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JEE • MATHEMATICS • DIFFERENTIAL EQUATIONS

Differential equations practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 494 questions

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271 Easy
271 of 494
Application +4 | -1
The solution of equation dydx=ax+qby+f\frac{d y}{d x}=\frac{a x+q}{b y+f} represents a circle only if
View answer and explanation
Correct option: B
a=−ba=-b
Option B (a=−ba=-b) is correct because for the given equation to represent a circle, the coefficients of x2x^2 and y2y^2 must be equal in magnitude and opposite in sign after integration.
272 Easy
272 of 494
Application +4 | -1
The differential equation for which sin⁡−1x+sin⁡−1y=c{\sin ^{ - 1}}x + {\sin ^{ - 1}}y = c is given by
View answer and explanation
Correct option: A
1−x2dy+1−y2dx=0\sqrt {1 - {x^2}} dy + \sqrt {1 - {y^2}} dx = 0
Option A (1−x2dy+1−y2dx=0\sqrt {1 - {x^2}} dy + \sqrt {1 - {y^2}} dx = 0) is correct because it is the differential equation obtained by differentiating the given equation and rearranging the terms.
273 Easy
273 of 494
Application +4 | -1
The differential equation of the family of curves y2=4a(x+a){y^2} = 4a\left( {x + a} \right), is
View answer and explanation
Correct option: B
y2(dydx)2+2xydydx−y2=0{y^2}{\left( {\frac{{dy}}{{dx}}} \right)^2} + 2xy\frac{{dy}}{{dx}} - {y^2} = 0
Option B (y2(dydx)2+2xydydx−y2=0{y^2}{\left( {\frac{{dy}}{{dx}}} \right)^2} + 2xy\frac{{dy}}{{dx}} - {y^2} = 0) is correct because it is the differential equation obtained by eliminating the parameter 'a' from the given family of curves.
274 Easy
274 of 494
Application +4 | -1
Solution of the differential equation x(dydx)2+2xydydx+y=0x\left(\frac{d y}{d x}\right)^2+2 \sqrt{x y} \frac{d y}{d x}+y=0, is
View answer and explanation
Correct option: D
x+y=a\sqrt{x}+\sqrt{y}=\sqrt{a}
Option D (x+y=a\sqrt{x}+\sqrt{y}=\sqrt{a}) is the correct solution obtained by recognizing the perfect square and integrating the resulting separable equation.
275 Easy
275 of 494
Application +4 | -1
Suppose y=y(x)y=y(x) satisfies the differential equation ydx+y2dy=xdyy d x+y^2 d y=x d y. If y(x)>0∀x∈Ry(x) > 0 \forall x \in \mathbf{R} and y(1)=1y(1)=1 then y(−3)y(-3) equals
View answer and explanation
Correct option: C
3
Option C (3) is correct because it is the value of y(-3) obtained by solving the given differential equation and applying the initial condition y(1)=1.
276 Easy
276 of 494
Application +4 | -1
y=4sin⁡3xy=4 \sin 3 x is a solution of the differential equation
View answer and explanation
Correct option: C
d2ydx2+9y=0\frac{d^2 y}{d x^2}+9 y=0
Option C (d2ydx2+9y=0\frac{{d^2 y}}{{d x^2}}+9 y=0) is correct because the second derivative of y=4sin⁡3xy=4 \sin 3x satisfies this differential equation.
277 Easy
277 of 494
Application +4 | -1
I.F. for yln⁡ydxdy+x−ln⁡y=0y \ln y \frac{d x}{d y}+x-\ln y=0 is
View answer and explanation
Correct option: B
ln⁡y\ln y
Option B (ln⁡y\ln y) is correct because the integrating factor is calculated as e∫Pdye^{\int P dy} where PP is the coefficient of xx after rewriting the equation in the standard form.
278 Easy
278 of 494
Understanding +4 | -1
The order and degree of the differential equation d2ydx2+(dydx)14+x15=0\frac{d^2 y}{d x^2}+\left(\frac{d y}{d x}\right)^{\frac{1}{4}}+x^{\frac{1}{5}}=0, respectively, are
View answer and explanation
Correct option: A
2 and not defined
Option A (2 and not defined) is correct because the order is the highest derivative (2), but the degree is not defined due to the fractional exponent on the first derivative.
279 Easy
279 of 494
Understanding +4 | -1
The differential equation of displacement of all "Simple harmonic motions" of given period 2π/n2 \pi / n, is
View answer and explanation
Correct option: B
d2xdt2+n2x=0\frac{d^2 x}{d t^2}+n^2 x=0
Option B (d2xdt2+n2x=0\frac{{d^2 x}}{{d t^2}}+n^2 x=0) is correct because it represents the standard differential equation for simple harmonic motion with angular frequency n.
