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JEE • MATHEMATICS • DIFFERENTIAL EQUATIONS

Differential equations practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 241-270 of 494 questions

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241 Easy
241 of 494
Understanding +4 | -1
The differential equation of all the lines in the xyx y-plane is
View answer and explanation
Correct option: C
d2ydx2=0\frac{d^2 y}{d x^2}=0
Option C (d2ydx2=0\frac{{d^2 y}}{{d x^2}}=0) is correct because the general equation of a line is y = mx + c, and its second derivative with respect to x is always zero.
242 Easy
242 of 494
Application +4 | -1
Let x=x(y)x = x\left( y \right) be the solution of the differential equation 2yexy2dx+(y2−4xexy2)dy=02y{e^{\frac{x}{{{y^2}}}}}dx + \left( {{y^2} - 4x{e^{\frac{x}{{{y^2}}}}}} \right)dy = 0 such that x(1)=0.x\left( 1 \right) = 0. Then x(e)x\left( e \right) is equal to
View answer and explanation
Correct option: D
−e2log⁡e(2)- {e^2}{\log _e}\left( 2 \right)
Option D (-e²logₑ(2)) is correct because it is the value of x(e) obtained by solving the given differential equation with the initial condition x(1) = 0.
243 Easy
243 of 494
Analyzing +4 | -1
The order of the differential equation of family of curves y=C1sin⁡−1x+C2cos⁡−1x+C3tan⁡−1x+C4cot⁡−1xy=C_1 \sin ^{-1} x+C_2 \cos ^{-1} x+C_3 \tan ^{-1} x+C_4 \cot ^{-1} x (where C1,C2,C3C_1, C_2, C_3 and C4C_4 are arbitrary constants) is
View answer and explanation
Correct option: C
4
Option D (None of These) is correct because after simplification, the given equation has only two independent arbitrary constants, making the order of the differential equation 2.
244 Easy
244 of 494
Understanding +4 | -1
The differential equation of all parabola whose axis of symmetry is parallel to xx-axis is of order
View answer and explanation
Correct option: B
3
Option B (3) is correct because the general equation of a parabola whose axis of symmetry is parallel to the x-axis has three arbitrary constants, thus the differential equation is of order 3.
245 Easy
245 of 494
Application +4 | -1
If the differential equation of the family of curve given by y=Ax+Be2xy=A x+B e^{2 x}, where AA and BB are arbitrary constants, is of the form (1−2x)ddx(dydx+ly)+k(dydx+ly)=0(1-2 x) \frac{d}{d x}\left(\frac{d y}{d x}+l y\right)+k\left(\frac{d y}{d x}+l y\right)=0, then the ordered pair (k,l)(k, l) is
View answer and explanation
Correct option: A
(2,−2)(2,-2)
Option A, (2,−2)(2,-2), is the correct ordered pair (k,l)(k, l) obtained by finding the differential equation of the given family of curves.
246 Easy
246 of 494
Analyzing +4 | -1
If mm and nn are the order and degree of the differential equation (d2ydx2)5+4(d2ydx2)3d3ydx3+d3ydx3=x2−1,\left(\frac{d^2 y}{d x^2}\right)^5+4 \frac{\left(\frac{d^2 y}{d x^2}\right)^3}{\frac{d^3 y}{d x^3}}+\frac{d^3 y}{d x^3}=x^2-1, then
View answer and explanation
Correct option: B
m=3,n=2m=3, n=2
Option B (m=3,n=2m=3, n=2) is correct because the order of a differential equation is the highest order derivative present, and the degree is the power of the highest order derivative after the equation has been made polynomial in derivatives.
247 Easy
247 of 494
Understanding +4 | -1
Order of the differential equation of the family of all concentric circles centred at (h,k)\left( {h,k} \right) is
View answer and explanation
Correct option: A
1
Option A (1) is correct because the family of concentric circles is defined by one parameter (the radius), leading to a first-order differential equation.
