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JEE • MATHEMATICS • DIFFERENTIATION

Differentiation practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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211 Medium
211 of 402
Application +4 | -1
If ln⁡(x+y)=2xy\ln (x+y)=2 x y, then y′(0)=y^{\prime}(0)=
View answer and explanation
Correct option: A
1
Option A is correct because it is the result of implicit differentiation and substitution to find y'(0).
212 Medium
212 of 402
Understanding +4 | -1
Let f(x)f\left( x \right) be a function such that f′(a)≠0f'\left( a \right) \ne 0. Then,at x=a,  f(x)x = a,\;f\left( x \right)
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because a function can have a minimum or maximum even if its derivative is not zero at a point (e.g., at a cusp or endpoint).
213 Medium
213 of 402
Application +4 | -1
If xexy=y+sin⁡2xx e^{x y}=y+\sin ^2 x, then at x=0,dydxx=0, \frac{d y}{d x} is equal to
View answer and explanation
Correct option: B
1
Option B is correct because substituting x=0 into the differentiated equation yields dy/dx = 1.
214 Medium
214 of 402
Application +4 | -1
y=(tan⁡x)(tan⁡x)tan⁡xy=(\tan x)^{(\tan x)^{\tan x}}, then at x=π4x=\frac{\pi}{4}, the value of dydx\frac{d y}{d x} is equal to
View answer and explanation
Correct option: C
2
Option C is correct because at x=pi/4, the derivative simplifies to 2 after substituting the value.
215 Medium
215 of 402
Application +4 | -1
If y=sin⁡−1(5x+121−x213)y = {\sin ^{ - 1}}\left( {\frac{{5x + 12\sqrt {1 - {x^2}} }}{{13}}} \right), then dydx\frac{{dy}}{{dx}} is equal to
View answer and explanation
Correct option: A
11−x2\frac{1}{{\sqrt {1 - {x^2}} }}
Option A (11−x2\frac{1}{{\sqrt {1 - {x^2}} }}) is correct because after simplification using trigonometric identities, the derivative can be easily found.
216 Medium
216 of 402
Application +4 | -1
If xy=tan⁡−1(xy)+cot⁡−1(xy)xy = {\tan ^{ - 1}}\left( {xy} \right) + {\cot ^{ - 1}}\left( {xy} \right), then dydx\frac{{dy}}{{dx}} is equal to
View answer and explanation
Correct option: B
−yx- \frac{y}{x}
Option B (−yx- \frac{y}{x}) is correct because after using the identity tan⁡−1(x)+cot⁡−1(x)=π2\tan^{-1}(x) + \cot^{-1}(x) = \frac{\pi}{2}, the derivative simplifies to −yx- \frac{y}{x}.
217 Medium
217 of 402
Analyzing +4 | -1
If f(x)=x3+x2+f′(1)+xf′′(2)+f′′′(3),∀x∈Rf\left( x \right) = {x^3} + {x^2} + f'\left( 1 \right) + xf''\left( 2 \right) + f'''\left( 3 \right),\forall x \in R where f(x)f\left( x \right) is a polynomial of degree 3, then
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because when we solve for the coefficients of the cubic polynomial, all the given relations hold true.
218 Medium
218 of 402
Application +4 | -1
If x=3t1+t2,y=3t21+t2x=\frac{3 t}{1+t^2}, y=\frac{3 t^2}{1+t^2}, then dy/dxd y / d x at t=2t=2 is
View answer and explanation
Correct option: C
−43-\frac{4}{3}
Option C (−43-\frac{{4}}{{3}}) is correct because it is the value of dydx\frac{{dy}}{{dx}} calculated using parametric differentiation at t=2t=2.
219 Medium
219 of 402
Application +4 | -1
If y=tan⁡−1(sec⁡x−tan⁡x),y = {\tan ^{ - 1}}(\sec x - \tan x), then dydx\frac{{dy}}{{dx}} is
View answer and explanation
Correct option: D
−12- \frac{1}{2}
Option D (−12- \frac{1}{2}) is correct because after simplifying the expression inside the inverse tangent and differentiating, the result is −12- \frac{1}{2}.
