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JEE • MATHEMATICS • DIFFERENTIAL EQUATIONS

Differential equations practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 494 questions
61 Easy
61 of 494
Application +4 | -1
The solution of (x−ycos⁡yx)dx+xcos⁡yxdy=0\left(x-y \cos \frac{y}{x}\right) d x+x \cos \frac{y}{x} d y=0, y(1)=0y(1)=0 is given by
View answer and explanation
Correct option: A
sin⁡yx+log⁡∣x∣=0\sin \frac{y}{x}+\log |x|=0
Option D (y sin(y/x) + log|x| = 0) is correct because it is the solution obtained by solving the homogeneous differential equation with the given initial condition.
62 Easy
62 of 494
Application +4 | -1
The solution of the differential equation xdydx+2y=x2(x≠0)x\frac{{dy}}{{dx}} + 2y = {x^2}(x \ne 0) with y(1)=1,y(1) = 1, is
View answer and explanation
Correct option: A
y=x24+34x2y = \frac{{{x^2}}}{4} + \frac{3}{{4{x^2}}}
Option A (y=x24+34x2y = \frac{{{x^2}}}{4} + \frac{3}{{4{x^2}}}) is correct because it is the solution to the differential equation after finding the integrating factor and applying the initial condition.
63 Easy
63 of 494
Application +4 | -1
The solution of the differential equation dydx+y=cos⁡x\frac{d y}{d x}+y=\cos x is
View answer and explanation
Correct option: A
y=12(cos⁡x+sin⁡x)+ce−xy=\frac{1}{2}(\cos x+\sin x)+c e^{-x}
Option A, y=12(cos⁡x+sin⁡x)+ce−xy=\frac{1}{2}(\cos x+\sin x)+c e^{-x}, is the correct solution because it satisfies the given first-order linear differential equation.
64 Easy
64 of 494
Understanding +4 | -1
The solution of the differential equation d2ydx2=−1x2\frac{d^2 y}{d x^2}=-\frac{1}{x^2} is
View answer and explanation
Correct option: A
y=log⁡x+c1x+c2y=\log x+c_1 x+c_2
Option A (y=log⁡x+c1x+c2y=\log x+c_1 x+c_2) is the correct solution obtained by integrating the given second-order differential equation twice.
65 Easy
65 of 494
Application +4 | -1
Solution of the differential equation y(xy+2x2y2)dx+x(xy−x2y2)dy=0y\left(x y+2 x^2 y^2\right) d x+x\left(x y-x^2 y^2\right) d y=0 is given by
View answer and explanation
Correct option: A
2log⁡∣x∣−log⁡∣y∣−1xy=C2 \log |x|-\log |y|-\frac{1}{x y}=C
Option A (2log⁡∣x∣−log⁡∣y∣−1xy=C2 \log |x|-\log |y|-\frac{{1}}{{x y}}=C) is the correct solution after simplifying and integrating the given differential equation.
66 Easy
66 of 494
Application +4 | -1
Let y=y(x)y = y(x) be the solution of the differential equation, dydx+ytan⁡x=2x+x2tan⁡x,x∈(−π2,π2)\frac{{dy}}{{dx}} + y\tan x = 2x + {x^2}\tan x,x \in \left( { - \frac{\pi }{2},\frac{\pi }{2}} \right), such that y(0)=1. Then
View answer and explanation
Correct option: A
y′(π4)−y′(−π4)=π−2y'\left( {\frac{\pi }{4}} \right) - y'\left( { - \frac{\pi }{4}} \right) = \pi - \sqrt 2
Option A (y′(π4)−y′(−π4)=π−2y'(\frac{\pi}{4}) - y'(-\frac{\pi}{4}) = \pi - \sqrt 2) is correct because it results from solving the differential equation and evaluating the derivative at the given points.
67 Easy
67 of 494
Application +4 | -1
The solution of the differential equation cos⁡xsin⁡y dx+sin⁡xcos⁡y dy=0\cos x \sin y \,d x+\sin x \cos y \,d y=0, is
View answer and explanation
Correct option: D
sin⁡xsin⁡y=C\sin x \sin y=C
Option D (sin⁡xsin⁡y=C\sin x \sin y = C) is correct because it is the result of recognizing the differential equation as an exact differential and integrating.