248 Easy
248 of 494
Application +4 | -1
The curve whose subtangent is nn times the abscissa of the point of contact and passes through (2,3)(2,3) represent
View answer and explanation
Correct option: D
a parabola with vertex origin and axes coincide with xx-axis for n=2n=2
Option D (a parabola with vertex origin and axes coincide with xx-axis for n=2n=2) is correct because the given condition leads to the equation yn=Cxy^n = Cx, which represents a parabola when n=2n=2 with vertex at the origin and axis along the x-axis.
249 Easy
249 of 494
Understanding +4 | -1
Which of the following is a second order of differential equation?
View answer and explanation
Correct option: B
y′y′′+y=sin⁡xy^{\prime} y^{\prime \prime}+y=\sin x
Option B (y′y′′+y=sin⁡xy^{\prime} y^{\prime \prime}+y=\sin x) is correct because it contains a second derivative (y′′y^{\prime \prime}) and no higher-order derivatives.
250 Easy
250 of 494
Application +4 | -1
The area of the region enclosed between the two circles x2+y2=1x^2+y^2=1 and (x−1)2+y2=1(x-1)^2+y^2=1, is
View answer and explanation
Correct option: A
(2π3−34)\left(\frac{2 \pi}{3}-\sqrt{\frac{3}{4}}\right)
Option A is correct because it represents the area of the intersection of two circles, calculated using geometry and trigonometry.
251 Easy
251 of 494
Application +4 | -1
If sin⁡x\sin x is an intergrating factor of the differential equation dydx+Py=Q,\frac{d y}{d x}+P y=Q, then PP can be
View answer and explanation
Correct option: B
cot⁡x\cot x
Option B (cot⁡x\cot x) is correct because if sin⁡x\sin x is the integrating factor, then PP must be the derivative of log⁡(sin⁡x)\log(\sin x), which is cot⁡x\cot x.
252 Easy
252 of 494
Application +4 | -1
An equation of the curve for which the portion of yy-axis cut off between the origin and the tangent varies as the cube of the abscissa of the point of contact is ( KK is constant of proportionality)
View answer and explanation
Correct option: C
y=−Kx3/2+Cxy=-K x^3 / 2+C x
The correct answer is C (y=−Kx3/2+Cxy=-K x^3 / 2+C x) because it satisfies the differential equation derived from the given condition about the y-intercept of the tangent.
253 Easy
253 of 494
Understanding +4 | -1
The order and degree of the differential equation y+d2ydx2=x+(dydx)32\sqrt {y + \frac{{{d^2}y}}{{d{x^2}}}} = x + {\left( {\frac{{dy}}{{dx}}} \right)^{\frac{3}{2}}} are
View answer and explanation
Correct option: A
2,22,2
Option A (2,2) is correct because, after squaring twice to remove the square roots, the highest order derivative is 2 and its power is 2.
254 Easy
254 of 494
Application +4 | -1
Let f(x),g(x)f(x), g(x) be twice differentiable function on [0,2][0,2] satisfying f′′(x)=g′′(x),f′(1)=2g′(1)=4f^{\prime \prime}(x)=g^{\prime \prime}(x), f^{\prime}(1)=2 g^{\prime}(1)=4 and f(2)=3,g(2)=9f(2)=3, g(2)=9, then the value of f(4)−g(4)f(4)-g(4) is
View answer and explanation
Correct option: D
-2
Option D (-2) is correct because it is the value obtained by integrating the given differential equation and using the provided conditions to find the constants.
255 Easy
255 of 494
Analyzing +4 | -1
Let y=y1(x)y=y_1(x) and y=y2(x)y=y_2(x) be two distinct solution of the differential equation dydx=x+y\frac{d y}{d x}=x+y, with y1(0)=0y_1(0)=0 and y2(0)=1y_2(0)=1 respectively. Then, the number of points of intersection of y=y1(x)y=y_1(x) and y=y2(x)y=y_2(x) is
View answer and explanation
Correct option: A
0
Option A (0) is correct because the two distinct solutions of the differential equation, given the initial conditions, never intersect, meaning they are parallel lines in a transformed space.
