanation
Correct option: C
exx+c\frac{e^x}{x}+c
Option C (exx+c\frac{{e^x}}{{x}}+c) is correct because the integral is of the form ∫ex[f(x)+f′(x)]dx=exf(x)+c\int e^x [f(x) + f'(x)] dx = e^x f(x) + c, where f(x)=1xf(x) = \frac{{1}}{{x}} and f′(x)=−1x2f'(x) = -\frac{{1}}{{x^2}}.
643 Easy
643 of 995
Application +4 | -1
∫1xcos⁡2(1+log⁡x)dx=\int \frac{1}{x \cos ^2(1+\log x)} d x=
View answer and explanation
Correct option: A
tan⁡(1+log⁡x)+c\tan (1+\log x)+c
Option A is correct because the integral simplifies to tan⁡(1+log⁡x)+c\tan(1 + \log x) + c after applying the substitution method.
644 Easy
644 of 995
Application +4 | -1
∫010  ∣ x  (x−1)  (x−2)∣  dx  is   equal   to\int \nolimits_0^{10} \,\,\left| {\,x\,\,\left( {x - 1} \right)\,\,\left( {x - 2} \right)} \right|\,\,dx\,\,\mathrm{is}\,\mathrm{\;equal\;}\,\mathrm{to} is equal to
View answer and explanation
Correct option: B
1600.5
The correct answer is A (1600.5) because the integral is evaluated by splitting the integral into intervals where the function inside the absolute value is either positive or negative.
645 Easy
645 of 995
Application +4 | -1
If ∫  dx5+4  cos⁡  x=A  tan⁡−1(B  tan⁡  x/2)  +  C\int \,\,\frac{{dx}}{{5 + 4\,\,\cos \,\,x}} = A\,\,{\tan ^{ - 1}}\left( {B\,\,\tan \,\,x/2} \right)\,\, + \,\,C, then
View answer and explanation
Correct option: B
A=2/3,   B=1/3A = 2/3,\;\,B = 1/3
Option B (A=2/3,   B=1/3A = 2/3,\;\,B = 1/3) is correct because after applying trigonometric substitutions and integrating, the values of A and B match the given form.
646 Easy
646 of 995
Application +4 | -1
∫  ex(log⁡  sin⁡  x  +  cot⁡  x)  dx\int \,\,{e^x}\left( {\log \,\,\sin \,\,x\,\, + \,\,\cot \,\,x} \right)\,\,dx is equal to
View answer and explanation
Correct option: B
ex  log⁡  sin⁡  x  +  c{e^x}\,\,\log \,\,\sin \,\,x\,\, + \,\,c
Option B (ex  log⁡  sin⁡  x  +  c{e^x}\,\,\log \,\,\sin \,\,x\,\, + \,\,c) is correct because the integral matches the form ∫ex[f(x)+f′(x)]dx=exf(x)+c\int e^x [f(x) + f'(x)] dx = e^x f(x) + c, where f(x)=log⁡(sin⁡x)f(x) = \log(\sin x).
647 Medium
647 of 995
Application +4 | -1
∫x−sin⁡x1−cos⁡xdx=\int \frac{x-\sin x}{1-\cos x} d x=
View answer and explanation
Correct option: B
−xcot⁡x2+c-x \cot \frac{x}{2}+c
Option B (−xcot⁡x2+c-x \cot \frac{x}{2}+c) is correct because it results from integrating the given expression after using trigonometric identities and integration by parts.
648 Easy
648 of 995
Understanding +4 | -1
∫10x9+10xlog⁡e1010x+x10dx=\int \frac{10 x^9+10^x \log _e 10}{10^x+x^{10}} d x=
View answer and explanation
Correct option: B
log⁡(10x+x10)+c\log \left(10^x+x^{10}\right)+c
Option B (log⁡(10x+x10)+c\log \left(10^x+x^{10}\right)+c) is correct because the derivative of the denominator is exactly the numerator.
649 Easy
649 of 995
Application +4 | -1
∫x9(4x2+1)6dx\int \frac{x^9}{\left(4 x^2+1\right)^6} d x is equal to
View answer and explanation
Correct option: D
110(1x2+4)−5+C\frac{1}{10}\left(\frac{1}{\mathrm{x}^2}+4\right)^{-5}+\mathrm{C}
Option D (110(1x2+4)−5+C\frac{{1}}{{10}}(\frac{{1}}{{x^2}}+4)^{-5}+C) is correct because simplifying the integral and using substitution leads to this result.
650 Easy
650 of 995
Analyzing +4 | -1
∫  (1+x−x−1)ex+x−1  dx\int \,\,\left( {1 + x - {x^{ - 1}}} \right){e^{x + {x^{ - 1}}}}\,\,dx is equal to
View answer and explanation
Correct option: D
xex+x−1  +  cx{e^{x + {x^{ - 1}}}}\,\, + \,\,c
Option D (xex+x−1 + cx{e^{x + {x^{ - 1}}}}\, + \,c) is correct because by using integration by parts, the integral simplifies to this expression.
651 Medium
651 of 995
Application +4 | -1
∫  dxsin⁡  x−cos⁡  x+2\int \,\,\frac{{dx}}{{\sin \,\,x - \cos \,\,x + \sqrt 2 }} equals
View answer and explanation
Correct option: C
12  cot⁡  (x2  +  π8)  +  c\frac{1}{{\sqrt 2 }}\,\,\cot \,\,\left( {\frac{x}{2}\,\, + \,\,\frac{\pi }{8}} \right)\,\, + \,\,c
Option D (−12cot⁡(x2+π8)+,c- \frac{1}{{\sqrt 2 }}\cot \left( {\frac{x}{2} + \frac{\pi }{8}} \right)\\ + \\,c) is the correct result after simplifying the integral using trigonometric identities and substitution.