68 Easy
68 of 494
Application +4 | -1
The solution of log⁡(dydx)=ax+by\log \left( {\frac{{dy}}{{dx}}} \right) = ax + by is
View answer and explanation
Correct option: B
e−by−b=eaxa+c\frac{{{e^{ - by}}}}{{ - b}} = \frac{{{e^{ax}}}}{a} + c
Option B (e−by−b=eaxa+c\frac{{{e^{ - by}}}}{{ - b}} = \frac{{{e^{ax}}}}{a} + c) is correct because it is the solution obtained by separating variables and integrating the given differential equation.
69 Easy
69 of 494
Understanding +4 | -1
y=c1ex−c2e−xy=c_1 e^x-c_2 e^{-x} is the general solution of a differential equation. The order of the differential equation is , where c1c_1 and c2c_2 are arbitrary constants.
View answer and explanation
Correct option: C
2
Option C (2) is correct because the general solution contains two arbitrary constants, implying a second-order differential equation.
70 Easy
70 of 494
Analyzing +4 | -1
If c1,c2,c3,c4,c5{c_1},{c_2},{c_3},{c_4},{c_5} and c6{c_6} are constants, then the order of the differential equation whose general solution is given by
y=c1cos⁡(x+c2)+c3sin⁡(x+c4)+c5ex+c6y = {c_1}\cos (x + {c_2}) + {c_3}\sin (x + {c_4}) + {c_5}{e^x} + {c_6} is
View answer and explanation
Correct option: C
4
Option C (4) is correct because the given expression can be simplified to contain four independent arbitrary constants, thus the order of the differential equation is 4.
71 Easy
71 of 494
Application +4 | -1
If x2+y2=1x^2+y^2=1, then [\left[\right. Note :y′=dydx,y′′=d2ydx2]\left.: y^{\prime}=\frac{\mathrm{dy}}{\mathrm{dx}}, \mathrm{y}^{\prime \prime}=\frac{\mathrm{d}^2 \mathrm{y}}{\mathrm{dx}^2}\right]
View answer and explanation
Correct option: B
yy′′+(y′)2+1=0y y^{\prime \prime}+\left(y^{\prime}\right)^2+1=0
Option B (yy′′+(y′)2+1=0y y^{\prime \prime}+(y^{\prime})^2+1=0) is correct because it is the result of differentiating the given equation twice and eliminating x.
72 Easy
72 of 494
Analyzing +4 | -1
Let the solution curve y=y(x)y = y\left( x \right) of the differential equation
[xx2−y2+eyx]xdydx=x+[xx2−y2+eyx]y\left[ {\frac{x}{{\sqrt {{x^2} - {y^2}} }} + {e^{\frac{y}{x}}}} \right]x\frac{{dy}}{{dx}} = x + \left[ {\frac{x}{{\sqrt {{x^2} - {y^2}} }} + {e^{\frac{y}{x}}}} \right]y
pass through the points (1, 0) and (2α,α),  α>0.\left( {2\alpha ,\alpha } \right),\,\,\alpha > 0. Then α\alpha is equal to
View answer and explanation
Correct option: A
12exp⁡(π6+e−1)\frac{1}{2}\exp \left( {\frac{\pi }{6} + \sqrt e - 1} \right)
Option A (12exp⁡(π6+e−1)\frac{1}{2}\exp \left( {\frac{\pi }{6} + \sqrt e - 1} \right)) is correct because it is the solution obtained by solving the given differential equation with the provided initial conditions.
73 Easy
73 of 494
Application +4 | -1
If dydx=f(x)+∫01f(x)dx\frac{d y}{d x}=f(x)+\int_0^1 f(x) d x, then the equation of the curve y=f(x)y=f(x) passing through (0,1)(0,1) is
View answer and explanation
Correct option: A
f(x)=2ex−e+13−ef(x)=\frac{2 e^x-e+1}{3-e}
Option A (f(x)=2ex−e+13−ef(x)=\frac{2 e^x-e+1}{3-e}) is correct because it satisfies the given differential equation and the initial condition.