280 Easy
280 of 494
Analyzing +4 | -1
If f(x)f(x) is differentiable function in the interoal (0,∞)(0, \infty) such that f(1)=1f(1)=1 and lim⁡t→xt2f(x)−x2f(t)t−x=1\lim\limits _{t \rightarrow x} \frac{t^2 f(x)-x^2 f(t)}{t-x}=1 for each x>0x>0, then f(32)f\left(\frac{3}{2}\right) is equal to
View answer and explanation
Correct option: D
3118\frac{31}{18}
Option D is correct because it is the value of f(3/2) obtained after solving the differential equation and applying the initial condition f(1)=1.
281 Easy
281 of 494
Application +4 | -1
If y=y(x)y=y(x) is the solution of the differential equation, ey=exe^y=e^x such that y(0)=0y(0)=0, then y(1)y(1) is equal to:
View answer and explanation
Correct option: A
1+log⁡e21+\log _e 2
Option A (1+log⁡e21+\log _e 2) is correct because it is the value of y(1) obtained after solving the given differential equation and applying the initial condition y(0) = 0.
282 Easy
282 of 494
Application +4 | -1
The differential equation for which y=acos⁡x+bsin⁡xy=a \cos x+b \sin x is a solution, is
View answer and explanation
Correct option: A
d2ydx2+y=0\frac{d^2 y}{d x^2}+y=0
Option A (d2ydx2+y=0\frac{d^2 y}{d x^2}+y=0) is correct because it is the differential equation that results from differentiating the given function twice.
283 Easy
283 of 494
Understanding +4 | -1
Degree of differential equation edy/dx=x{e^{dy/dx}} = x is
View answer and explanation
Correct option: A
1
Option A (1) is correct because after taking the natural logarithm, the highest order derivative is 1 and its power is 1.
284 Easy
284 of 494
Application +4 | -1
The differential equation of all circles passing through the origin and having their centres on xx-axis
View answer and explanation
Correct option: C
(x2−y2)+2xydydx=0\left(x^2-y^2\right)+2 x y \frac{d y}{d x}=0
Option C, (x2−y2)+2xydydx=0\left(x^2-y^2\right)+2 x y \frac{d y}{d x}=0, is the correct differential equation representing the family of circles passing through the origin and having their centers on the x-axis.
285 Easy
285 of 494
Understanding +4 | -1
Assertion: The differential equation x2=y2+xydydxx^2=y^2+x y \frac{d y}{d x} is an ordinary differential equation.

Reason: An ordinary differential equation involves derivatives of the dependent variable with respect to only one dependent variable.
View answer and explanation
Correct option: A
Assertion is correct, Reason is correct; Reason is a correct explanation for assertion.
Assertion is correct, Reason is correct; Reason is a correct explanation for assertion because the given equation involves derivatives of the dependent variable with respect to only one independent variable.
286 Easy
286 of 494
Understanding +4 | -1
The order of the differential equation (d2ydx2)3=(1+dydx)1/2\left(\frac{d^2 y}{d x^2}\right)^3=\left(1+\frac{d y}{d x}\right)^{1 / 2}
View answer and explanation
Correct option: A
2
Option A is correct because after squaring both sides to eliminate the fractional exponent, the highest order derivative is d2y/dx2, making the order 2.
287 Easy
287 of 494
Application +4 | -1
If the solution curve f(x,y)=0f(x, y)=0 of the differential equation (1+log⁡ex)dxdy−xlog⁡ex=ey,x>0\left(1+\log _{e} x\right) \frac{d x}{d y}-x \log _{e} x=e^{y}, x > 0, passes through the points (1,0)(1,0) and (α,2)(\alpha, 2), then aaa^{a} is equal to
View answer and explanation
Correct option: A
e2e2e^{2 e^{2}}
Option A (e2e2e^{2 e^{2}}) is correct because after solving the differential equation and applying the given conditions, we find aa=e2e2a^a = e^{2e^2}.
288 Easy
288 of 494
Application +4 | -1
An equation of the curve satisfying x dy−y dx=x2−y2 dxx \mathrm{~d} y-y \mathrm{~d} x=\sqrt{x^2-y^2} \mathrm{~d} x and y(1)=0y(1)=0 is
View answer and explanation
Correct option: B
y=xsin⁡(log⁡∣x∣)y=x \sin (\log |x|)
Option B (y=xsin⁡(log⁡∣x∣)y=x \sin (\log |x|)) is correct because it satisfies the given differential equation and the initial condition y(1)=0y(1)=0.
289 Easy
289 of 494
Application +4 | -1
A function y=f(x)y=f(x) satisfies the differential equation f(x)⋅sin⁡2x−cos⁡x+(1+sin⁡2x)f′(x)=0f(x) \cdot \sin 2 x-\cos x+\left(1+\sin ^2 x\right) f^{\prime}(x)=0 with initial condition y(0)=0y(0)=0. The value of f(π/6)f(\pi / 6) is equal to
View answer and explanation
Correct option: D
2/52 / 5
Option D, 2/52 / 5, is the correct value of f(π/6)f(\pi / 6) obtained by solving the given differential equation with the initial condition y(0)=0y(0)=0.