652 Medium
652 of 995
Application +4 | -1
If ∫f(x)dx=F(x)\int f(x) d x=F(x), then ∫x3f(x2)dx\int x^3 f\left(x^2\right) d x is equal to
View answer and explanation
Correct option: B
12[x2F(x2)−∫F(x2)d(x2)]\frac{1}{2}\left[x^2 F\left(x^2\right)-\int F\left(x^2\right) d\left(x^2\right)\right]
Option B (12[x2F(x2)−∫F(x2)d(x2)]\frac{1}{2}\left[x^2 F\left(x^2\right)-\int F\left(x^2\right) d\left(x^2\right)\right]) is correct because it uses integration by parts with appropriate substitutions.
653 Easy
653 of 995
Application +4 | -1
I=∫x2−1x32x4−2x2+1dxI=\int \frac{x^2-1}{x^3 \sqrt{2 x^4-2 x^2+1}} d x equal to
View answer and explanation
Correct option: D
2x4−2x2+12x2+C\frac{\sqrt{2 x^4-2 x^2+1}}{2 x^2}+C
Option D is correct because the integral can be solved by substitution after manipulating the expression.
654 Easy
654 of 995
Application +4 | -1
If ∫f(x)dx=ψ(x)\int f(x) d x=\psi(x), then ∫x5f(x3)dx\int x^5 f\left(x^3\right) d x is equal to
View answer and explanation
Correct option: C
13x3ψ(x3)−∫x2ψ(x3)dx+C\frac{1}{3} x^3 \psi\left(x^3\right)-\int x^2 \psi\left(x^3\right) d x+C
Option C (13x3ψ(x3)−∫x2ψ(x3)dx+C\frac{{1}}{{3}} x^3 \psi(x^3)-\int x^2 \psi(x^3) dx+C) is correct because it represents the result of the given integral after applying substitution and integration by parts.
655 Medium
655 of 995
Application +4 | -1
The value of ∫(tan⁡−1(sin⁡x+1))cos⁡x(3+2sin⁡x−cos⁡2x)dx\int \frac{\left(\tan ^{-1}(\sin x+1)\right) \cos x}{\left(3+2 \sin x-\cos ^2 x\right)} d x is (where c\mathrm{c} is the constant integration)
View answer and explanation
Correct option: C
(tan⁡−1(sin⁡x+1))22+c\frac{\left(\tan ^{-1}(\sin x+1)\right)^2}{2}+c
Option C ((tan⁡−1(sin⁡x+1))22+c\frac{{(\tan^{-1}(\sin x+1))^2}}{{2}}+c) is correct because it is the result of the integration after a suitable substitution.
656 Easy
656 of 995
Application +4 | -1
∫log⁡x(1+log⁡x)2dx=\int \frac{\log x}{(1+\log x)^2} d x=
View answer and explanation
Correct option: C
x1+log⁡x+c\frac{x}{1+\log x}+c
Option C (x1+log⁡x+c\frac{{x}}{{1+\log x}}+c) is correct because the integral evaluates to this expression after substitution and simplification.
657 Medium
657 of 995
Application +4 | -1
If B=∫1ex+1dx=−f(x)+CB=\int \frac{1}{e^x+1} d x=-f(x)+C, where, CC is the constant of integration and ef(0)=2e^{f(0)}=2, then the value of ef(−1)e^{f(-1)} is
View answer and explanation
Correct option: B
e+1{e}+1
Option B (e+1) is correct because it is the value obtained after evaluating the integral, finding f(x), and substituting x = -1 into the exponential of f(x).
658 Easy
658 of 995
Application +4 | -1
The value of ∫3x+2(x−2)2  (x−3)  dx\int \frac{{3x + 2}}{{{{\left( {x - 2} \right)}^2}\,\,\left( {x - 3} \right)}}\;dx is
View answer and explanation
Correct option: C
11    log⁡  x−3x−2  +  8x−2+c11\,\,\;\log \,\,\frac{{x - 3}}{{x - 2}}\,\, + \,\,\frac{8}{{x - 2}} + c
Option C (11   log⁡  x−3x−2  +  8x−2+c11\,\;\log \,\,\frac{{x - 3}}{{x - 2}}\,\, + \,\,\frac{8}{{x - 2}} + c) is correct because it is the result of integrating the given rational function using partial fraction decomposition.
659 Easy
659 of 995
Application +4 | -1
The function ff whose graph passes through (4,−20)(4,-20) and whose derivative is cos⁡(4−x)\cos (\sqrt{4-x}) is given by
View answer and explanation
Correct option: D
−(2x+12)4−xsin⁡4−x+(4−6x)cos⁡4−x-(2 x+12) \sqrt{4-x} \sin \sqrt{4-x} \\ +(4-6 x) \cos \sqrt{4-x}
Option C (−2(4−xsin⁡4−x+cos⁡4−x)−18-2(\sqrt{4-x} \sin \sqrt{4-x}+\cos \sqrt{4-x})-18) is correct because integrating the derivative and using the given point yields this function.
660 Easy
660 of 995
Application +4 | -1
∫1sin⁡3x  cos⁡  xdx\int \frac{1}{{\sqrt {{{\sin }^3}x\,\,\cos \,\,x} }}dx is equal to
View answer and explanation
Correct option: A
− 2tan⁡  x+C\frac{{ - \,2}}{{\sqrt {\tan \,\,x} }} + C
Option A (− 2tan⁡  x+C\frac{{ - \,2}}{{\sqrt {\tan \,\,x} }} + C) is correct because after rewriting the integrand in terms of tan(x), a simple substitution and power rule integration yields the result.
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