74 Easy
74 of 494
Application +4 | -1
The elimination of the arbitrary constant mm from the equation y=emxy=e^{m x} gives the differential equation
View answer and explanation
Correct option: C
dydx=(yx)log⁡y\frac{d y}{d x}=\left(\frac{y}{x}\right) \log y
Option C (dydx=(yx)log⁡y\frac{{d y}}{{d x}}=\left(\frac{{y}}{{x}}\right) \log y) is correct because eliminating 'm' from y=emxy=e^{mx} leads to this differential equation.
75 Easy
75 of 494
Understanding +4 | -1
The degree of the differential equation y32/3+2+3y2+y1=0y_3^{2/3} + 2 + 3{y_2} + {y_1} = 0, is
View answer and explanation
Correct option: B
2
Option B (2) is correct because after raising to the power of 3 to eliminate the fractional exponent, the power of the highest order derivative becomes 2.
76 Easy
76 of 494
Application +4 | -1
General solutions of y′=ey/x+y/xy^{\prime}=e^{y / x}+y / x is
View answer and explanation
Correct option: B
log⁡∣Cx∣=−e−y/x\log |C x|=-e^{-y / x}
Option B (log⁡∣Cx∣=−e−y/x\log |C x|=-e^{-y / x}) is correct because it is the general solution to the given differential equation.
77 Easy
77 of 494
Understanding +4 | -1
Which of the following statements on ordinary differential equations is/are true?
(i) The number of arbitrary constants is same as the degree of the differential equation.
(ii) A linear differential equation can contain products of the dependent variable and its derivatives.
(iii) A particular integral cannot contain arbitrary constants.
(iv) By putting v=yxv=\frac{y}{x} any homogeneous first order differential equation transforms to variable separable form.
View answer and explanation
Correct option: C
(iii) only
Option C ((iii) only) is correct because only statement (iii) is true; a particular integral cannot contain arbitrary constants.
78 Easy
78 of 494
Application +4 | -1
The differential equation of the family of lines through the origin, is
View answer and explanation
Correct option: A
xdydx−y=0x \frac{d y}{d x}-y=0
Option A (xdydx−y=0x \frac{d y}{d x}-y=0) is correct because it represents the differential equation of the family of lines through the origin.
79 Easy
79 of 494
Application +4 | -1
Which of the following transformation reduce the differential equation dz dx+zxlog⁡z=zx2(log⁡z)2\frac{\mathrm{d} z}{\mathrm{~d} x}+\frac{z}{x} \log z=\frac{z}{x^2}(\log z)^2 into the form du dx+uP(x)=Q(x)\frac{\mathrm{d} u}{\mathrm{~d} x}+u P(x)=Q(x)
View answer and explanation
Correct option: C
u=ezu=e^z
Option B (u=(log⁡z)−1u=(\log z)^{-1}) is correct because it transforms the given differential equation into a linear form suitable for solving.
80 Easy
80 of 494
Understanding +4 | -1
The differential equation of the family of non-vertical lines is .......
View answer and explanation
Correct option: A
d2ydx2=0\frac{d^2 y}{d x^2}=0
Option A (d2ydx2=0\frac{d^2 y}{d x^2}=0) is correct because the general equation of a non-vertical line is y = mx + c, and its second derivative is zero.
81 Easy
81 of 494
Application +4 | -1
If y=asin⁡(5x+c)y = a\sin (5x + c), then
View answer and explanation
Correct option: C
d2ydx2=−25y\frac{{{d^2}y}}{{d{x^2}}} = - 25y
Option C (d2ydx2=−25y\frac{{{d^2}y}}{{d{x^2}}} = - 25y) is correct because the second derivative of the given function equals -25 times the original function.
82 Easy
82 of 494
Application +4 | -1
Let y=y(x)y=y(x) be the solution of the differential equation x3dy+(xy−1)dx=0,x>0,y(12)=3−ex^{3} d y+(x y-1) d x=0, x>0, y\left(\frac{1}{2}\right)=3-e. Then y(1)y(1) is equal to
View answer and explanation
Correct option: D
1
Option D (1) is correct. The solution involves solving a first-order linear differential equation and using the given initial condition.
83 Easy
83 of 494
Application +4 | -1
A solution of y=xy′−3y′3y=x y^{\prime}-3 y^{\prime 3} is
View answer and explanation
Correct option: C
y=x−3y=x-3
The correct answer is C (y=x-3) because it satisfies the given Clairaut's equation y=xy'-3y'^3 when y'=1.