256 Easy
256 of 494
Application +4 | -1
The numbers P,Q and R for which the function f(x)=Pe2x+Qex+Rxf\left( x \right) = P{e^{2x}} + Q{e^x} + Rx satisfies the conditions f(0)=−1, f1(log⁡2)=31f\left( 0 \right) = - 1,\,{f^1}\left( {\log 2} \right) = 31 and ∫0log⁡4[f(x)−Rx]dx=392\int_0^{\log 4} {\left[ {f\left( x \right) - Rx} \right]dx=\frac{{39}}{2}} are given by
View answer and explanation
Correct option: D
P=5, Q=-6, R=3
Option D (P=5, Q=-6, R=3) is correct because these values satisfy all the given conditions for the function f(x).
257 Easy
257 of 494
Analyzing +4 | -1
Let ff be a differentiable function such that f′(x)=7−34f(x)x,  (x>0)f'\left( x \right) = 7 - \frac{3}{4}\frac{{f\left( x \right)}}{x},\,\,\left( {x > 0} \right) and f(1)≠4f\left( 1 \right) \ne 4. Then, lim⁡x→0+x f(1x)\lim\limits_{x \to {0^ + }} x\,f\left( {\frac{1}{x}} \right)
View answer and explanation
Correct option: D
Exists and equals 4
Option D (Exists and equals 4) is correct because by solving the given differential equation and finding the limit, we obtain a value of 4.
258 Easy
258 of 494
Application +4 | -1
A curve passes through the point (1,π/6)(1, \pi / 6). Let the slope of the curve at each point (x,y)(x, y) be yx+sec⁡(yx),x>0\frac{y}{x}+\sec \left(\frac{y}{x}\right), x>0. Then, the equation of the curve is
View answer and explanation
Correct option: A
sin⁡(yx)=log⁡x+12\sin \left(\frac{y}{x}\right)=\log x+\frac{1}{2}
Option A, sin⁡(yx)=log⁡x+12\sin \left(\frac{y}{x}\right)=\log x+\frac{1}{2}, is correct because it is the solution to the given differential equation that passes through the specified point.
259 Easy
259 of 494
Understanding +4 | -1
Solution of the differential equation dxx+dyy=0\frac{d x}{x}+\frac{d y}{y}=0, is
View answer and explanation
Correct option: C
xy=Cx y=C
Option C (xy=Cx y=C) is the correct solution because it is obtained by integrating the given differential equation and simplifying the result.
260 Easy
260 of 494
Application +4 | -1
A curve such that the area of the trapezoid formed by coordinate axes, ordinate at an arbitrary point and the tangent at this point equals half the square of its abscissa is
View answer and explanation
Correct option: B
y=(1/2)x+Cx2y=(1 / 2) x+C x^2
Option B (y=(1/2)x+Cx2y=(1 / 2) x+C x^2) is correct because it is the curve that satisfies the given condition about the trapezoid area.
261 Easy
261 of 494
Application +4 | -1
Let y=y(x)y=y(x) be the solution of the differential equation xlog⁡exdydx+y=x2log⁡ex,(x>1)x \log _e x \frac{d y}{d x}+y=x^2 \log _e x,(x>1). If y(2)=2y(2)=2, then y(e)y(e) is equal to
View answer and explanation
Correct option: C
4+e24\frac{4+e^2}{4}
Option C (4+e24\frac{{4+e^2}}{{4}}) is correct because it is the value of y(e) obtained by solving the given differential equation with the initial condition y(2)=2.