220 Medium
220 of 402
Application +4 | -1
The derivative of f(x)=3∣2+x∣f\left( x \right) = 3\left| {2 + x} \right| at the point x0=−3{x_0} = - 3, is
View answer and explanation
Correct option: B
−3- 3
Option B (−3- 3) is correct because the derivative of f(x)=3∣2+x∣f(x) = 3|2 + x| at x0=−3x_0 = -3 is -3, as the function is defined as f(x)=−3(2+x)f(x) = -3(2+x) for x<−2x < -2.
221 Medium
221 of 402
Application +4 | -1
Let ff and gg be differentiable functions and f′(x)=2g(x)f^{\prime}(x)=2 g(x) and g(x)=−f(x)g(x)=-f(x) and let T(x)=(f(x))2−(g(x))2T′(x)=T(x)=(f(x))^2-(g(x))^2 \quad T^{\prime}(x)=
View answer and explanation
Correct option: D
6f(x)g(x)6 f(x) g(x)
Option D (6f(x)g(x)6 f(x) g(x)) is correct because it is the result of differentiating T(x)T(x) using the product rule and substituting the given derivatives of f(x)f(x) and g(x)g(x).
222 Medium
222 of 402
Application +4 | -1
If xy=ex−y{x^y} = {e^{x - y}}, then dydx\frac{{dy}}{{dx}} is equal to
View answer and explanation
Correct option: C
log⁡x.(1+log⁡x)−2\log x.{\left( {1 + \log x} \right)^{ - 2}}
Option C, log⁡x.(1+log⁡x)−2\log x.{\left( {1 + \log x} \right)^{ - 2}}, is correct because it represents the derivative dy/dx obtained by implicit differentiation and simplification of the given equation xy=ex−y{x^y} = {e^{x - y}}.
223 Medium
223 of 402
Application +4 | -1
If y=(log⁡x)x+xlog⁡xy=(\log x)^x+x^{\log x}, then dydx=\frac{d y}{d x}=
View answer and explanation
Correct option: A
(log⁡x)x[log⁡(log⁡x)+1log⁡x]+xlog⁡x⋅(2log⁡xx)(\log x)^x\left[\log (\log x)+\frac{1}{\log x}\right]+x^{\log x} \cdot\left(\frac{2 \log x}{x}\right)
Option A is correct because it accurately applies the chain rule and logarithmic differentiation to find the derivative of the given function.
224 Medium
224 of 402
Application +4 | -1
Let y=xxx…y = {x^{{x^{x \ldots }}}}, then dydx\frac{{dy}}{{dx}} is equal to
View answer and explanation
Correct option: B
y2x(1−ylog⁡x)\frac{{{y^2}}}{{x(1 - y\log x)}}
Option B (y2x(1−ylog⁡x)\frac{{{y^2}}}{{x(1 - y\log x)}}) is correct because it results from applying logarithmic differentiation to the given function and solving for dydx\frac{{dy}}{{dx}}.
225 Medium
225 of 402
Understanding +4 | -1
If f(x)f\left( x \right) is a polynomial of degree n(>2)n\left( { > 2} \right) and f(x)=f(α−x)f\left( x \right) = f\left( {\alpha - x} \right), (where α\alpha is fixed real number), then the degree of f′(x)f'\left( x \right) is
View answer and explanation
Correct option: B
n−1n - 1
Option B (n−1n - 1) is correct because the derivative of a polynomial of degree nn is a polynomial of degree n−1n-1.
226 Medium
226 of 402
Analyzing +4 | -1
If y=cos⁡2x  cos⁡3xy = \cos 2x\,\,\cos 3x, then yn{y_n} is equal to
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because the nth derivative of the product of cosine functions involves a sum of cosine functions with arguments adjusted by nπ/2, and the given options do not match the correct form.