84 Easy
84 of 494
Analyzing +4 | -1
If the curve y=y(x)y = y(x) is the solution of the differential equation
2(x2+x5/4)dy−y(x+x1/4)dx=2x9/4dx,  x>02({x^2} + {x^{5/4}})dy - y(x + {x^{1/4}})\mathrm{ }dx = 2{x^{9/4}}dx,\,\,x > 0 which passes through the point (1,  1−43log⁡e2)\left( {1,\,\,1 - \frac{4}{3}{{\log }_e}2} \right),then the value of y(16)y(16) is equal to
View answer and explanation
Correct option: C
4(313−83log⁡e3)4\left( {\frac{{31}}{3} - \frac{8}{3}{{\log }_e}3} \right)
Option C (4\left( {\frac{{31}}{3} - \frac{8}{3}{{{\log }_e}3} \right)4\left( {\frac{{31}}{3} - \frac{8}{3}{{{\log }_e}3} \right)) is correct because it is the result of solving the given differential equation and applying the provided initial condition to find y(16).
85 Easy
85 of 494
Application +4 | -1
The value of the constant ' mm ' and ' cc ' for which y=mx+cy=m x+c is a solution of the differential equation D2y−3Dy−4y=−4xD^2 y-3 D y-4 y=-4 x.
View answer and explanation
Correct option: B
is m=1;c=−3/4m=1 ; c=-3 / 4
Option B (m=1 ; c=-3 / 4) is correct because substituting these values into the differential equation satisfies the given condition.
86 Easy
86 of 494
Application +4 | -1
If y=cesin⁡−1xy=ce^{\sin ^{-1} x}, then corresponding to this the differential equation is
View answer and explanation
Correct option: A
dydx=y1−x2\frac{d y}{d x}=\frac{y}{\sqrt{1-x^2}}
Option A (dydx=y1−x2\frac{{d y}}{{d x}}=\frac{{y}}{{\sqrt{{1-x^2}}}}) is correct because the derivative of y=cesin⁡−1xy=ce^{\sin^{{-1}}x} satisfies this equation.
87 Easy
87 of 494
Application +4 | -1
When x=0,y=1x=0, y=1 the particular solution of the differential equation (1+y2)dx+(1+x2)dy=0\left(1+y^2\right) d x+\left(1+x^2\right) d y=0 is
View answer and explanation
Correct option: B
x+y+xy−1=0x+y+x y-1=0
Option B, x+y+xy−1=0x+y+x y-1=0, is the correct particular solution obtained by solving the differential equation and applying the given initial condition.
88 Easy
88 of 494
Understanding +4 | -1
Statement 1: The degrees of the differential equations dydx+y2=x\frac{d y}{d x}+y^2=x and d2ydx2+y=sin⁡x\frac{d^2 y}{d x^2}+y=\sin x are equal.

Statement 2: The degree of a differential equation, when it is a polynomial equation in derivatives, is the highest positive integral power of the highest order derivative involved in the differential equation, otherwise degree is not defined.
View answer and explanation
Correct option: D
Statement 1 is true, Statement 2 is true; Statement 2 is a correct explanation of Statement 1 .
Option D (Statement 1 is true, Statement 2 is true; Statement 2 is a correct explanation of Statement 1) is correct because both statements are true and statement 2 correctly explains statement 1.
89 Easy
89 of 494
Application +4 | -1
The differential equation of the family of parabolas having vertex at the origin and the yy-axis as the axis of symmetry, is
View answer and explanation
Correct option: C
xy1−2y=0x y_1-2 y=0
Option C (xy1−2y=0x y_1-2 y=0) is correct because it represents the differential equation of the given family of parabolas.
90 Easy
90 of 494
Application +4 | -1
The general solution of y′+sin⁡x+y2=sin⁡x−y2y^{\prime}+\sin \frac{x+y}{2}=\sin \frac{x-y}{2} is
View answer and explanation
Correct option: C
log⁡∣tan⁡(y/4)∣=C−2sin⁡x/2\log |\tan (y / 4)|=C-2 \sin x / 2
Option C (log⁡∣tan⁡(y/4)∣=C−2sin⁡x/2\log |\tan (y / 4)|=C-2 \sin x / 2) is correct because it is the general solution of the given differential equation.
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