290 Easy
290 of 494
Application +4 | -1
If y=y(x)y=y(x) satisfies the differential equation 8x(9+x)dy=(4+9+x)−1dx,x>08 \sqrt{x}(\sqrt{9+\sqrt{x}}) d y=(\sqrt{4+\sqrt{9+\sqrt{x}}})^{-1} d x, x > 0 and y(0)=7y(0)=\sqrt{7}, then y(256)=y(256)=
View answer and explanation
Correct option: A
3
Option D ((x−C)ex+y+1=0(x-C)e^{x+y} + 1 = 0) is correct because it is the solution obtained by substituting x+y=vx+y=v and integrating the resulting equation.
291 Easy
291 of 494
Application +4 | -1
Solution of differential equation xdy+ydx=exy−ℓnx2(xdy−ydx)x d y+y d x=e^{x y-\ell n x^2}(x d y-y d x) is given by: (where C{C} is arbitrary constant)
View answer and explanation
Correct option: A
yx+e−xy=C\frac{y}{x}+e^{-x y}=C
Option A (yx+e−xy=C\frac{y}{x}+e^{-x y}=C) is the correct solution to the given differential equation, obtained by rearranging and integrating.
292 Easy
292 of 494
Application +4 | -1
A solution of the equation xdy dx=y(log⁡y−log⁡x+1)x \frac{\mathrm{d} y}{\mathrm{~d} x}=y(\log y-\log x+1) is
View answer and explanation
Correct option: A
y=xecty=x e^{c t}
Option A (y=xecxy=x e^{c x}) is correct because it satisfies the given differential equation after substituting y=vxy=vx and solving the resulting separable equation.
293 Easy
293 of 494
Application +4 | -1
Solution of dydx=x−y+3x+y+7\frac{d y}{d x}=\frac{x-y+3}{x+y+7} is
View answer and explanation
Correct option: A
x2−y2−2xy+6x−14y=cx^2-y^2-2 x y+6 x-14 y=c
Option A, x2−y2−2xy+6x−14y=cx^2-y^2-2 x y+6 x-14 y=c, is the correct solution obtained by rearranging the equation and integrating.
294 Easy
294 of 494
Application +4 | -1
The differential equation xdydx−y=x2x \frac{d y}{d x}-y=x^2, has the general solution
View answer and explanation
Correct option: B
2y−x3=Cx2 y-x^3=C x
Option B (2y−x3=Cx2 y-x^3=C x) is correct because it represents the general solution obtained after solving the given differential equation using the integrating factor method.
295 Easy
295 of 494
Understanding +4 | -1
The degree of the differential equation (d2ydx2)2+(dydx)2=xsin⁡(dydx)\left(\frac{d^2 y}{d x^2}\right)^2+\left(\frac{d y}{d x}\right)^2=x \sin \left(\frac{d y}{d x}\right) is
View answer and explanation
Correct option: D
not defined
Option D (not defined) is correct because the presence of the derivative inside the sine function makes it impossible to express the equation as a polynomial in derivatives.
296 Easy
296 of 494
Application +4 | -1
Solution of the differential equation ln⁡(dydx)=ax+\ln \left(\frac{d y}{d x}\right)=a x+ by is
View answer and explanation
Correct option: A
−1be−by=1aeax+c-\frac{1}{b} e^{-b y}=\frac{1}{a} e^{a x}+c
Option D (−1be−by=1aeax+c-\frac{1}{b} e^{-b y}=\frac{1}{a} e^{a x}+c) is the correct solution to the differential equation, obtained by separating variables and integrating.
297 Easy
297 of 494
Application +4 | -1
The solution of dydx=ax+bcy+d\frac{d y}{d x}=\frac{a x+b}{c y+d} represents a parabola if
View answer and explanation
Correct option: C
a=0,c≠0a=0, c \neq 0
Option C, a=0,c≠0a=0, c \neq 0, is correct because it results in an equation of the form cy2+dy=bx+Kcy^2 + dy = bx + K, which represents a parabola.
298 Easy
298 of 494
Application +4 | -1
The solution of x dyx2+y2=(yx2+y2−1)\frac{x \mathrm{~d} y}{x^2+y^2}=\left(\frac{y}{x^2+y^2}-1\right) dx\mathrm{d} x is
View answer and explanation
Correct option: C
y=xtan⁡(c−x)y=x \tan (c-x)
Option C (y=xtan⁡(c−x)y=x \tan (c-x)) is correct because it is the solution obtained by rewriting the given differential equation, separating variables, and integrating.
299 Easy
299 of 494
Application +4 | -1
The solution of the differential equation dydx=ex+y\frac{{dy}}{{dx}} = {e^{x + y}} is
View answer and explanation
Correct option: C
ex+e−y=c{e^x} + {e^{ - y}} = c
Option C (ex+e−y=c{e^x} + {e^{ - y}} = c) is correct because it is the solution to the given separable differential equation.
300 Easy
300 of 494
Application +4 | -1
The value of ∫0πsin⁡3xcos⁡2xdx\int_0^\pi \sin ^3 x \cos ^2 x d x is
View answer and explanation
Correct option: B
415\frac{4}{15}
Option B (415\frac{4}{15}) is correct because it uses the properties of trigonometric integrals and Wallis' formula to efficiently compute the definite integral.
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