227 Medium
227 of 402
Application +4 | -1
If f(x)=alog⁡e∣x∣+bx2+xf(x)=a \log _{e}|x|+b x^{2}+x has extremum at x=1x=1 and x=3x=3, then
View answer and explanation
Correct option: A
a=−3/4,b=−1/8a=-3 / 4, b=-1 / 8
Option A (a=−3/4,b=−1/8a=-3 / 4, b=-1 / 8) is correct because these values satisfy the conditions for the function to have extrema at x=1 and x=3.
228 Medium
228 of 402
Understanding +4 | -1
If ϕ(x)\phi \left( x \right) is the inverse of the function f(x)f\left( x \right) and f′(x)=11+x5,f'\left( x \right) = \frac{1}{{1 + {x^5}}}, then ddxϕ(x)\frac{d}{{dx}}\phi \left( x \right)
View answer and explanation
Correct option: C
1+{ϕ(x)}51 + {\left\{ {\phi \left( x \right)} \right\}^5}
Option C (1+{ϕ(x)}51 + {\{\phi (x)\}^5}) is correct because it is derived from the inverse function differentiation rule.
229 Medium
229 of 402
Application +4 | -1
The derivative of tan⁡−1(1+x1−x)\tan ^{-1}\left(\frac{1+x}{1-x}\right) is
View answer and explanation
Correct option: B
11+x2\frac{1}{1+x^2}
Option B (11+x2\frac{1}{1+x^2}) is correct because after substituting x=tan⁡θx = \tan \theta and simplifying the expression, the derivative is found to be 11+x2\frac{1}{1+x^2}.
230 Medium
230 of 402
Application +4 | -1
Let 3f(x)−2f(1x)=x,3f\left( x \right) - 2f\left( {\frac{1}{x}} \right) = x, then f′(2)f'\left( 2 \right) is equal to
View answer and explanation
Correct option: B
12\frac{1}{2}
Option B (12\frac{1}{2}) is correct because it is the value of the derivative f′(2)f'(2) after solving for f(x)f(x) and differentiating.
231 Medium
231 of 402
Application +4 | -1
If f(x)=xnf(x)=x^n, then the value of f(1)+f′(1)⌊1‾+f′′(1)2‾+f′′′(1)3‾+⋯+f(n)(1)n‾n‾f(1)+\frac{f^{\prime}(1)}{\lfloor\underline{1}}+\frac{f^{\prime \prime}(1)}{\underline{2}}+\frac{f^{\prime \prime \prime}(1)}{\underline{3}}+\cdots+\frac{f^{(n)}(1)}{\underline{n} \underline{n}} is
View answer and explanation
Correct option: B
2n2^n
Option B (2n2^n) is correct because the given expression is the binomial expansion of (1+1)n(1+1)^n, which equals 2n2^n.
232 Medium
232 of 402
Analyzing +4 | -1
The derivative of sin⁡−1(2x1−x2){\sin ^{ - 1}}\left( {2x\sqrt {1 - {x^2}} } \right) with respect to sin⁡−1(3x−4x3){\sin ^{ - 1}}\left( {3x - 4{x^3}} \right) is
View answer and explanation
Correct option: A
23\frac{2}{3}
Option A (23\frac{2}{3}) is correct because by substituting x=sin⁡θx = \sin \theta, the expression simplifies, and the derivative becomes a simple ratio.
233 Medium
233 of 402
Application +4 | -1
If y=(f∘fof)(x)y=(f \circ f o f)(x) and f(0)=0,f′(0)=2f(0)=0, f^{\prime}(0)=2, then y′(0)y^{\prime}(0) is equal to
View answer and explanation
Correct option: C
8
Option C (8) is correct because it follows from the chain rule applied to composite functions.