262 Easy
262 of 494
Application +4 | -1
Solution of differential equation dydx+yx=1(1+ℓnx+ℓny)\frac{\mathrm{dy}}{\mathrm{dx}}+\frac{\mathrm{y}}{\mathrm{x}}=\frac{1}{(1+\ell \mathrm{nx}+\ell \mathrm{ny})} is (where C\mathrm{C} is an integration constant)
View answer and explanation
Correct option: D
2xyℓn(xy)=x2+C2 x y \ell n(x y)=x^2+C
Option A (5) is correct because after simplifying the summation, we get tan⁡−12021\tan^{-1} \frac{20}{21}, so m+n = 41 and [log⁡241]=5\left[\log_2 41\right] = 5.
263 Easy
263 of 494
Application +4 | -1
The trajectories orthogonal to x2+y2=2axx^2+y^2=2 a x is
View answer and explanation
Correct option: B
y=C(x2+y2)y=C\left(x^2+y^2\right)
The correct answer is B (y=C(x2+y2)y=C(x^2+y^2)) because it represents the family of curves orthogonal to the given trajectories, found by solving the differential equation.
264 Easy
264 of 494
Application +4 | -1
Solution to 9yy′+4x=09 y y^{\prime}+4 x=0 represent
View answer and explanation
Correct option: B
family of ellipses
Option B (family of ellipses) is correct because the solution to the given differential equation represents an ellipse.
265 Easy
265 of 494
Understanding +4 | -1
The degree and order of the differential equation of the family of all parabolas whose axis is xx - axis, are respectively.
View answer and explanation
Correct option: C
1,2
Option C (1,2) is correct because the degree of the differential equation is 1 and the order is 2.
266 Easy
266 of 494
Understanding +4 | -1
The order and degree of differential equation [1+(dydx)2]=d2ydx2\left[1+\left(\frac{d y}{d x}\right)^2\right]=\frac{d^2 y}{d x^2} are
View answer and explanation
Correct option: C
2,1
Option C (2,1) is correct because the order is the highest derivative (2) and the degree is the power of the highest derivative (1).
267 Easy
267 of 494
Application +4 | -1
Let a smooth curve y=f(x)y=f(x) be such that the slope of the tangent at any point (x,y)(x, y) on it is directly proportional to (−yx)\left(\frac{-y}{x}\right). If the curve passes through the points (1,2)(1,2) and (8,1)(8,1), then ∣y(18)∣\left|y\left(\frac{1}{8}\right)\right| is equal to
View answer and explanation
Correct option: B
4
Option B (4) is correct because solving the differential equation and applying the given conditions leads to the equation of the curve, which allows us to find the value of |y(1/8)|.
268 Easy
268 of 494
Understanding +4 | -1
The solution of the equation d2ydx2=e−2x\frac{d^2 y}{d x^2}=e^{-2 x} is
View answer and explanation
Correct option: B
14e−2x+cx+d\frac{1}{4} e^{-2 x}+c x+d
Option B (14e−2x+cx+d\frac{{1}}{{4}} e^{-2 x}+c x+d) is the correct solution obtained by integrating the given second-order differential equation twice.
269 Easy
269 of 494
Application +4 | -1
The solution of differential equation yy′−x(y2x2+f(y2/x2)f′(y2/x2))y y^{\prime}-x\left(\frac{y^2}{x^2}+\frac{f\left(y^2 / x^2\right)}{f^{\prime}\left(y^2 / x^2\right)}\right) is
View answer and explanation
Correct option: A
f(y2/x2)−cx2f\left(y^2 / x^2\right)-c x^2
Option A is correct because it is the solution obtained by solving the given differential equation using the substitution method.
270 Easy
270 of 494
Application +4 | -1
The curves whose subtangents are proportional to the abscissas of the point of tangency (the proportionality factor is equal to kk ) is
View answer and explanation
Correct option: A
yk=Cxy^k=C x
Option A (yk=Cxy^k=C x) is correct because it is the solution obtained by integrating the differential equation formed from the given condition about subtangents.
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