234 Medium
234 of 402
Application +4 | -1
If y=xlog⁡exy=x^{\log _{\mathrm{e}} x}, then dydx\frac{d y}{d x} equals
View answer and explanation
Correct option: A
2x(log⁡ax−1)⋅log⁡ex2 x^{\left(\log _a x-1\right)} \cdot \log _e x
Option A (2x(log⁡ax−1)⋅log⁡ex2 x^{\left(\log _a x-1\right)} \cdot \log _e x) is correct because by applying logarithmic differentiation, we can find the derivative of the given function.
235 Medium
235 of 402
Application +4 | -1
If cos⁡−1(x2−y2x2+y2)=log⁡ a,{\cos ^{ - 1}}\left( {\frac{{{x^2} - {y^2}}}{{{x^2} + {y^2}}}} \right) = \log \,a, then dydx\frac{{dy}}{{dx}} is
View answer and explanation
Correct option: C
yx\frac{y}{x}
Option C (yx\frac{y}{x}) is correct because it is the derivative dy/dx obtained after simplifying the given equation using trigonometric identities and differentiating implicitly.
236 Medium
236 of 402
Analyzing +4 | -1
If f(x)={1,x<01+sin⁡x,0≤x≤π2f\left( x \right) = \left\{ {\begin{array}{cccccccccccccccccccc} {1,x < 0}\\ {1 + \sin x,0 \le x \le \frac{\pi }{2}} \end{array}} \right. then derivative of f(x)f\left( x \right) at x=0x = 0
View answer and explanation
Correct option: D
Does not exist
Option D (Does not exist) is correct because the left-hand derivative and right-hand derivative at x=0x = 0 are not equal.
237 Medium
237 of 402
Application +4 | -1
If y=log⁡2{log⁡2(x)}\mathrm{y}=\log _2\left\{\log _2(\mathrm{x})\right\}, then dydx\frac{d y}{d x} is
View answer and explanation
Correct option: A
log⁡2exln⁡x\frac{\log _2 \mathrm{e}}{\mathrm{x} \ln \mathrm{x}}
Option A (log⁡2exln⁡x\frac{\log _2 \mathrm{e}}{\mathrm{x} \ln \mathrm{x}}) is correct because it is the result of applying the chain rule and change of base formula to differentiate the given logarithmic function.
238 Medium
238 of 402
Application +4 | -1
Let ϕ(x)\phi \left( x \right) be the inverse of the function f(x)f\left( x \right) and f′(x)=11+x5f'\left( x \right) = \frac{1}{{1 + {x^5}}}, then ddxϕ(x)\frac{d}{{dx}}\phi \left( x \right) is equal to
View answer and explanation
Correct option: C
1+[ϕ(x)]51 + {\left[ {\phi \left( x \right)} \right]^5}
Option C (1+[ϕ(x)]51 + {\left[ {\phi \left( x \right)} \right]^5}) is correct because it is the derivative of the inverse function, calculated using the given derivative of the original function.
239 Medium
239 of 402
Application +4 | -1
For the function f(x)=x100100+x9999+…+x22+x+1,f(x)=\frac{x^{100}}{100}+\frac{x^{99}}{99}+\ldots+\frac{x^2}{2}+x+1, f′(1)=mf′(0),f^{\prime}(1)=m f^{\prime}(0), where mm is equal to
View answer and explanation
Correct option: C
100
Option C (100) is correct because f'(1) = 100 and f'(0) = 1, so f'(1) = 100f'(0).
240 Medium
240 of 402
Application +4 | -1
Let f(x+y)=f(x)f(y)f\left( {x + y} \right) = f\left( x \right)f\left( y \right) for all x,y∈Rx,y \in R. f′(1)=2f'\left( 1 \right) = 2 and f(4)=4f\left( 4 \right) = 4, then f′(4)f'\left( 4 \right) equal to
View answer and explanation
Correct option: D
8
Option D (8) is correct because by using the given functional equation and derivative information, we can find f'(4).
Revision notes and key takeaways

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